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Moving the object in a certain radius towards the click

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kalyn last edited by

Hello. There's a circle inside the circle, a circle smaller. I need the inner circle to move towards the click, but not beyond the wider circle. Like tochpad in libgdx, but it only responds to clicks inside the circle.
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emmalee last edited by
Try redefining the method hit Class Touchpad as follows:
```
@Override
public Actor hit (float x, float y, boolean touchable) {
    return this;
}
```
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There are some classes that can help with this, they are Line, Polygon and Canvas.It's a bit complicated but there's an example using the class Line. /*O construtor da classe Line recebe 4 parâmetros opcionais, eles correspondem as coordenadas 'x' e 'y', os dois primeiros onde começa a linha, os dois ultimos onde termina a linha. Você terá que criar duas linhas, onde uma terminar a outra vai começar. Supondo que sua ListView tenha uma largura de 400px, para o triângulo ficar ficar mais ou menos no centro você pode fazer assim:*/ Line line1 = new Line(175, 50, 200, 0);//startX = 175, startY = 50, endX = 200, endY = 0 Line line2 = new Line(200, 0, 225, 50);//startX = 200, startY = 0, endX = 225, endY = 50 // coloque dentro de um HBox HBox hbox = new HBox(); hbox.getChildren().addAll(line1, line2); //centralize as linhas no hbox hbox.setAlignment(Pos.CENTER); //depois coloque o hbox e a listview dentro de um VBox VBox vbox = new VBox(); vbox.getChildren().addAll(hbox, listview); It may not be the best way, but it's an option.Coordinate system: https://pt.wikipedia.org/wiki/Sistema_de_coordenadas_cartesiano
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One option I would adopt:var indice = listaImagens.indexOf(listaImagens.filter(function(obj){ return obj.idCategoria == 2; })[0]); JSFiddle: http://jsfiddle.net/ruipimentel/cfLmLrex/ 1. ExplanationFunction filter() [ https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter ]It is available throughout Array. Receives as first parameter a function; this function is called callback, and is executed (by function filter()) once for each element of the array. The function filter() has the array itself output, but filtered.The callback function is who performs this filtering, returning true (keep) or false (cut) for each element of the array. Such a function is based on up to 3 parameters (below) for this choice, but in my case I chose to receive from the function filter() only the first:[Obligation] current element of the array (in my case, obj);[Optional] index of this element in the array;[Optional] a reference to the array being pursued;In my example, I made only the elements with the condition obj.idCategoria == 2 return true and therefore eliminated the other elements of the array.Function indexOf() [ https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/indexOf ]This function returns the index of an element within the array. For this, it determines, strictly (===), the equality of the parameter informed with each element of the array. In the case of literal objects, as is the case here, strict comparison will only return true if the parameter is a Reference to an array element. For this reason, it was necessary to carry out the filtration (filter()) and the selection of the first element of the postfiltration array ([0]).2. Resolution of this problem in the near futureThe future reserves an even more practical method of discovering the index of an element within an array. Firefox was the first to run ahead and implement a proposed function in ECMAScript6, called findIndex(), and also available in the Array prototype [ https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/findIndex ]It works very similar to the functions map() and filter(), receiving a callback function as parameter that will be executed in sequence by each element of the array; so a callback execution returns true, the element index will be returned by the function findIndex().In this way, the code could be reduced further to:var indice = listaImagens.findIndex(function(obj){ return obj.idCategoria == 2; }); Remembering once again that the implementation of this function has not been completed in most browsers, even in the latest versions of Google Chrome.
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const obj1 = { action: 'U', author: 'DZC\\PavelK', data: { accreditationSheetDate: '2021-11-15T00:00:00', accreditationSheetNumber: '100', accreditationTerm: { value: '6 gadi', valueEn: '6 years', }, accreditationTermId: '30a827ff-dd9e-4809-bd37-7b619c060aaf', accreditationFrom: '2021-11-12T00:00:00', accreditationTo: '2021-11-26T00:00:00', director: 'asdasdasdasd', justification: 'zxfccvxcbn,m', }, date: '2021-11-08T12:44:51.433', id: 22, }; const obj2 = { action: 'I', author: 'DZC\PavelK', data: { accreditationSheetDate: '2021-11-17T00:00:00', accreditationSheetNumber: '110', accreditationTerm: { value: '8 gadi', valueEn: '8 years', }, accreditationTermId: '30a827ff-dd9e-4567-bd37-7b619c060aaf', accreditationFrom: '2021-11-15T00:00:00', accreditationTo: '2021-11-25T00:00:00', director: 'asdasdasdasd', justification: 'zxfccvxcbn,m', }, date: '2021-11-09T14:48:51.433', id: 23, }; const convert = (obj1, obj2) => { return Object.entries(obj1).reduce((acc, [key, value]) => { if (value instanceof Object) { return { ...acc, [key]: convert(value, obj2[key]) }; } else if (value !== obj2[key]) { return { ...acc, [key]: { prev: value, curr: obj2[key] } }; } else return { ...acc }; }, {}); }; console.log(convert(obj1, obj2));Well, it's on its own.
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When you call JFrameCadastroPessoa frame = new JFrameCadastroPessoa();, the object Person is created with the null attributes in the JFrame class, and JRE follows the normal flow, running all the main lines without interruption, and when it arrives in System.out.println(pessoa.toString());, it displays the object created in its class JFrameCadastroPessoawith the null properties.You should add the view inside the actionperformed so that it is displayed only when clicking the button, in this way:private void jBSalvarActionPerformed(java.awt.event.ActionEvent evt) { pessoa.setNome(jTFNome.getText()); pessoa.setApelido(jTFApelido.getSelectedText()); System.out.println(pessoa.toString()); } Here yes, it will display exactly what is typed in the fields.UpdateAfter the comments, I created an example where you can use a custom JOptionPane, passing a JPanel to it:public class ExibePessoa { public static void main(String[] args) { Pessoa pessoa; JPanel p1 = new JPanel(); JPanel p2 = new JPanel(); JPanel panelPrincipal = new JPanel(new BorderLayout()); JLabel lbNome = new JLabel("Nome:"); JTextField txtNome = new JTextField(20); JLabel lbApelido = new JLabel("Apelido:"); JTextField txtApelido = new JTextField(20); p1.add(lbNome); p1.add(txtNome); p2.add(lbApelido); p2.add(txtApelido); panelPrincipal.add(p1, BorderLayout.NORTH); panelPrincipal.add(p2, BorderLayout.SOUTH); JOptionPane.showMessageDialog(null, panelPrincipal, "Acesso Restrito", JOptionPane.PLAIN_MESSAGE); pessoa = new Pessoa(txtNome.getText(), txtApelido.getText()); System.out.println(pessoa.toString()); } }
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Transferring the reference to Activity to other objects is not a good idea, as it is to keep static variables in Activity. There are several options.The Singleton class can be created and when activated onCreate(s) is activated, then data can be obtained at any location.Create your class when the activists are created, obtain the size and only determine the values (screen size).
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Well, maybe it's not very optimistic what I think of you, but I did it to see how you can do such processes without using repeat cycles, it's already a matter of you putting the code and leaving it as you like. I created 1 method and 2 functions, executor(), fillArrangement() e PrintDatos() Although the executioner can replace it with the builder, it will work the same way. I leave the code for you to execute it and analyze it.package stackoverflow; import java.util.ArrayList; import java.util.List; public class ContadorLimiteRegreso { private int contador = 0; private int cantidadDatosArreglo; private int cantidadImprimir; private boolean bandera = false; public void ejecutarProceso() { this.cantidadDatosArreglo = 3; this.cantidadImprimir = 7; List<Integer> datos = llenarArreglo(new ArrayList<>()); this.contador = 0; imprimirDatos(datos); } private List<Integer> llenarArreglo(List<Integer> datos) { if (datos.size() < this.cantidadImprimir) { if (contador == this.cantidadDatosArreglo - 1 || bandera) { bandera = true; if (contador == 2) { datos.add(contador); } contador--; if (contador == 0) { bandera = false; } if (datos.size() < this.cantidadImprimir) { datos.add(contador); } } else { bandera = false; if (datos.size() > 0 && contador == 0) { contador++; } datos.add(contador); contador++; } return llenarArreglo(datos); } return datos; } private List<Integer> imprimirDatos(List<Integer> datos) { if (this.cantidadImprimir > 0) { System.out.println(datos.get(contador)); contador++; this.cantidadImprimir--; return imprimirDatos(datos); } return null; } } And in your main you run it the following way:public static void main(String[] args) { try { // vender(); System.out.println("Iniciar Proceso"); new ContadorLimiteRegreso().ejecutarProceso(); System.out.println("Finalizar Proceso"); } catch (Exception e) { e.printStackTrace(); } } You can leave the main without the block try/catch I don't remember how it's called to that process where the function is called to itself until the sentence is fulfilled, thus generating a repeat cycle, if you find out, you can let it know.
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The first thing you have to do is detect in which box you are clicking. This can be done with raycast for example. Once you detect where you want to go, then you will have to move the transform to the selected point. If you can move it directly, that would be enough:public GameObject myPersonaje; public GameObject casilla1; void Update() { if (Input.GetMouseButtonUp(0)) { Ray ray = Camera.main.ScreenPointToRay(Input.mousePosition); RaycastHit hit; if (Physics.Raycast(ray, out hit)) { if (hit.collider.gameobject.name == "casilla1") { myPersonaje.transform.position = casilla1.transform.position; } } } } Basically what this piece of code does is: When you click on the left mouse button, throw a raycast and look at what you're hitting. If the lightning strikes someone and that someone has as a square1 name, then teleport the player to the box.This code is a quick thing, but I guess it'll be worth you to get an idea.PD: For raycast to crash with other objects colliders are needed.
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var humans = new List<Human> { new Human{ Name="Имя1", Sex = Sex.Male ,Item = Item.Здоровый}, new Human{ Name="Имя2", Sex = Sex.Female ,Item = Item.Больной} }; humans.AddRange(humans .Where(h => h.Item == Item.Здоровый) .Select(h => new Human {Name=h.Name, Sex=h.Sex, Item = Item.Больной}) .ToArray()); humans.ForEach(h => Console.WriteLine($"{h.Name} {h.Sex} {h.Item}")); ConclusionИмя1 Male Здоровый Имя2 Female Больной Имя1 Male Больной
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I've managed to solve the problem. My encroachment was at the forefront, and in the end, when I tried to move my wrist into a cell that was above the hierarchy - my Raycast fell on my own stick. In the OnBeginDrag method, I would have made the variable Raycast Target in the stick equal to false, and in the OnEndDrag method, it would have been true.
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A JFrame by default establishes a container 'BorderLayout' which organizes and reassesses its components to make them in 5 Regions 'NORTH, SOUTH, EAST, WEST, and CENTER.'I'm going to give you an example, in which the Main Class is a JFrame, and the other two classes are JPanel and we will place one of them in the Central area of JFrame and the other class in the Left or West area of that JFrame.Example:public class DosDibujos extends JFrame { public DosDibujos() { setTitle("Paneles"); setBounds(300, 300, 400, 350); setDefaultCloseOperation(EXIT_ON_CLOSE); this.add("Center", new DibujoDer()); this.add("West", new DibujoIzq()); } public static void main(String[] args) { new DosDibujos().setVisible(true); } } class DibujoDer extends JPanel { public DibujoDer() { this.setBackground(Color.MAGENTA); } } class DibujoIzq extends JPanel { public DibujoIzq() { JLabel label = new JLabel("Texto Izquierdo"); this.add(label); } } Outcome: The key is in these 2 lines. .this.add("Center", new DibujoDer()); this.add("West", new DibujoIzq()); Where we added a panel to the central area and another panel to the left area. It could also be added in this way with already predefined constants.this.add(new DibujoDer(), BorderLayout.CENTER); this.add(new DibujoIzq(), BorderLayout.WEST);
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Software Programming • android node.js http post logc languageat • • esther

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When I see your code is correct, but the codes I've made I've never placed the port next to the ip, try removing the port you added to the url and access only by ip and /signup as follows:HttpPost post = new HttpPost("http://192.168.25.32/signup"); Then tell me if it worked.Hugs.

Moving the object in a certain radius towards the click

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