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Is it possible to have a characteristic transformed not in the matrix?

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Kadyn last edited by

I'm writing animating CSS properties. transform♪ For that, I need to get the primary value of the properties and of course. Of course, the user indicates when the function is started. Initially tried to get out of getComputedStyle, but he's returning the matrical value.matrix3d(0.751754, 0, 0.273616, 0, 0, 0.8, 0, 0, -0.34202, 0, 0.939693, 0, 50, 0, 0, 1)) Is it possible to obtain a primary value as translateX(-50px) sclae(.8) rotateY(-20deg) ? Or should we work with the matrix? What are the options available for programme animation transform ?
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Pearlaqua last edited by

We need to calculate the values by formula. The formula is too much to add them in response, so I'll give you a reference: https://css-tricks.com/get-value-of-css-rotation-through-javascript/
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Query Transformation
Software Programming • sql server sql query databank database table • • derk

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If you want to create a new table based on query data, use the clause INTO:SELECT campo1, campo2, campo3 INTO nova_tabela FROM tabela https://docs.microsoft.com/pt-br/sql/t-sql/queries/select-into-clause-transact-sql?view=sql-server-ver15 SELECT…INTO creates a table in the default file group and inserts in it the rows resulting from the query.
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How to count and make change in all ElementID
Software Programming • javascript • • esther

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using getElementById("id") he will return only the first element with the id, so to select all elements with the same id we can use the querySelectorAll("#id"), which had returned all elements with that id.let elements = document.querySelectorAll("#currency"); after selecting all the elements we can use forEach to add the event to each element this way: elements.forEach(el => { el.onblur = () => { //number-format the user input el.value = parseFloat(el.value.replace(/,/g, '')) .toFixed(2) .toString() .replace(/\B(?=(\d{3})+(?!\d))/g, '.'); //set the numeric value to a number input el.value = el.value.replace(/,/g, ''); }; }); Remembering that it is not recommended to have more than one element with the same id in a html file, I believe you could identify the elements using a class and get the elements in this way:let elements = document.querySelectorAll(".currency"); So you could pass a forEach on elements the same way.html used for testing:<td> <tr> <input name='product_cost[]' placeholder='0.00' class='currency' type='text' class='form-control' placeholder='0.00' required> </tr> </td> <td> <input name='product_pvp[]' placeholder='0.00' class='currency' type='text' class='form-control' placeholder='0.00' required> </td> <td> <input name='product_pvp[]' placeholder='0.00' class='currency' type='text' class='form-control' placeholder='0.00' required> </td> <td> <input name='product_pvp[]' placeholder='0.00' class='currency' type='text' class='form-control' placeholder='0.00' required> </td>
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matrix android
Software Programming • android canvas • • fbio

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Everything's moving a little right and down. Why?It's very simple. When you make a change in size, there's got to be a backbone that's all that's changing. Also in turn.We need to find out where this is. The answer is simply at the beginning of coordinates (0.0). But here's the cliff in the OpenGL, the exact one will be downtown, and at 2D mode, where you're going, the point is up the left. That's why, when you're expanding the picture, it's gonna change down the right. (and in openGL it will be expanded to different sides about the centre. In a way, it looks "natural." So, when you turn, you take it and it'll be okay.
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Photograph on the elements of the list of keyboard arrows (as in tab)
Software Programming • javascript jquery navigation accessibility tab • • Saumya

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I think the next code is intuitively clear and meets all the conditions:$('li').keydown(function(ev) { if (ev.keyCode === 9) { if (ev.shiftKey) { $(this).parent().prev().focus(); } else { ev.preventDefault(); $(this).parent().next().focus(); } } else if (ev.keyCode === 38) { ev.preventDefault(); if ($(this).is(':first-child')) { $(this).siblings(':last-child').focus(); } else { $(this).prev().focus(); } } else if (ev.keyCode === 40) { ev.preventDefault(); if ($(this).is(':last-child')) { $(this).siblings(':first-child').focus(); } else { $(this).next().focus(); } } }) .click(function() { $(this).focus(); }) .attr('tabindex', '-1').filter(':first-child').attr('tabindex', '0');li:focus, li:focus-visible, li:active { outline: 2px solid red; }<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script> <a href="#">useless link</a> <br> <a href="#">useless link</a> <br> <ul> <li>elem 1</li> <li>elem 2</li> <li>elem 3</li> <li>elem 4</li> </ul> <a href="#">useless link</a> <br> <a href="#">useless link</a> <br> <ul> <li>elem 1</li> <li>elem 2</li> </ul> <a href="#">useless link</a> <br> <a href="#">useless link</a> <br>If there are any questions on this code, please ask the comments below.
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How do you make a mistake, "Object is not iterable"?
Software Programming • javascript reactjs react hook • • derk

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If you create a context with a mass, the element index is important. In setting context Patients It's the third in the account, and when the context'scattered, you're trying to extract it from the first position.The context should either be sorted out:const [selectedPatient, setSelectedPatient, patients, patientsHasChanged] = useContext(PatientContext); or replace the mass in the context of the object: <PatientContext.Provider value={{selectedPatient, setSelectedPatient, patients, patientsHasChanged}}> <Sidebar /> <Content /> </PatientContext.Provider> (follow attention on the replacement of square brackets with figures). In the latter case, the arrangement of the variables at the spraying may be arbitrary:const {patients, setSelectedPatient} = useContext(PatientContext);
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Submit from varios forms with AJAX, one at a time
Software Programming • javascript php html ajax • • Cleofas

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The button will no longer send the form, in place jQuery will capture every time it is clicked. To do this, add the value in the button class bt_form<button class="btn btn-block btn-primary bt_form"> And now add the jQuery code below in place of saveAluno// Toda vez que algum button for clicado $('button.bt_form').on('click', function(event){ event.preventDefault(); // Cancela submit padrão do button // Faz a mesma coisa que saveAluno mas usa .closest para pegar o form do button var data1 = $(this).closest('form'); console.log(data1); $.post("controller/setters/addAlunoRotina.php", data1.serialize(), function (response) { alert("Salvo com sucesso!"); }); });
Matrix in JAVA
Software Programming • • Alberto

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In the consecutive reading of numerical values and String one must empty the keyboard buffer before reading the String value, for example:int n; String s; System.out.printf("Informe um Número Inteiro: "); n = ler.nextInt(); ler.nextLine(); // esvazia o buffer do teclado System.out.printf("Informe uma cadeia de caracteres:\n"); s = ler.nextLine();
C+++. Using "va_arg" a change-of-type error (possible to transform float into float)
Software Programming • c++ conversion • • Alberto

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Use it right! wins = va_arg(list, float); And you'll be able to... At least VC+++ is very clear and working. ♪ ♪UpdateOn the treatment of the fields... This is a real live code for VC++ 2015:#include <stdarg.h> #include <iostream> using namespace std; struct Test { float a,b,c; Test(float x):a(x),b(2x),c(xx){}; }; float Sum(int count, Test Args, ...) { float sum = Args.a; va_list list; va_start(list, Args); for(int i = 0; i < count-1; ++i) { sum += va_arg(list, Test).a; } va_end(list); return sum; } int main() { cout << Sum(3,Test(2.0),Test(4.0),Test(5.0)) << endl; } As you can see, different objects can be transferred.
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No React processor
Software Programming • javascript html reactjs • • kalyn

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First, we define the function: function onClick() {...}, then we call it onClick(). That is, for the beginning, the definition of the function and the challenge of the function was divided.The processor onClick (as any other) shall accept Definition responsibilities, he will call it in action: onClick={props.click} instead of onClick={props.click("items)}.But we need a function to make arguments, there are different ways to do it, the simplest thing to do is to challenge the function in the wind, that is, to defuse the function - definition: function onClick1() { return props.click("items)}; and then the definition of the function can be transmitted to the processor: onClick={onClick1}.The shooter function or is not relevant (if this is not used inside, but this is another story), for convenience, the challenge is dried directly into the processor: onClick=(() =state props.click("items)} (as the commentaries have written), there is nuance in the record, but the same is the way to accomplish the task.
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Chain several events in javascript?
Software Programming • javascript html ec languagemasc languager • • Rossere

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On the property buttons from a mouse event you can get if you are clicking on any button on it. (1 = left, 2 = right)paint(ev){ if (ev.buttons === 1) { /*El resultado de esto es que solo se ejecuta una vez cuando hago click Es como si ignorara el otro evento y no me imprimiera lo que necesito*/ //ev2 reemplazado a ev ya que ev2 ya no existe en el contexto actual console.log(ev); } }
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Matrix with Strings in C++
Software Programming • c++ string matrix • • Amritpal

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I think you know you have only 3 lines here[['3325309756482910474', 'CARRO', '2506794813021649539', '618.57'], ['3325309756485249504', 'MOTO', 2506794813021649539', '649.32'], ['3328687456208678517', 'BIKE', '2506794813021649539', '649.43']] and 4 in the excerpt that posted and that is a function in C, despite having used the C++ tagIn C++ use a class. It's simpler.autoauto in C has another meaning. It's not a type definition. In C++ auto does not apply to this context, as the compiler must have said.In C++ you can write string m[4][4] = { { "3325309756482910474", "CARRO", "2506794813021649539", "618.57"} , {"3325309756485249504", "MOTO", "2506794813021649539", "649.32" }, { "3328687456208678517", "BIKE", "2506794813021649539", "649.43" } }; If you prefer to declare "Matrix" you can even writeusing Matriz = string[4][4]; Like this example#include <iostream> using namespace std; using Matriz = string[4][4]; int main(void) { string m[4][4] = { { "3325309756482910474", "CARRO", "2506794813021649539", "618.57"} , {"3325309756485249504", "MOTO", "2506794813021649539", "649.32" }, { "3328687456208678517", "BIKE", "X506794813021649539", "649.43" } }; Matriz uma{}; uma[3][3] = m[2][2]; cout << "M[3][3] = "" << uma[3][3] << ""\n"; return 0; } Which shows the expectedM[3][3] = "X506794813021649539" Use a class and write the methods as you need them. Or even the operators for Matriz.
Convert object array to an array of arrays
Software Programming • javascript array • • Analeea

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Here’s a native JavaScript version, it’s pretty simple:var convertida = original.map(function(obj) { return Object.keys(obj).map(function(chave) { return obj[chave]; }); }); jsFiddle: https://jsfiddle.net/8k3o1v80/ The code has two .map(). The first is because you start with an array (of objects), and you want to keep an array with the same number of elements. The second .map() is to transform/map each object into an array. And you can do that by returning to that callback .map() the value of this key: obj[chave].
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How to generate a 3 column matrix where for each column there are 3 distinct possibilities?
Software Programming • java c sharp something • • meriah

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This problem is known as https://www.mathsisfun.com/combinatorics/combinations-permutations.html . I searched other sources and in Portuguese to explain the problem better, but unfortunately I only found garbage (excuse the term, but I am referring to websites that copy the badly formatted and poorly explained content from somewhere).As for the algorithm, usually this problem is solved more easily using a recursive algorithm. Each call should generate the combinations for one of the set positions.For example, given the set:int[] conjunto = {0, 0, 0}; And the position p that the current call should permute, we will set a routine:permutar(int[] set, int p)Remembering that the elements of conjunto has the values 0, 1 or 2 and p refers to the position of the vector therefore 0 <= p <= 2. Each time you are implementing recursiveness, you need to make clear what is the criterion for recursion. In this case, it could be something like:If p <= 2Permutation p+1Include conjunto[p]Repeat steps 1 and 2 while conjunto[p] < 3Clear conjunto[p] (attribut zero to future iterations) If p == 3Print conjunto and returns I know it's complicated, but the idea here is that the method permutar will generate combinations for a position p and call yourself recursively to generate the position p+1 and so on to the limit of conjunto. When the limit is reached, print the current content and return.The table test would be like this:C0 C1 C2 p 0 0 0 0 permutar(conjunto, p) 0 0 0 1 |_ permutar(conjunto, p + 1) 0 0 0 2 |_ permutar(conjunto, p + 1) 0 0 0 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 0 1 2 |_ Incrementar `conjunto[p]` 0 0 1 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 0 2 2 |_ Incrementar `conjunto[p]` 0 0 2 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 0 0 2 |_ Limpar `conjunto[p]` 0 1 0 1 |_ Incrementar `conjunto[p]` 0 1 0 2 |_ permutar(conjunto, p + 1) 0 1 0 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 1 1 2 |_ Incrementar `conjunto[p]` 0 1 1 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 1 2 2 |_ Incrementar `conjunto[p]` 0 1 2 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 1 0 2 |_ Limpar `conjunto[p]` 0 2 0 1 |_ Incrementar `conjunto[p]` 0 2 0 2 |_ permutar(conjunto, p + 1) 0 2 0 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 2 1 2 |_ Incrementar `conjunto[p]` 0 2 1 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 2 2 2 |_ Incrementar `conjunto[p]` 0 2 2 3 |_ permutar(conjunto, p + 1) 3 |_ imprime 0 2 0 2 |_ Limpar `conjunto[p]` 0 0 0 1 |_ Limpar `conjunto[p]` 1 0 0 0 |_ Incrementar `conjunto[p]` ... After the last line, this table repeats twice now with the first value 1 and then with the value 2. Note that the outermost version of permutar kept the value 0 in the first position while recursive calls were changing the other positions, generating all permutations with possible repetition.The Java algorithm for this is like this:public static void permutar(int[] conjunto, int p) { if (p == 3) { System.out.printf("{%d, %d, %d}%n", conjunto[0], conjunto[1], conjunto[2]); } else { do { permutar(conjunto, p + 1); conjunto[p]++; } while (conjunto[p] < 3); conjunto[p] = 0; } } And the call like this: public static void main(String[] args) { int[] conjunto = {0, 0, 0}; permutar(conjunto, 0); } Note that the algorithm does exactly what is described above, except that commands may be in a slightly different order.Although the ideal was for each developer to be able to solve the above problems without looking at alien code, unfortunately this does not work, mainly for those who are starting. If you are studying algorithms, my suggestion is to look at implementations as above and try to understand how it works. Then go back to your editor and try re-employing as you remember it. Even though seeing you will still likely lose some detail. Over time, after exercising enough you can be able to create the solution for this and other types of problem without consultation. But it is a utopia and it is not even correct to think that all developers can simply solve these challenges by themselves. This would be like telling math students that they need to derive all the formulas again rather than consulting a book.
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Change button when activating card hoover and making it diagonal?
Software Programming • html css • • authera

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You can do it the following way:You have a div that in turn serves as a link container a that will do the button timesWe apply to the div a display with the flex value to be able to manipulate the orientation and accommodation of its internal elements, in this case the buttonOf the border property we use: width, style and color to create the triangle figureThe content of the + sign and the x sign when it is hovered we get it with: the pseudo-element before and the key contentWe use the same pseudo-element again but this time to be able to access with the pseudo- when the user passes the cursor and again with contentAs the content generated by the pseudo-element was broken then I put it with absolute position and move it with bottom and left to stay inside your containerEJEMPLO <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width"> <title>JS Bin</title> <style> body { font-size: 1.5em; } div { width: 300px; height: 200px; background-color: tomato; display: flex; flex-direction: column; justify-content: flex-end; align-items: flex-end; border: 1px solid; } a { width: 0; height: 0; border-style: solid; border-width: 0 0 80px 80px; border-color: transparent transparent white transparent; } a::before { content: "+"; position: absolute; left: 280px; bottom: 195px; } a:hover::before { content: "x"; } </style> </head> <body> <div> <a href=""></a> </div> </body> </html> Visually this would be: Links of interest http://apps.eky.hk/css-triangle-generator/
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Create matrix from original matrix blocks (Python)
Software Programming • python matric languages • • rosemadder

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For everything to work as quickly as possible, yours would be to calculate everything with numpy operations, without using explicit loops.Depending on whether or not you want to remove the missing elements to make the dimensions a multiple of the BLOCK_SIZES, you can add zeros (np.pador remove the remaining elements (slicing).With a.reshape(r_, nrows, c_, ncols) the matrix can be converted into a set of submatrics. np.count_nonzero you can count how many elements are not zero. Axis 1 and 3 form submatrics. Turning the result into Bool converts every zero into False and the other numbers in True. Although not recommended, you can convert those into zeros and one with astype(np.int).Example code:import numpy as np def create_mask(a, nrows, ncols, pad_with_zeros=False): r, c = a.shape if pad_with_zeros: r_, c_ = int(np.ceil(r / nrows)), int(np.ceil(c / ncols)) a = np.pad(a, ((0, r - r_ * nrows), (0, c - c_ * ncols))) # añadir ceros para que cada submatriz sea igual else: r_, c_ = r // nrows, c // ncols a = a[:r_ * nrows, :c_ * ncols] # quitar los últimos elementos para que cada submatriz sea igual a = a.reshape(r_, nrows, c_, ncols) return np.count_nonzero(a, axis=(1,3)).astype(np.bool).astype(np.int) N = 8 cnt = 10 a = np.zeros((N, N), dtype=np.int) ind = np.random.randint(0, N-1, cnt*2).reshape(-1,2) a[ind[:,0], ind[:,1] ] = np.arange(1, cnt+1, dtype=np.int) print(a) print(create_mask(a, 2, 2)) Example of result:[[ 5 0 0 0 10 0 0 0] [ 9 0 0 2 0 6 0 0] [ 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0] [ 8 0 7 4 0 0 3 0] [ 0 0 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0]] [[1 1 1 0] [0 0 0 0] [1 1 0 1] [0 0 0 0]] To calculate directly matrix B, the code would be a little different:import numpy as np def comprime_matrix(a, nrows, ncols, pad_with_zeros=False): r, c = a.shape if pad_with_zeros: r_, c_ = int(np.ceil(r / nrows)), int(np.ceil(c / ncols)) a = np.pad(a, ((0, r - r_ * nrows), (0, c - c_ * ncols))) # añadir ceros para que cada submatriz sea igual else: r_, c_ = r // nrows, c // ncols a = a[:r_ * nrows, :c_ * ncols] # quitar los últimos elementos para que cada submatriz sea igual a = np.vstack(np.swapaxes(a.reshape(r_, nrows, c_, ncols), 1, 2)) return a[np.count_nonzero(a, axis=(1, 2)).astype(np.bool)].swapaxes(0, 1).reshape(2, -1) N = 8 cnt = 10 a = np.zeros((N, N), dtype=np.int) ind = np.random.randint(0, N-1, cnt*2).reshape(-1,2) a[ind[:,0], ind[:,1] ] = np.arange(1, cnt+1, dtype=np.int) print(a) print(comprime_matrix(a, 2, 2)) Example of result:[[ 0 0 0 10 0 0 0 0] [ 2 0 0 0 0 1 0 0] [ 4 0 0 0 3 0 7 0] [ 0 0 0 0 8 0 0 0] [ 0 0 0 0 0 0 9 0] [ 0 0 0 0 0 0 0 0] [ 0 6 0 0 0 0 0 0] [ 0 0 0 0 0 0 0 0]] [[ 0 0 0 10 0 0 4 0 3 0 7 0 9 0 0 6] [ 2 0 0 0 0 1 0 0 8 0 0 0 0 0 0 0]]

Is it possible to have a characteristic transformed not in the matrix?

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