How to reduce the recording of JS - to normalize (short rooms)

[Burma]

Please indicate how to bring the jquery code into normal appearance:

$('.go0').click(function(){
    carousel.trigger('owl.goTo', 0)
});
$('.go1').click(function(){

carousel.trigger('owl.goTo', 1)

});
$('.go2').click(function(){

carousel.trigger('owl.goTo', 2)

});
$('.go3').click(function(){

carousel.trigger('owl.goTo', 3)

});
$('.go4').click(function(){

carousel.trigger('owl.goTo', 4)

});
$('.go5').click(function(){

carousel.trigger('owl.goTo', 5)

});
$('.go6').click(function(){

carousel.trigger('owl.goTo', 6)

});
$('.go7').click(function(){

carousel.trigger('owl.goTo', 7)

});
$('.go8').click(function(){

carousel.trigger('owl.goTo', 8)

});

Elements.go0♪ .go1 It could be infinitely a lot, and it's not normal to write them like that.

Unfortunately, I didn't find a way to write this down as n+1 or something.

[zymir]

Decision "not including brains"

for (var ix = 0; ix < 9; ix += 1) {
    $('.go' + ix).click(function (ix) {
        return function() {
            carousel.trigger('owl.goTo', ix);
        };
    }(ix));
}

Now a normal decision:

Typically, the cruising switches have a common ancestor and the elements themselves are in a row. So it's enough to find a descendant number at the ancestor that in jQuery is a trivial task. Suppose all switches have a class. go:

$('.go').click(function() {
    carousel.trigger('owl.goTo', $(this).index());
});

If the elements .go There's still one of them in their spine, instead. $(this) It will be necessary to indicate an ancestor whose position within its ancestor can give a slide number.