How do you find the amount 1 + 1/2 + 1/3 + ... + 1/N?

[kalyn]

A whole number of N (state 0). Figure 1 + 1/2 + 1/3 + ... + 1/N

n = input()
s = float(0)

a = float
for i in range(1, n + 1):

a = 1 / i

s = s + a

i = i + 1
print s

What's wrong?

[charlenef]

Three things are wrong:

(1) a = float - Why is that even?

(2) a = 1 / i - in Pitton 2 is a full division. a = 1.0 / i

(3) i = i + 1 in cycle You can just...

s = 0.0
for i in range(1, n + 1):
    s += 1.0 / i
print s