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How is it right to fill and load Procfile bot with a telegram on Heroku?

Demir last edited by

Why, after loading, Procfile continues to write: Warning: Your application is missing a Procfile. This file tells Heroku how to run your application. ?

That's the file:
Contained Procfile:
web: python main.py
Why is this happening? How do you do it right?
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Bogopo last edited by

Procfile should be without expansion .txt For example, you can keep the file in the notebook, the name of the file in the quote, the type-- all the files. ♪"
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How, with the Powers Command, hell Invoke-WebRequest load the telegram bot api file?
Software Programming • powershell bot telegram api • • Saumya

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Could not create SSL/TLS secure channelI'm guessing the problem is that PowerShell can't verify the validity of the certificate. Try adding the next code before the challenge. Invoke-Webrequest:# Make invoke-webrequest to ignore cert check add-type @" using System.Net; using System.Security.Cryptography.X509Certificates; public class TrustAllCertsPolicy : ICertificatePolicy { public bool CheckValidationResult( ServicePoint srvPoint, X509Certificate certificate, WebRequest request, int certificateProblem) { return true; } } "@ [System.Net.ServicePointManager]::CertificatePolicy = New-Object TrustAllCertsPolicy It helped me, really, in the reverse situation, it had to be downloaded from https to circumvent the certificate. I don't know how it works backwards.
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Establishment of a long-distance window for GUI
Software Programming • python pyqt5 gui pyqt qthread • • Raziyah00

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A long function must be performed in an additional flow from which you transmit some data to the main flow and visualize them there.import sys from PyQt5 import QtCore, QtWidgets, QtGui class Ui_MainWindow(object): def setupUi(self, MainWindow): MainWindow.setObjectName("MainWindow") self.centralwidget = QtWidgets.QWidget(MainWindow) self.horizontalLayout = QtWidgets.QHBoxLayout(self.centralwidget) self.table = QtWidgets.QTableWidget(self.centralwidget) self.table.setRowCount(0) self.table.setColumnCount(1) self.horizontalLayout.addWidget(self.table) self.btn1 = QtWidgets.QPushButton(self.centralwidget) self.btn1.setText('Start thread') self.horizontalLayout.addWidget(self.btn1) MainWindow.setCentralWidget(self.centralwidget) QtCore.QMetaObject.connectSlotsByName(MainWindow) +++ vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv class WorkThread(QtCore.QThread): threadSignal = QtCore.pyqtSignal(int) def __init__(self, numStart, numEnd): super().__init__() self.numStart = numStart self.numEnd = numEnd def run(self): for i in range(self.numStart, self.numEnd): self.msleep(100) # имитируем длительную загрузку self.threadSignal.emit(i) self.finished.emit() +++ ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ class StartingWindow(QtWidgets.QMainWindow): def init(self): super(StartingWindow, self).init() self.ui = Ui_MainWindow() self.ui.setupUi(self) self.ui.btn1.clicked.connect(self.add_row) self.thread = None self.numStart = 0 self.numEnd = 1_000_000 def add_row(self): self.label = QtWidgets.QLabel() self.label.setAttribute(QtCore.Qt.WA_TranslucentBackground, True) self.label.setWindowFlags( self.windowFlags() | QtCore.Qt.FramelessWindowHint | QtCore.Qt.WindowStaysOnTopHint ) self.label.setText('Ожидайте заавершения операции') self.movie = QtGui.QMovie('loading.gif') self.label.setMovie(self.movie) self.movie.start() self.label.show() if self.thread is None: self.thread = WorkThread(self.numStart, self.numEnd) self.thread.threadSignal.connect(self.on_threadSignal) self.thread.finished.connect(self.threadFinished) self.thread.start() self.ui.btn1.setText("Stop thread") else: self.label.close() self.thread.terminate() self.thread = None self.ui.btn1.setText("Start thread") self.numStart += 1 def on_threadSignal(self, num): rows = self.ui.table.rowCount() self.ui.table.insertRow(rows) item = QtWidgets.QTableWidgetItem(f"example1 {num}") self.ui.table.setItem(rows, 0, item) self.numStart = num def threadFinished(self): self.movie.stop() self.label.close() self.thread = None self.ui.btn1.setText("Start thread") if self.numStart+1 == self.numEnd: self.numStart = 0 if name == 'main': app1 = QtWidgets.QApplication(sys.argv) start_win = StartingWindow() start_win.show() sys.exit(app1.exec_())
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List in csv
Software Programming • python python 3.x csv • • Saumya

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It's a pretty weird requirement to record the data in one column in the sv file. ♪ https://ru.wikipedia.org/wiki/CSV This is the format of the table presentation in the form of a text file, where each line is divided into a field by a certain sectioner (e.g. a comma). For example, a rolling stackoverflow list with the number of questions asked could begin as follows:php;12557;18;78 javascript;8419;13;84 java;6435;9;59 So, if there's only one column in the sv-fail, the task would have been different from "help the elements of the list into the file, every new line." There's nothing to separate.However, the author sees: Вывести список в одну колонку csv It's like this:import csv data = ['5', '18', '0', '0', '0', '0', '2', '0', '0', '0', '0', '0', '0'] with open('list_to_csv.csv', 'w', newline='') as csv_file: csv_writer = csv.writer(csv_file) for item in data: csv_writer.writerow([item])
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Telegram-bot with multiple users
Software Programming • python • • fbio

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You did it with your hands.user = {} class user_pojo(): login = '' password = '' up = '' def init(self, login, password, up): self.login = login self.password = password self.up = up def set_login(self, login): self.login = login def set_password(self, password): self.password = password def set_up(self, up): self.up = up
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How to check if a string is within a string set?
Software Programming • python python 3. x • • Saumya

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I didn't quite understand the part of "use string as value", but it's possible to check if a string is within a list, tuple and other iterables.In your example code, the comparison returned False because a string is different of a tuple containing strings, as well as "1" is different from 1. To check if a string is within an iterable (in your case a string tuple), you must replace the operator == by in. Here's how it would look:valores = ('M', 'F') print(valores) sexo = input('Digite o seu sexo [M/F]: ').upper()[0].strip() print(sexo) if sexo in valores: print('Valor registado com sucesso.') else: print('Dados incorretos. Digite novamente.') The operator in different from ==, check whether an object (may be an object of any type) is within an iterable, or rather saying, it checks whether the target object contains the object you are specifying.You can make this check not only with strings, but also with objects of other types. See the examples below:"Masculino" in ["Masculino", "Feminino"] # True 17 in [19, 23, 3, 1023, 17, 65] # True 3 in ["3", 2, True, "bola"] # False ("3" é diferente de 3) True in [False, True, False, False] # True Remember I said that in verifies whether an object contains an element? So... this verification occurs through the method contains that receives a value and checks whether or not there is the past object. Example:class MinhaClasse(): def contains(self, value): if value == 7: return True else: return False objeto = MinhaClasse() 3 in objeto # False 7 in objeto # True Note that the object to be checked is always before the operator. Soon if I reversed the code to objeto in 7, I would be checking if the object is in the number 7 and besides not working, it would still generate an error, because int does not have the method contains.
Adamine rights of the python telegram
Software Programming • python telegram bot pytelegrambotapi python 3.7 telegrambots • • Mystic

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I took it from my code. But I think you'll figure it out.def tlg_kick_user(bot, chat_id, user_id): '''Telegram Kick (no ban) a user of an specified chat''' return_code = 0 try: user_data = bot.getChatMember(chat_id, user_id) if (user_data['status'] != "left") and (user_data['status'] != "kicked"): bot.kickChatMember(chat_id, user_id) bot.unbanChatMember(chat_id, user_id) return_code = 1 else: return_code = -1 except Exception as e: printts("[{}] {}".format(chat_id, str(e))) if str(e) == "Not enough rights to restrict/unrestrict chat member": return_code = -2 elif str(e) == "User is an administrator of the chat": return_code = -3 return return_code if new_user["join_retries"] < 5: printts("[{}] Captcha not solved, kicking {} ({})...".format(chat_id, new_user["user_name"], new_user["user_id"])) # Try to kick the user kick_result = tlg_kick_user(bot, new_user["chat_id"], new_user["user_id"]) if kick_result == 1: # Kick success bot_msg = TEXT[lang]["NEW_USER_KICK"].format(new_user["user_name"]) # Increase join retries new_user["join_retries"] = new_user["join_retries"] + 1 printts("[{}] Increased join_retries to {}".format(chat_id, new_user["join_retries"])) # Set to auto-remove the kick message too, after a while tlg_send_selfdestruct_msg(bot, chat_id, bot_msg) else: # Kick fail printts("[{}] Unable to kick".format(chat_id)) if kick_result == -1: # The user is not in the chat bot_msg = ['Юзер не в чате'].format( new_user["user_name"]) # Set to auto-remove the kick message too, after a while tlg_send_selfdestruct_msg(bot, chat_id, bot_msg) elif kick_result == -2: # Bot has no privileges to ban bot_msg = ['Нет прав'].format( new_user["user_name"]) # Send no rights for kick message without auto-remove try: bot.send_message(chat_id, bot_msg) except Exception as e: printts("[{}] {}".format(chat_id, str(e))) else: # For other reason, the Bot can't ban bot_msg = TEXT[lang]['не могу кикнуть'].format(new_user["user_name"]) # Set to auto-remove the kick message too, after a while tlg_send_selfdestruct_msg(bot, chat_id, bot_msg)
Module requests: When the page is downloaded, it is distorted by a keel
Software Programming • python • • Marcee

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Let's sort out the parts of you written-- what kinds of changes happen in every case. b'' It's gonna be a blue line, u'' - a young row.For illustration as meaning r.text I'll take it. u'Вася' (single line)Python 2:r.text , u'Вася'r.text.encode('utf-8') , b'Вася' (coding UTF-8)str(r.text.encode('utf-8')) , b'Вася': in the second type str Yes Byte row. unicodeSo nothing's changed.open('test.html', 'w') - opens a record file. Byte Lines. And your white line is recorded as it is.Python 3:r.text , u'Вася'r.text.encode('utf-8') , b'Вася' (coding UTF-8)str(r.text.encode('utf-8')) , u"b'\\xd0\\x92\\xd0\\xb0\\xd1\\x81\\xd1\\x8f'" - Oh! In the third python type str Yes Youth row. bytes) However, it can't transform the white line into a young one because at least it doesn't know the coding. For unknown types str returns the result of the challenge repr, a for the white line repr That's the idea, all the non-ASCII and all the specials are screened.open('test.html', 'w') - opens a record file. young people Line. That's how you're recording screened bays in the file.How to fix Python 3open The default file opens up for the record of the youth lines, so you can take a blunt and write it down. r.text (please clearly indicate the code in case):import requests headers = { 'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.9; rv:45.0) Gecko/20100101 Firefox/45.0' } url = 'http://www.2ip.ru' r = requests.get(url, headers = headers) with open('test.html', 'w', encoding='utf-8') as output_file: output_file.write(r.text) Bonus: How do we make the code for both Python 2 and 3In the third python. open this function. io.openin the second python function open It's not. io.openbut io.open You can import. In the third python, literal lines of the species 'вася' It's young, and in the second python, it's white, but it's possible to change with future.Using these two knowledge, a code that works equally in both pythons:from future import unicode_literals import io import requests headers = { 'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10.9; rv:45.0) Gecko/20100101 Firefox/45.0' } url = 'http://www.2ip.ru' r = requests.get(url, headers = headers) with io.open('test.html', 'w', encoding='utf-8') as output_file: output_file.write(r.text)
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Codify text bytes Python
Software Programming • python python 3.x • • gionna

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The hash is perfectly safe. So sure it is impossible. recover the original text from hash I do not know if this will be what you intend to...In any case, conversion with encode() is perfectly valid, and what is saved in the file is yes that they are bytes "encoded". The problem is that your editor knows the code that has been used because it is a standard. Therefore, when you open a file with an editor, you will read the text again (because the editor visualizes the bytes in the file as characters, since at last it is an editor).You're confusing, I think, coding with encryption. If what you're looking for is some way that the text is unreadable by opening it with an editor, you're looking for an encryption.If you don't care about security and just want it not to be easy to read, you can use simple methods, such as making a xor between each byte of the message with a certain byte chosen by you (for example with 0xff). That leaves the text unreadable enough. On the other hand it is trivial to undo that "cipher" because it is enough to do it again xor with the same byte. Unfortunately, even if you did not know what byte you used (or if you did not even know that you used this method), someone could "break the code" by a statistical analysis of the bytes, because the alphabet letters appear in Spanish with different frequency.Even so, if you're interested in the method or just curiosity, it would be like this:mensaje = 'Esto es una demostración de un cifrado trivial' msj_bytes = mensaje.encode("utf-8") cifrado = bytes(b ^ 0xff for b in msj_bytes) print(cifrado) The result isb'\xba\x8c\x8b\x90\xdf\x9a\x8c\xdf\x8a\x91\x9e\xdf\x9b\x9a\x92\x90\x8c\x8b\x8d\x9e\x9c\x96<L\x91\xdf\x9b\x9a\xdf\x8a\x91\xdf\x9c\x96\x99\x8d\x9e\x9b\x90\xdf\x8b\x8d\x96\x89\x96\x9e\x93' that you could already save in a file and opening up in an editor would look like crap. To get back the original message, you apply the same xor (which on python is ^) and decode the resulting bytes to characters using utf8:recuperado = bytes(b ^0xff for b in cifrado) print(recuperado.decode("utf-8")) And it comes out:Esto es una demostración de un cifrado trivial If you want more robust encryptions, you'd have to use cryptographic libraries.
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Problem with simultaneous requests for bot telegrams
Software Programming • java multi point telegram bot • • jonetta

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I've done something like: We'll build a bullet, and every new, important peddade sends all actions to a new flow.private ExecutorService executorService = Executors.newCachedThreadPool(); @Override public void onUpdateReceived(Update update) { if (update.hasMessage() && update.getMessage().hasText()) { Message message = update.getMessage(); if (message.getText().equals("/start") || message.getText().equals("/start@" + getBotUsername())) { executorService.submit(() -> startUser(update.getMessage())); } else if (message.getText().equals("/cancel") || message.getText().equals("/cancel@" + getBotUsername())) { executorService.submit(() -> cancelOperation(message)); } else if (message.getText().equals(ADD_NEW_SERIAL)) { executorService.submit(() -> startAddNewSerial(message)); } else if (message.getText().equals(LIST_SERIALS)) { executorService.submit(() -> showSerialCategories(message)); } else { executorService.submit(() -> checkUserStep(message)); } } else if (update.hasCallbackQuery()) { executorService.submit(() -> checkUserCallback(update.getCallbackQuery())); } }
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webhook telegram bot ques in mysql
Software Programming • telegram bot • • rielyn

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$update["message"]['text'] == '/start' The team comes with "how" including the slash. With regard to the OBD conject, make sure that the variables used for it are accessible within your function. There might be something in it that should be transmitted within the parameters of the challenge.
TypeError: translate() takes exactly one argument (2 given)
Software Programming • python • • Alberto

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https://docs.python.org/2/library/stdtypes.html#str.translate have different interfaces. Depending on the Piton version [type] str] and availability from __future__ import unicode_literals Normal structural constants, type 'abc' may be either bytes or Unicode. Your code is written using bytes.translate Interface, but 'abc' It's a young line on Piton 3 and that's why it's an incomprehensible Unique version. translate The method is to start Pitton 2 code on Pitton 3, you get the TypeError error here.Use Unicode to Windows. https://ru.stackoverflow.com/q/527815/23044 Then [in the form of a bonus] the code will also work on Pitone 2 and 3:remove_digits_table = dict.fromkeys(map(ord, u"0123456789")) no_digits = [name.translate(remove_digits_table) for name in os.listdir(u'C:\\Users\\name\\folder')] If you're going to give it to me os.listdir() Unicode, the result will be a list of Unicode names, so the Unicode version translate(s) of the method on both versions is called to accept the dictionary: the symbol number - the line for which to replace or replace Noneto remove the symbol:>>> dict.fromkeys([1, 2, 3]) {1: None, 2: None, 3: None} If you don't need Pitton 2 to support, https://docs.python.org/3/library/pathlib.html#basic-use :#!/usr/bin/env python3 import string from pathlib import Path remove_digits_table = dict.fromkeys(map(ord, string.digits)) for path in Path(r'C:\Users\name\folder').iterdir(): path.replace(path.with_name(path.name.translate(remove_digits_table))) Not here. os.chdir() The function that should be avoided because it makes it difficult to read the code and/or to prevent several things from being performed simultaneously in larger crypts.
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How to add a violin in a car load under the original rights
Software Programming • linux • • Trenton

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The graphic application requires a graphic server. As an option, launch a virtual.Create the violin. /home/ubuntu/Desktop/mqtt/mod_on_xspice.sh#!/bin/bash export DISPLAY=:4 /usr/bin/Xspice --port 5900 --disable-ticketing $DISPLAY & /home/ubuntu/Desktop/mqtt/mod And start service through it.
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Similar visual editor (constructor) for python only
Software Programming • python web programming designer idle • • obi

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There's a very good analog, really a feeble. https://zennolab.com/ru/products/zennoposter/
It's right to mark the incorrectly filled-in clue.
Software Programming • javascript html css form • • Demir

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Without the style and with this piece of the code, it's hard to tell, for sure, why is it so obvious to you? But if you remove the position absolute and just add the display of the block, errors must appear in the place where you're waiting. If it doesn't help, we need to look at a fully replicated example. Below is your slightly modified code:.error { display: block; font-style: normal; font-weight: normal; font-size: 12px; line-height: 15px; color: #f00; } <div class="popup popup_reduction-window"> <div class="popup__container popup__container_profile"> <h2 class="popup__title">Обсудить проект</h2> <button type="button" class="popup__close-button"></button> <form class="popup__formfield popup__formfield_profile" name="name" novalidate autocomplete="off"> <div class="popup__input-warapper"> <input id="name-input" type="text" name="name-input" class="popup__formfield-input popup__formfield-input_name" placeholder="Имя" minlength="2" maxlength="40" required /> <span id="name-input-error" class="error">Error</span> </div> <div class="popup__input-warapper"> <input type="tel" name="about" id="about" pattern="([\+]*[7-8]{1}\s?[$]*9[0-9]{2}[$]*\s?\d{3}[-]*\d{2}[-]*\d{2})" class="popup__formfield-input popup__formfield-input_job" placeholder="Телефон" minlength="2" maxlength="20" required /> <span id="about-error" class="error">Error</span> </div> <div class="popup__input-warapper"> <input type="email" name="about" id="about2" class="popup__formfield-input popup__formfield-input_job" placeholder="Email" minlength="2" maxlength="40" required /> <span class="error">Error</span> </div> <button type="submit" class="popup__save-button">Отправить</button> </form> </div> </div>
A

How to create Procfile for Heroku
Software Programming • heroku • • amarantha

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It's easier to do this through Visual Studio Code. It could create a Procfile file without expansion.

How is it right to fill and load Procfile bot with a telegram on Heroku?

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