Python. Pandas. Minimum and its index

[zymir]

DataFrame:

    0         1         2          3          4          5
0 NaN  2.828427  3.162278  10.198039  12.165525  13.601471
1 NaN       NaN  3.162278   8.944272  10.770330  12.529964
2 NaN       NaN       NaN   7.071068   9.055385  10.440307
3 NaN       NaN       NaN        NaN   2.000000   3.605551
4 NaN       NaN       NaN        NaN        NaN   2.236068
5 NaN       NaN       NaN        NaN        NaN        NaN

C x.min() Yes, it is.

0         NaN
1    2.828427
2    3.162278
3    7.071068
4    2.000000
5    2.236068

C min(x.min()[2:]) Yes, it is. 2.0♪ How do you get two together with her index 4?

[Pearlaqua]

First, you can get a vector with minimum poles and then get an absolute minimum and an index using it. https://pandas.pydata.org/pandas-docs/stable/reference/api/pandas.Series.idxmin.html :

mn = df.min()
min_, min_idx = mn.min(), mn.idxmin()
print(f"min: {min_}, min_index: {min_idx}")
# min: 2.0, min_index: 4