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How to get a text from resources (string.xml)

T
tahishae last edited by
I have a code.
```
Pattern p = Pattern.compile(R.string.regexDate + R.string.regexTime + R.string.regexLast);
```
Method Pattern.compile(String string)requires a string parameter, but from string.xml I get it. int♪ So, I'm getting the interns from the R.javabut I need straight lines. ♪ ♪
Resources from string.xml
```
<string name="regexDate" >^[2][\\d]{3}[0-1]{1}[\\d]{1}[0-3]{1}[\\d][_]</string>
<string name="regexTime">[0-2][\\d]([0-5][\\d]){2}[_]</string>
<string name="regexLast">[0]{3}[b][\\.][d][b]$</string>
```
Read the documentation. ♪ ♪
One optionrow:
```
String s = getString(R.string.regexDate);
```
Second option:
```
Resources res = getResources();
res.getString(R.string.regexDate)
```
I can't use these options as methods. getString(...), getResources() Eclipse can't see.
How do I get it? string.xml straight away, not her. id? If it's an example.
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R
Rossere last edited by

Methods getResources() or getString() from Contextbecause context has access to programme resources.
You can't get the line. string.xml♪
As a colt, you can write enum♪ but don't do it or use it ♪ public static final string in the class that Pattern uses
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V4 and V7 on Android
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This function is used to let you know if the list can be down or up or you've already reached one of the ends of your list:direction = 1 для скрола вниз (bottom) direction = -1 для скрола вверх (top) If the method returns false, which means you have reached the upper or lower level, depends on the direction. That's how you move everything into a variable:boolean canScrollDownMore = recyclerView.canScrollVertically(1);
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You'll.textView.setTextAppearance(int styleResId);
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Look at the maximum length TextView And just do the test, if it's not me, otherwise change... it's a rude method. ♪
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Get the text that matches a number at the beginning of the text
Software Programming • java regex • • shizuka

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Problems in your regexThere are 2 groups in your expression:"^([0-9]{1,12}\\.{1}[0-9]{1,3})|^([0-9]{1,12}).*$"; ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ ^^^^^^^^^^^^^ grupo 1 o grupo 2 Get the text that coincidedThe text with which it coincided Everything. the regex is returned by .group(0) (which is the same thing as .group()).The captures of the 2 will always be returned https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#cg So you don't need to go through them with a loop. The text captured by the first group is always obtained with .group(1), and the text captured by group 2 is always obtained with .group(2). In your expression, only one of these groups can match (it is one or the other), so one will return the number and the one that is not used for the match will return null.One or multiple matches on the same textThe loop in while (matcher.find()) It serves you in case there's more than one match in the string. 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(expresión) but it does not occupy memory unnecessary to capture the text. It would be:"^\d{1,12}(?:\.\d{1,3})?" How to get all the numbers in a string?Originally you were using while (matcher.find()) with the intention of obtaining all the coincidences in the text. To do this, we will not use ^ and $. Instead, we will ensure that it is not preceded by a digit or a point, and that it ends in a https://docs.oracle.com/javase/tutorial/essential/regex/bounds.html . That will allow us to match the different numbers, anywhere in the text.Regular expression(?<![\d.])\d{1,12}(?:.\d{1,3})?+\b (?<![\d.]) - Negative backward inspection.The current position is not preceded by: [\d.] - https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#cc - a https://docs.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html or a point.\d{1,12} - between 1 and 12 https://docs.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html .(?:\.\d{1,3})?+ https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#special , it is https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#greedy with ? and https://docs.oracle.com/javase/8/docs/api/java/util/regex/Pattern.html#poss with +.Match with: \. - a point (literal).\d{1,3} - between 1 and 3 https://docs.oracle.com/javase/tutorial/essential/regex/pre_char_classes.html .\b - https://docs.oracle.com/javase/tutorial/essential/regex/bounds.html (not followed by an alphanumeric or _).Codeimport java.util.regex.Matcher; import java.util.regex.Pattern; private void filtraNumeros(String texto){ String regex = "(?<![\\d.])\\d{1,12}(?:\\.\\d{1,3})?+\\b"; Pattern patron = Pattern.compile(regex); Matcher matcher = patron.matcher(texto); int contador = 0; //bucle para cada coincidencia. while (matcher.find()) { //Imprimir todo el texto con el que se coincidió System.out.println( ++contador + "° número: " + matcher.group() ); } } // Prueba String prueba ="abc 123 def 12.345 -- demasiados decimales: 1.1234 987654321.321 0"; filtraNumeros(prueba); Outcome1° número: 123 2° número: 12.345 3° número: 987654321.321 4° número: 0 Demo: http://ideone.com/jieOuc
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I used that. https://motorola-global-portal.custhelp.com/app/answers/prod_answer_detail/a_id/97326/p/30,6720,9050 to download the driver and run using the http://developer.android.com/sdk/installing/studio.html , but it is likely to work pro Eclipse too.
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With the text.setText (R.string.slovo + " + intValue); - the address of the resource is set.
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All right, you have to look at the resources of theer. getResources.Example getResources().getString(R.string.slovo )
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It is possible to assemble in Map by group (group - Main list of words) and then to set the values. Example:Stream<String> src = Stream.of("word", "hello", "dude", "word and word2", "stackoverflow", "question", "ask", "word", "example"); final AtomicInteger group = new AtomicInteger(0); Stream<Stream<String>> streamResult = src.map(s -> new AbstractMap.SimpleEntry<>(s, s.startsWith("word") ? 0 * group.incrementAndGet() - 1 : group.get())) .filter(entry -> entry.getValue() > -1) .collect(Collectors.groupingBy(Map.Entry::getValue, Collectors.mapping(Map.Entry::getKey, Collectors.toList()))) .values().stream().map(List::stream); If you need a result in a form List<List<String>> to:List<List<String>> listResult = new ArrayList<>(src.map(s -> new AbstractMap.SimpleEntry<>(s, s.startsWith("word") ? 0 * group.incrementAndGet() - 1 : group.get())) .filter(entry -> entry.getValue() > -1) .collect(Collectors.groupingBy(Map.Entry::getValue, Collectors.mapping(Map.Entry::getKey, Collectors.toList()))) .values()); Although in your situation it's not clear why to use the stream-- it's easier to just blend in the collection and get the results in the right form.
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How to get the dimension of the xml marking
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Colleague,You don't seem to know exactly how Android's final system works.XML is your wish, as you wish, to look like a screen. Next, your fantasy is on the physical screen. The verification shall be carried out in two stages:The dimensions shall be measured according to the wishes specified in the XML and the restrictions imposed by the parent. This part is performed by method View.measure()method onMeasure()which may be intercepted by the developer.The relevant dimensions of the calculations are then assigned. measure/onMeasure() - this is done by View.layout()attribution of size onLayout()which may also be intercepted.Measurement of size and attribution occurs dynamic i.e. runtime, there is therefore no way to apply the static dimensions in XML.Dynamicly find the size of the device ' s screen is not a complex, type code:WindowManager wm = (WindowManager) context.getSystemService(Context.WINDOW_SERVICE); Display display = wm.getDefaultDisplay(); Point size = new Point(); display.getSize(size); int width = size.x; //ширина экрана в пикселях int height = size.y; //высота экрана в пикселях These dimensions are supposed to be used. onMeasure()/onLayout()in order to give size to your caste. ViewGoogle it. custom+view+android
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What happens when the signature key expires?
Software Programming • android • • rosemadder

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After 25 Years make sure that Google will make several improvements to how to make an application available, and for sure the developers will not stay in hand. The technology advances and will be different in 2040, don't worry about this issue, it's not the time to spend effort since it's 25 years, until then, you can create another app with another new signature, but keeping your proposal in the application. There are numerous alternatives, so be quiet about it.

How to get a text from resources (string.xml)

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