# I'm confused with a++ line.

• Hello, everyone!

I have a program that removes the amount of the cypher in it.

Let's get a line. `"qwrtt56hhbb055ghjj"`♪ Accordingly, the programme withdraws `"5 цифр"`

How do I find their money now? You mean 5+6+0+5+5?

• I think it's easier to use normal cycles here.

This is a demonstration programme that shows two approaches, depending on where the line is stored.

``````#include <iostream>
#include <string>
int main()
{
{
const char *s = "qwrtt56hhbb055ghjj";
unsigned int sum = 0;
for ( const char *t = s; *t; ++t )
{
if ( *t &gt;= '0' &amp;&amp; *t &lt;= '9' ) sum += *t - '0';
}

std::cout &lt;&lt;  "sum = " &lt;&lt; sum &lt;&lt; std::endl;

}
{
std::string s( "qwrtt56hhbb055ghjj" );
unsigned sum = 0;

for ( char c : s )
{
if ( c &gt;= '0' &amp;&amp; c &lt;= '9' ) sum += c - '0';
}

std::cout &lt;&lt;  "sum = " &lt;&lt; sum &lt;&lt; std::endl;

}
return 0;

}
``````

In both cases, the consolation will be

``````sum = 21
sum = 21
``````

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