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How do you command the DS to open a C++ graphic file?

carriann last edited by
I can't open a graphic file. First tried it:
```
#define FNAME "D:/Scream297and396.jpg"              
...            
int main() { char fname [50] =FNAME;        
FILE *fout;            
fout = fopen(FNAME,"r");           
return 0; }
```
...but there's nothing going on when this program starts, the file doesn't open. More specifically, it may still be open, but to read the file itself by the same program.
I need to open the file. programme♪ for the usera default in the operating system. In this case, the file D:/Scream297and396.jpg shall be opened in the screener with the pictures prescribed for *.jpg♪
How do you do that?
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C
courtlanda last edited by
I think you need something like that:
```
ShellExecute(handle, "open", "D:\\Scream297and396.jpg", nullptr, nullptr, SW_SHOWNORMAL);
```
Details of opportunities ShellExecute read it. https://msdn.microsoft.com/ru-ru/library/windows/desktop/bb762153(v=vs.85).aspx
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Software Programming • c++ loop stream • • Analeea

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I did another test and the original code I posted does not work in any situation. I made another one that's more complicated, but it works. He's got one. string and try to convert it to int. If it fails, it is the same as if the number is invalid. Before it works when there was a specific error, now it treats any invalid input. And as it is done through specialized function, no need to worry about the state of stream stream stream stream stream stream standard.#include <iostream> #include <string> #include <sstream> using namespace std; int ActionGenerator() { int Action; string Input = ""; while(true) { cout << endl << "SELECIONE UMA ACTION: " << endl; cout << "[1 = ActionX]" << endl << "[2 = ActionZ]" << endl; getline(cin, Input); stringstream myStream(Input); if ((myStream >> Action) && (Action == 1 || Action == 2)){ return Action; } else { cout << endl << "ACTION INVALIDA !" << endl; } } } int main() { cout << ActionGenerator() << endl << "ok" <<endl; return 0; } See https://ideone.com/jR1xDW . And https://repl.it/join/uvzdtstg-maniero . Also https://github.com/maniero/SOpt/blob/master/CPP/Console/GetChars.cpp .Note that I did a test with a string more than a character. This failed the previous code.The code is hard to understand because it's not badly indented. It may seem silly but this makes a huge difference to understand the code.It's part of it that will never be executed. And in fact there is no logic to get out of loop unless you type 1 or 2. And in these cases the execution of the function is closed.But the problem is that you are not releasing the state of stream stream stream stream stream stream. When an error occurs flag error is sealed for you to know that there was a problem when you tried to get a valid value. When you type something that cannot be converted into the expected type, in case one int, besides the number being converted to 0, is flag Stay sealed and only if you explicitly clear this is that you can go back to work with stream stream stream stream stream stream. If flag you are sealed the stream stream stream stream stream stream doesn't work.Another problem occurs that the typed data still stays in buffer and you need to ignore what is in it.That is, the stream stream stream stream stream stream state guard and you have to solve this.I took advantage and made an improvement for this case:#include <iostream> using namespace std; int ActionGenerator() { int Action; while(true) { cout << endl << "SELECIONE UMA ACTION: " << endl; cout << "[1 = ActionX]" << endl << "[2 = ActionZ]" << endl; cin >> Action; if (Action == 1 || Action == 2){ return Action; } else { cout << endl << "ACTION INVALIDA !" << endl; cin.clear(); //Limpa a flag de erro quando há falha no parse do valor entrado cin.ignore(); //Limpa o buffer } } } int main() { cout << ActionGenerator() << endl << "ok" <<endl; return 0; } See https://ideone.com/K9EhtD . And https://repl.it/join/gebrzbmh-maniero . Also https://github.com/maniero/SOpt/blob/master/CPP/Console/GetChars2.cpp .You have other ways to treat this but I think for the simple example you gave doesn't have because you do anything more complex than this.Note that I simplified the loop too. There was no reason to exist that control in this case.
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Binary file/Binary file - C++
Software Programming • c++ structures • • zymir

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You can record the structure in the file by pre-defining the intake operator or recording each field, opening the file on the binary record. But you can read only if you know in advance the number of symbols recorded in the file as the field of structure. If it helps to understand, at your request, I'll give you an example of how to put the line in binary form and how to read the binary records:#include <iostream> #include <string> #include <bitset> using namespace std; int main() { string s = "abcdefgh", res; bitset<8> b; size_t n = s.size(); // записываем строку посимвольно в бинарном виде for (size_t i = 0; i < n; ++i) { b = s[i]; cout << b << endl; } // если вводить все что получили на выводе, то res будет иметь значение s while( cin >> b) res += char(b.to_ulong()); cout << res; return 0; } If there's something wrong, I hope there's someone who'll be happy.
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.jar files do not open
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You forgot to indicate your main class in the jar. The 'c' flag indicates that you want to create a new jar file and 'f' the file name.The 'e' flag (for 'entrypoint') creates or replaces the Main-Class manifest attribute. It can be used while creating or updating a JAR file. Use it to specify the application input point without editing or creating the manifest file.jar cfe arquivo.jar foo.Main foo/Main.class foo/Outra.class Source: https://docs.oracle.com/javase/tutorial/deployment/jar/appman.html
What's the mistake? Find the percentage of pairs, odds and zeros
Software Programming • c++ c language • • Laycee

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It's better if the itera loop from scratch:for(int i = 0; i < n; i++) The check can be done with:if(num[i] == 0) ceros++; else (num[i] & 1) ? n_impares++ : n_pares++; An alternative can also be:if(num[i] == 0) { ceros++; } else if (num[i] & 1) { n_impares++; } else { n_pares++; } Every odd number has the least significant bit activated. On the other hand, pair numbers always have their less significant bit equal to zero.We can take advantage of that particularity if we use the operator AND from bit to bit (&), not to confuse with AND logic (&&). xxxx ... xxx0 número par en binario, un ejemplo puede ser el número 20: 0010 0100 & 1 0 => Resultado 0, entonces el número es par xxxx ... xxx1 número impar en binario, un ejemplo puede ser el número 21: 0010 0101 & 1 1 => Resultado 1, entonces el número es impar Then, to calculate the percentages it is preferable to work with numerical floating variables float, but if you want to use integers, then you should leave the division for the last, that is to say it must be the last operation of the code line:p_pares = 100 * n_pares/n; p_impares = 100 * n_impares/n; p_ceros = 100 * ceros/n; Full code:#include <iostream> #include <conio.h> using namespace std; int main(){ int n; int num[100]; int n_pares=0; int n_impares=0; int ceros=0; int p_pares; int p_impares; int p_ceros; cout<<"numero de digitos : "; cin>>n; for(int i=0;i<n;i++){ cout<<"numero "<<i+1<<":"<<endl; cin>>num[i]; if(num[i] == 0) ceros++; else (num[i] & 1) ? n_impares++ : n_pares++; } p_pares=100n_pares/n; p_impares=100n_impares/n; p_ceros=100*ceros/n; cout<<"\n"; cout<<"-----------------------"<<endl; cout<<"porcentaje de pares : "<<p_pares<<endl; cout<<"porcentaje de impares : "<<p_impares<<endl; cout<<"porcentaje de ceros : "<<p_ceros<<endl; getch(); return 0; }
Opening and reading of the file, recording in the file
Software Programming • python • • Bogopo

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import re with open('dishes_list.txt', encoding="utf-8") as f: text = f.read() def parse_block(block): name, _, data = block.partition('\n') data = re.findall(r'[\r\n]([^\r\n\d]*)\s+\|\s*(\d+)\s+\|\s*([^\r\n\|]*)', data) return {name:[dict(ingridient_name=tup[0], quantity=int(tup[1]), measure=tup[2])] for tup in data} res = {name:data for block in text.split('\n\n') for name, data in parse_block(block).items()} result:{'Омлет': [{'ingridient_name': 'Помидор', 'quantity': 2, 'measure': 'шт'}], 'Утка по-пекински': [{'ingridient_name': 'Соевый соус', 'quantity': 60, 'measure': 'мл'}], 'Запеченный картофель': [{'ingridient_name': 'Сыр гауда', 'quantity': 100, 'measure': 'г'}], 'Фахитос': [{'ingridient_name': 'Помидор', 'quantity': 2, 'measure': 'шт'}]}
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C+++ files not counted
Software Programming • c++ fstream • • kalyn

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You're not doing the right thing. fstream f; f.open("in.txt", ios::in); f << ..информация для записи..;
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Files in C++
Software Programming • c++ • • Pearlaqua

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fwrite(&pm[index], sizeof(PRICE), 1, file); In that line you're blowing content in binary to the file.When you do:int variable = 5; In memory the number is stored in binary, i.e.: 0...0101that in 32 bits and hexadecimal would be 00 00 00 05. If you then turn the value as in a file what you are going to store is a four-character sequence: 3 knots and the non-printable 0x05 character.If you want to write in the file in text format you can choose to use fprintf to format the output or you can choose to use ofstream, object of c++ to write files.In the case of fprintf, more compatible with what you have, the code would remain like this:for (index = 0; index<size; index++) { cin.ignore(); cout << "Number of orden: "; cin >> pm[index].number; cout << "Product cost: "; cin >> pm[index].cost; cout << "Quantity in stock: "; cin >> pm[index].quantity; cout << "-----------------------------------\n" << endl; fprintf(file, "%d %d %d\n", pm[index].number, pm[index].cost, pm[index].quantity); } In the case of using ofstream, you could do something similar to:ofstream file; file.open ("D:\8.txt"); for (index = 0; index<size; index++) { cin.ignore(); cout << "Number of orden: "; cin >> pm[index].number; cout << "Product cost: "; cin >> pm[index].cost; cout << "Quantity in stock: "; cin >> pm[index].quantity; cout << "-----------------------------------\n" << endl; file << pm[index].number << ' ' << pm[index].cost << ' ' << pm[index].quantity << '\n'; } file.close(); By the way, in C++ the structures should be declared as follows:struct PRICE { int number; int cost; int quantity; }; And the alias of the pointer:typedef PRICE* LPPRICE; The latter from the C++11 standard (standard released in 2011) could also:using LPPRICE = PRICE*; I recommend not to use C-specific syntax in C++ projects.
Fibonacci &apos; s chiel added at the beginning of the dynamic mass
Software Programming • c++ fibonacci • • emmalee

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If you close your eyes to different mistakes, the program is likely to fly out because of the recurring calculation of Fibonacci's numbers. Yeah, it's good to explain the way it is, but for real life, it's not.So we'll write it differently (I tried to preserve your code style).void FillFib(int *array, int size) { if (size > 0) *(array) = 1; if (size > 1) *(array+1) = 1; for (int i = 2; i < size; i++) { *(array+i) = *(array+i-1) + *(array+i-2); } } If we need at least one element, we'll fill it in. At least two of them both. And then, in classics, the sum of the two previous ones.and in the main code for the cycle FillFib(first, amount); Now, even with big numbers flying.But then I drew attention to the strange data transfer code.for(int a = n_s, i = 0, j = size; i <= size; i++, j--, a--){ *(first + a)=*(first+j); *(first+j) = 0; } And here it is. In the first instance, the element is being copied outside the range. *(first+a) = *(first+n_s)♪ Switch.for(int a = n_s-1, j = size-1; j>=0; j--, a--){ *(first + a)=*(first+j); } and Impressed. But in general, I would replace memove here (and so write in style).And we'll see about there.first = (int*) realloc(first,n_s * sizeof(int)); if(first == NULL){ cout << "Memory is not available!" << endl; free(first); } At first, a typical realloc error. If he has not been able to identify his memory, he will return NULL, but the original memory will not touch. And in that case, you'll lose it. And if that's the case, calling free for the NULL sign doesn't make any sense - he won't do anything. For a training example, I think that if you can remove it, just without forgetting to add a check that the user has requested a zero size (or worse, negative).And there's a second mistake in the same bite. Let's say the memory didn't come out. But the code goes on. And the index is NULL. ♪ ♪I'd like to rewrite it like that.int* temp = (int*) realloc(first,n_s * sizeof(int)); if(temp == NULL){ cout << "Memory is not available!" << endl; free(first); return 1; } first = temp; In the absence of return at the end of the main, the standard allows this to be done. It's legal.
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C# Change of xml file from txt file
Software Programming • c sharp xml liabilities datatable textt • • amarantha

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We have a text file with this contents.Package.ConnectionManagers[xxx].{XXX-XXXX-XXXX-XXXX}.Data Source=YYYYY; User ID=fjfjf; AvailableACS Available Moths.dtsThere's a XML file.<?xml version="1.0" encoding="utf-8"?> <connections> <connection refId="PackageId..." connectionManagerID="conManagerId..." connectionManagerRefId="conManRefId..." description="des..." name="OleDbConnection..." /> </connections> After that, we have a file.<?xml version="1.0" encoding="utf-8"?> <connections> <connection refId="PackageId..." connectionManagerID="{XXX-XXXX-XXXX-XXXX-XXXX}" connectionManagerRefId="Package.ConnectionManagers[xxx]" description="des..." name="OleDbConnection..." /> </connections> Here's the whole program code, you can experiment.class Program { static void Main(string[] args) { string xmlFile = @"D:\cons.xml"; string txtFile = @"D:\cons.txt"; //MakeXML(xmlFile); ChangeConnectionAttributes(xmlFile, txtFile); } private static void MakeXML(string xmlFile) { XDocument doc = new XDocument(); XElement elm = new XElement("connections", new XElement("connection", new XAttribute("refId", "PackageId..."), new XAttribute("connectionManagerID", "conManagerId..."), new XAttribute("connectionManagerRefId", "conManRefId..."), new XAttribute("description", "des..."), new XAttribute("name", "OleDbConnection..."))); doc.Add(elm); doc.Save(xmlFile); } private static void ChangeConnectionAttributes(string xmlFile, string txtFile) { var strs = File .ReadAllText(txtFile) .Split(new[] { '|' }, StringSplitOptions.RemoveEmptyEntries); XDocument doc = XDocument.Load(xmlFile); var c1 = doc.Descendants("connection") .First() .Attributes() .First(a => a.Name == "connectionManagerID").Value = strs[1]; var c2 = doc.Descendants("connection") .First() .Attributes() .First(a => a.Name == "connectionManagerRefId").Value = strs[0]; doc.Save(xmlFile); } }
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How can I make a while containing 3 variables?
Software Programming • c++ • • Saumya

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while(RA0=0,RA1=0,RA2==0)while evaluation one condition ...and you're going through three, then it's totally normal that it doesn't work.You have to get those three variables to give a single result and how do you get that? Well, with boolean logic (AND, OR, XOR).That is, for the loop to be repeated if the 3 conditions are met at once:while(RA0==0 && RA1==0 && RA2==0) Even if you notice that the contents of the loop do not modify the variables evaluated... so unless they change in another thread it is perfectly likely that you end up entering an endless loop.
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How to load a text file by opening the file before the application?
Software Programming • c sharp • • Avante

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to achieve what you intend to do you must make some changes in your application. In the Program.cs file where the entry point to your application is located when running, you have to modify it like this:static class Program { /// <summary> /// Punto de entrada principal para la aplicación. /// </summary> [STAThread] static void Main(string[] args) { if (args.Length > 0) // Mostramos el archivo asociado a la aplicación que se pretende // abrir con la misma. MessageBox.Show("ARCHIVO: " + args[0]); Application.EnableVisualStyles(); Application.SetCompatibleTextRenderingDefault(false); // Abrimos con el formulario principal de la aplicación: Application.Run(new Form1()); } } Note that Main() supports parameters. When a file is associated with an application for opening and we double-click on it, the operating system releases the executable with the file as a parameter.So having made the modifications to the Main function, just sit with the Windows browser on the file you want to open and right-click on it and open it with... and tell it you want to open it with your application.
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Ubuntu, Qt5. No project coming up with opengl
Software Programming • c++ linux qt qt5 opengl • • Kadyn

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Videocraft doesn't have to. You don't have a liba. The ink's gone.I think. QtOpengl♪ OpenGL is compatible with almost all the versions. You don't have basic definitions, so there's nothing to do with the version.B .pro shall be QT = core gui opengl but... QT += opengl I have to work too.Use the command. ldconfig -p | grep libGL.so To check the packages and find a way to check whether the leash is being collected from the exit of this team.Try the team. sudo apt-get --reinstall install libqt4-opengl-dev
How do you add the object to the map?
Software Programming • c++ map • • Demir

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Your distinctive behavior, (map <BYTE,ifunct*>) creates a temporary facility map <BYTE,ifunct*>♪ Each such introduction shall create an individual temporary facility that is automatically destroyed at the end of the expression. All the actions you're doing, you're doing exactly with such temporary facilities. The addition of the element is also made in one of these temporary facilities and, of course, disappears without trace with it.Subject FuncBytes[sign] Your actions are not affected.
File C+++
Software Programming • c++ files file system • • emmalee

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We'll cut the "c:/tmp/a.c" file on 5 bay:#include <filesystem> int main() { uintmax_t n = std::filesystem::file_size("c:/tmp/a.c"); std::filesystem::resize_file("c:/tmp/a.c", n - 5); return 0; } Workability depends on what version of your compiler is on VS2015, for example. std::experimental::filesystem
A

Consolidated C+++
Software Programming • c++ console consol graphics schedule • • Amritpal

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D

Put in your alphabet symbolic matrix (for these 5 letters) followed by a double cycle with a withdrawal пробела - for value нуля and звездочки - for единицы♪So, something like that:matrix abc[255]; ... void echo1( const char*pszText, int scale ){ ... for( y = 0 ; y < cy ; ++y ){ for( p = pszText ; *p ; ++p ){ for( x = 0 ; x < cx ; ++x ){ put_char( abc[*p][x][y] ? '*' : ' ' ); for( s = scale ; s-- ; put_char( ' ' ) ); } put_char( ' ' ); } for( s = scale + 1 ; s-- ; put_char( '\r' ), put_char( '\n' ) ); } } void echo2( const char*pszText, int scale ){ ... for( y = 0 ; y < cy * ( scale + 1 ) ; ++y ){ for( p = pszText ; *p ; ++p ){ for( x = 0 ; x < cx ; ++x ){ ch = abc[*p][x][y/scale] ? '*' : ' '; for( s = scale + 1 ; s-- ; put_char( ch ) ); } put_char( ' ' ); } put_char( '\r' ); put_char( '\n' ); } } void _echo3( const char*pszText, int length, int scale ){ ... for( y = 0 ; y < cy * ( scale + 1 ) ; ++y ){ for( p = pszText, counter = length ; counter-- ; ++p ){ for( x = 0 ; x < cx ; ++x ){ ch = abc[*p][x][y/scale] ? '*' : ' '; for( s = scale + 1 ; s-- ; put_char( ch ) ); } put_char( ' ' ); } put_char( '\r' ); put_char( '\n' ); } } /** @param scale - масштаб символа (в символах: 0 - *, 1 - **, 2 - ***, ...) @param screen_width - ширина экранного буфера (в символах) @param indent - расстояние между строками (в символах), в случае перевода строки */ bool echo3( const char*pszText, int screen_width, int scale = 0, int indent = 0 ){ ... char_len = ( scale + 1 ) * cx; text_len = strlen( pszText ) * char_len; if( 0 == ( line_len = screen_width / char_len ) ){ // если и одного символа не вывести - печаль return false; } for( lines = text_len / screen_width ; lines-- ; pszText += line_len ){ _echo3( pszText, line_len, scale ); for( i = indent + 1 ; i-- ; put_char( '\r' ), put_char( '\n' ) ); } if( text_len % screen_width ){ echo2( pszText, scale ); for( i = indent + 1 ; i-- ; put_char( '\r' ), put_char( '\n' ) ); } return true; }

How do you command the DS to open a C++ graphic file?

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