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Will there be an instance of blocks in the abstract class?

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nishika last edited by

And if they work, what happens?
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charlenef last edited by

https://docs.oracle.com/javase/specs/jls/se8/html/jls-8.html#jls-8.6 will always be able to produce a copy of the class that inherits https://docs.oracle.com/javase/specs/jls/se8/html/jls-8.html#jls-8.1.1.1 :
A subclass of an abstract class that is not abstract itself may be instantiated, resulting in the execution of a constructor for the abstract class and, therefore, the execution of the field initializers for instance variables of that class.
Translation:
A copy of the heir to an abstract class that is not abstract may be created, which will result in the construction Abractic class and initiators of the field of a copy for this class.
Procedure for establishing a new copy is described in https://docs.oracle.com/javase/specs/jls/se8/html/jls-12.html#jls-12.5 or https://ru.stackoverflow.com/questions/464028/ ♪
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Remove location within a certain time
Software Programming • java android service • • rielyn

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Did it with help. Firebase Cloud Messages and FirebaseJobDispatcher♪ It's just that the server at some point sent a message to the user. The phone was sent back to the Geolocation server within an hour.
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Static method of abstract Class, C+++
Software Programming • c++ inheritance static • • rosemadder

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class A { public: static void show(const A* object) { object->show(); } virtual void show() const = 0; }; class B : public A { public: void show() const override { std::cout << "hello from B" << std::endl; } }; class C : public A { public: void show() const override { std::cout << "hello from C" << std::endl; } }; int main() { std::vector<A*> arr; arr.push_back(new B()); arr.push_back(new C()); for (const auto& it : arr) A::show(it); return 0; } Is that okay?UPD1:class A { public: static void show(const std::unique_ptr<A>& object) { object->show(); } virtual void show() const = 0; }; class B : public A { public: void show() const override { std::cout << "hello from B" << std::endl; } }; class C : public A { public: void show() const override { std::cout << "hello from C" << std::endl; } }; int main() { std::vector<std::unique_ptr<A>> arr; arr.push_back(std::make_unique<B>()); arr.push_back(std::make_unique<C>()); for (const auto& it : arr) A::show(it); return 0; }
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How do I make a standard DAO abstract java class to inherit in the dao classes?
Software Programming • java godfather • • Jolied

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Apparently you would like to implement a http://docs.spring.io/spring-data/commons/docs/current/api/org/springframework/data/repository/CrudRepository.html that is part of Spring Data, but is used as a strategy for persistent entities (JPA). As you do not want to use any JPA provider, we proceed to an alternative:O https://github.com/nurkiewicz/spring-data-jdbc-repository that seeks a generic, lightweight and simple approach to RDBMS, was based on http://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/jdbc/core/JdbcTemplate.html (Spring Framework).It delivers the full implementation of Spring's PagingAndSortingRepository abstraction without using JPA, XML. public interface PagingAndSortingRepository<T, ID extends Serializable> extends CrudRepository<T, ID> { T save(T entity); Iterable<T> save(Iterable<? extends T> entities); T findOne(ID id); boolean exists(ID id); Iterable<T> findAll(); long count(); void delete(ID id); void delete(T entity); void delete(Iterable<? extends T> entities); void deleteAll(); Iterable<T> findAll(Sort sort); Page<T> findAll(Pageable pageable); Iterable<T> findAll(Iterable<ID> ids); } The following are a reference for use:Page<User> page = userRepository.findAll( new PageRequest( 5, 10, new Sort( new Order(DESC, "reputation"), new Order(ASC, "user_name") ) ) ); And http://architects.dzone.com/articles/spring-data-jdbc-generic-dao with api idealizer Tomasz Nurkiewicz.
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"Can you instance objects of a class without the New Operator"
Software Programming • java android android studio • • elysha

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The case you propose is not necessary:editName = new EditText ((EditText)findViewById(R.id.editText Name)); Since what you're doing with the findviewbyid is collecting the object from the XML view is a form of mapping for the activity to know what the XML objects are.editName =(EditText)findViewById(R.id.editText_Name);
Cloning Object's with the retrofit final
Software Programming • java op • • emmalee

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If in the copyable object class all fields are final, and the cloned object will be unreplaceable.class Original impl Clonable{ private final Object obj; Original(Object obj){ this.obj=obj; } Original clone(){ return new Original(this.obj); } This unreplaceable object (all fields final) is being copied with a new unreplaceable objectIf you're talking about cloning the object and if the variable containing the object is final, it's all up to its announcement.final Object clone = original.clone(); - final variable object
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How do you get a value from JSON in every single class block?
Software Programming • jquery json • • Trenton

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I'm doing it like that. I mean, it's like you're only in the cycle going through the blocks and then pulling a name. a function init registers in ready function init() { $.getJSON("main.json", out); } function out(data) { var out = ''; for (var key in data) { out += '<div class="card">' out += '<h2>' + data[key].name + '<h2>' out += '</div>' } $(".biling").html(out) } $(function() { init(); })example json { "main": { "name": "name", "family": "family", "stage": "40", "country": "counter", "city": "city", "experience": "4", "img": "img/user.jpg" } }
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Dynamic SQL request
Software Programming • java sql oracle hibernate • • Anderson

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You have a field in both tables. ID and since you're using * for field names, field ID I don't know what to do. As a result, hibernate is fighting for the duplication of the ayas.To fix this, we need to rename the alias for the two tables that you're joining so there's no match.
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Referral to class to other class
Software Programming • javascript • • zymir

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Almost. If you do the code you wrote, you'll get a mistake about what's more than the call stack. Why is that? It's just because the Vk designer initiates VkMessages, and it in turn extend Vk. Thus, the Vk designer is being implemented again and again as long as there is a place in the call stack, and when there is no place, there is a mistake.But VkMessages don't need to extend Vk, do they? So we're making a tiny change in your code, and we're getting a working option:class Vk { constructor(token, version = 5.95) { this.token = token; this.version = version; this.messages = new VkMessages(); } } class VkMessages // ← Вот тут изменение. { getDialogs() { return []; } } const test = new Vk(''); test.messages.getDialogs(); This is a more complete example where token and version Moved into a separate class that represents the context of the programme and transferred from Vk to VkMessages♪class VkContext { constructor(token, version = 5.95) { this.token = token; this.version = version; } } class Vk { constructor(context) { this.context = context; this.messages = new VkMessages(context); } } class VkMessages { constructor(context) { this.context = context; } getDialogs() { return []; } } const context = new VkContext(''); const test = new Vk(context); test.messages.getDialogs();
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Android service doesn't reconnect to the server when the phone is.
Software Programming • java android service soot • • emerson

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Maybe it works Doze Mode in Marshmallow. The ability to connect with the server is checked on SDK 23+ devices with additional request PowerManager♪ It's actually good to do that: if (connectivityManager.getActiveNetworkInfo() != null && connectivityManager.getActiveNetworkInfo().isConnected() && (Build.VERSION.SDK_INT < Build.VERSION_CODES.M || !powerManager.isDeviceIdleMode() || powerManager.isIgnoringBatteryOptimizations())) { // do something } If you need a vodkast to get out of Doze, you can go like this: registerReceiver(br, new IntentFilter( PowerManager.ACTION_DEVICE_IDLE_MODE_CHANGED)); Try to check it out first: add an annex to the linelist from the construction (Settings-Battery-Battery Optimization) and then, for your application, insert "Don't save" and see what changes.I've been doing a report in time, looking at the presentation, and there's still interesting little things in there (from 15 to 30 slides): http://www.slideshare.net/jollydroid/android-marshmallow-13112015
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I don't know the directory in the context file in cloud9.
Software Programming • java jsp tomc languageat • • Rossere

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I think it is faster to write the steps I did.Folder Structure:~/workspace (左UIではワークスペースの名前になる) |-apache-tomcat-8.5.8 | |-bin | |-config | | |-Catalina | | | |-localhost | | | |-helloZZZ.xml <- コンテキストファイル | | |-localhostフォルダ以外いろいろ | |-lib,logsなど動かすだけには関係無いもの | |-helloAAA <- コンテキストで指定したフォルダ |-index.html |-index.jsp First of all, Cloud9's Java is Java7 it is not supported by Tomcat9. De。 Tomcat8 and decompress.$JAVA_HOMEand$CATALINA_HOMEEnvironment Parameter Index($JAVA_HOMEThe folder may change in the future. /bin/javaPlease follow the link.$CATALINA_HOMEtomcat folder. )$ export JAVA_HOME=/usr/lib/jvm/java-7-openjdk-amd64 $ export CATALINA_HOME=~/workspace/apache-tomcat-8.5.8 Tomcat should be running at this stage, so start it.$ $CATALINA_HOME/bin/catalina.sh start Press "Preview" on the top or tabhttps://<ワークスペース名>-<ユーザー名>.c9users.io/Access to Tomcat to display the same page. write context~/workspace/tomcat/config/Catalina/localhost/Contact UsdocBase=Why?~/workspaceIt’s a good idea, so it’s an absolute path.helloZZZ.xmlContents (file name andpath=same. <Context path="/helloZZZ" docBase="/home/ubuntu/workspace/helloAAA"/> Make appropriate html and jsp filesdocBase=to the specified folder.https://<ワークスペース名>-<ユーザー名>.c9users.io/helloZZZYou should be able to access it like this.Example jsp:<html> <head> <title>Hello World!</title> </head> <body> <h1>Hello World!</h1> <% out.println(new java.util.Date()); %> </body> </html> Stop Tomcat (I think Cloud9 has stopped for about 2 hours even if left).$ $CATALINA_HOME/bin/catalina.sh stop
Can't connect to OBD FoxPro via bridge jdbc:odbc
Software Programming • java jdbc odbc dbf • • inna

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If you have a problem like this, then you just have to download jdk7 x86 and set it up. The 32-design version will never rewrite or replace or affect the 64-fold version. Then in Project Structure... point the way to this jdk. It's probably gonna be with you. Good luck!
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Create class instance in threads
Software Programming • c sharp net thread • • Duquan

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Object instance is object instance. Thread It is thread. Unless by the fact that one thread be a specific object, one thing has nothing to do with the other.Threads are finished when they are no longer being used (usually). Object instances are destroyed when they are no longer useful and C# has automatic management of this.Note that this is a little more complicated. The object containing the thread can be collected soon after giving https://pt.stackoverflow.com/q/166032/101 . It is no longer necessary after that thread comes into operation. She runs independently.A thread itself will exist while what is contained within it (CriarAnimal) is running. Note that it can rotate even with the "official" closure of the application, since it put in background.At the end of the code presented will create one array with 10 animals where each will go through some process of creation. This process is presumed to be long and the 10 may occur in https://pt.stackoverflow.com/q/166032/101 , give time :).And it is important to understand https://pt.stackoverflow.com/q/1946/101 and do not bring gains, on the contrary. has a great chance of the cost of creating a thread be higher than the cost of creating a Animal.Understand that it is a https://pt.stackoverflow.com/q/123173/101 . The use of tasks can help a little minimize waste of creation thread.See more or less what it would be like https://pt.stackoverflow.com/q/169079/101 .See also: https://pt.stackoverflow.com/q/157435/101 .According to the comments below, the question has been modified, and indicates that this solution seems less suitable yet.
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Can I change the password to identify myself in OpenXava (without XavaPro)?
Software Programming • java security openxava • • charlenef

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In the 'properties' folder within your project you can find a file called naviox-users.properties, with this content:# In plain OpenXava the users are added here in the form user=password # If you want full management of users, roles and modules stored in database, # get XavaPro from here: http://www.openxava.org/xavapro admin=admin Edit it and change admin=admin by admin=tucontraseña. You have to restart your application so that it take effect.To learn more about security and user management with OpenXava look: https://openxava.org/OpenXavaDoc/docs/security_es.html
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It doesn't matter if there's a checkbox or a block click, you have to make an active checkbox and add a class to the block. Remove the click.
Software Programming • javascript html jquery • • guilherme

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$(this).find(":checkbox").attr("input-chek", "checked"); // ?! ♪ input-chek - class name. The " notices " are called checked .attr("checked", "checked")$(".cheaper-content__card").on("click", function(e) { if ( $(e.target).is(":checkbox") ) { // Кликнули по чекбоксу, ничего не надо делать. return; } let $cb = $(this).find(":checkbox"); $cb.prop("checked", !$cb.prop("checked")).trigger("change"); // $cb.prop("checked") — true или false. // Устанавливается (!обратное) значение. // .trigger("change") — Вызывает событие "change", которое переключает класс. }); $(".cheaper-content__card").on("change", function(e) { // При любом изменении чекбокса... if ( $(e.target).is(":checkbox") ) $(this).toggleClass("selected"); });.cheaper-content__card { border: 1px solid #ddd; } .cheaper-content__card.selected { border-color: orange; }<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <div class="cheaper-content__card"> <div class="cheaper-content__chekbox"> <input type="checkbox" id="LV4010F0" name="LV4010F0" value="yes" class="input-chek"> <label for="LV4010F0"></label> </div> <img src="img/cheaper-1.png" alt=""> <a href="#"> </a> <span> 9 690 ₽ </span> </div> <div class="cheaper-content__card"> <div class="cheaper-content__chekbox"> <input type="checkbox" id="LV2010F0" name="LV2010F0" value="yes" class="input-chek"> <label for="LV2010F0"></label> </div> <img src="img/cheaper-2.png" alt=""> <a href="#"> </a> <span> 4 990 ₽ </span> </div>
Difference in Java and JS when creating a class and instance it?
Software Programming • javascript java mongodb api • • inna

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I don't understand why JS doesn't work the same way.Why would I have to? They are completely different languages that were born with needs and that meet different goals. It's like comparing Peras with Apples and saying why they don't know the same if both are fruits.Java implements POO in a very different way than JavaScript. The latter implements a prototyping POO, which is very different from the classic POO that implements Java. In fact, in JavaScript there is no class concept.Make the clarification, let's go for your mistake. Your mistake is you're not exporting anything. Node.js implements CommonJS in its source code, which is a library for code modularization, allowing you to write JavaScript in "modules" that are independent, which can be exported and imported from anywhere. Without the existence of CommonJS, You'd have to write everything in one file., making it extremely difficult for post-reflect tasks.To export a CommonJS module is used module.exports and no module.export how you're using: module.exports = moongose.model('Usuario', usuarioSchema); This puts the file in the CommonJS repository so it can be imported. In your case you're not exporting anything, then when you import UsuarioYou're importing the CommonJS object and This is not a builder..Remember also that this way an object is exported to be available by default. There is also the following way to export:var model = moongose.model('Usuario', usuarioSchema); exports.model = model; In this case, model will not be available as a default option to import, if not the entire export object will be exported containing model:var Usuario = require('../Usuario').model; Note: it is not necessary to add the suffix .js by importing.

Will there be an instance of blocks in the abstract class?

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