how to remove the element from the multiplicity
There are many.
b = [3,4,5] a = set(b)
When I'm trying to find a lot of equals to this, but without any element,
с = a.remove(3) c = None
Why so, how do you do that?
removeremoves the element from multiplicity and does not return many without the removed element
b = [3,4,5] a = set(b) a.remove(3) a set([4, 5])