It's not possible to put a reference in a slider on the image, tell us how this can be implemented.
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<div class="row-fluid"> <div class="span12 foto" id="wrapper"> <div id="slider_top"> <div class="slide" style="background-image: url(/wa-data/public/site/themes/1.jpg);"> <a href="http://www.webasyst.ru/store/theme/flamingo/instruktsiya/"> </a> </div> <div class="slide" style="background-image: url(/wa-data/public/site/themes/2.jpg);"> <a href="http://amulet-td.ru/"> </div> <div class="slide" style="background-image: url(/wa-data/public/site/themes/slide1-980x340.png);"> <a href="http://www.webasyst.ru/store/theme/flamingo/instruktsiya/"> <!-- <div class="slide-block"> </div>--> </a> </div> <div class="slide" style="background-image: url(/wa-data/public/site/themes/slide2-980x340.png);"> <a href="http://www.webasyst.ru/store/theme/flamingo/instruktsiya/"> </a> </div> <div class="slide" style="background-image: url(/wa-data/public/site/themes/slide3-980x340.png);"> <a href="http://www.webasyst.ru/store/theme/flamingo/instruktsiya/"> </a> </div> </div> </div>
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The default tag is inline, so it's gonna expand on the size of what's inside. Either take advantage of the @lexxl or ask the sss properties
height: 100%; display: block;
The height will be 100 per cent of the parent, and the block ' s properties will spread the element along the width of the parent. If it doesn't have a float: left.