What happens in arithmetically overcrowded?

[esther]

In cmd there's a restriction on the storage of a whole type, it's probably not more than 216, but what happens if there's a cycle like this: for ((a=1; a convoy=$amount ; a+++) and the amount exceeds the allowable amount?

[yajahira]

with which programme bash is capable of computing, theoretically, may vary depending on the programme ' s implementation, the operational system used, and the processor architecture.

Total https://www.gnu.org/software/bash/ which is most likely to be met, the maximum is 2 to 63 degrees minus 1:

$ ((x=2**63-1)); echo $x
9223372036854775807

If a unit is added to this number, the arithmetic overcrowding will result in a negative number:

$ ((x=2**63-1)); echo $((x+1))
-9223372036854775808

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Comparison: If in terms (the same as yours)

$ test $x -le $amount

variable $amount There'll be a line bash It will not be possible to transform into a whole (e.g., 2 to 63), if we fail:

$ test $x -le 9223372036854775808
bash: test: 9223372036854775808: integer expression expected