C+++. Using "va_arg" a change-of-type error (possible to transform float into float)

[Alberto]

Hey! Please help me. There's Hero--

class Hero
{
public:
    ...
    float wins;
    ...
}

It's Result.

int Result(float draw, Hero Args, ...)
{
    int i = 0; float wins;
    va_list list;
    va_start(list, Args);
    while (i != 2)
    {
        wins = va_arg(Args.wins, float);
        cout << wins << endl;
        i++;
    }
    va_end(list);
    return 0;
}

When compiling, I get a mistake, "Impossible to transform "float" into "float." But the same trick with INT variables in the same class is :

[Trenton]

Use it right!

    wins = va_arg(list, float);

And you'll be able to... At least VC+++ is very clear and working. ♪ ♪

UpdateOn the treatment of the fields... This is a real live code for VC++ 2015:

#include <stdarg.h>
#include <iostream>
using namespace std;
struct Test

{

float a,b,c;

Test(float x):a(x),b(2x),c(xx){};

};
float Sum(int count, Test Args, ...)

{

float sum = Args.a;

va_list list;

va_start(list, Args);

for(int i = 0; i < count-1; ++i)

{

sum += va_arg(list, Test).a;

}

va_end(list);

return sum;

}
int main()

{

cout << Sum(3,Test(2.0),Test(4.0),Test(5.0)) << endl;

}

As you can see, different objects can be transferred.