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Why does a 10000 byte not give maximum weight byte?

A
Avante last edited by
Why do you have to do it? int c = 10000 type bytethe variable becomes equal 16Not 128the maximum value byte?
```
int c = 10000;
byte d = (byte) c;
System.out.println(d);
```
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C
charlenef last edited by

You don't quite understand how the types are being introduced.
Attempt int to byte There is no " best approach " . There is a different way: " senior " baytes are simply thrown away.
10000 = 0x2710 consists of two byte: 0x27 and 0x10. Senior White's dropping off, left junior 0x10 = 16.
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I'll guess a little.4 - Bright indicates that the size should be 71. Although 75 bikes are leaving only 71, and all I don't know why he's doing that.Something tells me that 75 = 71 + 4 and 4 is exactly the first four bays that indicate the amount of the payload.And why the first three baytes are just zero.I want you to study the issue of the bikes. http://htrd.su/wiki/zhurnal/2013/10/21/big-endian_i_little-endian_shpargalka from me. The x86 uses Little-Endian, and the tape is used. uin32_t There will be:71 0 0 0 The network is used by the Byte Ordering, but it's Big-endian, so the same number accepts the type:0 0 0 71
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What happened and some work. public static void Broadcast(byte[] data) { r = new Mp3FileReader(WavToMP3(data)); while ((frame = r.ReadNextFrame()) != null) { foreach(Consumer c in WebCast.Clients) c.Audio(frame.RawData); Console.Title = frame.FrameLength.ToString(); } } public static MemoryStream WavToMP3(byte[] wavFile) { using(var retMs = new MemoryStream()) using(var ms = new MemoryStream(wavFile)) using(var rdr = new RawSourceWaveStream(ms, new WaveFormat(44100, 16, 1))) using(var wtr = new LameMP3FileWriter(retMs, rdr.WaveFormat, 128)) { rdr.CopyTo(wtr); wtr.Flush(); return new MemoryStream(retMs.ToArray()); } }
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In English-speaking SO enthusiasts https://stackoverflow.com/q/5331549/5238378 and found that the number of $in objects was not formally limited, but, as an argument, .find() The object is sent, and it is also subject to restrictions on the size of MongoDB facilities at 16 Mb.Object.bsonsize({ 'field' : { $in : [ value1, value2, ..., valueN] } }) This code will give you the amount of your request. Probably the larger the size of all that. field and valueXthe less they get on the request.Conclusion:If the aim is to send as many options as possible $inOne comrade. https://stackoverflow.com/a/18495467/5238378 ♪ maximum number of elements in $in approximately 1.5 millionIf the purpose is to be applied in practice, the limitation can be ignored in a calm manner)
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Why does a 10000 byte not give maximum weight byte?

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