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The challenge to the logic

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Nykeriab last edited by

I ran into this job at the interview. Personally, I didn't figure out what was going on here, and it would be interesting to hear the answer.
The Master's been given eight chains at six points each. He was asked. connect them to one continuous chain. He complied with the request, and he did so. I disconnected and reconnected only six lines. How did he do that?
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derk last edited by

Did you completely disband one chain and connect the rest with its components? (from my comment)
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A little logic Asp.NET and AngularJS Annexes
Software Programming • logic server client • • Raziyah00

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All security requirements are essentially related to:Server should never, under any circumstances, give to the client data that the client has no right to examine. It doesn't matter if the request for such data on the client, the request can always be forged. All rights checks should be carried out on the server, all information should be filtered according to server rights. That's it.Server shouldn't change the state of use when you get it. Such requests are sent by the browser without checking the cross-site security until the request is made and can be sent by malicious men (although he does not receive the answer, the server will process the request).
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Programming challenge
Software Programming • c++ liabilities • • emran

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There is no need for you to call a function of finding minimum elements immediately for only two-size. The function shall be separate for each line.The function may look as follows:int * min_element( int *a, int n ) { int *min = a + n; for ( int *p = a; p != a + n; ++p ) { if ( *p > 0 && ( min == a + n || *p < *min ) ) min = p; } return min; } The function returns the indicator to a minimum positive element in a single mass or at the end of the mass if there is no such element in the mass.The function may appear as follows:for ( int i = 0; i < arrayRow; i++ ) { int *min = min_element( array[i], arrayElements ); if ( min == array[i] + arrayElements ) { /* возникла ошибка. делайте, что хотите */ } else sqrtArray[i] = std::sqrt( ( double )*min ); }
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How do you calculate the number of new (unreaded) personal communications?
Software Programming • php mysql logic • • Avante

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Hello.For starters, you need to add a column like: activeIf this line is equal. 1 communication No. Readed. Then we can use this code, (To be at sessions):<?php session_start(); $sql = mysql_query("SELECT * FROM message WHERE user_id='".$_SESSION['user_id']."' AND active='1'"); if(mysql_nuw_rows($sql) > 0){ echo "У Вас новых сообщений: ".mysql_nuw_rows($sql); } ?> Explanations of the code:Table message - This is your table of messages.mysql_nuw_rows() - Turns the number of lines back.If active=1 - Communication Not readI hope that I understand:
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Logical Operators and Cycle While
Software Programming • python while operator • • Raziyah00

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You're misusing logical comparisons. You have a comparison where operator is different from "+", LUEGO has a separate expressions by AND that are evaluated very different from what you expect.Say a != b AND c AND d doesn't mean you compare to b, c and d. What's going on is,compared to bevaluate if c is true or falseevaluate whether d is true or falseSo, the python interpreter can't guess what you want is to compare the variable to each of those chains and you should tell them explicitly.a !=b AND a != c AND a != d
Structure and function challenge
Software Programming • c++ functions structures • • inna

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I'm not sure what's right, but it works.#include <iostream> #include <conio.h> #include <string> using namespace std; struct autoDescription { string autoName; int autoYear; int autoSpeed; }; autoDescription initStruct(string autoName, int autoYear, int autoSpeed) { autoDescription Toyota{ "Toyota", 1995, 180 }; autoDescription Nissan{ "Nissan", 2002, 220 }; autoDescription Honda { "Honda ", 2010, 250 }; return Toyota,Nissan,Honda; } void printStruct(autoDescription Cars) { autoDescription Toyota{ "Toyota", 1995, 180 }; autoDescription Nissan{ "Nissan", 2002, 220 }; autoDescription Honda { "Honda ", 2010, 250 }; // addprintf cout << Toyota.autoName<< "\t" << Toyota.autoYear<< "\t" << Toyota.autoSpeed << "\n"; cout << Nissan.autoName<< "\t" << Nissan.autoYear<< "\t" << Nissan.autoSpeed << "\n"; cout << Honda.autoName<< "\t" << Honda.autoYear << "\t"<< Honda.autoSpeed << "\n"; } int midSpeed() { autoDescription Toyota { "Toyota", 1995, 180 }; autoDescription Nissan { "Nissan", 2002, 220 }; autoDescription Honda { "Honda ", 2010, 250 }; const int mSpeed = 3; int allSpeed = Toyota.autoSpeed + Nissan.autoSpeed + Honda.autoSpeed; int avgSpeed = allSpeed / mSpeed; cout <<"Avarage speed is: "<< avgSpeed << endl; return avgSpeed; } autoDescription massAuto(string autoName, int autoYear, int autoSpeed) { autoDescription Toyota{ "Toyota", 1995, 180 }; autoDescription Nissan{ "Nissan", 2002, 220 }; autoDescription Honda { "Honda ", 2010, 250 }; const int n = 3; autoDescription* ptrAuto; autoDescription masAuto[n]; ptrAuto = masAuto; for (int i = 0; i < n; i++) { cout << ptrAuto[i].autoName << "\t" << ptrAuto[i].autoSpeed << "\t" << ptrAuto[i].autoYear << "\t\n"; } return Toyota, Nissan, Honda; } int main() { autoDescription Toyota{ "Toyota", 1995, 180 }; autoDescription Nissan{ "Nissan", 2002, 220 }; autoDescription Honda { "Honda ", 2010, 250 }; initStruct("Toyota", 1995, 180); initStruct("Nissan", 2002, 220); initStruct("Honda ", 2010, 250); printStruct(Toyota); midSpeed(); //massAuto("Toyota", 1995, 180); //massAuto("Nissan", 2002, 220); //massAuto("Honda ", 2010, 250); _getch(); }
Timely challenge
Software Programming • c++ time function • • morde

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This is how C++11 (not the best option, but fast in operation):#include <atomic> #include <thread> #include <chrono> #include <iostream> template<typename Callback, typename... Args> std::atomic_bool& set_interval(const std::chrono::milliseconds& interval, Callback callbakc, Args... args) { std::atomic_bool is_running = true; auto function = std::bind(std::forward<Callback>(callbakc), std::forward<Args>(args)...); std::thread thread([=, &is_running] { while (is_running) { std::this_thread::sleep_for(interval); function(); } }); thread.detach(); return is_running; } int main(int argc, char** argv) { std::atomic_bool& is_running = set_interval(std::chrono::milliseconds(5000), [] { std::cout << "Hello world" << std::endl; }); std::this_thread::sleep_for(std::chrono::milliseconds(25000)); return EXIT_SUCCESS; }
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Looking for a library, triple logic.
Software Programming • php logic • • courtlanda

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Got it. http://tools.sh4dow.ru/l3/ (ibid. http://tools.sh4dow.ru/download/?file=class.l3.php and look at the truth sheets leaflets for future generations:define('TRUE3', 1); define('NULL3', 0); define('FALSE3', -1); function l3validate(&$arg) { if ($arg !== FALSE3 and $arg !== NULL3 and $arg !== TRUE3) { $arg = NULL3; return FALSE3; } return TRUE3; } function l3not($a) { // НЕ, инверсия l3validate($a); if ($a === TRUE3) return FALSE3; if ($a === FALSE3) return TRUE3; return NULL3; } function l3and($a, $b) { // И, конъюнкция l3validate($a); l3validate($b); if ($a === TRUE3 and $b === TRUE3) return TRUE3; if ($a === FALSE3 or $b === FALSE3) return FALSE3; return NULL3; } function l3andm() { // И, несколько аргументов $result = TRUE3; foreach (func_get_args() as $arg) { l3validate($arg); if ($arg === NULL3) $result = NULL3; if ($arg === FALSE3) return FALSE3; } return $result; } function l3or($a, $b) { // ИЛИ, дизъюнкция l3validate($a); l3validate($b); if ($a === $b and $a === FALSE3) return FALSE3; if ($a === TRUE3 or $b === TRUE3) return TRUE3; return NULL3; } function l3orm() { // ИЛИ, несколько аргументов $result = FALSE3; foreach (func_get_args() as $arg) { l3validate($arg); if ($arg === NULL3) $result = NULL3; if ($arg === TRUE3) return TRUE3; } return $result; } function l3xor($a, $b) { // ЛИБО ... ЛИБО ..., строгая дизъюнкция l3validate($a); l3validate($b); if ($a === $b and $a !== NULL3) return FALSE3; if (($a === TRUE3 and $b === FALSE3) or ($a === FALSE3 and $b === TRUE3)) return TRUE3; return NULL3; } function l3imp($a, $b) { // ->, импликация l3validate($a); l3validate($b); if ($a === FALSE3 or $b === TRUE3) return TRUE3; if ($a === TRUE3 and $b === FALSE3) return FALSE3; return NULL3; } function l3bimp($a, $b) { // <-, обратная импликация l3validate($a); l3validate($b); if ($a === TRUE3 or $b === FALSE3) return TRUE3; if ($a === FALSE3 and $b === TRUE3) return FALSE3; return NULL3; } function l3eq($a, $b) { // =, эквивалентность l3validate($a); l3validate($b); if ($a === NULL3 or $b === NULL3) return NULL3; if ($a === $b) return TRUE3; return FALSE3; } ALL: For @Dex: https://rus.stackexchange.com/questions/1032/%D0%BB%D0%BE%D0%B3%D0%B8%D0%BA%D0%B0-%D1%82%D1%80%D0%BE%D0%B8%D1%87%D0%BD%D0%B0%D1%8F-%D1%82%D0%B5%D1%80%D0%BD%D0%B0%D1%80%D0%BD%D0%B0%D1%8F-%D1%82%D1%80%D0%B5%D1%85%D0%B7%D0%BD%D0%B0%D1%87%D0%BD%D0%B0%D1%8F So you took it. But look at the discussion, it was complicated and purely aesthetic. Even the triple-valent option would be correct in lexo per cent.UPDATE: Fixed the ideano, any "unidentified" turns into NULL3. If you want to be more tolerant, there's a method in the class. castround to the nearest logical.
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Logical operation
Software Programming • php logic • • emerson

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That's what you need to use.if (empty($login) || empty($email)) {$error = 'Поля не должны быть пустыми.';}
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How do you write stderr without time?
Software Programming • golang logic • • Kadyn

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(Revision https://stackoverflow.com/q/29721449/1892060 . First, a new one can be created to cover without time. Zero flag logger: var l = log.New(os.Stderr, "", 0) l.Println("hello world") Second, you can just write directly into it. os.Stderr: n, err = os.Stderr.WriteString("hello world") Or if a formatted conclusion is needed: n, err = fmt.Fprintf(os.Stderr, "number: %d", i)`
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There's no logic.
Software Programming • php mysqli • • emerson

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I don't know what you've got, the trouble may not be condensed with the base, maybe something else, but here's the work code for your case. Check the sample for the number of elements if more than 0 means there's a user with a password in the database. P.C. Use the players.<?php session_start(); $er = False; if (empty($_POST['login']) || empty($_POST['pass'])) exit ("Неправильный логин или пароль!<a href='../login.php'>Ввести еще раз!</a>"); // include "db_connect.php"; $mysqli = new mysqli('localhost', 'my_user', 'my_password', 'my_db'); if ($mysqli->connect_error) { die('Connect Error (' . $mysqli->connect_errno . ') ' . $mysqli->connect_error); } /////////////////////////// $stmt = $mysqli->prepare("SELECT * FROM users WHERE login = ? and password = ?")) $stmt->bind_param("ss", $_POST['login'], sha1($_POST['pass'])); $stmt->execute();
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Python. Don't frustrate the log through a regular expression where there might be a mistake?
Software Programming • python json parser logic re • • Kadir

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You wrote the wrong regular expression, I fixed it. This is the working version of the code:import re import json def reader(filename): regexp = r'{(?s:.*)}' with open(filename) as f: log = f.read() json_value = re.findall(regexp, log) print(json.loads(json_value[0])) if name == 'main': reader('test.log') Explanation of the structure of regular expression:{(?s:.)} - It's possible to find a structure in the format text. {...}{ - open bracket(?s:.)} - The structures make it possible to find the last entry. } in the text.Function json.loads() passes json line, converts it into class object. dict (Speaker)
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Interview task
Software Programming • c++ interview assignment • • guilherme

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Privacy n = 3, balance of separation (n % 2) equal to 1, respectively, in the design switch/case moving on to mark 1case 1:and variable i is increased by 1. The value n is further reduced by 1 and the exit condition is checked.n = 2which is more than 0. There is no exit from the cycle body, so the has continued since the beginning of the block do {♪ There is an increase of variable i by 2 in the tele-cycle++i; case 1: ++i;) Design switch/case There's no "work." The n value shall be reduced by 1 and the exit condition checked.n = 1the exit condition has not been met, the previous paragraph shall be repeated. Modified i increases by 2.n = 0the cycle ends and the end value i is 5, respectively.Verification https://ideone.com/Mox6J6
I can't change the challenge.
Software Programming • javascript fumes • • Alberto

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function animation(args, elem) { // некоторые аргументы определим на будущее var $ = { radius: 250, // радиус окружности speed: 20 // скорость/задержка ( в js это мс, например 10 мс = 100 кадров в секунду) } var f = 0; var s = 2 * Math.PI / 180; //Вычислим угол setInterval(function() { // функция движения f += s; // приращение аргумента elem.style.left = 235 + $.radius * Math.sin(f) + 'px'; // меняем координаты элемента, подобно тому как мы это делали в школе в декартовой системе координат. Правда, в данном случае используется полярная система координат, изменяя угол elem.style.top = 235 + $.radius * Math.cos(f) + 'px'; }, $.speed) } animation({}, document.querySelector('#round .css'));body { background: #000000; } .css { position: absolute; background: #6495c4; width: 30px; height: 30px; left: 70px; top: 40px; border: 3px solid #fff; cursor: pointer; border-radius: 19px; -webkit-border-radius: 19px; -moz-border-radius: 19px; } #round { position: absolute; left: 50%; margin-left: -250px; top: 100px; width: 500px; height: 500px; border: 5px solid #6495c4; border-radius: 250px; -webkit-border-radius: 250px; -moz-border-radius: 250px; }<div id="round"> <div class="css"></div> </div>
JavaScript and page challenge
Software Programming • javascript asp.net • • Alberto

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It's called the callback function or the "back-up function" on them all the JavaScript thing, count and build. In brief, the browser generates the request and performs it as soon as he has received a response from the server, he sees what function he has to call it (referring to it in the third Parameter of GetPersonalInfo) and calls it on his own hand with the parameters.You can read about JavaScript technology called Ajax, which is used.
MergeSort, logic problem
Software Programming • java algorithm classification • • Laycee

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There are two mistakes. The first one is here: int[] aux = new int[10]; It was to be new int[x.length]!But your big mistake is here: for(i = inicio_vetor1;i<=meio;i++){ aux[poslivre]=x[inicio_vetor1]; poslivre+=1; } for(i = inicio_vetor2;i<=fim;i++){ aux[poslivre]=x[inicio_vetor2]; poslivre+=1; } Note that you are not using the variables i inside the loops! It should be this: for(i = inicio_vetor1;i<=meio;i++){ aux[poslivre]=x[i]; poslivre+=1; } for(i = inicio_vetor2;i<=fim;i++){ aux[poslivre]=x[i]; poslivre+=1; } With these changes, it works straight. https://ideone.com/WPAhng - I also took advantage of and packed some code formatting details.

The challenge to the logic

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How do you write stderr without time?
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