Definition when print(s) stops writing Python

[meriah]

Hello, everyone! I had a question about the print(s) at Python. For one thing, I need to perform a function that needs to be determined when it stops writing. Please tell me. The best I've ever thought of is:

eyes2 = cv2.rectangle(img, (x+ex, y+ey), (x+ex + ew, y+ey + eh), (255, 0, 0), 2) # тут выдает значение, а я его компилирую yes
if eyes2.any():
   success2221 = "yes"
   success222 = print(success2221)
if 'yes' in success222:
   print('Есть такой текст')
if 'no' in success222:
   print('Нет такого текста')

Please help me!

[morde]

I finally understood the question. The problem is, print() returns None

print() Always returning. None Anyway,

success2221 = "yes"
success222 = print( success2221 ) # тут выводится yes
print( success222 )               # тут печатается None

There are functions that return value, such as the square root, and there are functions that never return anything as a result (they just do something and they don't return anything). If you do your job and you don't return anything. result, so Python's adding to the code. result = None♪ Same as in the functions print() It says result = None

So no matter what. print() the result

print( print( '' ) ) Always. None