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Compendium of words for study

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esther last edited by
Started to study programming, set up a challenge to write a program on Pitton that would help me learn the English words of programming. The concept is simple.
1. To create a record book that I'll make and translate. I think we should use tkinter.
2. Maintain the database or file.
3. The programme should give an accidental word from the base and several versions of the verification response correctly or not.
Maybe who's faced this code with commentaries.
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Oba22 last edited by

tkinter is suitable for an interface in five minutes if you want a really good and more functional interface, then a pyqt with his designer. Pyqt's gonna make it easy to work with bases and, uh, logic is easier to write. Pyqt needs to know classes, dictionaries, lists, functions. Pyqt will spend more time studying tkinter, but it's worth it.
In order to begin the study, I suggest that the following resources be looked at: https://pythonworld.ru/gui/pyqt5-firstprograms.html https://tproger.ru/translations/python-gui-pyqt/ Well, different videos from the utubus.
I highly advise not to copy the code, but to fully study the subject.
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Your STATICFILES_STORAGE configuration is responsible for duplicating the files. Try to comment and try using collectstatic again. Commenting on it will use default values.[ 'django.contrib.staticfiles.finders.FileSystemFinder', 'django.contrib.staticfiles.finders.AppDirectoriesFinder', ]
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Normally, the save button is only enabled after some change in the document is performed by Word itself (without automation). For Word to understand that the document can be saved, use Saved property, as in example: var Word, Doc: OleVariant; begin Word := CreateOleObject('Word.Application'); Doc := Word.Documents.Add; ... //outros comandos Doc.Saved := False; end;
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It's all done through the control panel itself.
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Addition of its view in QMdiArea and extension of the window
Software Programming • python pyqt5 gui pyqt qmdiarea • • nishika

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It works exactly the same way. This is an example:import sys from PyQt5.QtCore import * from PyQt5.QtGui import * from PyQt5.QtWidgets import * class Forma(QWidget): # Есть свой виджет(Forma()) def init(self): super().init() self.button1 = QPushButton('Forma: Show button1...', self) # в ней пару кнопочек в layoute self.button2 = QPushButton('Forma: Show button2...', self) # в ней пару кнопочек в layoute self.grid = QGridLayout(self) self.grid.addWidget(self.button1, 0, 0) self.grid.addWidget(self.button2, 1, 0) class MainWindow(QMainWindow): count = 0 def init(self, parent=None): super(MainWindow, self).init(parent) self.mdi = QMdiArea() self.setCentralWidget(self.mdi) bar = self.menuBar() file = bar.addMenu("File") file.addAction("New") file.addAction("cascade") file.addAction("Tiled") file.triggered[QAction].connect(self.windowaction) self.setWindowTitle("MDI demo") sub = QMdiSubWindow() sub.setAttribute(Qt.WA_DeleteOnClose) sub.setWidget(QPushButton('Show')) sub.setWindowTitle("PushButton "+str(MainWindow.count)) self.mdi.addSubWindow(sub) sub.show() def windowaction(self, q): print("triggered-> q ->", q.text()) if q.text() == "New": MainWindow.count = MainWindow.count+1 sub = QMdiSubWindow() sub.setAttribute(Qt.WA_DeleteOnClose) sub.setWidget(Forma()) # <------- sub.setWindowTitle("subwindow"+str(MainWindow.count)) self.mdi.addSubWindow(sub) sub.show() if q.text() == "cascade": self.mdi.cascadeSubWindows() if q.text() == "Tiled": self.mdi.tileSubWindows() if name == 'main': app = QApplication(sys.argv) ex = MainWindow() ex.show() sys.exit(app.exec_())
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In Java, you can't compare. ==that is, in this case, you compare the references to the objects, not the strings themselves. Replace. showInfo == "Show information" ♪ showInfo.equals("Show information")♪
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Software Programming • python c++ makefile swig • • simrah

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Got a more and less working solution with Python.h. I don't know how literate this is, if anyone's dealing with it, please.The first file describes the PyObject class, the function or object Python.cregister.cpp#include <python3.4/Python.h> #include <stdlib.h> /***********************************************/ /* 1) code to route events to Python object */ /* note that we could run strings here instead */ /***********************************************/ class Caller{ private: PyObject* Route_Event(int count) { PyObject *args, pres; / call Python handler / args = Py_BuildValue("(i)", count); / make arg-list / pres = PyEval_CallObject(Handler, args); / apply: run a call */ return pres; } public: PyObject Handler; / keep Python object in C / Caller() { Handler = NULL; / keep Python object in C */ } // /* 2) python extension module to register handlers / / python imports this module to set handler objects */ // void setHandler(PyObject arg) { / save Python callable object / Handler = arg; //Py_XDECREF(Handler); / called before? / //PyArg_Parse(arg, "(O)", &Handler); / one argument / //Py_XINCREF(Handler); / add a reference / } void triggerEvent(int arg) { / let Python simulate event caught by C */ Route_Event(arg); } }; Second file is the swig interface:cregister.i%module cregister %{ #include "cregister.cpp" %} %include cregister.cpp makefile to gather all this:makefilePYLIB = /usr/local/bin PYINC = /usr/include/python3.4 CMODS = _cregister.so CFLAGS = -O3 -fopenmp all: $(CMODS) cregister.py обертка + действительный класс $(CMODS): cregister_wrap.o cregister.o g++ $(CFLAGS) -shared cregister_wrap.o cregister.o -L $(PYLIB) -o $@ генерирует модуль обертки класса cregister_wrap.o: cregister_wrap.cxx g++ $(CFLAGS) cregister_wrap.cxx -c -g -fPIC -I $(PYINC) cregister_wrap.cxx: cregister.i swig -c++ -python cregister.i cregister.py: cregister.i swig -c++ -python cregister.i программный код обертки класса C++ cregister.o: g++ $(CFLAGS) ../wavenet/cregister.cpp -c -g -fPIC -Wno-deprecated clean: rm -f *.pyc *.o *.so *.cxx cregister.py And finally, an illustration of Python3:creg.py#! /usr/bin/python3 """ ######################################################################### in Python, register for and handle event callbacks from the C language; compile and link the C code, and launch this with 'python3 creg.py' ♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪♪ ""#################################### C calls these Python functions; handle an event, return a result #################################### class Caller(object): def init(self, str): self.str=str def call(self, count): print(self.str.format(count)) ####################################### Python calls a C extension module to register handlers, trigger events ####################################### import sys sys.path.append('you_bin_path/') import cregister cal = Caller("Helllo{0}") cb = cregister.Caller() print('\nTest1:') cb.setHandler(cal) # register callback function for num in range(1, 10): res = cb.triggerEvent(num) # simulate events caught by C layer
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Suggestion of code improvement, for opening varios csv files in different directories
Software Programming • python pandas csv data sc languageienc lang • • guilherme

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Hello, welcome to Stack Overflow. I don't know if I've been able to understand your problem well, but I still have a solution:import os import pandas as pd def getListOfFiles(dirName): listOfFile = os.listdir(dirName) allFiles = list() for entry in listOfFile: fullPath = os.path.join(dirName, entry) if os.path.isdir(fullPath): allFiles = allFiles + getListOfFiles(fullPath) else: allFiles.append(fullPath) return allFiles diretorio = r"C:\seu\diretório\base\nesta\variável" files = getListOfFiles(diretorio) df = pd.DataFrame() for key, file in enumerate(files): if file.endswith(".csv"): df_x = pd.read(file, sep=";") df_x['workcenter'] = key df.append(df_x) What this solution does is: The function reads all folders and subfolders in a directory and filters only the files, bringing them in a list.Take each file from the returned list and, if the file ends with the extension .csv, it reads and saves on a temporary dataframe df_x. In the end, it simply adds this temporary dataframe to a final dataframe df.I don't know if it's clear the solution, nor does it meet your expectations. In case negative, comment here and we will evaluate until we get the best solution for you.
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What you should do is every time the person writes to make a call to an endpoint that returns a json with the information of the sorcerers, then with jquery to clean the div where you keep the information and generate the new information of the sorcerers.
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In regular expressions, there are special "non-conscious" checks for such cases.(?<!-)слово(?!-)
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No https://docs.python.org/3/library/stdtypes.html#str.format , you should use < to align to the left:for x in range(1, 11): print('{0:<2d} {1:<3d} {2:<4d} {3:<6d}'.format(x, x**2, x**3, x**4)) Output:1 1 1 1 2 4 8 16 3 9 27 81 4 16 64 256 5 25 125 625 6 36 216 1296 7 49 343 2401 8 64 512 4096 9 81 729 6561 10 100 1000 10000 More details about the formats can be seen in https://docs.python.org/3/library/string.html#formatspec .In fact, the same documentation quotes that - is used to indicate that the signal should only be shown if the number is negative (and as all the numbers of your code are positive, this does not affect at all the output, and it uses the default alignment, which for numbers is right).This is different from the operator %, what https://docs.python.org/3/library/stdtypes.html#printf-style-string-formatting use the hyphen to align to the left.From Python 3.6 you can use https://docs.python.org/3/reference/lexical_analysis.html#f-strings , which also uses the < to align to the left:for x in range(1, 11): print(f'{x:<2d} {x ** 2:<3d} {x ** 3:<4d} {x ** 4:<6d}')
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How do you compare words?
Software Programming • java • • rielyn

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Instead of a method equals We need to use it. equalsIgnoreCase
a word that is part of a string
Software Programming • python • • emmalee

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replaceregex=TrueIf you add a regular expression search, you can replace it if partial match.The number 1 of the sample code is displayed.You can also replace the partial match with str.replace. (Part 2)I think that it can be removed from the contents of this question, but the code that replaces the entire part is also described in the sample code. (Part 3,4)import pandas as pd # pandas import numpy as np df = pd.DataFrame( {'x': ['カレーライス', 'ピラフ; チャーハン', 'チャーハン', 'ハンバーグ; 餃子', '餃子', 'そば; 玉丼', 'うどん']}) words = ["チャーハン","餃子"] for w in words: # 1.正規表現で一致箇所を置換 df["x"]=df["x"].replace(w, "その他", regex=True) # 2.strで一致箇所を置換 #df["x"]=df["x"].str.replace(w, "その他") # 3.正規表現で一括置換 #df["x"]=df["x"].replace("^.{}.$".format(w), "その他", regex=True) # 4.strで一括置換 #df.loc[df["x"].str.contains(w), "x"] = "その他" print(df) Result of Section 1,2 x 0 カレーライス 1 ピラフ; その他 2 その他 3 ハンバーグ; その他 4 その他 5 そば; 玉丼 6 うどん Result of Section 3,4 x 0 カレーライス 1 その他 2 その他 3 その他 4 その他 5 そば; 玉丼 6 うどん
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How do you start studying programming?
Software Programming • c++ c language • • kalyn

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From the books, it's called Datales, "How to program on C," "How to program on C+++."But first of all, there's a compiler and a tool for editing the original code, and it's even better than complete. http://ru.wikipedia.org/wiki/%D0%98%D0%BD%D1%82%D0%B5%D0%B3%D1%80%D0%B8%D1%80%D0%BE%D0%B2%D0%B0%D0%BD%D0%BD%D0%B0%D1%8F_%D1%81%D1%80%D0%B5%D0%B4%D0%B0_%D1%80%D0%B0%D0%B7%D1%80%D0%B0%D0%B1%D0%BE%D1%82%D0%BA%D0%B8 ♪Windows is good. http://www.microsoft.com/express/Downloads/ ♪ You'll pick a S+++, English is better.Good luck =
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How do I find a specific paragraph with repeated words and a key word in between?
Software Programming • javascript regex • • terrea

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I could tell you that with /<Task>[^<]*(?:<(?!(?:\/Task|nme)>)[^<]*)*<nme>Comandos<\/nme>[^<]*(?:<(?!\/Task>)[^<]*)*<\/Task>/gi You'd fix it, but it's completely ridiculous to use regex to process an XML. Think well, you're running JavaScript code into a browser, an application specifically designed to process XML documents like HTML, but don't you want to process it as if it were text?!?!?!?! Ridiculous, right? In addition, there are many ways in which a small modification in the XML would fail (you can read many of the answers on the site saying why you don't use regex).It's very simple to do it the right way. I show you a way.Using https://developer.mozilla.org/en-US/docs/Web/API/DOMParser you can patch an XML, transforming it into an XMLDocument (which inherits methods of Document). And that allows you to use the same selectors as if you were taking an element of the website.//el string con un XML de la pregunta const elStringDelXML = ` <Task> <nme>Hola mundo</nme> <label>ffff</label> .(más codigo) . </Task> <Task> <nme>aaaa</nme> <label>bien</label> .(más codigo) . </Task> <Task> <nme>Comandos</nme> <label>bien</label> .(más codigo) . </Task> <Task> <nme>Abrir puerta</nme> <label>aaaa</label> .(más codigo) . </Task>`; //El XML de la pregunta es inválido porque no tiene un elemento raíz //todos los XML tienen que tener un tag (con cualquier nombre) que //englobe a todo el documento. Lo llamo <Raiz> por ejemplo let xmlCorregido = <Raiz>${ elStringDelXML }</Raiz>; //DOMParser.parseFromString() genera un documento desde un string //devuelve un documento, que es el que después usamos para todo let parser = new DOMParser(), doc = parser.parseFromString(xmlCorregido, 'application/xml'); //Y ahora usamos selectores como con cualquier documento HTML... //Cada uno de los <Task> for (let task of doc.querySelectorAll('\Task')) { //El primer <nme> let nme = task.querySelector('\nme'); if (nme.innerHTML == 'Comandos') { //Si es <nme>Comandos</nme> //obtener todo el <Task> como texto let textoDelTask = task.outerHTML; console.log(textoDelTask); } }
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Hello. Danas are two symbols. One of them is a line and one word. Can't figure out how many words are in the line?
Software Programming • c++ • • Raziyah00

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unsigned wcount(const char* arr, const char* word) { const char* first = strstr(arr, word); unsigned count = 0, ws = strlen(word); while (first) { ++count; // пропускаем слово, чтобы искать в остальной части first += ws; first = strstr(first, word); } return count; }

Compendium of words for study

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