# How do you mirror the lines on the horizontal axis of symmetry in the body?

• There's nothing on the Internet, I want to know how to do it. Here's the program with the body itself.

``````class з4 {
public static void main (String[] args){
int[][] a=new int;
for (int i=0;i < a.length;i++){
for (int j=0;j < a[i].length;j++){
a[i][j]=(int)(Math.random()*10);
}
}
for (int i=0;i < a.length;i++,System.out.println()){
for (int j=0;j < a[i].length;j++){
System.out.print(a[i][j]+" ");
}
}
}
}
``````

• Best:

``````for (int i = 0; i < a.length / 2; ++i)
{
int tmp[] = a[i];
a[i] = a[a.length - i - 1];
a[a.length - i - 1] = tmp;
}
``````

Well, if you want to be harder or you have to save your memory, you can say,

``````for (int i = 0; i < a.length; ++i)
for (int j = 0; j < a[i].length; ++j)
{
int tmp = a[i][j];
a[i][j] = a[a.length - i - 1][j];
a[a.length - i - 1][j] = tmp;
}
``````

P.S. Actually, I'm not sure the second option would be to save memory. The first version of the compiler could simply re-examine the references.

Update

TC, I'm good tonight. I'll forgive the community... Hold the code:

``````class Test4
{
public static void main (String[] args)
{
// Инициализация матрицы.
int[][] a = new int;
for (int i = 0; i < a.length; i++)
for (int j=0; j < a[i].length; j++)
a[i][j] = (int)(Math.random()*10);
// Вывод исходной матрицы
for (int i=0;i &lt; a.length;i++,System.out.println())
for (int j=0;j &lt; a[i].length;j++)
System.out.print(a[i][j]+" ");

// Трансформация матрицы.
for (int i = 0; i &lt; a.length / 2; ++i) {
int tmp[] = a[i];
a[i] = a[a.length - i - 1];
a[a.length - i - 1] = tmp;
}

// Вывод изменённой матрицы.
System.out.println();
for (int i=0;i &lt; a.length;i++,System.out.println())
for (int j=0;j &lt; a[i].length;j++)
System.out.print(a[i][j]+" ");
}

}
``````

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