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build a sin(x)^sgn(sin(100x) graph on the [-10:10] step 0.1

guilherme

I know the task is childish, but I don't know what a mistake is.

    x=-10:0.1:10;
y=sin(x)^sgn(sin(100*x))
plot(x,y)
title('График функции cos(3x)')
xlabel('Ось X')
ylabel('Ось Y')
legend('y=cos(3x)')
grid on

M
meriah last edited by
The second line shall be:
```
y=sin(x).^sign(sin(100*x)) 
```
First of all, not sgn♪ signAnd second, not ^♪ .^♪ Without a point of view, this is the operation of the matrix to the degree through the matrix. There's got to be a real build. sin(x) to the extent required by the mass sign(sin(100*x))and therefore the use of a swap operation should be used to a degree .^♪
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Basically, the copy/conversion code between the arrays would be more or less like this:for( i = 0; i < N - 1; i++ ) for( j = 0; j < N - 1; j++ ) comp[i][j] = mat[i+1][j+1]; Follow your modified code with the problem solution:#include <stdio.h> #include <stdlib.h> #define N (3) int main( void ) { int i,j; int mat[N][N]; int comp[N-1][N-1]; /* Preenche matriz 3x3 */ for( i = 0; i < N; i++ ) { for( j = 0; j < N; j++ ) { printf("Entre com o Valor [%d][%d]: ", i + 1, j + 1 ); scanf("%d", &mat[i][j] ); } } /* Copia conteudo das matrizes ignorando a primeira linha e coluna */ for( i = 0; i < N - 1; i++ ) for( j = 0; j < N - 1; j++ ) comp[i][j] = mat[i+1][j+1]; /* Exibe matriz 3x3 */ printf("\nMatriz 3 X 3:\n"); for( i = 0; i < N; i++ ) { for( j = 0; j < N; j++ ) printf("%d ", mat[i][j] ); printf("\n"); } /* Exibe matriz 2x2 */ printf("\nMatriz 2 X 2:\n"); for( i = 0; i < N - 1; i++ ) { for( j = 0; j < N - 1; j++ ) printf("%d ",comp[i][j]); printf("\n"); } return 0; } Testing:Entre com o Valor [1][1]: 1 Entre com o Valor [1][2]: 2 Entre com o Valor [1][3]: 3 Entre com o Valor [2][1]: 4 Entre com o Valor [2][2]: 5 Entre com o Valor [2][3]: 6 Entre com o Valor [3][1]: 7 Entre com o Valor [3][2]: 8 Entre com o Valor [3][3]: 9 Matriz 3 X 3: 1 2 3 4 5 6 7 8 9 Matriz 2 X 2: 5 6 8 9 See working on https://ideone.com/WFAMN1
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It's a different number because address The variable is intact. In the 32-design system, it's gonna look like, 0x124a53b0Inside, logical variables are 0 and 1, which you see in the first case.
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If you want to make the theoretical chart just continue the same way you started, asking for the values and showing the figure for one and another case. You can show the result in the same figure or separate figures. I recommend using a time t dependent on the value of Tau. A condenser carries/discharges fully in 5*Tau, so the next code shows figures always adjusted to the value of Tau.C = input ('Digite o valor do condensador (em uF): ') R = input ('Digite o valor da resistencia (em Ohms): ') E = input ('Digite o valor da fonte de tensao (em V): ') C = 10^-6 Tau = R * C; t = linspace (0,5Tau,100); %100 amostras de 0 a 5Tau segundos figure (1) hold on % carga do capacitor plot (t,E*(1-exp(-t/(R*C))),'b-') % descarga do capacitor %figure (2) %para graficos separados descomente essa linha plot (t,E*(exp(-t/(R*C))),'r-')
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Fastcgi_split_path_info (/.+) Is it necessary?What should I do after *.php?fastcgi_split_path_info ^/monitor/(.+\.php)(.*)$; fastcgi_param SCRIPT_FILENAME /usr/share/cacti/site/$fastcgi_script_name;
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Good day!I understand correctly that you need to just connect to the C# project? If so, just under Matlab, scoop the DL with this code and use it. Engage the newly created DLL, and further create a function. Here. https://habrahabr.ru/post/132487/ ♪

build a sin(x)^sgn(sin(100x) graph on the [-10:10] step 0.1

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