Exception in main

[Saumya]

Why in the method main I need to write. throws Exception? Why would that be? Who will accept the exception?

[emmalee]

Operator throws shows that under certain conditions, the method may be waived by the processor. try-catch There will be no exception or no.
So, mainif there are unintended errors in a type code, the method mandatory If there is no exception, the method will end its work in peace. Me throws - it's a warning, which might be an exception in the method.
Well, to avoid situations of exclusion in the main method. main, doubtful actions should be processed try-catch♪

For example, I think you know you can't share zero, that's what this action doesn't make sense. Therefore, it can be assumed that if we split zero, there will be an exception:

public static void main(String[] args) throws Exception {
    System.out.println(1/0); // Пытаемся делить на нуль
}

That's the method. main() We got an exception.

Exception in thread "main" java.lang.ArithmeticException: / by zero

It may be envisaged that the user might want to share a zero curve, so we'll just work out the exception:

public static void main(String[] args) throws Exception {
    try {
        System.out.println(1/0); // Пытаемся делить на нуль
    } catch(ArithmeticException exc) { System.out.println("На нуль делить нельзя"); }
}

Thus the method main() I didn't throw out the exception because the design try-catch I'm sorry. ArithmeticException

And who's stopping you from using just:

public static void main(String[] args) {
}