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How is it right to collect an app in py2ex?

E
elysha last edited by
I'm gonna have to transfer a pyru to the sky. To translate this team,
```
C:\Python27\python.exe setup.py py2exe
```
After the collection, the app works, only doesn't have access to the Internet. There's no such problem when the piton file starts. https://drive.google.com/file/d/0B07aYSnGHQe9dWpsTDhmc1k2SVU/view?usp=sharing ♪
What am I doing wrong?
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briley last edited by

Try Pyinstaller or cx_freeze.
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Recognize the row number. SQL
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It's possible with Window Function. ROW_NUMBER()♪ https://dbfiddle.uk/?rdbms=sqlite_3.27&fiddle=f3f960f146af9d8b29da32956d83112f SQLCREATE TABLE mock (ID INTEGER PRIMARY KEY, Name VARCHAR(30)); INSERT INTO mock (ID, Name) VALUES (11, 'user1'), (15, 'user2'), (17, 'user3'); SELECT ROW_NUMBER() OVER (ORDER BY ID) AS RowNum , ID, Name FROM mock; Outcome+---------+-----+-------+ | RowNum | ID | Name | +---------+-----+-------+ | 1 | 11 | user1 | | 2 | 15 | user2 | | 3 | 17 | user3 | +---------+-----+-------+
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It is true that there is no evidence in the commentaries that the means for such conduct are built.We must act bypass.For example, a mechanism can be used https://ru.wikipedia.org/wiki/Inotify ♪package https://packages.debian.org/jessie/inotify-tools which is probably part of all popular distributors, there's a program. inotifywaitwhich can be used for the case.This is an example of the crypt, which monitors the arrival of files/cataloges in an endless cycle and, if they do not meet any criterion, remove them. This example uses " group ownership "quot; , but it is not difficult to change to adapt to the actions of the programme that is allowed to create files/cataloges in a traceable catalogue.#!/bin/bash d=/путь/к/отслеживаемому/каталогу g=имя_группы while true; do r=$(inotifywait -re create --format '%w%f' $d 2>/dev/null) #echo $r if [ -n "$r" ]; then gr=$(stat --printf='%G' "$r") if [ "$gr" != "$g" ]; then rm -rf "$r" fi fi done
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You can use the function apply() of type objects Series. With it you can apply any function that returns something. Thus, you can set a correction function and apply it. For example:def corrigir_nomes(nome): nome = nome.replace('.', '').replace('ç', 'c').replace('ô', 'o').replace('é', 'e') return nome And then apply in the column you want:df['NAME'] = df['NAME'].apply(corrigir_nomes) The result will be something like:0 Jose L da Silva 1 Ricardo Proenca 2 Antonio de Morais Name: NAME, dtype: object
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There's a library called RUtils. There's a transliteration module.Also, the words on the Latin are written differently, like the street of Pushkinskiy,St. Pushkinskii,St. Puschkinski St. Puschkinsky. And that's just an example of the end of "s" and "s."In such a situation, for example, with ends, certain prefixes and assumptions and, in general, of course, the distances of Levenstein and Hamming should be used.
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TypeError: unhashable type: 'peticion' python
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One solution is to add the beat hash in the requested class,def __hash__(self): return hash((self.srcIP, self.dstIP, self.prtcl)) By defining it you already evaluate the condition correctly.
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How do you get a photo and a signature?
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Useable https://docs.python.org/3/library/random.html#random.choice from the random bag. She needs an indexed sequence, so first turn to the list:import random some_dict = {'text1': 'photo1', 'text2': 'photo2', 'text3': 'photo3'} text, photo = random.choice(list(some_dict.items())) >>> text 'text3' >>> photo 'photo3'
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getElementsByTagName returns a list with the elements that match the label, to obtain those products whose attribute name have a certain value you should only iterate about it and use Element.getAttribute('name') to compare it to the value. Exactly the same applies to addresslist:from xml.dom.minidom import parse NOMBRE = "THIS" TIPO = "FIND" doc = parse('O365IPAddresses.xml') for producto in doc.getElementsByTagName("product"): if producto.getAttribute('name') == NOMBRE: for addr_list in producto.getElementsByTagName("addresslist"): if addr_list.getAttribute('type') == TIPO: for addr in addr_list.getElementsByTagName("address"): print(addr.firstChild.data) Stop:<?xml version="1.0" encoding="utf-8"?> <products updated="5/6/2018"> <product name="ETC"> <addresslist type="ACME"> <address>5485:7845</address> </addresslist> </product> <product name="THIS"> <addresslist type="FIND"> <address>5658:8742</address> <address>5658:4562</address> <address>5658:4582</address> </addresslist> <addresslist type="WRONG"> <address>8965:3254</address> </addresslist> </product> <product name="ABC"> <addresslist type="FIND"> <address>5485:7845</address> <address>5658:8454</address> </addresslist> </product> </products> We'd get:5658:87425658:45625658:4582 For who I can use xml.etree.ElementTree (Python  2.5) or the external library lxml you can simplify everything using xpath:import xml.etree.ElementTree as ET tree = ET.parse('O365IPAddresses.xml') addresses = tree.findall('.//product[@name="THIS"]/addresslist[@type="FIND"]/address') for address in addresses: print(address.text) import lxml.etree as etree doc = etree.parse('O365IPAddresses.xml') addresses = doc.xpath('//product[@name="THIS"]/addresslist[@type="FIND"]/address') for address in addresses: print(address.text)
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Well, with initialization through such a selector, there's no way to use or do not have to, everything's counting.$().fancybox({ selector: '[data-fancybox="gallery"]', ...
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Just collect the dictionary in the cycle.l = [{'Категория': 'Белые вина', 'Название': 'Белая леди', 'Сорт': 'Дамский пальчик', 'Цена': 399, 'Картинка': 'belaya_ledi.png'}, {'Категория': 'Напитки', 'Название': 'Коньяк классический', 'Сорт': '', 'Цена': 350, 'Картинка': 'konyak_klassicheskyi.png'}, {'Категория': 'Белые вина', 'Название': 'Ркацители', 'Сорт': 'Ркацители', 'Цена': 499, 'Картинка': 'rkaciteli.png'}, {'Категория': 'Красные вина', 'Название': 'Черный лекарь', 'Сорт': 'Качич', 'Цена': 399, 'Картинка': 'chernyi_lekar.png'}, {'Категория': 'Красные вина', 'Название': 'Хванчкара', 'Сорт': 'Александраули', 'Цена': 550, 'Картинка': 'hvanchkara.png'}, {'Категория': 'Белые вина', 'Название': 'Кокур', 'Сорт': 'Кокур', 'Цена': 450, 'Картинка': 'kokur.png'}, {'Категория': 'Красные вина', 'Название': 'Киндзмараули', 'Сорт': 'Саперави', 'Цена': 550, 'Картинка': 'kindzmarauli.png'}, {'Категория': 'Напитки', 'Название': 'Чача', 'Сорт': '', 'Цена': 299, 'Картинка': 'chacha.png'}, {'Категория': 'Напитки', 'Название': 'Коньяк кизиловый', 'Сорт': '', 'Цена': 350, 'Картинка': 'konyak_kizilovyi.png'}] res = {} for x in l: res.setdefault(x['Категория'], []).append(x) print(res)
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The thing is, masses are. https://msdn.microsoft.com/ru-ru/library/4d43ts61(v=vs.90).aspx ♪ That's what this means in the context of your task: your list is not made of Same objects, one object. How did that happen? Answer: You've got a mat reference.Changed the object to which reference mat indicatesAdded the reference to the site on the listChanged the object to which mat refers, so you changed the object that was already added to the collection.Added the reference to the facility to the list (the most traumatized object) After these actions, we have mat, list[0], list[1] point to the same object in a controlled brush. It is sufficient to replace the problem list.Add(mat); ♪ list.Add((byte[,])mat.Clone()); but such a decision can only be used with the masses of the types of values.
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One copy of the class Answer may be considered as one answer. You can create a few options for answering and connect each of them with an external key to a copy of Class Question.class Answer(models.Model): question = ForeginKey(Question, on_delete=models.CASCADE) answer_text = models.CharField(max_length=300) correct = models.BooleanField(default=False) # True, если ответ верный
How to make rounding up with Python?
Software Programming • python mathematic languages • • jeanid

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Using pure mathematics whenever you want to round a number up add an entire unit of the value that the rounding is done and take the whole part, this will ensure that it will always fall into the next value. But it has a problem that the question deals with, when it is already whole it cannot make the sum, so it has no way to escape it:x = x + (1 if x % int(x) else 0) If you want you can use a Python-ready function that is https://docs.python.org/3/library/math.html#math.ceil that makes hit the ceiling:x = ceil(x) https://github.com/maniero/SOpt/blob/master/Python/Math/Rounding.py .But note that this has some criteria, and they can even be more suitable if you understand them. It can result differently if it is negative or positive.In the background the function will make these checks for you, it is not that you are doing less, just are abstracted for you.
Am I doing this exercise right?
Software Programming • java objec languaget orientati • • irl

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There are some mistakes. The main mistake is that you should not use == or != to compare Strings. Use the method equals. to avoid having to worry about one of them being null in the method equals, you can use Objects.equals(a, b).So, instead: if(this.nome[c] == this.nome[i]) { You should use this: if (Objects.equals(this.nome[c], this.nome[i])) { And also, instead: if (this.nome[c] == nome) { You would use this: if (Objects.equals(this.nome[c], nome)) { Your ties are also with the wrong limits:for (int c=0; c<=5; c++){ It was supposed to be this:for (int c = 0; c < 5; c++) { There's another problem. You shouldn't use one for in the method buscarIndex, after all the index is already given to it as parameter. Just do it:public void buscarIndex(int i) { System.out.println("Nome: " + this.nome[i]); System.out.println("Idade: " + this.idade[i]); System.out.println("Altura: " + this.altura[i]); } There are other things that could be considered. In particular it would be a good idea to have a class Contato with nome, idade and altura and also getters and setters and then do the Agenda having a List<Contato>, which also saves you from the restriction of having the maximum size of the fixed schedule in 5 and would also facilitate enough addition, removal and search operations on the agenda.
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Firebase push notifications from an app android to an iOS app
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You may need to add the background mode in the Signing & Capabilities section
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Download old version of App Store when iOS app is released
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Yes. The App Store (or iTunes Connect) keeps ipa for each version. If you try to download on an unsupported device, the version of ipa will be downloaded. However, downloadable is only available for Apple account.

How is it right to collect an app in py2ex?

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