I'm with a college exercise, but I'm lost in my logic and how to solve it. I have to collect the game results and set the score for each result. the winner takes 3 points, a draw guarantees 1 point and the defeat not from any point.

I know I don't have much yet but I wrote it here:

Obs: The teacher asks you to use only two-dimensional string arrays!

(Define a two-dimensional array of Strings representing the results of matches. and a four-element array of ints representing scores of teams of Germany, Ireland,Poland and Scotland (in this order). The program calculates total score for each team (3 points for a win, 1 for a draw, 0 for a defeat), puts them into the array and then prints it)

Obs2: this English only because I study and live in Poland and the course and in English.

public class Jogos {
public static void main(String[] args) {
String [][] resultados = new String[12][4];

resultados [0][0]="Alemanha";
resultados [0][1]=2;
resultados [0][2]="Escocia";
resultados [0][3]=1;

resultados [1][0]="Polonia";
resultados [1][1]=2;
resultados [1][2]="Alemanha";
resultados [1][3]=0;

resultados [2][0]="Alemanha";
resultados [2][1]=1;
resultados [2][2]="Irlanda";
resultados [2][3]=1;

resultados [3][0]="Polonia";
resultados [3][1]=2;
resultados [3][2]="Escocia";
resultados [3][3]=2;

resultados [4][0]="Escocia";
resultados [4][1]=1;
resultados [4][2]="Irlanda";
resultados [4][3]=0;

resultados [5][0]="Irlanda";
resultados [5][1]=1;
resultados [5][2]="Polonia";
resultados [5][3]=1;

resultados [6][0]="Irlanda";
resultados [6][1]=1;
resultados [6][2]="Escocia";
resultados [6][3]=1;

resultados [7][0]="Alemanha";
resultados [7][1]=3;
resultados [7][2]="Polonia";
resultados [7][3]=1;

resultados [8][0]="Escocia";
resultados [8][1]=2;
resultados [8][2]="Alemanha";
resultados [8][3]=3;

resultados [9][0]="Irlanda";
resultados [9][1]=1;
resultados [9][2]="Alemanha";
resultados [9][3]=0;

resultados [10][0]="Escocia";
resultados [10][1]=2;
resultados [10][2]="Polonia";
resultados [10][3]=2;

resultados [11][0]="Polonia";
resultados [11][1]=2;
resultados [11][2]="Irlanda";
resultados [11][3]=1;

for (int i=0; i<resultados.length; i++){
  for (int j=0; j<resultados[i].length; j++){
    System.out.print(resultados[i][j] + " - ");
  }
  System.out.println();
}

}

}

Modifying the values

First store the Hash in a variable

meu_hash = {
    [ "Begin", "Dom" ] => 0,
    [ "Begin", "Seg" ] => 8,
    [ "Begin", "Ter" ] => 10,
    [ "Begin", "Qua" ] => 30,
    [ "Begin", "Qui" ] => 20,
    [ "Begin", "Sex" ] => 1,
    [ "Begin", "Sáb" ] => 0,
    [ "Finish", "Dom" ] => 0,
    [ "Finish", "Seg" ] => 1,
    [ "Finish", "Ter" ] => 0,
    [ "Finish", "Qua" ] => 0,
    [ "Finish", "Qui" ] => 0,
    [ "Finish", "Sex" ] => 0,
    [ "Finish", "Sáb" ] => 0
}

Then create a loop to modify the values for whatever you want and ready! See:

meu_hash.each_key do |key|
  meu_hash[key] = 5
end

I used it Hash#each_key since I didn't need it value the Hash during the loop. If you are using, use Enumerable#each in this way:

meu_hash.each do |key, value|
  meu_hash[key] = value * 5
end

You can also opt for Enumerable#map, but I do not like this solution in Hash, since it does not modify or return a Hash:

novo_hash = Hash[meu_hash.map {|key, value| [key, value * 5]}]

This form is pure because it does not affect meu_hash, creating a new instance.

Leaving the code a little more idiom

You can use a shortcut to create an array of strings, https://stackoverflow.com/questions/1274675/what-does-warray-mean . It would be like this:

meu_hash = {
  %w[Begin Dom] => 0,
  %w[Begin Seg] => 8,
  %w[Begin Ter] => 10,
  %w[Begin Qua] => 30,
  %w[Begin Qui] => 20,
  %w[Begin Sex] => 1,
  %w[Begin Sáb] => 0,
  %w[Finish Dom] => 0,
  %w[Finish Seg] => 1,
  %w[Finish Ter] => 0,
  %w[Finish Qua] => 0,
  %w[Finish Qui] => 0,
  %w[Finish Sex] => 0,
  %w[Finish Sáb] => 0
}

I'm getting data from one https://api.coinmarketcap.com/v1/ticker/ and I intend to make a check if percent_change_1h is less than 0, and if so it presents a different text color.

  <ion-row>
    <ion-col>
      <ion-label ng-if="top.percent_change_1h < 0" style="color: #b21a91;">
        <b>1H: </b>{{top.percent_change_1h}}
      </ion-label>
      <ion-label ng-if="top.percent_change_1h > 0">
        <b>1H: </b>{{top.percent_change_1h}}
      </ion-label>
    </ion-col>
  </ion-row>

How can I make this comparison process, in case it is less than 0 present a color, and if it is greater or equal to zero present another?

Perhaps your command echo be interpreting the value of the REMOTE_HOST variable.

echo 'xdebug.remote_host='${REMOTE_HOST};

After creating the image, probably, php.ini should be staying like this:
xdebug.remote_host=abcd

And you want him to look like this:
xdebug.remote_host=${REMOTE_HOST}

Try to place the variable inside the simple quotes or try to make an escape from the special character "$" of the variable so that the final result is as in the line above:
echo 'xdebug.remote_host=${REMOTE_HOST}';

Installation of the license

A license has two information: "Owner" and "Key". This information should be stored in a file called LICENSE.INI, located in the folder where is the DYNCRYPTO.DLL file.

1) Open Notepad

2) Copy and paste in Notepad the text below by changing the license information (Owner and Key) as per your case:

--- begin of  file ---
[License]
Owner = 30 Days Evaluation

Key = KKkNLxYEj6VXd1WEF9+fvrXA4yAPvtpz7vSHFWnGNn8=
--- end of file ---

(3) Save the file with the name LICENSE. INI in the same folder where is the DYNCRYPTO file. DLL

More information you find in http://www.dyncrypto.com/Installation.htm .

Galera, good afternoon! I'm having a hard time consulting down. I want you to bring all the tasks only when the salary (lack field) is equal to the month after the opening date (tardata). But nothing came in the consultation.

select * 
from Tarefa 
where TarID = 173151 
    and MONTH(TarVencimento) = DATEADD(MONTH,1,TarData)

I would like to pass the mouse over a table cell the column and the respective cell line to change the background only until the cell. follow an example of how this and how I want you to stay:

<!DOCTYPE html>
<html>
<head>
</head>
<body>
<table>

<tr>

<th>Company</th>

<th>Contact</th>

<th>Country</th>

</tr>

<tr>

<td>Alfreds Futterkiste</td>

<td>Maria Anders</td>

<td>Germany</td>

</tr>

<tr>

<td>Centro comercial Moctezuma</td>

<td>Francisco Chang</td>

<td>Mexico</td>

</tr>

<tr>

<td>Ernst Handel</td>

<td>Roland Mendel</td>

<td>Austria</td>

</tr>

<tr>

<td>Island Trading</td>

<td>Helen Bennett</td>

<td>UK</td>

</tr>

<tr>

<td>Laughing Bacchus Winecellars</td>

<td>Yoshi Tannamuri</td>

<td>Canada</td>

</tr>

<tr>

<td>Magazzini Alimentari Riuniti</td>

<td>Giovanni Rovelli</td>

<td>Italy</td>

</tr>

</table>
</body>

</html>

In that case my mouse was about Helen Bennett

I have the following function:

public requisicaoXPTA() {
  this.database.executeSql("SELECT * FROM tbl_xpta",
      []).then((data) => {
      // o resultado retorna aqu na variável data
  }, (error) => {
    console.log(error);    

});

}

Qndo I will use this function I do this way:

this.requisicaoXPTA();

this.atualizar();

Most often, the function atualizar() is executed before requisicaoXPTA(). I would like to perform the function atualizar() after having made the request in the table. What better way to do this synchronously?

After the statement

int[ ] a;

what is stored in the variable a? null or an indefinite value where a cannot be used until something is assigned to it?

I have a contact list and I need it to be removed duplicates, I was trying to solve using the code below:

Elemento* remove_duplicados(Elemento* agenda)
{
    Elemento* a = NULL; //POnteiro do Elemento anterior
    Elemento* p;
    Elemento* q;
for(p = agenda; p != NULL; p = p -> prox){//Analisa do primeiro elem até o ultimo
    for(q = p -> prox; q != NULL; q = q -> prox){//Analisa proximo elem de p até o fim
        if(0 != strcmp(p -> info.nome, q -> info.nome)){
            a = q; 
        }
    }

    if(a == NULL){ //Remove elemento do início e aponta para o 2º
        agenda = p -> prox;
    } 
    else
        a -> prox = p -> prox; //Ponteiro anterior levará para o prox

    free(p); //Libera o espaço
}
return agenda;

}

The problem is that when running the program, when arriving at this stage it ends:/