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Check of the list in the cycle

Alberto last edited by
```
import os
import win32api

path = ['E:/keys.txt', 'G:/keys.txt']  # Эти файлы не существуют

result_path = path
for x in path:
    if os.path.isfile(x) is False:
        volume_lbl = win32api.GetVolumeInformation(x[:3])
        print(f'Ключ отсутствует на накопителе {x[:3]} с меткой {volume_lbl[0]}!')
        result_path.remove(x)
```
The function shall verify that there is a file on the way on the list. Problem is, if the files don't exist, the cycle. for interrupted without reaching the end of the list path♪ After the result_path will contain ['G:/keys.txt'], although by my logic the list should remain empty.
I tried to invert if, do the cycle while (a-l C++) it didn't work.
How do you fix it?
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1 Reply Last reply
inna last edited by
It's all about memory management in the python.
You create an object. list path
Then you take it. result_path His meaning.
Inside the python, it doesn't work the way most newcomers expect.
result_path and path References to the same list♪
As a result, when changed result_path change path♪ This leads to the work of your cycle for nothing you've ever thought about.
What do we do? Use such designs as:
```
result_path  = deepcopy(path)
```
or
```
result_path  = list(path)
```
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Try it. var eq = objects1.SequenceEqual(objects2);
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It would be desirable to take such heavy things into separate parts. https://medium.com/dartlang/dart-asynchronous-programming-isolates-and-event-loops-bffc3e296a6a ♪ And the triple cycle will always be long, there's nothing you can do. ♪ ♪I can't imagine what this is for, but here's the:import 'dart:convert'; void main() { print("Start 1"); List<List<List<MapData>>> temp = mapDataFromJson(""" [ [ [ { "a": "1", "b": "2", "c": "3" }, { "a": "1", "b": "2", "c": "3" } ], [ { "a": "1", "b": "2", "c": "3" }, { "a": "1", "b": "2", "c": "3" } ], [ { "a": "1", "b": "2", "c": "3" }, { "a": "1", "b": "2", "c": "3" } ] ], [ [ { "a": "1", "b": "2", "c": "3" }, { "a": "1", "b": "2", "c": "3" } ], [ { "a": "1", "b": "2", "c": "3" }, { "a": "1", "b": "2", "c": "3" } ], [ { "a": "1", "b": "2", "c": "3" }, { "a": "1", "b": "2", "c": "3" } ] ] ] """); print(temp[0][0][0].a); print("Start 2"); temp.forEach((x) => x.forEach((y) => y.forEach((z) => print(z.b)))); } List<List<List<MapData>>> mapDataFromJson(String str) => List<List<List<MapData>>>.from(json.decode(str).map( (x) => List<List<MapData>>.from(x.map( (x) => List<MapData>.from( x.map((x) => MapData.fromJson(x)), ), )), )); String mapDataToJson(List<List<List<MapData>>> data) => json.encode(List<dynamic>.from( data.map((x) => List<dynamic>.from( x.map((x) => List<dynamic>.from( x.map((x) => x.toJson()), )), )), )); class MapData { final String a; final String b; final String c; MapData({ this.a, this.b, this.c, }); factory MapData.fromJson(Map<String, dynamic> json) => MapData( a: json["a"], b: json["b"], c: json["c"], ); Map<String, dynamic> toJson() => { "a": a, "b": b, "c": c, }; }
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The answer is, "Look hands."Iteration 1Internal if Replace by Linq Whereforeach (var token in tokens) { it++; foreach (var item in LexemTypes.Keyword.Where(x => x == token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Ключевое слово" }); } foreach (var item in LexemTypes.ArithmeticSign.Where(x => x == token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Арифметическая операция" }); } foreach (var item in LexemTypes.LogicalSign.Where(x => x == token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Логическая операция" }); } foreach (var item in LexemTypes.Separator.Where(x => x == token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Разделитель" }); } } Iteration 2But why? foreachif item no use is made, and the addition takes place only on a specific condition if the collection contains an element. Let's say it. List<T>Then you can use it. List.Contains:foreach (var token in tokens) { it++; if (LexemTypes.Keyword.Contains(token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Ключевое слово" }); } else if (LexemTypes.ArithmeticSign.Contains(token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Арифметическая операция" }); } else if (LexemTypes.LogicalSign.Contains(token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Логическая операция" }); } else if (LexemTypes.Separator.Contains(token)) { list.Add(new TokensTable() { Id = it, Token = token, Type = "Разделитель" }); } } And to improve productivity, I added else♪ Token can't be multiple types at the same time?Iteration 3DRY = Don't Repeat Yourself = don't repeat yourself. I'll add a variable, stored and bracketed for beauty.foreach (var token in tokens) { it++; string type; if (LexemTypes.Keyword.Contains(token)) type = "Ключевое слово"; else if (LexemTypes.ArithmeticSign.Contains(token)) type = "Арифметическая операция"; else if (LexemTypes.LogicalSign.Contains(token)) type = "Логическая операция"; else if (LexemTypes.Separator.Contains(token)) type = "Разделитель"; else continue; list.Add(new TokensTable() { Id = it, Token = token, Type = type }); } Iteration 4For entertainment, I've written if- you're in the form of thernar operators, but you could also stop on the previous iteration.foreach (var token in tokens) { it++; string type = LexemTypes.Keyword.Contains(token) ? "Ключевое слово" : LexemTypes.ArithmeticSign.Contains(token) ? "Арифметическая операция" : LexemTypes.LogicalSign.Contains(token) ? "Логическая операция" : LexemTypes.Separator.Contains(token) ? "Разделитель" : null; if (type != null) list.Add(new TokensTable() { Id = it, Token = token, Type = type }); } Everything within the code shown and not altering the data storage conditions here is unlikely to be done.
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Instead of a compression list you use better sum and a generating expression, if you just want to count on creating a list is a loss of resources:sum(sublista[0] > 0 for sublista in lista) Although what you have is a Numpy array, not a list, in such a case for this particular example, you should do:sum(1 for h in histr_b if h[0] > 0) or sum(histr_b[:, 0] > 0) But better take advantage of NumPy:np.count_nonzero(histr_b > 0) that should be the preferred option for efficiency (*see at the end of the answer). It could also be used numpy.sum:np.sum(histr_b > 0) If you have more than one column (which is not the case) you should do a previous slicing or count the more than 0 in all:np.count_nonzero(histr_b[:, 0] > 0) np.sum(histr_b[:, 0] > 0) or use the argument axis with value 0, which will tell us the greater than zero per column:np.count_nonzero(histr_b > 0, axis=0) np.sum(histr_b > 0, axis=0) the output is another array with an integer for each column whose value is the number of numbers greater than 0 in that column.*If we make a small comparison of execution times:%timeit sum(1 for h in histr_b if h[0] > 0) 23.3 µs ± 222 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each) %timeit sum(histr_b[:, 0] > 0) 37.6 µs ± 505 ns per loop (mean ± std. dev. of 7 runs, 10000 loops each) %timeit np.count_nonzero(histr_b > 0) 4.08 µs ± 33.2 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each) %timeit np.sum(histr_b > 0) 12.4 µs ± 102 ns per loop (mean ± std. dev. of 7 runs, 100000 loops each) The clear winner is numpy.count_nonzero.
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Looks like this row doesn't contain the Eilerov of the cycle:import networkx as nx # pip install networkx import matplotlib.pyplot as plt distances = { 'A': {'B': 2, 'C': 1, 'D': 3, 'E': 9, 'F': 4}, 'B': {'C': 4, 'E': 3}, 'C': {'D': 8}, 'D': {'E': 7}, 'E': {'F': 5}, 'F': {'C': 2, 'G': 2, 'H': 2}, 'G': {'F': 1, 'H': 6}, 'H': {'F': 9, 'G': 8}} G = nx.DiGraph() for k,v in distances.items(): for k2,v2 in v.items(): G.add_edge(k, k2, dist=v2) In [24]: nx.draw(G, with_labels=True) In [25]: nx.is_eulerian(G) Out[25]: False In [26]: nx.eulerian_circuit(G) Out[26]: <generator object eulerian_circuit at 0x000000000AD631A8> In [27]: list(nx.eulerian_circuit(G)) NetworkXError Traceback (most recent call last) <ipython-input-27-d4bc2ec5ddbd> in <module> ----> 1 list(nx.eulerian_circuit(G)) ~\Anaconda3\envs\ml\lib\site-packages\networkx\algorithms\euler.py in eulerian_circuit(G, source, keys) 168 """ 169 if not is_eulerian(G): --> 170 raise nx.NetworkXError("G is not Eulerian.") 171 if G.is_directed(): 172 G = G.reverse() NetworkXError: G is not Eulerian. Example of simple Eilerov cycle:In [30]: G2 = nx.from_edgelist([('A','B'),('B','C'),('C','D'),('D','A')], create_using=nx.DiGraph) In [31]: list(nx.eulerian_circuit(G2)) Out[31]: [('A', 'B'), ('B', 'C'), ('C', 'D'), ('D', 'A')] In [32]: list(nx.eulerian_circuit(G2, 'C')) Out[32]: [('C', 'D'), ('D', 'A'), ('A', 'B'), ('B', 'C')] In [33]: nx.draw(G2, with_labels=True)

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