Windows



  • Tell me if there's any way to launch software applications from Windows. Process.Start(path) does not work as does the exe-fill double click



  • We need to use the method. https://msdn.microsoft.com/en-us/library/windows/desktop/hh706903.aspx ♪ Activation code (using interop):

    public enum ActivateOptions
    {
        None = 0x00000000,  // No flags set
        DesignMode = 0x00000001,  // The application is being activated for design mode, and thus will not be able to
        // to create an immersive window. Window creation must be done by design tools which
        // load the necessary components by communicating with a designer-specified service on
        // the site chain established on the activation manager.  The splash screen normally
        // shown when an application is activated will also not appear.  Most activations
        // will not use this flag.
        NoErrorUI = 0x00000002,  // Do not show an error dialog if the app fails to activate.                                
        NoSplashScreen = 0x00000004,  // Do not show the splash screen when activating the app.
    }
    

    [ComImport, Guid("2e941141-7f97-4756-ba1d-9decde894a3d"), InterfaceType(ComInterfaceType.InterfaceIsIUnknown)]
    interface IApplicationActivationManager
    {
    // Activates the specified immersive application for the "Launch" contract, passing the provided arguments
    // string into the application. Callers can obtain the process Id of the application instance fulfilling this contract.
    IntPtr ActivateApplication([In] String appUserModelId, [In] String arguments, [In] ActivateOptions options, [Out] out UInt32 processId);
    IntPtr ActivateForFile([In] String appUserModelId, [In] IntPtr /IShellItemArray / itemArray, [In] String verb, [Out] out UInt32 processId);
    IntPtr ActivateForProtocol([In] String appUserModelId, [In] IntPtr /
    IShellItemArray* */itemArray, [Out] out UInt32 processId);
    }

    [ComImport, Guid("45BA127D-10A8-46EA-8AB7-56EA9078943C")]//Application Activation Manager
    class ApplicationActivationManager : IApplicationActivationManager
    {
    [MethodImpl(MethodImplOptions.InternalCall, MethodCodeType = MethodCodeType.Runtime)/, PreserveSig/]
    public extern IntPtr ActivateApplication([In] String appUserModelId, [In] String arguments, [In] ActivateOptions options, [Out] out UInt32 processId);
    [MethodImpl(MethodImplOptions.InternalCall, MethodCodeType = MethodCodeType.Runtime)]
    public extern IntPtr ActivateForFile([In] String appUserModelId, [In] IntPtr /IShellItemArray / itemArray, [In] String verb, [Out] out UInt32 processId);
    [MethodImpl(MethodImplOptions.InternalCall, MethodCodeType = MethodCodeType.Runtime)]
    public extern IntPtr ActivateForProtocol([In] String appUserModelId, [In] IntPtr /
    IShellItemArray* */itemArray, [Out] out UInt32 processId);
    }

    class Program
    {
    static void Main(string[] args)
    {
    ApplicationActivationManager appActiveManager = new ApplicationActivationManager();//Class not registered
    uint pid;
    appActiveManager.ActivateApplication("2c123c17-8b21-4eb8-8b7f-fdc35c8b7718_n2533ggrncqjt!App", null, ActivateOptions.None, out pid);
    Console.WriteLine();
    Console.ReadLine();
    }
    }

    The first and main parameters are the annex identifier. It can be found from the registry:

    реестр

    Explanation https://stackoverflow.com/a/12927313/1985167 from enSO.




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