By your comments on the question, you said:

when I try to access the name I have the return " Undefined index: name

This is because the array in the position [13] does not have the index name. To fix this, you can put your foreach as follows:

<?php foreach($menu as $m): ?>                  
    <a class="nav-item nav-link" data-toggle="tab" href="#nav-file"><?php echo (isset($m['name'])) ? $m['name'] : ''; ?></a>                                 
<?php endforeach; ?>

In this way, your code will check if there is the index to print, if there is no, it ignores and prints empty.

No one knows for sure how Google’s algorithm verifies domains and properties to rank each one, but of course it’s not based on one and another technique. It is also known that Google cares a lot for the user's experience when accessing something, from speed to readability, in short, the usability as a whole, so I think the following, maybe it's not the correct answer (but as no one knows Google's algorithm can't say it's wrong), but for me it follows that logic.

If you follow some parameters and test some points in each question, you can reach a favorable solution in every way. So think:

• Which of the links would be more interesting/easy for the user write/decorate/access

• See if there is a significant difference in performance between two methods.

If there are, compare other points for other metrics as well. And remember, it's no good to have a cute link and it's a wagon pulled by a dummy, maximize all possible points ever.

I wonder if there is how to send message to WhatsApp via site. Example: The customer is there on the site and there is a field to enter a message and click on "send" and I receive the message on my WhatsApp.

Both.

There is https://en.wikipedia.org/wiki/Java_(programming_language) and a platform that people call Java too. It may be a bit confusing, but almost always the distinction is not important. Anyway I think I better use https://en.wikipedia.org/wiki/Java_(software_platform) when you're talking about the platform.

Platform is not necessarily a technology, the platform is composed of various technologies.

The programming language is no longer a technology. Technology is knowledge, it is a tool that uses a certain knowledge. The Java language is not the only one used on the Java platform.

There is also a VM called https://en.wikipedia.org/wiki/Java_virtual_machine that is part of the platform.

   try {

           public void remover(T objeto) {
            manager.getTransaction().begin() ;
            Object  o = manager.merge(objeto);
            manager.remove(o);
            manager.getTransaction().commit();
         }

 } catch (Exception ex) {
    ex.printStackTrace();                          
    manager.getTransaction().rollback();                         
 }

You can try another option!

manager.remove( manager.find(seuObjeto.class, id) );

If the other option does not work, try yes! if you have a method that searches for id you can use it to replace the manager.find().

Good morning, the mistake is in the bootstrap installation. To use the bootstrap you will need to install some other packages.

I recommend you reinstall the packages with the following command:

npm install bootstrap@4.0.0-beta.3 --save
npm install jquery --save
npm install popper.js --save
npm install tether --save

And after, just declare the style sheets in angular-cli.json of the packages, and should follow the order below:

"styles": [
    "../node_modules/bootstrap/dist/css/bootstrap.min.css",
    "styles.css"
  ],
  "scripts": [
    "../node_modules/popper.js/dist/umd/popper.js",
    "../node_modules/tether/dist/js/tether.min.js",
    "../node_modules/jquery/dist/jquery.min.js",
    "../node_modules/bootstrap/dist/js/bootstrap.min.js"
  ],

I hope you helped:D

I'm in demand for a php system.

I am listing documents from a given directory that is on the server on my html page

  <div class="tab-pane" id="docs">
                    &lt;div class="table-responsive"&gt;
                        &lt;table class="table"&gt;
                            &lt;thead&gt;
                                &lt;tr&gt;
                                    &lt;th&gt;Documento&lt;/th&gt;


                                &lt;/tr&gt;
                            &lt;/thead&gt;
                            &lt;tbody&gt;
                                &lt;?php
                                $result = mysql_query("SELECT * FROM gr_documento 
                                                                                                                    WHERE id_entidade_documento = ". $_GET['id']."
                                                                                                                    AND tipo = 1");
                                while ($row = mysql_fetch_array($result)) {                               
                                ?&gt;

                                &lt;tr&gt;
                                                                            &lt;td&gt;&lt;a href="/upload/docs/&lt;?php echo $row['novo_nome']?&gt;" target=“_blank” &gt;&lt;?php echo $row['nome_documento']?&gt;&lt;/a&gt;&lt;/td&gt;

                                &lt;/tr&gt;

                                 &lt;?php
                                 }
                                 ?&gt;

                            &lt;/tbody&gt;
                        &lt;/table&gt;
                    &lt;/div&gt;


                        &lt;/div&gt;

I wonder if it is possible for me to create a column on the left only by appearing an icon as the extension. Ex:

If the file has the .pdf extension display an icon attached to the PDF
If the file has the .xls extension display an icon attached to Excel
If the file has the .doc extension display an icon linked to Word
If the file has the .txt extension display an icon attached to the TXT

I do not know if there is any function that performs this process. Can you help me?

It follows code that I use in one of legacy apps, but solves your problem. You will put it along onActivityResult:

Bitmap img = (Bitmap)data.getExtras().get("data");
ByteArrayOutputStream stream = new ByteArrayOutputStream();

img.compress(Bitmap.CompressFormat.JPEG, 100, stream);

String foto = Base64.encodeToString(stream.toByteArray(), Base64.DEFAULT);

Just be careful with the request size, many web servers limit the size of the request.

I created an administrator page where I register the book data in the database. I did this html where this data will be shown. the matrix will create this "cabtitulo" block with all books registered on the admin pages, but I would like it to be visible only 4 of these blocks. so I put it down there, the background-color:green function, to check if my code worked, if it worked, I would put a display leaving these other blocks invisible. but all the blocks become green, not the larger than 3, as I define.

<div class="cabtitulo"><p>Promoções</p></div>
<?php 
$comando="select * from tb_promocao";
$matriz=mysql_query($comando);
$contador = 0;
while ($contador<4) {

while ($linha=mysql_fetch_array($matriz)) {

?>
<article class="livro">

<?php echo '<img src="img/' .$linha["imagempromo"]. '.jpg">'; ?>

<p><span class="titulo"><?php echo $linha["titulopromo"]; ?></span><br>

<span class="precode">R$ <?php echo $linha["precodelivro"]; ?></span><span class="preco">R$ <?php echo $linha["precoparalivro"]; ?></span><br><br></p>

<button>adicionar<i class="fa fa-shopping-cart" aria-hidden="true"></i></button>

<a href="">ver mais</a>

<h2><?php echo $contador; ?></h2>

</article>

<?php

$contador++;

}//close matriz
}//close contador
while ($contador>=3) {

echo '<style> .livro{ background-color:green;}</style>';

}
?>

Three Alternatives I found and worked:

First Alternative: Different Shaders

Use a different shader for objects with speculative and diffuse texture, and another shader for objects with only the diffuse texture.

Perhaps it is the best alternative if there is no need to create a realistic scene, that is, without the texture speculating on some objects. In addition to making graphic processing more robust.

Obs: Not all real-life materials have significant speculative behavior.

Second Alternative: Use Diffuse Texture as Specular

During the time of binding the textures you can check if the object has some speculative texture, if it does not, vincule the diffuse textures with the name of the speculative textures.

In this option you will simulate a speculative lighting. It will not result in something realistic but will not generate defects in lighting.

Obs: As in most speculative textures are obtained from the diffuse, it is possible to convert the diffuse image into gray tones to use as speculation. Third Alternative: Change the object

Using Blender, Maia, 3Ds Max, or any other editor, you can import the object, add a speculative texture (reusing the same mapping) and export the edited object

It is the most correct option if you want to ensure that all objects have speculative texture.

Below an example by adding the speculative texture to the object using Blender.