Purpose of the function of one class within the function of another class

[courtlanda]

How to transfer a function that returns some value from one class as a variable to a function defined in another class. For now, my code looks like,

float A::decay(){
    B b;
    float N;
    const int HL=946; 
    const int G=126;
    float T;
    if(b.min()>0){
        T=(float)(b.min()-G)/HL;
        N=pow(2,-T);
    }
    return N;
}
int B::min(){

int min=dtim[0][0][0];

for(int i=0;i<N;i++){

for(int j=0; j<K; j++){

for(int q=0; q<L; q++){

if (dtime[i][j][q] < min)min = dtime[i][j][q];

}

}

}

return min;

}

When attempting to challenge the function min() in decay(), min is always zero.

[Avante]

You've got a problem in your calculations. minand not in the transfer of the function. Not really. transfer♪ Call.♪ You don't do anything supernatural... The code below is your simplified version. But what do you have? dtimWe don't know that! Then, in you. decay Establishment B A default designer, right? Maybe that. b all elements dtim - zero?

It's another case, if you really need to transfer one class member's function to another. ♪ ♪

class B
{
public:
    B(int x):x(x){}
void out()
{
    cout << "b = " << x << endl;
}

private:

int x;

};
class A

{

public:

void func(int x)

{

B b(x);

b.out();

}

};
int main(int argc, const char * argv[])

{

A a;

a.func(5);

}