Python

[authera]

I'm studying the subject with the decorators, there's a mission. Condition: Announcing a function with a name get_sq, which calculates the area of a rectangle in two. Parameters: width and height - width and height of rectangle and return the result. Determine the decorator for this function with the name (external function) func_show, which displays the results on the screen in the form of a row (without skirt): _ Call for a decorated function get_sq.

I've set up a code, like it's working, but I'm not sure it's right, because the cycle will cross all arguments, not just two: width and height. I'd like to know how the two arguments could be made. Is the decorator right? I would appreciate your explanations and advice. Thank you.

def func_show(func):
def get_sq(**kwargs):

x = 1

for v in kwargs.values():

x *= int(v)

func(x)

return get_sq
@func_show

def result(kwargs):

print(f"Площадь прямоугольника: {kwargs}")
if name == 'main':

result(width=4, height=6)

[Jolied]

It's probably like this:

def get_sq(width, height):
    return width * height
def func_show(func):

def decor(width, height):

print(f"площадь прямоугольника: {func(width, height)}")
return decor

get_sq = func_show(get_sq)
get_sq(4, 6)

If there is a wish to retain the withdrawal as the original function:

def get_sq(width, height):

return width * height

def func_show(func):

def decor(width, height):

square = func(width, height)

print(f"площадь прямоугольника: {square}")

return square
return decor

get_sq = func_show(get_sq)
res = get_sq(4, 6)