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Initiation of the dynamic mass

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Saumya last edited by

How to initiate the dynamic mass of whole numbers (intWhen it's announced?
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juvenalb last edited by
Create. vector<int>♪ He has a designer:
```
explicit vector (size_type n, const value_type& val = value_type(),
                 const allocator_type& alloc = allocator_type());
```
Give it the number of elements and the primary value.
Or you can put the initial values into this designer if you already have them:
```
template <class InputIterator>
         vector (InputIterator first, InputIterator last,
                 const allocator_type& alloc = allocator_type());
```
The use of the vector will solve all your problems with changing the size of the dynamic mass in the future.
If you need a bare mass, you can fill it with zeros, recording it at the end of the box:
```
new int[n]();
```
Concrete values are maintained by modern compilators:
```
new int[n] { 1, 2 };
```
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How do you distort the mass by number of elements in his sub-masses?
Software Programming • php • • elysha

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usort Second argument accepted callback a function that should return a whole that is less than or more than zero if the first argument is smaller, equal or larger than the second. $a and $b - it's the order of the compared elements of the mass, not the key and value, as in your example.$arr = [ [1,2,], //2 элемента [1,4,5], //3 [1,], //1 [1,4,6,9], //4 ]; usort($arr, static function ($a, $b) { return count($a) < count($b); });
Use of limitation class
Software Programming • c++ classes boxes with++ • • emmalee

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We can call. But why?All checks are purely static, with no complete code, that is. No overhead time♪UpdateI have a C++11 option to make it easier:template<typename T, typename = enable_if_t<is_same<decltype(&T::f), // Имя функции-члена T* (T::*)()>::value>> // Ее тип, что нам нужен class C ... Well, or more fun:static_assert(is_same<decltype(&T::f),T* (T::*)(int)>::value,"Error"); Standard guru, what do you say? ♪ ♪
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Error C2075, initializing the mass
Software Programming • c++ lambda expression • • terrea

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You're trying to take over. info It's not a big deal.Get on the reference-- &info♪
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Dynamic initialization in s++
Software Programming • c++ initialization • • jules

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Recently read out here that the same variable can be dynamically initiated after it was statically initiated. Is that correct? If so, can the variable be triggered twice?Yeah, that's right. Yeah, the variable can be initialized twice.It's rather a question of terminology: Is it right to call the second initialization... The language standard says that, at the beginning of the programme, static initialization of static storage variables with static storage class is carried out.static initialization) They may then be further exposed to dynamic initialization during the programme process (see annex).dynamic initialization)The fact of dual initialization could well be found in practice. http://eel.is/c++draft/basic.start.static#note-2 :#include <iostream> using std::cout; using std::endl; inline double fd() { return 1.0; } extern double d1; double d2 = d1; // unspecified: // may be statically initialized to 0.0 or // dynamically initialized to 0.0 if d1 is // dynamically initialized, or 1.0 otherwise double d1 = fd(); // may be initialized statically or dynamically to 1.0 int main() { cout << "d1: " << d1 << endl; cout << "d2: " << d2 << endl; } Conclusion of the programme http://coliru.stacked-crooked.com/a/4cddbbb257dc63b9 ♪ https://ideone.com/5Oc0F8 d1: 1 d2: 0 The observed conduct can be explained as follows.Removed d1 and d2 Statically initiated by zero.Then variable d2 dynamically initiated by variable value d1 (sighs)double d2 = d1;)Finally, variable d1 dynamically initiated by a function challenge fd (sighs)double d1 = fd();)Well, it's not that simple. If not the variable d2codeinline double fd() { return 1.0; } double d1 = fd(); in general is equivalent to that code:double d1 = 1.0; Dynamic initiation of variables d1 can be replaced by static initialization, with variable value d1 No change. The language standard clearly permits such a replacement. See: http://eel.is/c++draft/basic.start.static#3 ♪ Stage of static initialization of variable d1 may be assigned value 1.0Not 0.0♪ That is, the observed may be such as:Modified d1 Statically initiated by the value 1.0and variable d2 Statically initiated by the value 0.0♪Then variable d2 dynamically initiated by variable value d1 (i.e. also takes importance 1.0)Finally, as a variable d2 eventually very specific, known at the compilation stage, it, as well as the variable d1may not be subject to dynamic initialization, but only static.Something like that.
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Dynamic memory/C++
Software Programming • c++ • • obi

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(Dynamic memory) all this has no direct relationship.)nullptr It doesn't have to be "different." NULL♪ In modern C+++, starting with C++11, macro NULL can be defined precisely as nullptr♪"Classic." NULL is a whole constant expression1 value 0i.e. may be used not only in reference but also in arithmetic contexts (including in error). nullptr not a general type and arithmetic contexts cannot be used2♪Possibility of using "classical" NULL Indicative contexts, it is based on the fact that the intended constant 0 Unidentifiable to the index type. However, such non-retroactivity does not occur in the context of the arguments of the template. I mean. NULL cannot be null-pointer constant on the table of argumentstemplate <void *p> struct S {}; int main() { S<NULL> s1; // Ошибка! S<(void *) NULL> s2; // OK S<nullptr> s3; // OK } nullptr free from this deficiency.1 - in modern C++ nullptr), NULL to be defined as whole lotteral value 0♪ Arbitrary whole constant expression with value 0 can no longer act as null-pointer constant. Also as null-pointer constant can no longer act false and \0♪2 - except for opportunity bool♪
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function of substantiation of arguments
Software Programming • c++ linux g+ • • gionna

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She considered the arguments.What do you mean? If it's about getting rid of the parameter. neither you're referring a number of arguments, obviously, or you're using some sign of the end of the list of arguments:PrintFloats( 3.0, 3.14159, 2.71828, 1.41421, 0.0 ); // 0.0 (или любое другое заранее оговоренное // значение, например, -1970.0) - конец, больше аргументов не будет I want to call for a function like that format.Do it.void format (const char * format, ...) { Examples of implementation - in absolutely any googlynex from the first references to the "va_arg examples" type request, they'll be dozens. Look, try. Even man va_arg There are examples. In this case, the list of arguments will be drawn from the line of the format, and it is not necessary specifically to transfer the number or signature.For example, a slightly refined example man va_arg:#include <stdio.h> #include <stdarg.h> static void format( const char * fmt, ... ) { union { double f; int d; char * s; } var; va_list ap; va_start( ap, fmt ); while( *fmt ) { if( *fmt == '%' ) { fmt++; if( *fmt ) { switch( *fmt ) { case 'f': var.f = va_arg( ap, double ); printf( "%f", var.f ); break; case 's': var.s = va_arg( ap, char * ); printf( "%s", var.s ); break; case 'd': var.d = va_arg( ap, int ); printf( "%d", var.d ); break; default: printf( "%c", *fmt ); break; } } } else { printf( "%c", *fmt ); } fmt++; } va_end( ap ); } int main() { format( "int: %d, double: %f, string: %s\n", (int)1, (double)2, "3" ); return 0; } P.S. I hope you don't seriously invent your bicycle to work with the OBD? If that's the case, you're gonna have to stop this idea and find the normal library ready.
How to capture keyboard action without pausing the C++ program?
Software Programming • c++ • • Marcee

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It is not possible to do this with pure C++ because it depends on the operating system and the console used. ( https://stackoverflow.com/a/421871/1683070 )An alternative is to use the function kbhit() available in the library conio.h. It checks if any key has been pressed, then just hit the function before scanf. However, it is necessary to look at why there are different implementations to http://sourceforge.net/projects/libconio/ and http://sourceforge.net/projects/linux-conioh/ . ( https://stackoverflow.com/a/422200/1683070 )On Windows, you can also use the function http://msdn.microsoft.com/en-us/library/windows/desktop/ms684961%28v=vs.85%29.aspx to read and empty the console input buffer. Note that this function also captures mouse events, so you need to check the http://msdn.microsoft.com/en-us/library/windows/desktop/ms683499(v=vs.85).aspx .One consideration about all this is that, depending on what you want, it is not good to do checks in a loop. That wastes CPU. One approach to solving this is to create new threads to do "heavy" processing and leave the main thread responsible for reading and writing on the console.
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Removal of symbols with lower registry and top register
Software Programming • c++ • • Avante

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str0++; to be removed if. There you go.while (str[str0]) { str1 = str[str0]; if(islower(str1)) { cout << str1; } str0++; } Otherwise, when you meet the symbol in the top register, your index increment stops, and you hang on that symbol forever.
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Like the social identifier to get his type, protocol... ?
Software Programming • c++ tall • • jules

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I don't know what you want, to be honest.Functions accept:int accept(int sockfd, struct sockaddr *addr, socklen_t *addrlen); Pass the second specimen to the sockaddr structure, and then you get the information you want.And you're sure it's an adjustment check:accept_socket!= WSAGetLastError() ?Compare with one.
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I have the task of producing elements in every column under the main diagonal of the matrix.
Software Programming • c language liabilities • • yajahira

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First, according to language standard C, function main without parameters should be declared as int main( void ) You don't initialize the variable. i at the beginning of the programme, and the next announcement of the mass is not correct. int i,j,k; int a[n][n]; int d[i]; ^^^^^^^^ Why don't you tell him how int d[n-1]; It's even better to define it as having long long int'Cause the whole thing might not fit in a type object. int long long int d[n-1]; The very function of the component in the columns under the main diagonal may look as follows:void dob ( const int a[n][n], long long int d[n-1] ) { size_t k = 0; for ( size_t col = 0; col < n; col++ ) { if ( col + 1 < n ) { long long int result = 1; for ( size_t row = col + 1; row < n; row++ ) { result *= a[row][col]; } d[k++] = result; } } } Accordingly, the challenge will be as follows:dob( a, d ); Any conclusion to the consolation of performance should be removed from the function and placed in main♪
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The method is sorting the mass, but the maximum element of the mass is missing. Why?
Software Programming • java amassia corroboration • • charlenef

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You just don't get him out because i < n - 1 Totalfor (int i = 0; i < n - 1; ++i) { Add at the end:System.out.print(arr[n - 1] + "\t");
How in the dynamics of the elements?
Software Programming • c language memory inspectors mother mamassiah • • jeanid

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I thought in a traditional way, like Mikhailo's answer, it took a long time to free memory, like,for(int i = 0; i < n; ++i) free(a[i]); free(a); But if one piece of memorial is given, one can be removed:a = malloc(n*(sizeof(int*)+m*sizeof(int))); for(int i = 0, ofs = n*sizeof(int*); i < n; i++) a[i] = (int*)((char*)a + ofs + i*m*sizeof(int)); .... free(a); Well, i.e., in an escrow of memory, the indexes are first used. n Line, and then it's on its own. n Lines m Poles. It is clear that for a specific question posed n==m♪
How do we establish the initial dimension of the party &apos; s extenuation when converted? ORA-02203: INITIAL storage options not allowed
Software Programming • sql oracle • • irl

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I need to point out the claus. storage for each Party, not for the whole table:create table t (val int) storage (initial 10m) / insert into t select level x from dual connect by level <= 5 / alter table t modify partition by range (val) interval (1) ( partition p1 values less than (2) storage (initial 8k), partition p2 values less than (3) storage (initial 64k), partition p3 values less than (4) storage (initial 128k)); select partition_name, initial_extent from user_tab_partitions where table_name='T'; PARTITION_NAME INITIAL_EXTENT P1 16384 P2 65536 P3 131072 SYS_P10883 10485760 SYS_P10884 10485760 Note, as this should be done for all parties, the automatically created parties will have the same initial size as the reference table.Modify by clause modify default attributes:insert into t values (6); alter table t modify default attributes storage (initial 16k); insert into t values (7); select partition_name, initial_extent from user_tab_partitions where table_name='T'; PARTITION_NAME INITIAL_EXTENT P1 16384 P2 65536 P3 131072 SYS_P10883 10485760 SYS_P10884 10485760 SYS_P10885 10485760 SYS_P10886 16384 Free translation https://stackoverflow.com/a/67720008 from the participant https://stackoverflow.com/users/1485955/chris-saxon
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Why don't you pop the pile?
Software Programming • c++ c language memory variables stac languagek • • Oba22

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The variable p was declared in this function. It will have the size of 4 or 8 bytes depending on the architecture. This variable is unique in the whole function and it seems all application is this code. Why would the stack burst with only one variable of such little size?The pile has a fixed size, not because it bursts. The burst only occurs when it is being occupied more and more, which does not occur. Obviously if no one stops this application it will never end.At some point the application will be very slow or will have problem with heap because virtual memory has limit and there is RAM limit.If the architecture is 32 bits when running little more than 1 billion times, it will occupy the 4GBB of total memory. As not everything should be in RAM should have some slowness to play in secondary storage. If you have a state-of-the-art SSD, you won't feel that much.If the architecture is 64 bits you will need more than 4 billion interactions to fill all space, of course you will need a secondary storage prepared to support such virtual memory, you would need hundreds of HDDs with the current capacity. I think it would take a few centuries to run this with current hardware.If you take it new no more allocation in heap, then it is all done in the pile, always in the same place, since there is always one variable, then there is neither the heap can burst. The stack, in essence, leaving aside small details, will occupy 4 bytes (may be different, but in practice it will be 4 bytes).The operator new is responsible for allocation in heap and he is running several times allocating an entire at a time, which https://pt.stackoverflow.com/q/57006/101 But that's another matter. It always returns a pointer that is stored in p superimposing the previous value, that is, the previously created object is without any pointer pointing to it, becomes inaccessible. How is not given a delete in the object, it is there occupying space without need.In a managed memory language this would not occur and the garbage collector would release memory. https://pt.stackoverflow.com/q/3797/101 .
Load on C++
Software Programming • c++ • • Demir

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nipplesprotocols http and ftp, available at https and ftps over time.It would be good to see the multi-pound programming - the one that once wrote a simple ftp-call, and the flows were very useful.

Initiation of the dynamic mass

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