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JQuery refuses to understand json format.

K
kalyn last edited by
Example: There's a file.js and .php
The file says approximately:
```
$.ajax({
   url:"index.php",
   datatype:"json",
   success:function(result){
      console.info(result);
   }
});
```
In file .php,
```
$array = array("object1" => "Boat","object2" => "Car","object3" => "Ship");
echo json_encode($array);
```
P.S If in file .js, in part of the success block, write this: $objectJson = JSON.parse(result)Then json's line would turn into json object, so I had the point. datatype: "json"? ?
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D
Duquan last edited by
```
dataType:"json" 
```
T is a big letter.
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Get the key in JSON C# (Newtonsoft.Json)
Software Programming • c sharp json • • nishika

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Connect the nuget library to Json. NET.Open the space of the name:using Newtonsoft.Json.Linq; Writing:var text = File.ReadAllText("test.json"); var json = JObject.Parse(text); var shortNames = json["result"] .Select(token => token["u_short_name"].Value<string>()) .ToArray(); comboBox.DataSource = shortNames; This method does not require class models. Sometimes it's convenient, thanks to simplicity. In other cases, it would be better to create classes.
S

obtain variable with js and send them by ajax
Software Programming • javascript php html mysql ajax • • simrah

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T

Try to create a function that gets all those values in an array and invokes it in the ajax call:function getValues(){ var values = []; var inputs = $('input.delete'); $.each(inputs,function(){ values.push($(this).val()); }); return values; } and on your ajax call:data: { id:getValues() }, Then you collect the values and work with them any way you want.I give you the example of the function here to see it "in situ":function getValues(){ var values = []; var inputs = $('input.delete'); $.each(inputs,function(){ values.push($(this).val()); }); return values; } var a = getValues(); $('#resultado').text(a);<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <input class="delete" value="123"> <input class="delete" value="124"> <input class="delete" value="hola"> <input class="delete" value=""> <input class="delete" value="-2"> <br> <br> <div>Tus valores: <span id="resultado"></span></div>UPDATEIf you want to just delete the id from the button you press:$('a.delete').click(function(){ var valor = $(this).siblings('input').val(); $.ajax({ type: "GET", url: "inc/deleteResource.php", data: { id:valor}, success: function(data) { $('#resultado').html(data); } }); }); With https://api.jquery.com/siblings/ You point only to the brothers and with the selector "input" only to those who are inputs. This is how you wrote your code. However, I would change the kind of link and put another one that was not the same as your inputs (delete). If you "order" a little better the code, you can use only one ajax function that manages everything (both of one or all the elements).Note that this is just to answer your doubt. But now you have to take into account one thing and it is that in the previous call ajax (send all ids) the values are an array that contains all id's. With this last code, the value is not an array of an element but is directly a value (numeric, string, etc...). It is also another reason for you to consider the previous paragraph and "reorder" all your code a little bit. One idea is to do the following:A function that suits you all ids or just one id: for example something like:function getValues(id):function getValues(id){ if(id){ //que te devuelva solo el id que le pasas } else{ //que te devuelva todos. } } in the html and events click:to the links you put a type class "eliminar-id" that invokes the function getValues(id) passing it as a parameter the id to eliminate.with the button or buttons you want to collect all the id's, le(s) you put another type "eliminate" or "eliminate-all" and invoke the same function but without passing any parameter. This will give you every id.In your "getValues" function, be one or all id's, that you always return them as an array. If it is only a id that you want to return, then return an array of an element (the id you want, in this case).In your "deleteResource.php" file you will always expect an array of n values (one or all). And from there you work as you like.A greeting!
R

How to slide the text within an input in the hover?
Software Programming • javascript html jquery css angularjs • • Rossere

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If I understood correctly could use a text-align:right and one transition:0.3s ease so that the text slides. Put this setting on:Hover
T

How to hide all the botstrap tabs?
Software Programming • jquery bootstrap • • terrea

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In jQuery UI, there's a way to hide all tab-content and how it is. Do you want to do Bootstrap Tabs?$('.nav-tabs > li').mouseout( function(){ $(this).removeClass('active'); $(".tab-content").find($(this).find("a").attr("href")).removeClass('active'); }); https://jsfiddle.net/8fnnsv0c/ UPD commentsThe user leads the mouse to the reference, the content opens, and it can. driving, clicking on the content, but as soon as the click outside the tabs, The content is automatically ruptured.$('.nav-tabs > li').hover( function(){ $(this).find("a").tab('show'); }, function(){ if(!$($(this).find("a").attr("href")).is(":hover")){ $(this).removeClass('active'); $(".tab-content").find($(this).find("a").attr("href")).removeClass('active'); } }); $('.tab-content').mouseout( function(){ $('.tab-content > .tab-pane').removeClass("active"); $('.nav-tabs > li').removeClass("active"); }); https://jsfiddle.net/8fnnsv0c/3/
Generate a minified file for each file inside a folder
Software Programming • javascript gulp gulpjs • • Analeea

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Yeah. Simply your attribute src delete this particular file. In a simple way, this could be solved with the following task:gulp.task('js', function(){ return gulp.src([ 'src/AppBundle/Resources/public/Frontend/js/*.js', '!src/AppBundle/Resources/public/Frontend/js/main.js' ]) .pipe(uglify()) .pipe(rename({ suffix: '.min' })) .pipe(gulp.dest('web/js')) }); Understand denial (!) in the attribute src, where I say that after I have selected all the files .js, one must be removed. See also that I removed your method concat(), to avoid concatering all files in one. Finally, note that this task only scans files directly inside the folder /js. Files inside folders inside this folder should be searched with the selector **
The event loop does not work as it should
Software Programming • javascript • • Demir

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Here are two details to be found:Although the IU is blocked, events continue to occur: If you click on a button but the main thread is occupied, the click event is registered and will be treated when you can, even within several seconds.Calls to console.log are managed asynchronously by the browser, to avoid blocking an application while saving a "log".I have slightly modified your example to see that even if you block the IU in a remarkable way, the click on the Names button is still registered and will be done when it can be done:const select = document.getElementById(`select`) const btnNombres = document.getElementById(`btnNombres`) const btnBucle = document.getElementById(`btnBucle`) btnNombres.addEventListener(`click`, () => { console.log("llamada AJAX"); xhr = new XMLHttpRequest() xhr.open(`GET`, `https://jsonplaceholder.typicode.com/users`) xhr.addEventListener(`load`, (e) => { const arrayObejt = JSON.parse(e.target.response) const fragment = document.createDocumentFragment() for (const objet of arrayObejt) { const option = document.createElement(`OPTION`) option.setAttribute(`value`, objet.id) option.textContent = `Nombre: ${objet.name} y su Email ${objet.email}` fragment.appendChild(option) } select.appendChild(fragment) }) xhr.send() }) btnBucle.addEventListener(click, () => { console.log("Bucle bloqueante"); setTimeout(() => { const limit = 10000000; const div = document.getElementById("div"); for (let i = 0; i < limit; i++) { div.style.left=${i/50000}px; } }); });#div { width: 50px; height: 50px; border: 1px solid blue; margin: 5px; position: absolute; }<button id="btnBucle">bucle</button> <button id="btnNombres">nombres</button> <select id="select"></select> <div id="div"></div>Note: The Timeout set is for the log to be displayed BEFORE the loop starts.
It doesn't work json success. Jquery
Software Programming • php jquery json • • Laycee

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You can check if there's any other way out after your function. Just redo the last line of the request.exit(json_encode($json)); If you have a mistake after that, something's coming out before the exit, you're gonna have to go through the code. It's the most obvious option.
How to show a jSon with jQuery and PHP?
Software Programming • php jquery json • • Analeea

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Try this: $.ajax({ type: 'post', data: $( this ).serialize(), dataType: 'json', url:'simulacao/dados.php', success: function(data){ alert(data); // passa a resposta de string para JSON var resposta = JSON.parse(data); var objeto = data; $('#resposta').text(resposta.total_direta); } }); I simply gave a JSON.parse() in the answer. Sometimes the answer is interpreted as string, so I do it and works for me.
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get JSON created by API with JQUERY
Software Programming • jquery api • • nishika

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Right there, in your success function, where you read the console, you can handle your answer to an arrangement.var lstRespuesta = []; $.ajax({ headers: {'Authorization':'Mi Clave de Usuario o API KEY', 'Content-Type':'application/json'}, url: 'https://api.envioclickpro.com/api/v1/quotation', type: 'POST', dataType: 'json', data: packInfo, success: function(respuesta){ console.log(respuesta); lstRespuesta.push(respuesta); } }) Then you can use it to upload your data to the div as you need it.let data = lstRespuesta[0].data; $("div#idTuDiv").html(data.idCarriersNoWsResult);
J

Doubt with JSON on JQuery Autocomplete
Software Programming • jquery json • • Jolied

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The function map translate an object (or list) into a list, where you must pass a function that makes the transformation. It itera about the properties and invokes its function to popular the new list.The problem in your case is that you are passing an object with only one property of your own rather than passing the customer list.Just call the function $.map the data.cliente rather than data only.That's it. http://jsfiddle.net/7572mmh7/ exemplify the solution.
A

Filter with JQuery, Json and Input
Software Programming • javascript html jquery json • • Anderson

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Well, I'll give you a generic example here with a JSON more or less the way you want.In jQuery, there is a function called grep (equal to linux) that serves to filter arrays, since a JSON is an object notation, you should have a structure more or less like this:var produtos = [ {nome:"produto", tamanho:34, preco:24.99}, {nome:"produt2", tamanho:37, preco:25.99}, {nome:"produto3", tamanho:38, preco:29.99}, {nome:"produto4", tamanho:32, preco:21.99} ]; Which would translate to an array of objects.So you could do something like this:$(produtos).grep(function(i,produto) { return produto.tamanho == $(seuoption).val(); }); Or using filter as well as https://stackoverflow.com/questions/23720988/how-to-filter-json-data-in-javascript-or-jquery .Take a look at the documentation http://api.jquery.com/jquery.grep/ and http://api.jquery.com/filter/ of jQuery to have a better idea.
B

Place the mass in JSON format
Software Programming • json masses perl • • baileigh

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Well, first of all, it would be nice to show the text of a mistake, telepaths, no.my $encoded = $json->encode(\ /users/1403/hash3r );
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Skip ResultSet to a JSON in Java JSP
Software Programming • java sql server json • • gionna

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When you work with your database layer, instead of returning a ResultSet, the best thing is to return an object or representation of the data you want to work, then you can transform that data as it turns out.In the case of your method GraficaDAO#reporteMensual The best thing you can do is get the data returned by the stored procedure on a list and then convert this list into a JSON object (or anything else you need).public class GraficaDAO { private static final String sproc = "{call sp_EquiposMes (?)}"; //devuelve una lista, no el ResultSet //una vez que cierres la conexión a base de datos, el ResultSet //estará cerrado y no podrá ser usado public List<ResultadosGrafico> reporteMensual(String mes) { List<ResultadosGrafico> lista = new ArrayList<>(); //todos los elementos de conexion a base de datos deben estar //en el menor alcance posible para el metodo Conexion con = Conexion.conectar(); //siempre dentro de un bloque try con recursos //automáticamente llamará al método close de los //recursos abiertos dentro de los "parámetros" del try //disponible desde Java 7 try (Connection conn = con.getCnn(); //para invocar procedimientos almacenados en Java //conviene usar CallableStatement CallableStatement cs = conn.prepareCall(sproc);) { //mes ya es un String, no tienes que llamar a su método toString cs.setString(1, mes); try (ResultSet res = cs.executeQuery()) { while (res.next()) { //parsea el resultado de cada fila del ResultSet ResultadosGrafico rg = new ResultadosGrafico(); //en lugar de usar el número de columna, mejor usa el nombre de la columna que se ha devuelto rg.setAtributo1(res.getString("columna1")); rg.setAtributo2(res.getString("columna2")); //etc... //importante: agregar este elemento en tu lista lista.add(rg); } } } catch (SQLException ex) { //por lo menos debes loguear esta excepción ex.printStackTrace(); } } return lista; } Then you can use a bookstore like https://github.com/stleary/JSON-java to convert the list List<ResultadosGrafico> to a JSON chain. But this is too much work. The best thing is to use bookstores like https://github.com/FasterXML/jackson or https://github.com/google/gson that make conversion simpler and is easier to maintain.Following the previous design and with a library like jackson, you can do as follows:public class ClienteReporteGrafico { public static void main(String[] args) throws Exception { //obtener la lista desde el dao GraficaDAO graficaDAO = new GraficaDAO(); List<ResultadosGrafico> lista = graficaDAO.reporte(); //jackson convierte tu objeto en json ObjectMapper mapper = new ObjectMapper(); String json = mapper.writeValueAsString(lista); //pintamos el json en la consola para ver el resultado System.out.println(json); } }
how to return the request to the json format
Software Programming • http golang • • Alberto

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That's it.decoder := json.NewDecoder(r.Body) err := decoder.Decode(&n0)Must be:encoder := json.NewEncoder(w) err := encoder.Encode(&n0)You codify the answer, not decode the request.
ABBBYY Lingvo API, how to select JSON response to jQuery
Software Programming • javascript jquery api json encode • • Analeea

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If it's been a long time to look back to the server, it's possible to find a similarity between the response and the vocabulary. https://www.lingvolive.com/ru-ru/translate/en-ru/word ♪ It appears that if each object is turned into an appropriate strategy, it is possible to obtain a similar structure on its website. But as almost any of the objects can contain a mass of similar objects, and within a range of objects, etc., we're gonna need a recurring function and array.forEach()Thus, the solution that is prepared may be:var response = JSON.parse(data); var html = ''; function recursive_reading(item) { var attr = ''; var style = ''; var tag = ''; //Готовим подсказку, если есть if (item.FullText) attr += ' title="'+item.FullText+'"'; //Присоседиваем доп данные, если есть if (item.FileName) attr += ' data-file="'+item.FileName+'"'; //Обозначаем тип узла и открываем тег switch (item.Node) { case 'Text': //Готовим дополнительное оформление, если есть if (item.IsAccent) style += 'font-weight:bold;'; if (item.IsItalics) style += 'font-style:italic;'; if (style) style = ' style="'+style+'"'; tag = 'span'; break; case 'CardRef': tag = 'a' attr += ' href="?w='+item.Text+'"' break; case 'Abbrev': tag = 'abbr'; break; case 'List': tag = 'ol'; break; case 'ListItem': tag = 'li'; break; default: tag = 'div'; attr += ' class="'+item.Node+'"'; } html += '<'+tag+attr+style+'>'; //Пишем текст узла, если есть if (item.Text) html += item.Text; //Углубляемся на следующий уровень, если есть if ('Markup' in item) { item.Markup.forEach(function(item) { recursive_reading(item); }); } //Углубляемся на следующий уровень, если есть if ('Items' in item) { item.Items.forEach(function(item) { recursive_reading(item); }); } //Закрываем тег html += '</'+tag+'>'; } response.forEach(function(item) { html += '<div class="dictionary">'; html += '<h3>'+item.Dictionary+'</h3>'; html += '<h4>'+item.Title+'</h4>'; item.Body.forEach(function(item) { recursive_reading(item); }); html += '</div>'; }); //Вывод результата $('#dictionary_entry').html(html);

JQuery refuses to understand json format.

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