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How do you get the first entry into xpath?

C
Cleofas last edited by
How do you get the first entry into xpath without the daughters? The request for this type of "/div" will make all div out of the document.
For example:
```
<body>
   <div>1</div>
   <div>
     <span>2</span>
     <div>2.1</div>
   </div>
   <div>
     <div>3.1</div>
   </div>
   <span>
     <div>4</div>
   </span>
</body>
```
The result of the operation would be to see not all div, but only four records:
```
1
<span>2</span>
<div>2.1</div>
<div>3.1</div>
4
```
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1 Reply Last reply
J
jonetta last edited by
That's the way you're gonna work.
```
(//div)[1]
```
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1 Reply Last reply

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I did it this way: substring(substring-after(//article[contains(@id, 'the-post')]/script/text(), 'dateCreated'),4, 25 ) and the result I can visualize it with tool called: Xpath Helper
PyQt5. How do you build a layout to get the view straight at first, not in the middle of the shape?
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Try this:<?xml version="1.0" encoding="UTF-8"?> <ui version="4.0"> <class>MainWindow</class> <widget class="QMainWindow" name="MainWindow"> <property name="geometry"> <rect> <x>0</x> <y>0</y> <width>718</width> <height>422</height> </rect> </property> <property name="windowTitle"> <string>MainWindow</string> </property> <widget class="QWidget" name="centralwidget"> <layout class="QGridLayout" name="gridLayout_2"> <item row="0" column="0"> <layout class="QHBoxLayout" name="horizontalLayout"> <item> <widget class="QPushButton" name="pushButton"> <property name="text"> <string>PushButton</string> </property> </widget> </item> <item> <widget class="QPushButton" name="pushButton_2"> <property name="text"> <string>PushButton</string> </property> </widget> </item> <item> <widget class="QPushButton" name="pushButton_3"> <property name="text"> <string>PushButton</string> </property> </widget> </item> </layout> </item> <item row="1" column="0"> <layout class="QGridLayout" name="gridLayout"> <item row="0" column="1"> <widget class="QLineEdit" name="lineEdit"/> </item> <item row="0" column="3"> <widget class="QPushButton" name="pushButton_4"> <property name="text"> <string>PushButton</string> </property> </widget> </item> <item row="0" column="2"> <widget class="QSpinBox" name="spinBox"/> </item> <item row="0" column="4"> <widget class="QPushButton" name="pushButton_5"> <property name="text"> <string>...</string> </property> </widget> </item> <item row="0" column="0"> <widget class="QCheckBox" name="checkBox"> <property name="text"> <string>CheckBox</string> </property> </widget> </item> <item row="1" column="1"> <spacer name="verticalSpacer"> <property name="orientation"> <enum>Qt::Vertical</enum> </property> <property name="sizeHint" stdset="0"> <size> <width>20</width> <height>40</height> </size> </property> </spacer> </item> </layout> </item> </layout> </widget> <widget class="QMenuBar" name="menubar"> <property name="geometry"> <rect> <x>0</x> <y>0</y> <width>718</width> <height>21</height> </rect> </property> </widget> <widget class="QStatusBar" name="statusbar"/> </widget> <resources/> <connections/> </ui> UpdateThat's right. But now another problem. I'm not doing this through designer, and I have a mistake addWidget(self, QWidget): argument 1 has unexpected type 'QSpacerItem'I don't quite understand your idea, but try the example below:import sys from PyQt5.QtCore import QObject, QRect, Qt from PyQt5.QtWidgets import (QApplication, QWidget, QMainWindow, QAction, qApp, QPushButton, QLineEdit, QGridLayout, QDockWidget, QListWidget, QSpacerItem, QSizePolicy) from PyQt5.QtGui import QIcon class GUI(QWidget): def init(self): super().init() self.i = 0 self.initUI() def initUI(self): btnAdd = QPushButton('Add') btnAdd.clicked.connect(self.addProblem) #grid layout self.layout = QGridLayout(self) self.layout.addWidget(btnAdd, self.i, 0, alignment=Qt.AlignLeft ) self.layout.setRowStretch(111, 1) self.i += 1 def addProblem(self): lineEdit = QLineEdit() btn = QPushButton(f'More {self.i}') self.layout.addWidget(lineEdit, self.i, 0) btn.clicked.connect(lambda ch, l=lineEdit: print(l.text())) self.layout.addWidget(btn, self.i, 1) self.i += 1 if name == 'main': app = QApplication(sys.argv) gui = GUI() gui.setWindowTitle('Planner') gui.resize(300, 400) gui.show() sys.exit(app.exec_())
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C # How to handle null values in a lamb expression?
Software Programming • c sharp linq null lambda • • Kadyn

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Hi if you can try this example return offices .Where(o => o.MaxCapacity >= suggestionRequest.CapacityNeeded && (resources == null ? true : resources.All(r => o.AvailableResources.Contains(r))) && (neigborhoodLocation == null ? true : neigborhoodLocation.Any(l => o.LocationName == l.Name))) .OrderBy(o => o.AvailableResources.Except(resources).Count()) .Select(o => new OfficeDto { Name = o.Name, LocationName = o.LocationName, MaxCapacity = o.MaxCapacity, AvailableResources = o.AvailableResources }); in the first condition validated the capacity, then asked if resources are nulo varifico contra bar because that condition is ignored, and the same with the neighborhoods, Greetings
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How can I update on a many EntityFramework 6 relationship with Repository and UnityOfWork?
Software Programming • c sharp asp.net entity framework • • tahishae

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By establishing a relationship of many to many with Entity Framework have two collection type navigation properties (one in each entity), which allow updating the values of that relationship.In this case the code of entities that would be generated for this model would be something like this:public class Usuario { /// <summary> /// Identificador del usuario /// </summary> public int IdUsuario { get; set; } /// <summary> /// Propiedad de navegación relación muchos a muchos Usuarios-Compromisos /// </summary> public virtual Collection<Compromiso> Compromisoes { get; set; } } public class Compromiso { /// <summary> /// Identificador del compromiso /// </summary> public int IdCompromido { get; set; } /// <summary> /// Propiedad de navegación relación muchos a muchos Usuarios-Compromisos /// </summary> public virtual Collection<Usuario> Usuarioes { get; set; } } and the DbContext that would be similar to this:public class MyDbContext: DbContext { public DbSet<Usuario> Usuarioes { get; set; } public DbSet<Compromiso> Compromisoes { get; set; } } Now let us imagine that there is a Commitment with Id = 3 and a User with Id = 1, the relationship between them would be established in this way:int idUsuario = 1; int idCompromiso = 3; using (var context = new MyDbContext()) { var usuario = context.Usuarioes.Find(idUsuario); var compromiso = context.Compromisoes.Find(idCompromiso); // Establecer la relación entre el usuario y el compromiso compromiso.Usuarioes.Add(usuario); context.SaveChanges(); } The problem of working like that is that on the property Usuarioes will load data from all users associated with the commitment even though this load can be avoided https://msdn.microsoft.com/es-es/library/system.data.objects.objectstatemanager(v=vs.110).aspx and establishing the relationship at low level:int idUsuario = 1; int idCompromiso = 3; using (var context = new MyDbContext()) { var usuario = context.Usuarioes.Find(idUsuario); var compromiso = context.Compromisoes.Find(idCompromiso); // Establecer la relación entre el usuario y el compromiso var stateManager = ((IObjectContextAdapter)context).ObjectContext.ObjectStateManager; stateManager.ChangeRelationshipState<Compromiso>( compromiso, usuario, c => c.Usuarioes, EntityState.Added); context.SaveChanges(); } As to how to do this using patterns Repository and UnitOfWorkAs I pointed https://es.stackoverflow.com/users/2600/leandro-tuttini in the comments, it depends much on how these patterns are implemented because there are several ways to do so.One option would be following the implementation of the generic repository http://www.asp.net/mvc/overview/older-versions/getting-started-with-ef-5-using-mvc-4/implementing-the-repository-and-unit-of-work-patterns-in-an-asp-net-mvc-application ASP.NET document article and was to add two methods, one to add elements to the relationship and the other to eliminate them.The implementation of these methods would be:public class GenericRepository<TEntity> where TEntity : class { ... public virtual void AddRelatedEntity( TEntity sourceEntity, object targetEntity, Expression<Func<TEntity, object>> navigationPropertySelector) { var stateManager = ((IObjectContextAdapter)context).ObjectContext.ObjectStateManager; stateManager.ChangeRelationshipState<TEntity>( sourceEntity, targetEntity, navigationPropertySelector, EntityState.Added); } public virtual void RemoveRelatedEntity( TEntity sourceEntity, object targetEntity, Expression<Func<TEntity, object>> navigationPropertySelector) { var stateManager = ((IObjectContextAdapter)context).ObjectContext.ObjectStateManager; stateManager.ChangeRelationshipState<TEntity>( sourceEntity, targetEntity, navigationPropertySelector, EntityState.Deleted); } } And the code to establish the relationship between the two entities using these patterns would be as follows:int idUsuario = 1; int idCompromiso = 3; using (var unitOfWork = new MyUnitOfWork()) { var usuario = unitOfWork.UsuarioRepository.GetByID(idUsuario); var compromiso = unitOfWork.CompromisoRepository.GetByID(idCompromiso); // Establecer la relación entre el usuario y el compromiso unitOfWork.UsuarioRepository.AddRelatedEntity( usuario, compromiso, u => u.Compromisoes); unitOfWork.Save(); } Note: The code of all examples is simplified to the maximum understand better, so it is not suitable to use it in production
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Software Programming • c++ dev c language++ • • jeanid

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Your problem was in the loop for:for(int i = 0;i <= veces;i++){ cout<<"Digite una frase: ["<<i<<"]:"<<endl; getline(cin,frase); archivo<<frase<<endl; } It should be:for (int i = 0; i <= veces; i++) { getline(cin, frase); cout << "Digite una frase: [" << i << "]:" << endl; archivo << frase << endl; } Plus tea I've removed the #include<stdlib.h> since it belongs to C and you don't need it.Full code :#include <iostream> #include <string> #include <fstream> using namespace std; void escribir() { int veces = 0; ofstream archivo; string frase; archivo.open("Frases.txt", ios::out); if (archivo.fail()) { cout << "No se puedo abrir el archivo..." << endl; exit(1); } cout << "Digite cuentas veces quiere escribir en el archivo: " << endl; cin >> veces; for (int i = 0; i <= veces; i++) { getline(cin, frase); cout << "Digite una frase: [" << i << "]:" << endl; archivo << frase << endl; } archivo.close(); } int main() { escribir(); system("PAUSE"); }
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Software Programming • php html • • tahishae

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Hello, Matheus!Your code is correct and that is possible. What's wrong is the image code you used. If you open this link in the browser and right-click on the image will appear: Copy Image URL. That's the URL you need to use. What you used is the entire mediafire page, including share button, login... Your correct code would look like this:<!DOCTYPE html> <html> <?php $imagem = 'http://www.mediafire.com/convkey/c9df/wg0156qxjkzulv3zg.jpg'; ?> <img src="<?php echo $imagem;?>" alt=""> </html>
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Software Programming • node.js mongodb express • • carriann

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Like many, I recommend reading the documentation to the right drive. Mongoose I don't know, working with a fighter mongodb, that's the solution:Connect to mongodb:const MongoClient = require('mongodb').MongoClient; // Connection URL const url = 'mongodb://localhost:27017'; // Database Name const dbName = 'myproject'; let client = await MongoClient.connect(connectionString, { useNewUrlParser: true }) const db = client.db(dbName) We get the collection and find the documents:const collection = db.collection('first'); // Find some documents let allDocs = await collection.find({}).toArray()
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How do you get the second fream to display only after the button on the first frime?
Software Programming • java gambling • • shizuka

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There are many ways. I'll make it simple through the streams. Put the flows like that. If the game isn't online, you'll do the same without a session.Flow number one is in charge, controls the entire application. At the start, the flow games are running. When you get the data for a session with flow number two, you'll have a session, you'll start the flow number three, and you'll send out a of flow three.Fry shall be stored when the correct entry data are obtained to provide the data for the session to flow No. 1 and to complete flow No.2 (If a game can't play online, you just send the meaning of authorization true)Flow #3 creates the object of the Class Display (when a session is received) and holds the session until the flow of #3 is closed.
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Software Programming • php html css • • emmalee

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Relative path is a problem in the described scenario. The 2 URLs mentioned are in fact on different paths, that "relative" would be which?http://local.dev/example http://local.dev/example/index In this case the relative to the root is less problematic (called absolute, but I believe it is not the best terminology, since it does not include the domain).An alternative, if you need to "relativize" yourself, is to force the script to always have a bar at the end (or never, making the respective adjustment on the CSS path).Something like this:<?php $caminho = $_SERVER['PHP_SELF']; if( substr( $caminho, -1 ) !== '/' && substr( $caminho, -4 ) !== '.php' ) { header( 'Location: '.$caminho.'/' ); die(); } If you need to use query string can add in header also, concatenating after the bar with a ?.Depending on the server and configuration, it may be the case of changing the PHP_SELF by PATH_INFO.
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Software Programming • javascript • • Alberto

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console.log(document.querySelector('.slide_block').children[0].id);<div class="slide_block"> <div class="slide" id="slide_1"></div> <div class="slide" id="slide_2"></div> <div class="slide" id="slide_3"></div> <div class="slide" id="slide_4"></div> <div class="slide" id="slide_5"></div> <div class="slide" id="slide_6"></div> </div>document.getElementsByTagName('button')[0].onclick = function(e) { document.querySelector('.slide_block').children[0].remove(); }<button>Remove first</button> <div class="slide_block"> <div class="slide" id="slide_1">1</div> <div class="slide" id="slide_2">2</div> <div class="slide" id="slide_3">3</div> <div class="slide" id="slide_4">4</div> <div class="slide" id="slide_5">5</div> <div class="slide" id="slide_6">6</div> </div>
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The size of the file in the lights is stored req.file.size:upload(req, res, async err => { console.log(req.file.size) // file size });
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Just press the ALT when you're distributed, start the right lines, and start putting in whatever your soul wants.This is an example of what it looks like (the truth in Notepad+++, I think VS Code is not divided):
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Try this:HTML<a href="#"><img id="adaptive" src="img/picture.jpg" /></a> CSS#adaptive{ content:url("img/small_picture.jpg"); } https://developer.mozilla.org/en-US/docs/CSS/content
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Software Programming • c sharp wpf xaml • • rosemadder

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I simplified the XAML counterol UserControl1 code, changed the recounting mechanism when it moved, and I have a little difference in the control room and windows when I move. UserContol.xaml.cs:/// <summary> /// Логика взаимодействия для UserControl1.xaml /// </summary> public partial class UserControl1 : Grid { Point _startPoint; Vector _startTransform; public UserControl1() { InitializeComponent(); } private void Grid_MouseLeftButtonDown(object sender, MouseButtonEventArgs e) { // Сохраняем начальные значения до того как захватываем мышь _startPoint = e.GetPosition(Parent as Window); _startTransform = new Vector(controlTranslateTransform.X, controlTranslateTransform.Y); CaptureMouse(); } private void Grid_MouseLeftButtonUp(object sender, MouseButtonEventArgs e) { ReleaseMouseCapture(); } private void Grid_MouseMove(object sender, MouseEventArgs e) { if (IsMouseCaptured) { Vector offset = Point.Subtract (e.GetPosition(Parent as Window), _startPoint); controlTranslateTransform.X = (_startTransform + offset).X; controlTranslateTransform.Y = (_startTransform + offset).Y; } } } UserControl.xaml:<Grid x:Class="WpfApp3.UserControl1" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" MouseLeftButtonDown="Grid_MouseLeftButtonDown" MouseLeftButtonUp="Grid_MouseLeftButtonUp" MouseMove="Grid_MouseMove"> <Grid.RenderTransform> <TranslateTransform x:Name="controlTranslateTransform"/> </Grid.RenderTransform> <Ellipse Fill="Blue"/> <Label Content="U" FontSize="40" FontWeight="Bold" HorizontalAlignment="Center" VerticalAlignment="Center" Foreground="LightPink"/> </Grid> The redesigned project is here (VS 2019): https://cloud.mail.ru/public/6mBA/dV2GMwY3o
The gradient style does not apply to the text
Software Programming • html cs • • Bogopo

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There's nothing wrong with html and sss! This is the most cross-sbrauser type of text gradient. html, body { height: 100%; background: #fff; font-family: Georgia, sans-serif; font-size: 42px; font-weight: bold } svg { position: absolute; width: 100%; height: 100%; }<svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 200 200" preserveAspectRatio="xMidYMid slice" id="svg"> <linearGradient id="grad"> <stop class="stop stop--1" stop-color="crimson" offset="0"></stop> <stop class="stop stop--2" stop-color="gold" offset="49%"></stop> </linearGradient> <mask id="mask"> <rect width="100%" height="100%" fill="white"> </rect> </mask> <g mask="url(#mask)"> <text x="50%" y="50%" dy=".25em" text-anchor="middle" fill="url(#grad)">Text</text> </g> </svg>

How do you get the first entry into xpath?

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