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How to pass the parameter on the position number, element listview, to the mass

morde

Injection listview We need to transfer the position to the mass without additional cycles.

    public class TicketActivity extends Activity {
//...
for (int n = 0; n < 20; n++) {
    int[] arrayAnswer = new int[20];
    //...    
    ArrayAdapter < String > adapter1 = new ArrayAdapter < String > (this, android.R.layout.simple_list_item_1, listNumber1);
    listAnswers.setAdapter(adapter1);
    listAnswers.setOnItemClickListener(new AdapterView.OnItemClickListener() {@
        Override
        public void onItemClick(AdapterView <? > parent, View v, int position, long id) {
            //нужно при каждом проходе цикла запихнуть значение position в массив arrayAnswer 
        }
    });

P
Pearlaqua last edited by

Do it. arrayAnswer and write it out. onItemClick()♪
I don't understand any more of your code, unfortunately.
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Parallel column in cycle for java
Software Programming • java for • • Pearlaqua

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I understand you need to be in the middle of something. a before b of the function f(x) If that's true, you don't need a rolling cycle.The conclusion should be approximately:for (double x = a; x <= b; x = x + h) { System.out.println("x" + count + "=" + x + " y" + count + "=" + f(x)); count = count + 1; }
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How to pass a string to a decimal if you have a decimal number greater than 0, or go in full if you have a decimal number equal to 0?
Software Programming • python string dec languageimal • • chanisef

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This function receives a numerical chain and returns its value as a type object intunless you have a different decimal part of zero, in which case you return float.def convertir_numero(valor): temp = float(valor) if temp % 1: return temp else: return int(temp) Operation module temp % 1 produces the fractional part of the value. If you don't have a fraction, or if this is zero, return zero.Demodef convertir_numero(valor): temp = float(valor) if temp % 1: return temp else: return int(temp) tests = ["1", "2.0", "3.1", "-2.9", "-10", "1e10", "1.0e12", "1.1e-1"] for test in tests: conv = convertir_numero(test) print(test, conv, type(conv)) produces1 1 <class 'int'> 2.0 2 <class 'int'> 3.1 3.1 <class 'float'> -2.9 -2.9 <class 'float'> -10 -10 <class 'int'> 1e10 10000000000 <class 'int'> 1.0e12 1000000000000 <class 'int'> 1.1e-1 0.11 <class 'float'> Process finished with exit code 0
T

[HY093]: Invalid parameter number: parameter was not defined
Software Programming • php mysql pdo • • tahishae

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The problem you're suffering is that you're using in the SQL a name marker (placeholder) :cruso (curso=:cruso) but then you assign value to the marker :curso in the bindValue.When running the PDO query you get an exception because MySQL does not find values for all markers, that's why you get that error message:Invalid parameter number: parameter was not definedIn Spanish:Number of invalid parameters: the parameter was not definedIdeally, bindValue it was the one who detected inconsistencies, but unfortunately it is not so and hence this is a very common mistake.I've arranged your code for the SQL to show the right name:public function actualizar($usuario) { $db = BaseDatos::conectar(); $actualizar = $db->prepare(' UPDATE Usuario SET usuario = :usuario, contrasena = :contrasena, nombre = :nombre, apellido = :apellido, dni = :dni, email = :email, telefono = :telefono, direccion = :direccion, cod_postal = :cod_postal, fecha_nac = :fecha_nac, curso = :curso, foto = :foto, estado = :estado, tipo = :tipo WHERE id_usuario = :id_usuario '); $actualizar->bindValue(':usuario', $usuario->getUsuario()); $actualizar->bindValue(':contrasena', $usuario->getContrasena()); $actualizar->bindValue(':nombre', $usuario->getNombre()); $actualizar->bindValue(':apellido', $usuario->getApellido()); $actualizar->bindValue(':dni', $usuario->getDni()); $actualizar->bindValue(':email', $usuario->getEmail()); $actualizar->bindValue(':telefono', $usuario->getTel()); $actualizar->bindValue(':direccion', $usuario->getDireccion()); $actualizar->bindValue(':cod_postal', $usuario->getCodPostal()); $actualizar->bindValue(':fecha_nac', $usuario->getFechaNac()); $actualizar->bindValue(':curso', $usuario->getCurso()); $actualizar->bindValue(':foto',$usuario->getFoto()); $actualizar->bindValue(':estado',$usuario->getEstado()); $actualizar->bindValue(':tipo',$usuario->getTipo()); $actualizar->bindValue(':id_usuario', $usuario->getIdUsuario()); $actualizar->execute(); }
Pass parameter on jquery .on
Software Programming • javascript jquery • • jeanid

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You can declare your listener with on and get a date attribute with your parameter, for example:I changed your button a little to pass the date attribute and add the class:$(xml).find("gasto").each(function() { if($(this).attr("user") == user) { $("#tablex tr:last").after("<tr><td>"+$(this).find("descricao").text()+"</td><td>"+$(this).find("valor").text()+'</td><td><button class='btn-click' data-id=' + $(this).attr("id")+'">X</button></td><td><button class="up">U</button></td></tr>'); } }); and your listener for the click event on the button: $(document).on("click", ".btn-click", function(){ var id = $(this).data("id"); }); I just didn't understand that there was the return of undefined function in the example you cited.
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Dun is a set of valid numbers from N members to calculate how many negative, positive and zero elements it contains
Software Programming • python • • gionna

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That's how it works.my_list = [1, 2, 3, 4, 5, 0, 0, 0, 0, -1, -2, -3, -4, -5] positive = 0 negative = 0 zero = 0 for num in my_list: if num > 0: positive += 1 continue if num < 0: negative += 1 continue zero += 1 print('Положительных: ', positive) print('Отрицательных: ', negative) print('Нулей: ', zero)
R

Warning: mysqli_stmt::bind_param(): Number of elements in type definition string doesn't match number of bind variables in /pg2.php on line 318
Software Programming • php mysql • • Raziyah00

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Finally, friends, I found the inconvenience and described it for those who are going through this same problem. Almost three days fighting the code to find that answer:The sentence I wrote was:$stmt->bind_param('iiisssssssdiiiddsssidddssssssss', 2016, 2, 1, 'texto1', 'texto2', 'texto3', 'texto4', 'texto5', 'texto6', 'texto7', 0.01, 1, 1, 1, 0.01, 0.01, 'texto8', 'texto9', 'texto10', 11, 0.01, 0.01, 0.01, 'texto11', 'texto12', 'texto13', 'texto14', 'texto15', 'texto16', 'texto17', 'texto18'); And it would really be right, if "bind_param()"to pass values directly. The truth is that it is necessary to send a variable for every value that is sent, it is not possible to send the values "naked" but encapsulated within a variable.I mean, the right way to send the sentence was:$stmt->bind_param('iiisssssssdiiiddsssidddssssssss', $int1, $int2, $int3, $string1, $string2, $string3, $string4, $string5, $string6, $string7, $double1, $int4, $int5, $int6, $double2, $double3, $string8, $string9, $string10, $int7, $double4, $double5, $double6, $string11, $string12, $string13, $string14, $string15, $string16, $string17, $string18); That way, the information was loaded into the DB without any other error in the code. It was obviously a matter of capricious syntax of this function, but it must surely keep some logic.Thanks to those who have given me some clues and serve those who may need it.
References to mass elements
Software Programming • php masses • • Demir

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The point is, $v You have a reference to the last element of the mass even during the second passage. Each quotation of the last value is attributed to the current element. Well, at the time you've reached the end, the final value is as follows:To avoid it, do it. unset($v) Right after the first cycle. It'll break the connection.Look at this example:$a = array(1,2,3,4,5); foreach ($a as &$v){ $v = $v + 1; } foreach ($a as $key => $v){ echo 'текущий = '.$v.'<br />'; echo 'последний = '. $a[count($a)-1].'<hr />'; } Get:текущий = 2 последний = 2 текущий = 3 последний = 3 текущий = 4 последний = 4 текущий = 5 последний = 5 текущий = 5 последний = 5 Details can be read: http://schlueters.de/blog/archives/141-References-and-foreach.html
How do you put the elements of the mass on each other?
Software Programming • python pandas numpy • • Bogopo

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Use the method. https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.Series.pct_change.html :res = 1 + s.pct_change() Examples:In [3]: s1 = pd.Series([1, 2, 4, 6]) In [4]: 1 + s1.pct_change() Out[4]: 0 NaN 1 2.0 2 2.0 3 1.5 dtype: float64 In [5]: s2 = pd.Series(np.linspace(0,20,10)) In [6]: s2 Out[6]: 0 0.000000 1 2.222222 2 4.444444 3 6.666667 4 8.888889 5 11.111111 6 13.333333 7 15.555556 8 17.777778 9 20.000000 dtype: float64 In [7]: 1 + s2.pct_change() Out[7]: 0 NaN 1 inf 2 2.000000 3 1.500000 4 1.333333 5 1.250000 6 1.200000 7 1.166667 8 1.142857 9 1.125000 dtype: float64
C

Make HTTP Petitions for USB and Sockets
Software Programming • java android soc languageket android async languagetas • • courtlanda

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@BrandoT checks your code if you put the mouse pointer over the line, I can ensure you have a message like this:Condition '(line = LoginActivity.Globals.socketIn.readLine()) != null' is always 'true'Which indicates that you have an infinite "loop", you can make this change to work properly: String line = LoginActivity.Globals.socketIn.readLine(); while (line != null) { builder.append(line); line = LoginActivity.Globals.socketIn.readLine(); } }
A

Why is matcher returning false?
Software Programming • java api test automation rest assured • • Anderson

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The result of this code is:String value = response.path("data.color").toString(); will be a set of all the values found. data.color♪In your example, at least two of them.I mean, it's gonna be a line like, [#98B2D1, #C74375, ...]♪This line does not fully correspond to the intended regular expression.
J

Compare time in Java.sql format with current time
Software Programming • java sql server • • juvenalb

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To compare the time you have to use the method toLocalTime() class java.sql.Time to convert object to class LocalTime and make comparisons, I show you an example of how to perform it with java 8+:import java.sql.Time; import java.time.LocalTime; import java.util.Date; public class CompararHoras { public static void main(String[] args) { Date date = new Date(); // Hora que obtendrías de la base de datos. Time time = new Time(date.getTime()); //Utilizamos el método toLocalTime() para convertir el objeto a LocalTime LocalTime horaDB = time.toLocalTime(); // Hora actual para realizar las comparaciones LocalTime horaActual = LocalTime.now(); System.out.println(horaDB.isAfter(horaActual)); //true System.out.println(horaDB.isBefore(horaActual)); //false System.out.println(horaDB.getHour() == horaActual.getHour()); //true } }
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Determine the number of elements between the first and last zero element of the matrix
Software Programming • c++ • • Burma

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As first advice I would recommend you not to use conio.h. It is a non-standard and doubtful bookstore in real developments.On the other hand, when you do delete []m; You must be aware that you're not erasing anything but m, the size reserves c They're staying in limbo. The general rule is that for each new to include a delete And in your code there are two new and a single delete.In my way of seeing (and this is a totally personal opinion) the way you tabulate the code complicates its reading quite. That the closing keys at the end of the line forces you, for example, to have to count how many there are to know what the next instruction is to execute... the fact of concatening without coming to the story several instructions in the same line does not help the code be readable.As for the variables, you don't need to reuse the entire program. You can create the variables within the loops. The advantage of doing so is that you reduce the scope of the variable and improve the reading of the program (if a variable ceases to exist it is no longer a problem).The recommendations are that, recommendations, are not compulsive but they are never more and can help you make less mistakes in the future.A detail that would squeeze me especially is that of calculating the distance of two elements from a matrix. You said arrayThen I'm afraid you don't have to create a matrix but an element vector. If my suspicions are true, the algorithm will simplify you a lot. If, instead, you have to create a matrix, it doesn't make me clear why you understand that the distance between two elements passes by linearizing the matrix as if it were a vector.Well, let's review the first loop of your search algorithm:for (int i=0; i<r; i++) { for (int j=0; j<c; j++) { if (m[i][j]==0) break; else count++; if (j!=c) break; } } Note that break Just leave a loop and you have two nests. When you arrive breakThe execution will leave the loop j and will continue to execute the loop iSo he'll end up entering the loop again. j. In the second loop exactly the same.If the idea is to look for two positions within a vector (and you are treating the matrix as a vector) I preferred to directly manage a vector.// Un único new implica un único delete int* vector = new int[filas*columnas]; Finally, the search for the first and last element of X features could be encapsulated in a function, avoiding duplicating the code. To do this part there are several options, although perhaps the easiest one is a function that returns the next position of a value given an initial position and -1 if there are no more values. Then ask for the first value and then ask for the second in loop until the function returns you -1, the value that gave you the previous time (and that you have to memorize) is the position of the last '0' of the list. Something with a signature such that:// valor es el número a buscar // ptr el inicio del vector // inicio es el índice por donde empieza a buscar // final indica el índice donde debe finalizar la búsqueda (final del array) int Posicion(int valor, int* ptr, int inicio, int final); A greeting.
Selection of all combinations of n-started elements
Software Programming • java algorithm c+++ multiplicity combination • • Bogopo

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Imagine that this is the numbers on the respective locations.Set the first number-- 1aA (or how many places it takes) Then we'll just increase the last element until we get everything over. After this, we shall set it up with an equal minimum element and increase the previous (if it is also maximalene, drop it to a minimum and move to the preceding).1aA 1aB 1aC // достигли максимума в последней позиции. переход- 1bA 1bB 1bC // достигли максимума в последней позиции. переход- 1bA 1bB 1bC // достигли максимума в последней позиции. переход- 1bA 1bB 1bC // достигли максимума в последней позиции. переход- 1сA 1сB 1сC // достигли максимума в последней позиции. переход- но во второй позиции // тоже максимум, перенос далее 2aA ... In short, it's just an algorithm.Generation in the Mixed Positioning SystemFrom page 330 4A of the volume "Programming Art." ♪ ♪
GPS coordinates
Software Programming • android coordinates • • Analeea

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If you need the dimensions of View, you can be obtained with myView.getMeasuredHeight() and change myView.getLayoutParams().height = newHeight with width, respectively. After you call myView.requestLayout if it's broken.
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Modification of elements in the mass
Software Programming • php liabilities • • amarantha

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$newArray = []; // $array - ваш массив foreach($array as $series){ $newArray[$series['season']][] = $series; } var_dump($newArray); There's a range of species.сериал => сезон 1 => серия 1 серия 2 сезон 2 => серия 1 серия 2

How to pass the parameter on the position number, element listview, to the mass

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