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Work with Russian lines. How do you know one of the letters?

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Cleofas last edited by

There's a line of numbers and letters of the Russian alphabet. We need to know the index of one of the letters. Use s.find('Н') There's a mistake.
Used python-2.7 Underneath Ubuntu♪
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Analeea last edited by
```
s.find(u'Н')
```
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transform list numbers into numbers of a matrix in python
Software Programming • python python 3.x matrix • • zymir

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You have several problems in your code, one of them is to do lista[i][j]. How lista is a list of numbers, so lista[i] is a number, and therefore has no way to access the position j this number. But even if I could, logic is wrong.As you have verified before if the size of the list is correct, you no longer need 2 loops nested. Simply iterate by the list, and when the amount of elements complete a line, you add in the matrix and start a new line:matriz = [] if len(lista) == linhas * colunas: linha = [] # criar uma nova linha for n in lista: # para cada elemento da lista linha.append(n) # adicionar na linha if len(linha) == colunas: # se já deu a quantidade de colunas, é porque a linha está preenchida matriz.append(linha) # adiciona a linha na matriz linha = [] # começa uma nova linha else: print('IMPOSSIVEL') Another way is you break the list in various sub-lists (whose sizes are the amount of columns), using the https://stackoverflow.com/q/509211 :matriz = [] if len(lista) == linhas * colunas: for i in range(0, len(lista), colunas): matriz.append(lista[i: i + colunas]) else: print('IMPOSSIVEL') In the case, range goes through the list, but instead of advancing from one to one, it advances from colunas in colunas. Then the slice [i: i + colunas] creates a sub-list whose size is the amount of columns.Another way to do is by using https://docs.python.org/3/tutorial/datastructures.html#list-comprehensions , much more succinct and /q/192343/112052 :if len(lista) == linhas * colunas: matriz = [ lista[i: i + colunas] for i in range(0, len(lista), colunas) ] else: print('IMPOSSIVEL') Remembering these solutions work because you checked the list size before, so we are sure that there will not be any elements left in the matrix. If the idea was to add elements, but take some action in case of leftover or missing, there would have to include this verification of the remaining elements (or missing), and take some action in each case.Finally, another solution (half overkill, but it is as curiosity) is:if len(lista) == linhas * colunas: matriz = list(map(list, zip(*[iter(lista)] * colunas))) else: print('IMPOSSIVEL') This solution is based on one of https://docs.python.org/3/library/itertools.html#itertools-recipes (but there is a more generic solution, already here I simplified because we checked before the size of the list is suitable, and do not need everything that has there).
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How do you connect the dialogue window to tk.Toplevel?
Software Programming • python python 3.x tkinter • • fbio

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The answer was quite simple. Turns out. messagebox There's an argument. parentwhich designates a parent window to which the dialogue should be switched after closure.
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Comparison of two data frames
Software Programming • python • • kalena

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How do you feel like this?import pandas as pd df1 = pd.DataFrame([["Jack","Male","USA",20,"mucsician","rock","movie"], ["Mary","Female","Canada","game",24,"unemployed","None"], ["Marco",25,"Italy","designer","fashion","tennis","None"], ["Isabel","Female","France",24,"shopping","actress","None"]]) df2 = pd.DataFrame([["Jack","Male","USA",20,"mucsician"], ["Mary","Female","Canada",24,"unemployed"], ["Marco","None","Italy",25,"designer"], ["Isabel","Female","France",24,"actress"]]) ret = pd.concat([df2, df1], axis=1).apply(lambda d: d.drop_duplicates().reset_index(drop=True), axis=1) print(ret) 0 1 2 3 4 5 6 0 Jack Male USA 20 mucsician rock movie 1 Mary Female Canada 24 unemployed game None 2 Marco None Italy 25 designer fashion tennis 3 Isabel Female France 24 actress shopping None
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I don't know how to work!
Software Programming • javascript node.js • • simrah

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var task = []; console.log(!task); console.log(task == null); console.log(task.length<=0); console.log(!task.length); console.log(!!task.length);Two Iphas are returning different results. Why?Because it's a bonus. task Not a mass, and she has no properties. length♪ https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/Array/find var a; console.log(a); console.log(a <= 0); console.log(!a);Checks if (task) or if (!task) That's enough.
How do you find lines with Russian symbols?
Software Programming • php regular expression • • irl

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$array = array('Строка1-ABC', 'QWE-строка', 'example-string', 'string-10101'); foreach($array as $string) { if (preg_match('/[а-яА-ЯёЁ]/', $string)) { echo "$string\n"; } } http://sandbox.onlinephpfunctions.com/code/cf4167f95ae9888b5dc46af58fb3b8122cfd2174
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LINE-HEIGHT is not working on my table
Software Programming • html css table div • • amarantha

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To solve this type of problem, the most recommended method is the display: flex;Try to change c of your . Table for the following form:.tabela { border: 1px solid; width: 350px; height: 198px; background-color: red; margin: auto; display: flex; } I think that's the answer you need.See this guide to help you better with flex: https://origamid.com/projetos/flexbox-guia-completo/
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Error: 'str' object is not callable
Software Programming • python • • Raziyah00

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Judging by https://github.com/csparpa/pyowm#get-started w.detailed_status It's not a function, it's a parameter, so you don't have to deal with it:answer = "В городе " + message.text + " сейчас " + w.detailed_status + "\n\n" Corrected code with Russianfrom pyowm import OWM from pyowm.utils import config from pyowm.utils import timestamps from pyowm.utils.config import get_default_config config_dict = get_default_config() config_dict['language']="ru" import telebot owm = OWM('токен', config_dict) mgr = owm.weather_manager() bot = telebot.TeleBot("токен") @bot.message_handler(content_types=['text']) def send_echo(message): observation = mgr.weather_at_place(message.text) w = observation.weather temp = w.temperature('celsius')['temp'] answer = "В городе " + message.text + " сейчас " + w.detailed_status + "\n\n" answer += "Температура сейчас в районе " + str(temp) + "\n\n" if temp >= -20: answer += "На улице очень холодно, одевай шубу!!" elif temp < -10: answer += "На улице прохладно, одевайся теплее!" else: answer += "На улице не очень холодно, одевайся как хочешь" bot.send_message(message.chat.id, answer) bot.polling( none_stop = True)
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How do you know the line code in Perl?
Software Programming • perl code • • Oba22

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Not at all. It's a difficult task to take over, to see how good words get. ♪ ♪I couldn't find anything fast, except http://msdn.microsoft.com/en-us/library/aa740985%28v=vs.85%29.aspx But I think there's a library.Look at that. https://stackoverflow.com/questions/909913/how-can-i-programmatically-determine-the-current-default-codepage-of-windows Maybe it's your case.Upd: a, no, there's something for Perl'a: https://stackoverflow.com/questions/1970660/how-can-i-guess-the-encoding-of-a-string-in-perl
Why is the element removed for only one line?
Software Programming • fortran • • Bogopo

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If you need to make a minimum for each line(s), you should have written that.integer,allocatable,dimension()::min; ... allocate(min(n)); do x=1,n min(x)=a(1,x) do y=1,m if(a(y,x)<min(x))then min(x)=a(y,x) end if end do end do do x=1,n print*,'Min na',x print*,'Stroke',min(x) end do deallocate(min)
How to customize an endpoint response_model?
Software Programming • python fastapi pydantic language • • Alberto

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Not directly, because the language itself does not allow.To customize more complex types and/or add additional field information set in schema, you can use the https://pydantic-docs.helpmanual.io/usage/schema/ the https://pydantic-docs.helpmanual.io/ . In your case more specifically, just declare a alias:from pydantic import BaseModel, Field class TRetRecepcaoLeitura(BaseModel): xmlns: str = Field(..., alias="@xmlns") versao: str = Field(..., alias="@versao") tpAmb: int verAplic: str cStat: int xMotivo: str dhResp: str NSU: str When the documentation is generated, you will have this result:
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Can the Python text be increased
Software Programming • python python 3.x • • esther

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Symbols are just symbols, they don't keep any information on their size so that you can speak on your question.The size of the print can only be increased in the terminal emulsor if it supports this function.
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Test and training sample
Software Programming • python python 3.x numpy car training • • chanisef

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With the next DataFrame:In [71]: df Out[71]: TRG_is_churn 0 True. 1 False. 2 NaN 3 Nonsense 4 NaN 5 None 6 NaN 7 NaN 8 True. In [72]: df['TRG_is_churn'].isna() Out[72]: 0 False 1 False 2 True 3 False 4 True 5 False 6 True 7 True 8 False Name: TRG_is_churn, dtype: bool Comparison with 'True.' He'll return the bulb. In [73]: df['TRG_is_churn'] == 'True.' Out[73]: 0 True 1 False 2 False 3 False 4 False 5 False 6 False 7 False 8 True Name: TRG_is_churn, dtype: bool which can be transformed into a whole:In [74]: y = (df['TRG_is_churn'] == 'True.').astype(np.int8) In [75]: y Out[75]: 0 1 1 0 2 0 3 0 4 0 5 0 6 0 7 0 8 1 Name: TRG_is_churn, dtype: int8 Same as Numpy array:In [76]: y = (df['TRG_is_churn'] == 'True.').astype(np.int8).values In [77]: y Out[77]: array([1, 0, 0, 0, 0, 0, 0, 0, 1], dtype=int8) PS try to avoid cycles with Pandas/Numpy/Scipy/sklearn/etc.
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How to display multiple lines of scraping results in one line
Software Programming • python • • kalena

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I don’t know the structure of the original HTML, so if you guess from the source code, each element seems to be one line.Since the specification is now ambiguous, I thought as follows.The source of the presented part is considered to be treated to a single URL, and the "multiple line display is displayed in one line"So, if you want to do the program, it will be the desired result.Comments are added to the changes.table = bsObj.findAll("table")[0] rows = table.findAll("tr") with open("ebooks.csv", "a", encoding='utf-8') as file: writer = csv.writer(file) csvRow = [] # テーブルの1行毎ではなく1つのURLの処理の全体で1回の初期化を行う for row in rows: for cell in row.findAll(['td']): csvRow.append(cell.get_text().replace(' ', '').replace('\n', '').replace('\r', '')) writer.writerow(csvRow) # 1つのURLの全ての要素を1つの行としてcsvに書き込む The ambiguous thing is:Only one of the first of the table is treatedtable = bsObj.findAll("table")[0])How do I have multiple tables?Will one URL be one line in vv as in the example of a question, or would it be multiple lines in vv based on the condition of something?How to handle multiple URLs? (Is the processing of multiple URLs after repeating the issuing source or at the beginning of this source?)There was an article that seems to be referenced by searching, but it seems that it is a program similar to the question article, and it is data as vv. https://qiita.com/hujuu/items/b0339404b8b0460087f9 So, it is important to think about how the site you want to get information and how the table is composed, and how to combine elements from them into each column of vv.
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I don't work nth-child() and I don't know why
Software Programming • css3 selec languagetors • • jules

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The problem is that the code has an error: it is not closing the label well <strong> because the closing label is </strong...> (with those three points). That's gonna make the structure of your page not the one you're expecting. If you take those off ..., then the tags and the structure of the page will already be correct and the CSS is correctly applied:#sliders #sobreMi #ejemplos article:nth-child(4) { margin-bottom: 100px; } /* #sliders #sobreMi #ejemplos article#ultimo{ margin-bottom: 100px; } */<div id="sliders"> <section id="sobreMi"> <div id="ejemplos"> <article class="articulo"> <div class="diseños"> <figure><img src="" alt=""></figure> <div class="subeInfo"> <h4>Diseño de <strong>logotipos</strong></h4> <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit. Lorem ipsum dolor sit amet, consectetur adipisicing elit</p> </div> </div> </article> <article class="articulo" > <div class="diseños"> <figure><img src="" alt=""></figure> <div class="subeInfo"> <h4>Diseño de <strong>logotipos</strong></h4> <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit.adipisicing elit. Lorem ipsum dolor sit amet, consectetur adipisicing elit</p> </div> </div> </article> <article class="articulo" > <div class="diseños"> <figure><img src="" alt=""></figure> <div class="subeInfo"> <h4>Diseño de <strong>logotipos</strong></h4> <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit.adipisicing elit. Lorem ipsum dolor sit amet, consectetur adipisicing elit</p> </div> </div> </article> <article class="articulo" id="ultimo"> <div class="diseños" > <figure><img src="" alt=""></figure> <div class="subeInfo"> <h4>Diseño de <strong>logotipos</strong></h4> <p>Lorem ipsum dolor sit amet, consectetur adipisicing elit.adipisicing elit. Lorem ipsum dolor sit amet, consectetur adipisicing elit</p> </div> </div> </article> </div> </section> </div>
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How do you know if there's a line?
Software Programming • c language • • emran

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Symbol \0 It's exactly the frame of the line, so I think if the length of the line is not known in advance, it's impossible to know if it has that symbol or not.If the length of the verifiable line is known, try it just in the cycle:// L - длина for (int i = 0: i < L; i++) { if (str[i] == '\0') { /* ура, такой символ есть */ } }

Work with Russian lines. How do you know one of the letters?

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