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Random displacement

Mystic last edited by

There is a body containing four elements, how these elements can be intermittently intermittently intermitted, i.e., the first element became the third, second quarter, etc. It's different every time.
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rielyn last edited by
If you don't think too hard about cryptographic persistence,
```
Collections.shuffle(list);
```
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Viktorina and random module
Software Programming • python python 3.x • • rielyn

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That's how it works.# Формируешь список вопросов: all_answers = [q1,q2,q3,q4] #Вариант первый -> Берешь рандомного из "колоды": while(len(all_ansewrs) != 0): print(all_answers.pop(random.randint(0, len(all_answers)-1))) #Вариант второй -> Замешиваешь "колоду" каждый раз, когда берешь из: while(len(all_answers) != 0): random.shuffle(all_answers) print(all_answers.pop()) In your version, you just printed a random element from the list. print(random.choice(all_answers))
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Problem when receiving, via Intent, a file shared by another app
Software Programming • java android intent • • jonetta

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In this exposed code it seems that at least the request for reading in the storage of the device is missing, as otherwise the permission error will always occur. The following suggestion of correction:// Storage Permissions variables private static final int REQUEST_EXTERNAL_STORAGE = 1; private static String[] PERMISSIONS_STORAGE = { Manifest.permission.READ_EXTERNAL_STORAGE, Manifest.permission.WRITE_EXTERNAL_STORAGE }; //persmission method. public static void verifyStoragePermissions(Activity activity) { // Check if we have read or write permission int writePermission = ActivityCompat.checkSelfPermission(activity, Manifest.permission.WRITE_EXTERNAL_STORAGE); int readPermission = ActivityCompat.checkSelfPermission(activity, Manifest.permission.READ_EXTERNAL_STORAGE); if (writePermission != PackageManager.PERMISSION_GRANTED || readPermission != PackageManager.PERMISSION_GRANTED) { // We don't have permission so prompt the user ActivityCompat.requestPermissions( activity, PERMISSIONS_STORAGE, REQUEST_EXTERNAL_STORAGE ); } } Solution found in: https://stackoverflow.com/questions/33030933/android-6-0-open-failed-eacces-permission-denied
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See if the darkness regime is included in Android 9 or 10?
Software Programming • java android • • Trenton

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https://developer.android.com/preview/features/darktheme Isn't it?int currentNightMode = getResources().getConfiguration().uiMode & Configuration.UI_MODE_NIGHT_MASK; switch (currentNightMode) { case Configuration.UI_MODE_NIGHT_NO: // ночная тема не активна, используется светлая тема break; case Configuration.UI_MODE_NIGHT_YES: // ночная тема активна, и она используется break; }
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Problem by calculating days between dates
Software Programming • java • • meriah

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Change of time zone, for example you can put it like this:public static Date sumarMeses(Date fecha, int meses) { Calendar calendar; calendar = Calendar.getInstance(TimeZone.getTimeZone("GMT+3")); calendar.setTime(fecha); calendar.add(Calendar.MONTH, meses); return calendar.getTime(); }
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JQuery Mobile - Displaced button
Software Programming • jquery jquery mobile • • magpie

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The problem is that the indentation of <li> I was like text space, and the snippet here is generating several   (space), as shown below: If you copy your code into a notepad and paste again into the snippet, you will remove these spaces and the button will be ok, as below shows:<!DOCTYPE html> <html lang="pt-BR"> <html> <head> <meta charset="UTF-8"> <meta name="viewport" content="width=device-width, initial-scale=1" /> <meta name='theme-color' content='#00974a'/> <title>Teste</title> <link rel="stylesheet" href="http://code.jquery.com/mobile/latest/jquery.mobile.min.css"/> <script src="http://code.jquery.com/jquery.min.js"></script> <script src="http://code.jquery.com/mobile/latest/jquery.mobile.min.js"> </script> <body> <div data-role="header" style="overflow:hidden;"> <h1>I'm a header</h1> <a href="#" data-icon="gear" class="ui-btn-right">Options</a> <div data-role="navbar"> <ul> <li><a href="#">One</a></li> <li><a href="#">Two</a></li> <li><a href="#">Three</a></li> </ul> </div> </div> <div data-role="content"> </div> </div> </body> </html>Now, give a review in your HTML, because it has duplicate tags and missing close <head>.
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Create random dates on Postgresql
Software Programming • sql postgresql date timestamp postgresql 12 • • jules

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Random()You can use the function random() to generate a decimal and use it to "screw" a date or timestamp: Select ( Select timestamp '2019-12-31 23:59:59' + random() * (timestamp '2019-01-01 00:00:01' - timestamp '2019-12-31 23:59:59') )::date As fecha_random; Using in the result a sum of a negative date we get a random date within the range that we. https://www.techonthenet.com/postgresql/functions/random.php
Net displacement
Software Programming • javascript html cs3 • • Mystic

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If I' correctly understood, there's a way to do this without backing down, to go on with the idea, I think the logic is understandable.children[i].style.background = 'red'; - it's given different color wides to show.margin-left: -.25em; - it's to remove the right back from the inline elements.var parent = document.getElementById('parent'); var parentWidth = parent.clientWidth; var children = document.getElementsByTagName('li'); var childrenWidth; for (var i=0; i<children.length; i++){ childrenWidth = children[i].clientWidth; if(childrenWidth/parentWidth <= 0.2){ children[i].style.width = parentWidth*0.2 + 'px'; children[i].style.background = 'red'; }else if(childrenWidth/parentWidth <= 0.4){ children[i].style.width = parentWidth*0.4 + 'px'; children[i].style.background = 'green'; }else if(childrenWidth/parentWidth <= 0.6){ children[i].style.width = parentWidth*0.6 + 'px'; children[i].style.background = 'blue'; }else if(childrenWidth/parentWidth <= 0.8){ children[i].style.width = parentWidth*0.8 + 'px'; children[i].style.background = 'yellow'; }else if(childrenWidth/parentWidth <= 1){ children[i].style.width = parentWidth + 'px'; children[i].style.background = 'grey'; } }ul{ width: 500px; box-sizing: border-box; padding: 0; } li{ display: inline-block; margin-left: -.25em; background: red; }<ul id="parent"> <li>Один</li> <li>Два два номер два</li> <li>Три три три</li> <li>Четыре</li> <li>Пять пять очень длинный пять</li> <li>Шесть</li> <li>Семь длинный семь</li> </ul>
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Issue with notification icon
Software Programming • java android firebase • • kalena

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After doing the test by changing the.setContentText(message) by .setContentText() Passed by my function")of the function that should be called It was noted that the firebase was treating push when the app was in background and so the image was not appearing.Knowing this we have two options:You can send the icon by setting up the push. The problem is that if it is essential that the push pass through the function, this solution will not solve.Doing push so that firebase always go through the function. Unfortunately I never did that but maybe that link will help you https://stackoverflow.com/a/37845174/2456894
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Java Poi does not download
Software Programming • java excel java ee apac languagehe poi • • Kadir

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You can write straight at the response request. Ex: response.setContentType("application/vnd.ms-excel"); response.setHeader("Content-disposition", "attachment; filename=qrquivo.xls"); wb.write(response.getOutputStream()); response.getOutputStream().flush();
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Like the rest of a random selection that was drawn out to make a new random until only 1 left?
Software Programming • python • • amarantha

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Disclaimer: With this I do not directly answer the statement of your question, but offer you an alternative approach to address your problem. .Considering you have a list with the names (names), you can make use of a very useful function of the module randomwhich allows you to mix the order of the internal elements of that list. This function is called shuffle().In addition, taking advantage of the multiple mapping feature that allows us to perform Python, we can have the code in a very succinct way, as shown below:import random names = ['Foo', 'Bar', 'Baz', 'FizzBuzz'] # En tu caso, esta lista la creas a partir del input del usuario random.shuffle(names) manager, secretary, treasurer, worker = names
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Random number between 0 and 8, except 5, in JavaScript using Math.random
Software Programming • javascript random • • meriah

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Quick solution:var numero = Math.floor(Math.random()*8); return numero>4 ? numero+1 : numero Explanation:You have many ways to do it, but I'm going to elaborate a simple asset for your case.First, let's understand the problem. You want one of eight possibilities, but the output is not sequential:0 1 2 3 4 5 6 7 <-- posição sequencial dos números (aqui é feito o random) 0 1 2 3 4 6 7 8 <-- saída desejada (simplesmente modificamos o retorno com if) So you want some of these eight numbers. That is:var numero = Math.floor(Math.random()*8); There are two sequences, from zero to four, and from six to eight, so just add one if it is larger than four:return numero>4 ? numero+1 : numero If you give 0 1 2 3 4 returns 0 1 2 3 4 respectively... ... and, if der 5 6 7 returns 6 7 8 respectivelySo the code is:var numero = Math.floor(Math.random()*8); return numero>4 ? numero+1 : numero If you do not know the conditional operator (called ternary) is the same as doing this:var numero = Math.floor(Math.random()*8); if (numero>4) { return numero + 1; } else { return numero; } Test here:function randomDeZeroAOitoMenosOCinco() { var numero = Math.floor(Math.random()*8); return numero>4 ? numero + 1 :numero; } document.getElementById('sortear').onclick = function() { document.getElementById('resultado').innerText = randomDeZeroAOitoMenosOCinco(); };<button id="sortear">Clique-me!</button> <span id="resultado">?</span>What if it was a more complex sequence?Whenever you think of a random of a variety of things (carta deck, non-sequential numbers, names) think of them as "items" and numere sequentially (even if they are numbers, you can "number each of them in sequence"). Then you would draw his index, and then take the value:var possibilidades = [ 0, 1, 2, 3, 4, 6, 7, 8 ]; return possibilidades[Math.random()*possibilidades.length]; Notice that in this case you can put no array the sequence you want?Test here:function randomCustomizado() { var possibilidades = [ 0, 1, 2, 3, 4, 6, 7, 8 ]; return possibilidades[Math.floor(Math.random()*possibilidades.length)]; } document.getElementById('sortear').onclick = function() { document.getElementById('resultado').innerText = randomCustomizado(); };<button id="sortear">Clique-me!</button> <span id="resultado">?</span>
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How to save parameters of a method in a variable?
Software Programming • java java swing • • kalyn

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The error is in the way you call the saving method, as it is an empty method(Void) what you can do is simply call the saving method without creating a String. You have this. String datos= DAO.guardar(new Estudiante(nombre, materia, Integer.parseInt(nota))); You'd leave it like that. DAO.guardar(new Estudiante(nombre, materia, Integer.parseInt(nota))); Another advice, the saving method should turn it booleano, so it twists you true or false, depending on whether or not the student could insert.
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How to order questions randomly?
Software Programming • c sharp unity3d random something games • • Saumya

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using System.Collections.Generic; [...]List<string> temp = new List<string>(); temp.Add(alternativa1[idPergunta]); temp.Add(alternativa2[idPergunta]); temp.Add(alternativa3[idPergunta]); temp.Add(alternativa4[idPergunta]); var r = new Random(); var c = r.Next(4); respostaA.text = temp[c]; temp.RemoveAt(c); c = r.Next(3); respostaB.text = temp[c]; temp.RemoveAt(c); c = r.Next(2); respostaC.text = temp[c]; temp.RemoveAt(c); respostaD.text = temp[0];
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Class NotFoundException at jar launch
Software Programming • java • • rielyn

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Glass shows that access to a file is used by name. resources\final_count.txt♪ When the process tries to open a file on a relative path, this path is looking for a relatively current business director of the process (in java as far as I know. https://bugs.java.com/bugdatabase/view_bug.do?bug_id=4045688 Change the current work directory.In command launch java -jar путь_до_файла\файл.jar The current work director will be the team. java i.e. first directory in путь_до_файла♪ Accordingly, the program will search the file in the catalogue. resources current catalogue. That's why you don't work when you put the file on the catalogue where you're in. файл.jar♪To get the file from jar, you need to open it without API access to the type file system. FileReaderusing getResource or getResourceAsStream Class ClassLoader♪ Like, if you put the file in the root. jar The file, you can get the flow:try (InputStreamReader isr = new InputStreamReader( this.getClass().getResourceAsStream("/final_count.txt")) { // используем isr точно так же как и FileReader } If you put a file in some file inside. фай.jar The file, we need to point out the complete way from the root of the jar file.
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Error when compiling code with import java.util. Random; random.nextInt()
Software Programming • java random compilation • • terrea

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The real problem you should observe in the first line of error:Random is already defined in this compilation unitYou gave Random's name to your class, and the compiler is confusing with the java.util.Random. How you do not have the method nextInt() defined in his class he says that this method does not exist.Change your class name to avoid conflicts that is to work Ok.See an example working on https://ideone.com/ZACEcP .

Random displacement

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Create random dates on Postgresql
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Issue with notification icon
Software Programming • java android firebase • • kalena

Java Poi does not download
Software Programming • java excel java ee apac languagehe poi • • Kadir

Like the rest of a random selection that was drawn out to make a new random until only 1 left?
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Software Programming • java random compilation • • terrea