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ListView with the possibility of moving elements

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Duquan last edited by

I've seen that listView and I need to do the same. So the user could ask for the order of the list elements by moving. Is there a solution or something you can write yourself?
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inna last edited by

Library https://github.com/bauerca/drag-sort-listview It's for your function. She's quite popular and tested.
She's got a completely castomized interface. Looks like a list.
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Java - how to get information from HTML pages
Software Programming • java html jsoup • • inna

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Probably. The desired element is created by JavaScript code Brauser and/or additional API requests. JSoup is not a browser. and there's no JavaScript movement. ♪ doc You're getting the reference "static" HTML.Options to address this issue are:automate the real browser through http://www.seleniumhq.org/docs/03_webdriver.jsp to open the desired page in selenium-powered browser, to allow him to carry out his work on downloading the page and to pass the necessary data; further or to obtain the source code of the page getPageSource() and give it to me. JSoup to password, or continue using the selenium webdriver APIInspect how the page (browser developer tools) is downloaded and developed, if the browser makes additional rivers, repeat them in its Java codeIt is also sometimes that the necessary data are already available in HTML, but only elsewhere. Like sometimes. script Gate, check it too.
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Android: Can the divider be held by ignoring the padding of the container?
Software Programming • android xml android sdk • • jules

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I can. We need to set up the container. android:clipToPadding="false", and the partitioner has a negative margin:<?xml version="1.0" encoding="utf-8"?> <GirdLayout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:app="http://schemas.android.com/apk/res-auto" android:layout_width="match_parent" android:layout_height="wrap_content" android:paddingStart="24dp" android:paddingEnd="24dp" android:clipToPadding="false" >  <View android:layout_width="match_parent" android:layout_height="1dp" android:layout_marginStart="-24dp" android:layout_marginEnd="-24dp" android:alpha="0.14" android:background="#000" /> </GirdLayout>
How can you rename the element in ListView?
Software Programming • c sharp • • emmalee

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If there is a collection of textual data that are displayed as ListView and there is a need to change these data, then ListView is an inappropriate contrast. Take the right one. http://msdn.microsoft.com/ru-ru/library/system.windows.forms.datagridview.aspx which can be designed to look like ListView. You can also take a wrap on ListView - http://objectlistview.sourceforge.net/cs/index.html which allows for editing.Hiring: http://msdn.microsoft.com/ru-ru/library/ms745183.aspx ♪
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Concatenation of values in method toString
Software Programming • java • • Rossere

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What you would have to do would be to add the colors and if you're not in the penultimate position, add a comma. At the time you get to the penultimate position instead of a coma, you'd put a "y." By the way, you were forgetting to return the final value.public String toString() { String cadena = nombreLst + " es un Avenger, tiene " + edad + " años."; // Bucle para tipTiendaLST if (colorTrajeLst != null && colorTrajeLst.size() > 0) { cadena += " El color de su traje es "; for (int index = 0; index < colorTrajeLst.size(); index++) { ColorTraje colorTraje = colorTrajeLst.get(index); cadena += colorTraje; if (index < colorTrajeLst.size()-2) { cadena += " , "; } else if (index < colorTrajeLst.size()-1) { cadena += " y "; } } return cadena; }
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How do we make all possible combinations of mass elements?
Software Programming • python python 3.x algorithm • • Jolied

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We could use a surrogate function.def f(arr, N, start=''): # Массив без первого элемента arr1 = arr[1:] # Сколько мест надо, чтоб разместить arr1 alen = sum(map(len, arr1))+len(arr1)-1 # Нужен ли 0 после первого элемента if(alen): alen += 1 # Размещаем первый элемент на всех возможных позициях for i in range(N-alen-len(arr[0])+1): add = '0'*i + arr[0] if(arr1): f(arr1, N-len(add)-1, start + add + '0') else: # Если элементов не осталось, печатаем результат print(start + add + '0'*(N-len(add))) arr = ['1','11'] N = 5 f(arr,N) https://eval.in/958498
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Elements moving down at their appendix
Software Programming • html cs • • Avante

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If it's your job to fix, turn off the margins and add the types. vertical-align: topThat's if you're a little scrutinizedized, you're getting a little bit of help out. float: left♪ but better use ul+li ♪#sitemenu { width: 960px; min-height: 540px; border: 1px solid black; margin: 0 auto; background-color: white; } #sitemenu>* { float: left; margin: 2px; } body { background-color: #F2F2F2; } .logo { padding: 30px } #sitemenu div { width: 240px; height: 240px; border: 1px solid black; } #sitemenu p { font-family: calibri; font-size: 20px; font-weight: bold; color: #2E9AFE; text-align: center; padding: 0; margin: 0; cursor: pointer; } #sitemenu p:hover { color: black }<div id="sitemenu"> <img class="logo" src="https://placeholdit.co//i/50x50" alt=""> <div id="kompania1"> <p id="kompania">Компания</p> <p id="about link">О нас</p> <p id="rabota link">Наши работы</p> </div> <div id="info1"> <p id="info">Информация</p> <p id="faq">FAQ</p> </div> <div id="contacts1"> <p id="contacts">Контакты</p> </div> </div>Here's your point.#sitemenu { width: 960px; height: 540px; border: 1px solid black; margin: 250px auto 250px auto; background-color: white; } body { background-color: #F2F2F2; } #yticon { margin-left: 30px; } #kompania { font-family: calibri; font-size: 20px; font-weight: bold; color: #2E9AFE; text-align: center; } #kompania1 { display: inline-block; width: 240px; height: 240px; border: 1px solid black; vertical-align: top } #info { font-family: calibri; font-size: 20px; font-weight: bold; color: #2E9AFE; text-align: center; } #info1 { display: inline-block; width: 240px; height: 240px; border: 1px solid black; vertical-align: top } #contacts { font-family: calibri; font-size: 20px; font-weight: bold; color: #2E9AFE; } #contacts1 { display: inline-block; width: 240px; height: 240px; border: 1px solid black; text-align: center; vertical-align: top } #about { font-size: 20px; color: #BDBDBD; font-weight: lighter; font-family: calibri; padding-left: 75px; } #about:hover { color: black; } #rabota { font-size: 20px; color: #BDBDBD; font-weight: lighter; font-family: calibri; padding-left: 75px; } #rabota:hover { color: black; } #faq { font-size: 20px; color: #BDBDBD; font-weight: lighter; font-family: calibri; margin-left: 60px; } #faq:hover { color: black; }<div id="sitemenu"> <img id="yticon" src="https://placeholdit.co//i/50x50" alt=""> <div id="kompania1"> <p id="kompania">Компания</p> <p id="about">О нас</p> <p id="rabota">Наши работы</p> </div> <div id="info1"> <p id="info">Информация</p> <p id="faq">FAQ</p> </div> <div id="contacts1"> <p id="contacts">Контакты</p> </div> </div>
The best way to flip the XML flow?
Software Programming • java xml sax • • Demir

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I don't know. XMLIf it comes to the speed of the final application rather than the speed of programming, normal manual processing may have some kind of gain in the speed (if the narrow spot is not reading data, but processing). But it depends on the nature of the task.With regard to SAX, sax parser opens up any data.In some cases, it may be faster than StAX than SAX. For example, we need to know if the word "you" is in the document? It was found in the middle of the document. The rest of the document could not even be read. SAX, read.
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How to move element randomly through the screen (css or jquery)?
Software Programming • html jquery css • • juvenalb

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I made an example in http://jsfiddle.net/zrL5qkhh/1/ adapted as a base https://stackoverflow.com/a/10234282 .JAVASCRIEN$(document).ready(function() { $('.bouncer').click( function(){ alert('clicaram no: ' + $(this).attr('title')); }); }); $(function() { var minSpeed = .02; var maxSpeed = .06; var varSpeed = .005; function startBounce(element) { var container = element.parent(); var width = container.innerWidth() - element.outerWidth(); var height = container.innerHeight() - element.outerHeight(); var vertSpeed = ((Math.random() * (maxSpeed - minSpeed)) + minSpeed); var horzSpeed = ((Math.random() * (maxSpeed - minSpeed)) + minSpeed); bounce(element, vertSpeed, height, 'top'); bounce(element, horzSpeed, width, 'left'); } function bounce(element, speed, max, dir) { speed += ((Math.random() * varSpeed) - (varSpeed / 2)); speed = speed < minSpeed ? minSpeed : (speed > maxSpeed ? maxSpeed : speed) var time = max / speed; var position = element.position(); if (position[dir] < 2) { target = max; } else { target = 0; } var style = { queue: false }; style[dir] = target; element.animate(style, { duration: time, queue: false, easing: "linear", complete: function() { bounce(element, time, max, dir); } }); } startBounce($('#bouncer1')); startBounce($('#bouncer2')); }); CSS#container{position:absolute; width:300px; height:200px} .bouncer{position:absolute; width:20px; height:20px;} HTML<div id="container"> <div class="bouncer" id="bouncer1" title="bouncer 1">•</div> <div class="bouncer" id="bouncer2" title="bouncer 2">•</div> </div> I am keeping the source code here as a guarantee, since the original question on SOEN was given as duplicate of a question that has already been removed.
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I'm getting the same list on a RecyclerView
Software Programming • android kotlin • • Avante

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You have an adapter so you must generate 2 different instances of this and assign them to each of the recyclers:val mEducationAdapter: EducationAdapter = EducationAdapter(); val mComplementaryAdapter: EducationAdapter = EducationAdapter();
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Mysql + Combobox
Software Programming • java mysql combobox • • nishika

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Well, the first thing you'd have to do is that your combobox loads the database query to deploy the list of states, and since this uploaded this information, you select a "state" and you'll need to consult the database that cities are related to the selected state with the following code you can "list" the id or the value that is related to the state that allows you to load the city query. ...$(document).ready(function(){ $("button#recargarCiudad").click(function(e){ $("#Estado").on('change', function(){ $("#Estado option:selected").each(function(){ var cadenaClave = $('#Estado').val(); $.ajax({ async:true, cache:false, type: 'POST', url: 'cargarCiudades.php',data{cadenaClave:cadenaClave} }) .done(function(data){ $('#Ciudades').html(data); }) .fail(function(){ alert('Hubo un error al cargar la lista de ciudades'); }); });// fin de each - función que escucha elemento- }); }); });This script what it does is to get a value that could be a id or any other data that will help you to do the query to the bd and return to the cities that belong to the selected state... or in its default that is for what I use, load a second selector dependent on the other, already having these data the Count accounts and you get the number of records that returns you.
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It's not possible to correctly position the element after the button is pressed.
Software Programming • html cs position • • jonetta

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I'm doing this by checkbox. Here's my code.@import url('https://fonts.googleapis.com/css?family=Roboto:300,400,400i,500'); *{ padding: 0; margin: 0; list-style: none; text-decoration: none; } body { font-family: 'Roboto', sans-serif; } .sidebar { position: fixed; left: -250px; width: 250px; height: 100%; background: #bdbddb; transition: all .5s ease; } .sidebar header { font-size: 22px; color: white; line-height: 70px; text-align: center; background: #bdbdff; user-select: none; } .sidebar ul a{ display: block; height: 100%; width: 100%; line-height: 65px; font-size: 20px; color: white; padding-left: 40px; box-sizing: border-box; border-bottom: 1px solid black; border-top: 1px solid rgba(255,255,255,.1); transition: .4s; } ul li:hover a{ padding-left: 50px; } .sidebar ul a i{ margin-right: 16px; } #check{ display: none; } label #btn,label #cancel{ position: absolute; background: #bdbdbd; border-radius: 3px; cursor: pointer; } label #btn{ left: 40px; top: 25px; font-size: 35px; color: white; padding: 6px 12px; transition: all .5s; } label #cancel{ z-index: 1111; left: -195px; top: 17px; font-size: 30px; color: white; padding: 4px 9px; transition: all .5s ease; } #check:checked ~ .sidebar{ left: 0; } #check:checked ~ label #btn{ left: 250px; opacity: 0; pointer-events: none; } #check:checked ~ label #cancel{ left: 195px; } #check:checked ~ section{ margin-left: 250px; } section{ background: url(bg.jpeg) no-repeat; background-position: center; background-size: cover; height: 100vh; transition: all .5s; }<!DOCTYPE html> <html lang="en" dir="ltr"> <head> <meta charset="utf-8"> <link rel="stylesheet" href="style.css"> <script src="https://kit.fontawesome.com/a076d05399.js"></script> </head> <body> <input type="checkbox" id="check"> <label for="check"> <i class="fas fa-bars" id="btn"></i> <i class="fas fa-times" id="cancel"></i> </label> <div class="sidebar"> <header>Сим-сим</header> <ul> <li><a href="#"><i class="fas fa-qrcode"></i>Мужские )))</a></li> <li><a href="#"><i class="fas fa-link"></i>Легкие</a></li> <li><a href="#"><i class="fas fa-stream"></i>Средные</a></li> <li><a href="#"><i class="fas fa-calendar-week"></i>Сложные</a></li> <li><a href="#"><i class="far fa-question-circle"></i>Для Гениев</a></li> </ul> </div> <section></section> </body> </html>
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Element's not moving in the scrub.
Software Programming • javascript • • Duquan

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The necessary action is transferred to a function that is causing in the scrub:var cont = document.getElementById("container"); window.onload = relocate; window.onscroll = relocate; function relocate(){ var scrolled = window.pageYOffset || document.documentElement.scrollTop; scrolled = (scrolled - 0.001) / 100 | 0; var background = ["512px 445px","500 445px","490px 445px","480px 445px","470px 445px","460px 445px","450px 445px","440px 445px","430px 445px","420px 445px"]; var coord = scrolled <=1 ? 0 :scrolled >= 2 ? 9 : scrolled; cont.style.backgroundPosition = background[coord]; }#container { width:1000px; height:1500px; border:1px solid; background-image:url(https://s-media-cache-ak0.pinimg.com/736x/e6/3f/6a/e63f6ac9864239e7064f48f94ddc68c6.jpg); background-repeat:no-repeat; background-position:512px 445px; }<div id="container"> </div>
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Help to move an element with Javascript?
Software Programming • javascript html5 dom • • Pearlaqua

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I'm not sure if that's what you wanted, but I made a couple modifications to your js (apart from adding some extra info to the html to know if the links were shown) and something like this remained. Tell me if that's what you needed:const links = document.querySelectorAll('[href^="/lola/"]') links.forEach(function(elem) { var slw = elem.parentNode.parentNode.querySelector('.Mover'); //se encuentran los elementos con la clase "Mover" dentro de la misma FILA. var slwdata = document.createElement('div'); slwdata.innerHTML = slw.outerHTML; elem.parentNode.appendChild(slwdata); });<table> <thead> <th>A</th> <th>B</th> <th>C</th> <th>D</th> </thead> <tbody> <tr> <td> <div class="ABC">link:</div> <div class="Mover"><a href="/lolo/1">1</a></div> </td> <td> </td> <td> </td> <td><a href="/lola/1">1</a></td> </tr> <tr> <td> <div class="ABC">link:</div> <div class="Mover"><a href="/lolo/2">2</a></div> </td> <td> </td> <td> </td> <td><a href="/lola/2">2</a></td> </tr> </tbody> </table>Ojo, the code you put, more than moving what it does is copying.
Is it possible to check if an element does not have the style attribute with jquery?
Software Programming • javascript jquery html5 html selec languaget • • Demir

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In jQuery it is possible to usevar visivel = $(elemento-ou-seletor).is(":visible"); var naoVisivel = $(elemento-ou-seletor).is(":hidden"); This verifies whether the element has display: none; or not. Ignore visibility, only the attribute you refer. Elements with opacity 0 or visibility: hidden are not considered because they are technically part of the page render and occupy space.More about the :visible here: https://api.jquery.com/visible-selector/
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How do remove the previously selected element in ListView?
Software Programming • c sharp wpf xaml • • nishika

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I need to clear the allocation. Visual.Like I said, for such purposes, just redesign the element style. Let's say we have standard. ListView with some elements:<ListView SelectionMode="Single" HorizontalContentAlignment="Stretch"> <ListView.Items> <sys:String>1</sys:String> <sys:String>2</sys:String> <sys:String>3</sys:String> <sys:String>4</sys:String> <sys:String>5</sys:String> </ListView.Items> </ListView> Doing style ListViewItem in which the entire visual effect of the allocation is removed, but leaves the response to the mouse:<Style TargetType="{x:Type ListViewItem}"> <Setter Property="Template"> <Setter.Value> <ControlTemplate TargetType="{x:Type ListViewItem}"> <StackPanel x:Name="panel"> <TextBlock Text="{Binding}"/> </StackPanel> <ControlTemplate.Triggers> <Trigger Property="IsMouseOver" Value="True"> <Setter TargetName="panel" Property="Background" Value="Gray"/> </Trigger> </ControlTemplate.Triggers> </ControlTemplate> </Setter.Value> </Setter> </Style> It's basically just...The style itself applies to all types of objects ListViewItem♪ If you need some, we'll do it. x:Key and necessary ListView specified ItemContainerStyle♪Stile redefines the one Item'a template.<Setter Property="Template">() On the one we have identified. And we're just pointing out. StackPanel with one text counter.Next. <ControlTemplate.Triggers> We're pointing out the necessary triggers of this template. In our case, it's only one trigger who changes color. StackPanel to the gray in the mouse.Start and look at the result: As we see in the mouse, we have a successful change in color, there is no clicking on the object (vizoally).That's all.Next, you're gonna have to build your own design, and maybe add some more triggers.For example, add the allocation, let the evidence on the site be given a certain colour. Let's do another trigger:<Trigger Property="IsSelected" Value="True"> <Setter TargetName="panel" Property="Background" Value="Lime"/> </Trigger> Result:

ListView with the possibility of moving elements

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Elements moving down at their appendix
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I'm getting the same list on a RecyclerView
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Is it possible to check if an element does not have the style attribute with jquery?
Software Programming • javascript jquery html5 html selec languaget • • Demir

How do remove the previously selected element in ListView?
Software Programming • c sharp wpf xaml • • nishika