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SearchView how to remove the falling list

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TestNG showing as test passed even if assertion fails
Automated Testing • java testng • • emran

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Its because you are catching the exception, your assertion is surrounded with try catch block, so your testcase gets pass. Update your catch block as below. catch(AssertionError e){ e.printStackTrace(); throw e; } OR catch(AssertionError e){ e.printStackTrace(); Assert.fail(); } This will throw the exception and your testcase will be failed.
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Rejection to google play market
Software Programming • android google play • • Rossere

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Use only that content you have the copyright to. Don't use other people's pictures, videos or sounds, even if your application helps to develop the author of this content. Be particularly careful with the title of your annex. From sin, don't add company names or any popular products. https://habrahabr.ru/post/231009/ Be careful when you're looking for a google. Instead of unlocking the application, they can only block an entire account for one letter. In addition to the general rules for annexes, there are more specific recommendations https://support.google.com/googleplay/android-developer/answer/113474?hl=ru with examples in Russian and in beautiful form.
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SocketTimeoutException help process the error.
Software Programming • java jsoup • • baileigh

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May I process it in such a way that the cycle continues to work from the place of error?Yes, you can.Is my implementation correct?Yes, I am.In order to test it, you can start asking for a little time-out.For example, the result of this code:for (int j=1; j<=10; j++) { try { System.out.println("Итерация #" + j); Document doc = Jsoup.connect("https://www.yandex.ru/").timeout(100).get(); System.out.println(" - Ок"); } catch (SocketTimeoutException ste) { System.out.println(" - Fail"); j--; continue; } } I have one:Итерация #1 - Ок Итерация #2 - Fail Итерация #2 - Ок Итерация #3 - Ок Итерация #4 - Ок Итерация #5 - Fail Итерация #5 - Ок Итерация #6 - Ок Итерация #7 - Ок Итерация #8 - Fail Итерация #8 - Ок Итерация #9 - Ок Итерация #10 - Fail Итерация #10 - Fail Итерация #10 - Ок Of course you might have another one.
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Remove last item from a list in C++
Software Programming • c++ list • • Duquan

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As the SuperG280 user says, the procedure error occurs when trying to remove the last node. It makes F = CAB and then delete F, which removes CAB. That is why it shows addresses in memory instead of the contents of the nodes. One of the solutions is to replace P=CAB; by F=CAB;. The corrected deletefinal code would be like this:void eliminarfinal(void){ system("cls"); int valor; if(AUX==NULL){ cout<<"LISTA VACIA"<<endl; getchar(); return; } cout<<"********ELIMINANDO ELEMENTO********"<<endl; system("pause"); if(AUX!=CAB){ F=CAB; //<---------- Acá está el cambio, P=CAB; por F=CAB; AUX=AUX->ant; AUX->sig=CAB; CAB->ant=AUX; valor=F->n; delete F; cout<<endl<<"se elimino " <<valor<<" de la lista"; }else if(AUX==CAB){ cout<<endl<<"se elimino "<<AUX->n<<", de la lista"; CAB = NULL; } getchar(); } Another way to correct the error would be assigned AUX to P instead of doing it to CAB as it appears in the code. It would be like this:void eliminarfinal(void){ system("cls"); int valor; if(AUX==NULL){ cout<<"LISTA VACIA"<<endl; getchar(); return; } cout<<"********ELIMINANDO ELEMENTO********"<<endl; system("pause"); if(AUX!=CAB){ F=AUX; //<---------- Acá está el cambio, F=CAB; por F=AUX; AUX=AUX->ant; AUX->sig=CAB; CAB->ant=AUX; valor=F->n; delete F; cout<<endl<<"se elimino " <<valor<<" de la lista"; }else if(AUX==CAB){ cout<<endl<<"se elimino "<<AUX->n<<", de la lista"; CAB = NULL; } getchar(); }
Remove empty lists from a dictionary in another Python list
Software Programming • python list dic languagetionaries • • jeanid

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Easy Muuy, we only go through the dictionary and choose the elements whose value is not this vacuum, so we can make a list compression or a dictionary compression, show both examples.Dictionary compressiondata1 ={...} #recorremos sus elementos y agregamos solo si es diferente de vacio data2 = {k:v for k,v in data1.items() if v !=[]} print(data2) Outcome{'Articulos': [{'abstract': 'El artículo hace una reseña', 'fecha_publicacion': '2005-02-04', 'indice': 'Artículos Publicados de Divulgación Local', 'keywords': '', 'mapeo': ['Abstract', 'Keywords', 'Indice', 'Fecha Publicacion']}], 'Proyectos': [{'codigo_proyecto': '', 'descripcion': 'Asadsadsadsadsa sadsadsadsa', 'fecha_inicio': '2005-02-01', 'mapeo': ['Fecha Inicio', 'codigo_proyecto', 'descripcion']}]} Listingdata2 = [v[0] for k,v in data1.items() if v !=[]] print(data2) Outcome[{'abstract': 'El artículo hace una reseña', 'fecha_publicacion': '2005-02-04', 'indice': 'Artículos Publicados de Divulgación Local', 'keywords': '', 'mapeo': ['Abstract', 'Keywords', 'Indice', 'Fecha Publicacion']}, {'codigo_proyecto': '', 'descripcion': 'Asadsadsadsadsa sadsadsadsa', 'fecha_inicio': '2005-02-01', 'mapeo': ['Fecha Inicio', 'codigo_proyecto', 'descripcion']}] As we can see returns a dictionary or list with all values that are not empty lists.
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How to write in a python list to remove duplicates
Software Programming • python • • kalyn

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{i.get("hoge"): i for i in query_set}.values() What is this?
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Single list, removal of element, C+++
Software Programming • c++ list indicator • • nishika

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The lists are worse than the fact that the lists cannot be addressed to the element at once: it is necessary to pass through previous elements. The disposal process therefore follows:You get to the element, the reference. NEXT which indicates the removed element;You're making a reference. NEXT Remote element reference of the previous element;Delete the element;Profit!This is how: +------+ +------+ +------+ |данные| |данные| |данные| \/\/\->+------+ +------+ +------+ | |--->| |--->| 0 | +------+ +------+ +------+ This is how it works: +------+ +------+ +------+ |данные| |удален| |данные| \/\/\->+------+ +------+ +------+ | | | 0 | .->| 0 | +------+ +------+ | +------+ \______________| You have a problem with you removing the element first, and then you try to find a reference to the next, that is, helping->Next->Next after removal no longer indicates the 3rd element. Try working with the markers first, and then remove the element.
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Could you help me because you don't remove it from the list?
Software Programming • • guilherme

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Do not remove from the list, simply because you did not implement the hashCode and Equals methods of the object, or this done wrongly.Thus the list does not find the object to be removed.Implement hashCode and Equals Methods in ProductsBelow a test tip, add some 3 product in the list and test.List<Produtos> produto = new ArrayList<Produtos>(); int indice=produto.indexOf(seuProdutoTeste); System.out.println(indice); It must print the correct index of your object, this is the test to ensure your hashCode and Equal Methods of object Products be correct.Usually it is not used name of objects in plural.I set an example ai: see, test, draw your conclusionspackage com; public interface IProduto { } package com; public class Produto implements IProduto { private Long id; public Produto(Long id) { this.id=id; } public Long getId() { return id; } public void setId(Long id) { this.id = id; } @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + ((id == null) ? 0 : id.hashCode()); return result; } @Override public boolean equals(Object obj) { if (this == obj) { return true; } Produto other = (Produto) obj; if (obj == null || getClass() != obj.getClass() || (id == null && other.id != null) || !id.equals(other.id)) { return false; } return true; } } package com; public class Milho extends Produto { private String nome; public Milho(Long id, String nome) { super(id); this.nome = nome; } public String getNome() { return nome; } public void setNome(String nome) { this.nome = nome; } @Override public int hashCode() { final int prime = 31; int result = super.hashCode(); result = prime * result + ((nome == null) ? 0 : nome.hashCode()); return result; } @Override public boolean equals(Object obj) { boolean result = false; if (this == obj) { result = true; } if (obj instanceof Milho) { Milho other = (Milho) obj; if (!(!super.equals(obj) || getClass() != obj.getClass() || (nome == null && other.nome != null) || !nome.equals(other.nome))) { result = true; } } return result; } } import java.util.ArrayList; import java.util.List; public class TesteRemoveList { public static void main(String[] args) { TesteRemoveList test = new TesteRemoveList(); test.testRemoveIProduto(); test.testRemoveProduto(); test.testRemoveMilho(); } public void testRemoveMilho() { System.out.println("--------------------"); final List<Milho> produtos = new ArrayList<Milho>(); produtos.add(new Milho(2L, "Amarelo")); produtos.add(new Milho(3L, "Verde")); produtos.add(new Milho(4L, "Cozido")); System.out.println(produtos.size()); //vamos remover o 2 produtos.remove(new Produto(2L)); System.out.println(produtos.size()); produtos.remove(new Produto(2L)); System.out.println(produtos.size()); //não acha produtos.remove(new Milho(2L, "Verde")); System.out.println(produtos.size()); //acha produtos.remove(new Milho(2L, "Amarelo")); System.out.println(produtos.size()); //não acha mais produtos.remove(new Milho(2L, "Amarelo")); System.out.println(produtos.size()); System.out.println("--------------------"); } public void testRemoveIProduto() { System.out.println("--------------------"); final List<IProduto> produtos = new ArrayList<IProduto>(); produtos.add((IProduto) new Produto(1L)); produtos.add((IProduto) new Produto(2L)); produtos.add((IProduto) new Milho(2L, "Amarelo")); produtos.add((IProduto) new Milho(3L, "Verde")); produtos.add((IProduto) new Milho(4L, "Cozido")); System.out.println(produtos.size()); //vamos remover o 2 produtos.remove(new Produto(2L)); System.out.println(produtos.size()); produtos.remove(new Produto(2L)); System.out.println(produtos.size()); //não acha produtos.remove(new Milho(2L, "Verde")); System.out.println(produtos.size()); //acha produtos.remove(new Milho(2L, "Amarelo")); System.out.println(produtos.size()); //não acha mais produtos.remove(new Milho(2L, "Amarelo")); System.out.println(produtos.size()); System.out.println("--------------------"); } public void testRemoveProduto() { System.out.println("--------------------"); final List<Produto> produtos = new ArrayList<Produto>(); produtos.add(new Produto(1L)); produtos.add(new Produto(1L)); produtos.add(new Produto(1L)); produtos.add(new Produto(2L)); produtos.add(new Produto(3L)); produtos.add(new Produto(4L)); System.out.println(produtos.size()); //encontrou um removeu produtos.remove(new Produto(1L)); System.out.println(produtos.size()); produtos.remove(new Produto(1L)); System.out.println(produtos.size()); produtos.remove(new Produto(1L)); System.out.println(produtos.size()); produtos.remove(new Produto(1L)); System.out.println(produtos.size()); System.out.println("--------------------"); } } It's just copying the code and adjusting the package and testing, it's well evolved
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Adjust the list of categories with subcategories removed
Software Programming • php htaccess • • Anderson

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RewriteRule ^cat1/subcat2/(.*) $1 [R=301,L] UpdateYeah. It's like the one where the frontend developer decided to practice fashion.With regard to the installation /rus/mos/phone/nexus/ -> /phone/nexus/ and /rus/spb/watch/tissot/ -> /watch/tissot/I don't think it's possible to make one universal rule.The point is, because of the internal device. мod_rewrite In this case, it will not be possible to apply a universal type template /\w+/\w+(.)♪ that would turn away ♪ /rus/mos/phone/nexus/ Total /phone/nexus/ with subsequent reference http://c%D0%B0%D0%B9%D1%82.%D1%80%D1%83/phone/nexus/ because after the first transformation of the route on the template, the application of the template will be repeated for the journey /phone/nexus/Which will lead to a complete cut to zero, and eventually the request will be redirected to the root of the site.So don't waste any castomied templates.RewriteRule ^rus/spb/(.) $1 [R=301,L] Although I don't exclude any lifhak I just don't know about.
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media player android view
Software Programming • android • • Avante

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In general, I believe that the issue is not correct,, because there are many decisions that each decides on its own. Cartochi songs can be implemented both through RecyclerView and ViewPager or ViewPager2 (mixture of the first two, but with the gradient in the second) https://ru.stackoverflow.com/a/472515/238266 (there was a ready option). The buttons are imagesView, button or even view. The list down is RecyclerView. Everything! Now what makes sense of audiowave is a lot of them, too, but I like this library: https://github.com/alxrm/audiowave-progressbar ♪ It's not complicated, light and sufficiently functional.
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Permanent mechanism for the withdrawal of Android notifications
Software Programming • android notifications • • amarantha

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You need a separate AlarmReceiver - he puts himself in an endless schedule to launch the service/action we need. In our case, he's always launching UpdateService. Pay attention to the fact that the service is not killed in the 6-7 Android, we need to reset on the set ExactAndAllowWhileIdle().This is a working example of such a director:public class AlarmReceiver extends WakefulBroadcastReceiver { public static final String INTENT_ALARM_UPDATE = "com.example.ALARM_UPDATE"; @Override public void onReceive(final Context context, Intent intent) { Log.d(Constants.LOG, "Сработал таймер для запуска сервиса обновления"); UpdateService.start(context, intent); setResultCode(Activity.RESULT_OK); // Next alarm schedule(context); } public static void schedule(Context context) { Calendar calUpdater = Calendar.getInstance(); calUpdater.add(Calendar.MILLISECOND, Constants.TIME_UPDATE); AlarmManager service = (AlarmManager) context.getSystemService(Context.ALARM_SERVICE); Intent intentAlarm = new Intent(INTENT_ALARM_UPDATE); PendingIntent pending = PendingIntent.getBroadcast(context, 0, intentAlarm, PendingIntent.FLAG_CANCEL_CURRENT); if (Build.VERSION.SDK_INT>Build.VERSION_CODES.M) { service.setExactAndAllowWhileIdle(AlarmManager.RTC_WAKEUP, calUpdater.getTimeInMillis(), pending); } else { service.set(AlarmManager.RTC_WAKEUP, calUpdater.getTimeInMillis(), pending); } } }
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Create a list of lists
Software Programming • java android android studio • • Raziyah00

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I need to initialize the PPPA listlistaPPA = new ArrayList<>();
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Pri primitive char ( char c=128; )
Software Programming • java char • • Nykeriab

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You've got a problem with coding or scrubbing in consoles. Java isn't here, the symbols are correct: https://ideone.com/b157B5
Remove the elements of the contingent list
Software Programming • python list • • morde

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lst = [0, 95, 0, 76, 0, 23, 68, 0, 23, 156, 95] # Поскольку перед первым элементом # нет ничего (и нуля в том числе, что соответствует условию), # то он добавляется в любом случае. # К тому-же при i == 0, i - 1 == -1 исключения не будет, # так-как элемент с индексом -1 присутствует в списке, # это последний элемент списка # Через цикл new_list = [] for i in range(len(lst)): if i == 0 or lst[i - 1] != 0: new_list.append(lst[i]) print(new_list) # Через генератор print([lst[i] for i in range(len(lst)) if i == 0 or lst[i - 1] != 0])
How to launch the sh violin, which is in the Assets folder, from the annex android
Software Programming • java android shell • • morde

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Code for binary or crypt:String appFileDirectory = getFilesDir().getPath(); String executableFilePath = appFileDirectory + "/" + FILENAME; Process process = Runtime.getRuntime().exec(executableFilePath); We will use the following code for reading or recording:DataOutputStream os = new DataOutputStream(process.getOutputStream()); DataInputStream osRes = new DataInputStream(process.getInputStream()); The algorithm of action is:Add a binary or a violin to the folder. assetsUse it. getAssets().Open(FILENAME)to get InputStream♪Write. /data/data/APPNAME/files (e.g. /data/data/ru.example.runfromassets/fileswhere your application has access to files for recording and execution.Do it. /system/bin/chmod 744 /data/data/APPNAME/files/FILENAMEusing the code above.Fill out the completed file or violin using the code above.

SearchView how to remove the falling list

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