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python code with telebot library ignores bot.polling

briley last edited by
After the code is launched, there are two prints and no mistakes, but the second print should have stopped, because the code was supposed to stop. bot.polling(none_stop=True, interval=0)♪
The token is right, the telebot(3.0.0) library has been installed, the interval has also been altered, the tokens are directly transferred, and the botts have been launched through the console.
Here's the code:
```
import telebot
import config
bot = telebot.TeleBot(config.TOKEN)

print(bot.get_me())
@bot.message_handler(content_types=['text'])

def lalala (massage):

bot.send_message(massage.chat.id, massage.text)
bot.polling(none_stop=True, interval=0)

print('out')
```
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1 Reply Last reply
G
guilherme last edited by
bot.polling(none_stop=True) should be recorded in the cycle while
```
while True:
    try:
        bot.polling(none_stop=True)    
    except Exception as e:
        time.sleep(15)
```
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I didn't quite understand the question, but it wouldn't be easier to write a random prefix team first. '/' and, for example, fully: '/give' then process any user text through a text-processing processor, how to process? First, check the text that begins at '/give' I mean: if message.text.startswith('/give') Then the next check, which will break the entire user ' s text in three parts through the gap, that is, the team, then the user who should be given a certain amount, after the sum itself and the case, simply through 'split(' ')'If the text is broken through the stove, there will be no error that can be processed as, whether the user has decided to balance the team with no arguments, or to do any action if the stove errors are not detected, then it is possible to write a user-check in which some amount is to be given, and even further, you can limit yourself to fantasy.
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Main points:set for storage of solutions Gives uniqueness to the box, now you don't have to check. not in xdivmod Instead of two cases, the amounts are now counted once.Extreme case (all one site) merged with the rest of the decision if i else (0, 0)def solve(a, n): variants = set(); for i in range(n): left, right = a[:i], a[i:] l_avg, l_rem = divmod(sum(left), i) if i else (0, 0) r_avg, r_rem = divmod(sum(right), n - i) if l_rem == r_rem == 0: variants.add(','.join([str(l_avg)] * i + [str(r_avg)] * (n-i))) return len(variants) Micro-optimizations, such as running sums, may be added, but it is unclear what criteria the code should be " improved " :def solve(a, n): variants = set(); l_sum, r_sum = 0, sum(a) for i in range(n): l_avg, l_rem = divmod(l_sum, i) if i else (0, 0) r_avg, r_rem = divmod(r_sum, n - i) if l_rem == r_rem == 0: # variants.add(','.join([str(l_avg)] * i + [str(r_avg)] * (n-i))) variants.add(f'{i}, {l_avg}, {r_avg}' if i and l_avg != r_avg else r_avg) l_sum += a[i] r_sum -= a[i] return len(variants) a = [10, 4, 2, 7, 5, 8, 6, 6, 15] assert solve(a, len(a)) == 3 a = [3, 5, 2, 7, 6, 4, 5, 8, 1, 7] assert solve(a, len(a)) == 3
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Having a ready algorithm for type conversions next_permutationit's hard to get a combination.Create a mass of length ncontaining n-k zero and k units.Let's get the alternation generator on it.For each reversal, use those elements from your original set of indices on which units are located. In your case, the elements of the mass are just a number. 1 before n, so when we're processing, i- where is the unit, record the number. i+1♪So reset [0,1,1,0] corresponds to the combination [2,3]EditLike Stanislav Volodarskiy, itertools.js The converter's generator is using the reset of the indices, so it's not going to be optimistic on an unmarked set.This is the code for the next in the lexicographic order of conversion based on the comparisons of the elements themselves, https://www.nayuki.io/page/next-lexicographical-permutation-algorithm (There's another version of the comparator.) However, the generating code has already been given directly, so the diagram is useful only in the context of general education./* * Next lexicographical permutation algorithm (JavaScript) * by Project Nayuki, 2018. Public domain. * https://www.nayuki.io/page/next-lexicographical-permutation-algorithm */ "use strict"; /* Basic version / / Computes the next lexicographical permutation of the specified array of numbers in place, returning whether a next permutation existed. (Returns false when the argument is already the last possible permutation.) */ function nextPermutation(array) { // Find non-increasing suffix var i = array.length - 1; while (i > 0 && array[i - 1] >= array[i]) i--; if (i <= 0) return false; // Find successor to pivot var j = array.length - 1; while (array[j] <= array[i - 1]) j--; var temp = array[i - 1]; array[i - 1] = array[j]; array[j] = temp; // Reverse suffix j = array.length - 1; while (i < j) { temp = array[i]; array[i] = array[j]; array[j] = temp; i++; j--; } return true; }
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Read Nikolai Anatolyevich Prohorenok - Python 3 and PyQt It's well educated to create an interface, round, transparency, etc.If you lie down, that's the answer. It's a simple way to make a rounded tkinter button use a picture.First, create an image that you want the button to look like keeping it as.png and removing the external background so that it rounds up, as shown below:https://i.stack.imgur.com/gPdrY.png Then insert the picture with the photoImage button as follows:self.loadimage = tk.PhotoImage(file="rounded_button.png") self.roundedbutton = tk.Button(self, image=self.loadimage) self.roundedbutton["bg"] = "white" self.roundedbutton["border"] = "0" self.roundedbutton.pack(side="top") Make sure the border=0 is used and the button frame is removed.I added. self.roundedborder["bg"] = "white" I want the button to be the same as the Tkinter window.Most of it is that you can use any figure you like, not just the usual shapes of the button.
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import sys # Las variables se escriben con minusculas y una barra baja donde debería haber un espacio # Agrega ': ' para mayor legibilidad # Encierra las conversiones de int() en un try-except de ValueError # ValueError salta cuando algo no se puede convertir a un entero de base 10 # Recoge la excepción y muestra un mensaje. # La funcion input() recibe un string opcionalmente, que se imprime por pantalla # al pregunta, no te hace falta usar print try: numero_1= int(input("Digame un numero: ")) except ValueError: print('Eso no es un numero!') sys.exit() try: numero_2= int(input("Digame otro numero: ")) except ValueError: print('Eso no es un numero!') sys.exit() # No ejecutes las operaciones antes de preguntarle al usuario, porque da igual que opcion # elija, tu programa ya tendria hecho las 4 de antemano, lo cual no es eficiente. # Agregado saltos de linea para un mensaje mas visual print ("Dime que operacion hago:\n1) --> sumar\m2) --> multiplicar\n3) --> restar\n4) --> dividir") # Agregado texto para ser mas visual y try-except try: operador= int(input('Opcion: ')) except ValueError: print('Eso no es un numero!') sys.exit() # Siempre usa if-elif-else. Esta estructura permite que, cuando python encuentra una # condición cierta, ejecuta el código que tiene debajo y luego deja de evaluar el resto # de la estructura if-elif-else. Si colocas siempre if, aunque el primero coincida, los # otros tres se evaluarán igualmente. if operador == 1: print('{} + {} = {}'.format(numero1, numero2, numero_1 + numero_2)) elif operador == 2: print('{} - {} = {}'.format(numero1, numero2, numero_1 - numero_2)) elif operador == 3: print('{} * {} = {}'.format(numero1, numero2, numero_1 * numero_2)) elif operador == 4: print('{} / {} = {}'.format(numero1, numero2, numero_1 / numero_2)) # Añade el else para cualquier opcion no definida. else: print('Operacion inválida!') P.DNext time you go up code, get in. https://stackoverflow.com/help/minimal-reproducible-example Useful references https://www.w3schools.com/python/python_conditions.asp https://www.w3schools.com/python/python_try_except.asp
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d = "2021-01-29 21:55:21.165643" date1 = datetime.strptime(d, "%Y-%m-%d %H:%M:%S.%f") date2 = datetime.now() delta = date2 - date1 print(delta.total_seconds() // 60)
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It's not a code for Piton, you're probably at C/C++/Java/PHP, ...Pitton's more simple. You must have wanted:Russ_sum = ("а","б","в","г","д","е","ё","ж","з","и","й","к","л","м","н","о","п","р","с","т","у","ф","х","ц","ч","ш","щ","ъ","ы","ь","э","ю","я") Code_sum = ("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z","a+","b+","c+","d+","e+","f+","g+") a = input() b = [] for i in a: # не надо индексов - i просто текущий символ из а j = Russ_sum.index(i) # индекс текущего символа в таблице Russ_sum b.append(Code_sum[j]) result = "".join(b) # строка из списка print(result) Example of entry:собака Conclusion:spbala
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If the adapter as expected follows the specifications https://www.python.org/dev/peps/pep-0249/ , Cursor to implement the known as iterating protocol, which means that you return the query rows one by one until they are exhausted, in each iteration generates us and returns a new tupla with the content of the next row until there is no one left, when it generates an error StopIteration.This has a very logical reasoning, iters/generators are in lazy essence, they don't generate anything before they are asked. In theory, a good implementation of a database adapter should obtain batch rows from the server, do not get the entire query at once with the consequent memory consumption by keeping the entire set of results stored simultaneously. This would be ideal, but the truth is that it depends on the adapter and database, there are cases in which the query is stored entirely on the client (whether using Python or C containers), where it is stored on the server... This does not really matter to us for what concerns us, what we need to be clear is that when it was about a cursor either by means of a for in, fethone, fetchall or any other method that implies iterar about it (p.e list(cursor)) this is "consuming." Your problem is actually due to the "innocent" print surely for the purpose of purification:print([str(x[0]) for x in cursorUsuario]) where you are about the full cursor to generate a list that you print and leave at the mercy of the garbage collector. When you go back to iterar in:self.dlg.comboLote.addItems([str(x[0]) for x in cursorUsuario]) the cursor has nothing to return because it was consumed in the previous for. We can emulate it with:>>> cursor = iter((("a", ), ("b", ), ("c", ), ("d", ))) >>> print([row[0] for row in cursor]) ['a', 'b', 'c', 'd'] >>> [row[0] for row in cursor] # Genera una lista vacía [] If you take that off print Everything will be fine. QComboBox.addItems accept any iterable while it contains chains, so you can simply do: self.dlg.comboLote.addItems(str(x[0]) for x in cursorUsuario) If you really need a list, itera on the cursor once and assign the list to a variable, for example:ls = [row[0] for row in cursorUsuario] print(ls) self.dlg.comboLote.addItems(ls) As you point aside, you should not use the reverse diagonal bar on the routes without escape. The reason is that </code> is used to determine escape sequences, so in "C:\fichero\registro" \r It's taken as a car return... Use the tilted bar / or you can normalize it with https://docs.python.org/3/library/os.path.html#os.path.normpath .
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By using "dataclass", you can write a program more concise than "data". because the class definition is shortened. This makes it easy to understand the structure of data.
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This error:SyntaxError: Non-UTF-8 code starting with 'xd0' in file C:/Users/Moto-Moto/Desktop/BotRemake/mainBot.py on line 131, but no encoding declared; see http://python.org/dev/peps/pep-0263/ for detailsMeaning that you have a file not in the utf-8 code, but in some other one (most in cp1251).Options for action:Remove the file in the utf-8 codeor add a line at the beginning of the file indicating the code as described in https://www.python.org/dev/peps/pep-0263/ (type line # -*- coding: cp1251 -*-)Python 3 default considers that the file is stored in utf-8 code, so if it is retained in utf-8, it is not necessary to specify further at the beginning of the file:Python supports writing source code in UTF-8 by default, but you can use almost any encoding if you declare the encoding being used.♪ ♪ ♪If you don’t include such a comment, the default encoding used will be UTF-8 as already mentioned.Source: https://docs.python.org/3/howto/unicode.html#unicode-literals-in-python-source-code
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How to allow only the creation of valid objects in Python?
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As Jefferson commented on the question, you can throw an exception when the set number is invalid, in this case, less than zero. The exception will divert the flow of the program, delegating the treatment logic of error for a top layer, the program that creates the instance of the class.class Linha(object): def __init__(self, x, y): self.x = x self.y = y @property def x(self): return self._x @x.setter def x(self, valor): if valor >= 0: self._x = valor else: raise ValueError("The x value must be a non-negative number") @property def y(self): return self._y @y.setter def y(self, valor): if valor >= 0: self._y = valor else: raise ValueError("The y value must be a non-negative number") Another detail that is possibly valid to do in this situation, since within the methods you compare the value with an entire number, is to ensure that this comparison is possible to make sure that the value is also numerical. I mean, if I did obj.x = 'a', would make a mistake saying that the operator >= does not support a comparison between a string and an integer. This is a terrible error message to deliver to your client (who uses the class). To circumvent this, you can convert the input value to whole (or float), before comparing:class Linha(object): def __init__(self, x, y): self.x = x self.y = y @property def x(self): return self._x @x.setter def x(self, valor): valor_inteiro = int(valor) if valor_inteiro >= 0: self._x = valor_inteiro else: raise ValueError("The x value must be a non-negative number") @property def y(self): return self._y @y.setter def y(self, valor): valor_inteiro = int(valor) if valor_inteiro >= 0: self._y = valor_inteiro else: raise ValueError("The y value must be a non-negative number") So if I try to create the instance Linha('a', 0), the error message will be:ValueError: literal invalid for int() with base 10: 'a'Which is much clearer than what is wrong in the code and even makes the method always throw the same exception, ValueError, in both possible cases, which facilitates treatment in the upper layer.try: x = input("Valor de x:") y = input("Valor de y:") linha = Linha(x, y) except ValueError as error: print(error)

python code with telebot library ignores bot.polling

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