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Is the number simple?

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Kadir last edited by

I want to write a walk on C++. She first asks for a number (only or not, proga checks) and then turns the result to the console. Explain, please, how to do or at least give a hint (fare dev-c++ 4.9.9.2), please.
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simrah

Write something in

int n;
// ввести n c клавиатуры
for (i = 2; i<sqrt(n); i++) {

if (n % i == 0) {

// вывести, что n  не простое, так как делится на i

return 0;

}

}

//вывести что n простое.

return 0;

Algorithm, of course, can be expedited at least twice, but it's enough for starters.

c++ 27608

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What if you put a length near the exe file?
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What is this operator **?
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Double Pointer Operator http://www.inf.pucrs.br/~pinho/PRGSWB/Ponteiros/ponteiros.html In case it can be an array of pointers, for example char** is a list of words.Obs: In other languages some language compilers that have no pointer,put as exponential operator
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What do you want zero-size?
Software Programming • c++ c language liabilities • • terrea

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And in C and C+, the proclamation of constant zero size is prohibited. Such announcements are incorrect in terms of these languages.In addition, in C, if the value of the size is not positive at the point of the variable length array, the conduct is not determined.A zero-size mass can be distinguished through new[] C+++.Clear zero-size announcements are supported by some compilers as non-standard language expansion to facilitate implementation https://ru.stackoverflow.com/questions/426296/%D0%98%D1%81%D0%BF%D0%BE%D0%BB%D1%8C%D0%B7%D0%BE%D0%B2%D0%B0%D0%BD%D0%B8%D0%B5-%D0%BC%D0%B0%D1%81%D1%81%D0%B8%D0%B2%D0%B0-%D0%BD%D1%83%D0%BB%D0%B5%D0%B2%D0%BE%D0%B3%D0%BE-%D1%80%D0%B0%D0%B7%D0%BC%D0%B5%D1%80%D0%B0 , though it's really good to be done without it. In C, starting with the C99, for this purpose, an announcement of the mass is made without any indication of the size at all.
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Verification of the matrix for transit in C+++
Software Programming • c++ • • Pearlaqua

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Well, I did. https://informatics.mccme.ru/moodle/mod/statements/view.php?chapterid=480#1 so:int main() { int n; cin >> n; vector<vector<int>> m(n,vector<int>(n,0)); for(int i = 0; i < n; ++i) for(int j = 0; j < n; ++j) cin >> m[i][j]; for(int i = 0; i < n; ++i) for(int j = 0; j < n; ++j) { if (i == j) continue; if (!m[i][j]) continue; for(int k = 0; k < n; ++k) { if (k == i || k == j) continue; if (m[j][k] == 0) continue; if (m[i][k] == 0) { cout << "NO\n"; return 0; } } } cout << "YES\n"; } You can reschedule. ♪
Know if a String has only numbers or letters and if it has numbers and letters
Software Programming • php • • irl

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With the function is_numeric():$dato = "2b"; if(is_numeric($dato)){ echo "solo numeros"; } else { echo "numeros y letras o algun otro caracter"; }
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Unavailable parenthood function and inaccessible transformation
Software Programming • c++ • • esther

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You're using private inheritance, so all parenting methods are private in the daughter. You probably need to use public inheritance:class Arc: public Shape { ... }
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Number of numbers on the list of three
Software Programming • lisp • • guilherme

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I noticed one inaccuracy in your wording. You argue that your function is to check the elements of the list to three, but in the example of the challenge, it is clear that in principle any number may be used as a divider. It should therefore be borne in mind that a function other than a list should also take into account the number to be checked. Now let's find out where to put a performance check on. numberp♪ I suggest adding an additional check with help. if and on its basis, further check the current element of the list to be valid or return the nil as a sign that the symbols cannot be repeated. In the end, we'll get something like this:(defun cn (w n) (count-if (lambda (a) (if (numberp a) (zerop (mod a n)) nil)) w)) And now on the challenge:(cn '(3 9 d dd) 3) We'll really get:2
K

“Debug assertion failed” and “Expression invalid pointer”
Software Programming • c++ • • Kadyn

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I guess adding a check to see if the file opened and only then working with it.if (!in.is_open()) { std::cout << "Error open file." << std::endl; return 1; }
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The calculation of prime numbers only returns the first number
Software Programming • c++ buc languageles somegoritmos • • amarantha

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The inner loop gives one or two laps before stopping1 With what you never get to check the numbers you're interested in, the reason is that the expression that calculates the last position doesn't do what you think it does:unsigned long int ult_pos = (sizeof(primos)/sizeof(primos[0]));//ultima posicion del array The size of primos (sizeof(primos)) is not the amount of elements of the formation if not the size of the pointer, which will be 4 or 8 bytes (depending on the architecture of your system), the size of the pointer primos[0] it's equally 4 or 8 bytes so ult_pos It will always return 1 or 2.You have the same problem when trying to show the data1 since you show one or two elements because the division returns 1 or 2:mostrar_primos(primos, (sizeof(primos)/sizeof(primos[0]))); // ^^^^^^^^^^^^^^ ^^^^^^^^^^^^^^^^^ <--- Esta división siempre es 1 o 2. Proposal.You're working on C++, you should use the language tools. Use the guy bool not integer for logical results.Declare the loop indizers in the loop itself.Use containers, not dynamic formations.The operation sqrt It's expensive, don't calculate it on every turn of the inner loop.Let your code breathe, tighten lines and operators only makes your code harder to read.Following these tips your code might look like:int main(){ cout << "Empezando...\n"; auto maximo = 20ul; //numero maximo a buscar // Criba secuencial std::vector<int> primos{2}; // Añadimos el 2 al array para poder saltarnos los pares primos.reserve(maximo); for (auto posible_primo = 3ul; posible_primo < maximo; posible_primo += 2) { /* Comprobamos si es primo buscando si en el array hay algun numero primo que lo divida, pero solo hasta raiz de n. */ const auto limite = sqrt(posible_primo); bool es_divisible = false; for (auto divisor : primos) { if (limite < divisor) break; if (es_divisible = !(posible_primo % divisor)) break; } if (!es_divisible) { primos.push_back(posible_primo); } } for (auto primo : primos) std::cout << primo << ' '; return 0; } You can see the code running in https://tio.run/##hVNbbtswEPzXKTYpishJKwXun6UYKILeooCxomibCEUyfBhtAh@qZ@jB3CUpy498lAA/NNwdzgxXzJivG8YOh09CMRl6Di0b0G@XxQkQ2nnLcTjHdpx5bZdFEZxQG1A4cGeQcXC@b4pCKA8DClXO3gugxXTw0LZw@2Mw/A1Vr6uq@qlum3SKwWsq/yUGDU8wfwyygbpWYeB2whG64BjaInXUNTxb0SE4zgJXTKBMON2@WGRtLWlYgrHU7N7n@8gI3//@wT4CwCXMASWgtfgbDFoEo3tuwaH0aBWVSNp0wF1izkQVfXK742VWNWuynLW2UCYXRjvRSb5K5WTmW/RyCbajpWv8gazPIOeVPN7Dsx6M1R1GxU4Ad1lGjoJCTKCKZrKPLW2Um6AmkjHE3PYaOLmCXuxEj1/AxBOnCdmi8wgWxRvQ46oK7uuJgWnlfH4iKQbhOblyr9aXF@qPScTVaS1J6yrek0qoY43S8WYqOQWWiuhrMSZ8nkBcYg3leG97LJ5dVKQraT5fmg@NVyJuLjXD54nwv4z74uQvMt@cU19rHmfFBLdddchePkR1Yh25r4YoqZsSmcrTdB9/pXGYWriDuzF8y32wCh6bYn84/AM .1Cosa you would've noticed if you had cleaned the code.
Algorithm to the conclusion of simple numbers
Software Programming • algorithm masses mathematics • • briley

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Approach to the forehead is a passage along the range and verification of each element by means http://ru.wikipedia.org/wiki/%D0%A0%D0%B5%D1%88%D0%B5%D1%82%D0%BE_%D0%AD%D1%80%D0%B0%D1%82%D0%BE%D1%81%D1%84%D0%B5%D0%BD%D0%B0 ♪Another approach is the preliminary definition of the maximum element in the mass, the selection of simple numbers up to the maximum, then the gangway and the comparison with the selected simple numbers.
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function replace_copy_if
Software Programming • c++ stl • • jules

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The third parameter shall be the terator at the beginning of the range in which the result will be recorded. This range shall not be less than the reference range. In your code, this condition is not met. I see three options for fixing it. (1) Increase the size str1 to size str assistance http://www.cplusplus.com/reference/string/string/string/ :string str1(str.size(), 0); (2) Used http://www.cplusplus.com/reference/iterator/back_inserter/?kw=back_inserter :std::replace_copy_if( str.begin(), str.end(), std::back_inserter(str1), [](char n) {return ( n > -65 && n < 0); }, ' '); (3) Make it right on the screen:std::replace_copy_if( str.begin(), str.end(), std::ostream_iterator<char>(std::cout), [](char n) {return ( n > -65 && n < 0); }, ' ');
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Find a number range with the nearest min to this number and the nearest max to this number
Software Programming • excel forms excel formula • • shizuka

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Column C for the lower range:=ЕСЛИ(ИНДЕКС(B2:B21;ПОИСКПОЗ(D1;A2:A21))=E1;ИНДЕКС(C2:C21;ПОИСКПОЗ(D1;A2:A21));"нет") Column C for the upper limit of the range:=ЕСЛИ(ИНДЕКС(B2:B21;ПОИСКПОЗ(D1;A2:A21)+1-СЧЁТЕСЛИ(A2:A21;D1))=E1;ИНДЕКС(C2:C21;ПОИСКПОЗ(D1;A2:A21)+1-СЧЁТЕСЛИ(A2:A21;D1));"нет") where D1 Number, E1 - conditionEquity checks remain. ------------------------------- The forms shown above shall be operated with the values of column A, which shall be increased.For non-sortized The formula is more complex:=МАКС(ЕСЛИ(A2:A20<=D1;ЕСЛИ(A3:A21>=D1;ЕСЛИ(B2:B20=E1;ЕСЛИ(B3:B21=E1;ЕСЛИ(C2:C20=C3:C21;СТРОКА(A2:A20))))))) The formula is introduced as a form of mass (Ctrl+Shift+Enter) Determines the right line. If there's no match, there'll be zero.You could have written shorter, instead of the EBLI cascade, logically and:(A2:A20<=D1)*(A3:A21>=D1)*(B2:B20=E1)*(B3:B21=E1)*(C2:C20=C3) but in this case the formula will count much more, and ECLE They can detect extra calculations. The result is used to find the value in column =ЕСЛИ(D2;ИНДЕКС(C2:C20;D2-1);"нет") where D2 - Line formula.
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Remove the highest number and the lowest number of a JavaScript array
Software Programming • javascript array • • emerson

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Javascript has the functions https://developer.mozilla.org/es/docs/Web/JavaScript/Referencia/Objetos_globales/Math/max and https://developer.mozilla.org/es/docs/Web/JavaScript/Referencia/Objetos_globales/Math/min to easily find the greater or lesser value of an array.Then you can look for the index of that value to delete it from the array with https://developer.mozilla.org/es/docs/Web/JavaScript/Referencia/Objetos_globales/Array/splice Here, for more versatility, I used a function.let numeros = [1, 5, 4, 9, 0, -3, 9, 4, -3]; removeMinMax(numeros); console.log(numeros); function removeMinMax() { var min = Math.min(...numeros); var max = Math.max(...numeros); /Remover cada valor por su índice/ numeros.splice(numeros.indexOf(min), 1); numeros.splice(numeros.indexOf(max), 1); }
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C# Number of telephone numbers
Software Programming • c sharp regex • • baileigh

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Try this.public class ExpRegTelefono { public static bool Validar(string telefono) { Regex exreg = new Regex("^\\d{7,10}$"); return exreg.IsMatch(telefono); } } With \d searches number {7,10} length and start ^ and finish $ Exactly. I don't know if I explained myself.
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How do you put the following higher numbers in the same numbers?
Software Programming • javascript algorithm • • Rossere

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This task is equivalent to the location of the next rectification in the lexicogram. Some language libraries have tools like std:: next_permutation C+++.A good description of the algorithm of receipt of the next conversion can be read, for example https://www.nayuki.io/page/next-lexicographical-permutation-algorithm The point is:Найти ближнюю к концу пару соседей, у которых нарушен порядок array[i − 1] < array[i] Найти самый большой индекс j такой, что j ≥ i и array[j] > array[i − 1] Обменять array[j] и array[i − 1] Перевернуть суффикс массива, начиная с индекса i JS code:function nextPermutation(array) { // Find non-increasing suffix var i = array.length - 1; while (i > 0 && array[i - 1] >= array[i]) i--; if (i <= 0) return false; // Find successor to pivot var j = array.length - 1; while (array[j] <= array[i - 1]) j--; var temp = array[i - 1]; array[i - 1] = array[j]; array[j] = temp; // Reverse suffix j = array.length - 1; while (i < j) { temp = array[i]; array[i] = array[j]; array[j] = temp; i++; j--; } return true; } // Example: arr = [0, 1, 0]; nextPermutation(arr); // (returns true) console.log(arr);

Is the number simple?

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