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How do you get all your ancestors with the atribut?

elysha

How with xslt and xpath from, for example, a xml file:

<a>
    <b1>
        <c1 value="1" />
    </b1>
&lt;b2&gt;
    &lt;c2 value="2" /&gt;
&lt;/b2&gt;

&lt;/b3&gt;
    &lt;c3&gt;
        &lt;d value="3" /&gt;
    &lt;/c3&gt;
&lt;/b3&gt;

</a>

To obtain full paths to the attribut value, i.e. the list of all ancestors.

a/b1/c1/@value

a/b2/c2/@value

a/b3/c3/d/@value

Attribution value and investment may be any

carriann last edited by
```
//*[@value]
```
- // any root (any root)
- * any teg (any tagName)
- @value has attribute value
The rest of the perverts are here-- https://sodocumentation.net/xpath/topic/3096/find-nodes-that-have-a-specific-attribute
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What you're missing is adding the instance number, you could also use a shorter xPath, for example=IMPORTXML("https://play.google.com/store/apps/details?id=es.lfp.gi.main","(//span[contains(@class, 'htlgb')])[3]")
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Intellij IDEA there's a built-in editor who's the XML'ki genius.I mean, I'd rather, in person, like, a handcope... No editor can replace that. WYSIWYG is a castle.UpdateOpen the xml file of the layaut and slap on the Design Tab. Looks like it. ♪ ♪
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Use an attribution tega test //tag[@attribute]:$param_value = $node->xpath('//param[@id]/@name'); $param_name = $node->xpath('//param[@id]'); $param_id = $node->xpath('//param/@id'); Yes, for $param_id It's not necessary to check, because it's already returning the attribute from the node only if the attribute exists.
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How do you get all your ancestors with the atribut?

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