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Estimate JS interest

K
kalena last edited by
I have two variables.
```
let valMax = 29
let valNow = 15
let valEnter = ?
```
variable valMax No change, variable valNow Always change.
variables valEnter I need to get the result out as a percentage, How to explain to Javascript that 29 is 100%.
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J
juvenalb last edited by
The simplest thing is
```
100 * текущее / максимальное
```
General formula
```
100 * (current - min) / (max - min)
```
a Reflecting borders and the inability to overcome them (in some cases no more than 100 per cent or less than 0 per cent)
```
(current < min) ? 0 : (current > max) ? 100 : (100 * (current - min) / (max - min))
```
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arithmetics 18

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How to test js
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In order to make a mistake in the entry of the numbers or the cancellation of the request or in the introduction of only gaps, it may be written as follows:if(!itemIncome || !itemIncome.trim() || /\d/.test(itemIncome) ){ console.log("ошибка"); };
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How do we make this interesting?
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Tabs, slider, animation. Combination of the sheep will have that effect. How do you do that? Take them as an example http://frondevo.com/js/main-2.js and try to figure out what's going on. ♪
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It's a array with a single object that in turn contains a property (colors) that has a property options which is a array of strings. As you see in this example the arrays are also an object:const cc = [ { 'colors': { 'options': ['black', 'grey', 'pink'] } } ]; console.log(Type of cc: ${typeof cc} - IsArray? ${Array.isArray(cc)}); console.log(Type of cc[0]: ${typeof cc[0]} - IsArray? ${Array.isArray(cc[0])}); console.log(Type of cc[0].colors: ${typeof cc[0].colors} - IsArray? ${Array.isArray(cc[0].colors)}); console.log(Type of cc[0].colors.options: ${typeof cc[0].colors.options} - IsArray? ${Array.isArray(cc[0].colors.options)});What exactly do you not understand?
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Can we turn js on the browser and not reload the page so js can make it?
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Yes, the JS should earn immediately after the insertion, but the events of the browser that are generated during the downloading of the page will not work. Moreover, the code connected to the tags script Nor will it be implemented without reloading the page. Also, there's no way you can trace the time when the JS was on the browser.As a consequence, I see no way of compelling the code on the JS page without reloading it.
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To obtain sequence each member of whom is equal to -1, 0, or 1
Software Programming • math number arithmetics calculation systems • • Kadyn

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In short, if it's three to n-- and I'm sure it's that: The number is 0, 1 and 2.Let's go from junior to senior, if we meet two, we're going to change to one and add to rank above the unit (in fact replace 2 = 3 - 1). Recurring. ♪ ♪For example, 743. In the trout system, 1,000112. We'll replace the last two with one. We get 1,00012i. Let's go to the double on the left. The same picture is 10002ii. And again... 1001iii. That's the idea:1*3^6+1*3^2+3+2=729+9+3+2=743 (1000112)1*3^6+1*3^3-3^2-3-1=729+27-9-1=743 (1001iii)
Replacement of index by indicator in cycle
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I think we can do this:int *pa = a, n_digits = *pa++, *pb = b, *pe = a + n_digits, c = 0; while (pa < pe) { c = c + *pa - *pb++ + 10; *pa++ = c % 10; c = (c < 10) ? -1 : 0; } pe--; while (*pe-- == 0) n_digits--; a[0] = n_digits;
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css and js
Software Programming • javascript css • • juvenalb

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See examples: http://matthew.komputerwiz.net/2012/05/jscanvas-polar-clock/ ♪ http://projects.joreteg.com/Polar-Clock-Canvas/ ♪ http://raphaeljs.com/polar-clock.html ♪
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Try to charge four-digit numbers:int lucky(int M, int N) { int s[10000] = {0}, total = 0; for(int i = 0; i <= 9999; ++i) { for(int k = i; k; k/=10) { s[i] += k%10; } } for(int i = M; i <= N; ++i) if (s[i/10000] == s[i%10000]) ++total; return total; } Your program works in my car 1.13 ±0.03s, mine 0.16 ±0.03s.For CrazyElf, microoptimization, which reduces the time from 1.16 to 1.15 - a little faster to calculate the table:int lucky(int M, int N) { int s[10000] = {0}, total = 0; for(int i = 0; i <= 999; ++i) { int sum = 0; for(int k = i; k; k/=10) { sum += k%10; } for(int j = 0; j < 10; ++j) s[10*i+j] = sum+j; } for(int i = M; i <= N; ++i) if (s[i/10000] == s[i%10000]) ++total; return total; }
Meteor or Node.js + Socket.io + MongoDB + Vue.js?
Software Programming • javascript node.js meteor • • Alberto

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Could be replaced. But for a large project, it's important to know meteor underwater stones, otherwise the productivity problems will come. In other words, if you didn't work with meteor, a major project would be better off on it.
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Remove timezone in request with node. js and express.js
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I suggest using a library for conversion. For example the extention of moment.js for timzones, the http://momentjs.com/timezone/ .To do natively you can use UTC and add the difference to your time, or format the date with the .toLocaleString('pt-br', {timezone: 'Brazil/brt'}). The problems that may arise are in the days of change between summer and winter hours that I am not sure that the browser knows this information.For example, having JSON's date repairs what we can extract:var json = "2017-10-02T13:58:34.000Z"; var date = new Date(json); console.log('Dia:', date.getUTCDate(), 'Hora:', [date.getUTCHours(), date.getUTCMonth() + 1, date.getUTCMinutes()].join(':')); console.log(date.toLocaleString('pt-br', {timezone: 'Brazil/brt'}));
Check whether all the figures are different (SI)
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"Why just, if it's difficult?"int checkDifferent(int n) { int digs[10] = {0}; for(;n;n/= 10) digs[n%10]++; for(int i=0; i<10; ++i) if (digs[i]>1) return 0; return 1; } Or evenint check(int n) { for(int digs[10] = {0};n && ++digs[n%10] <= 1;n/=10); return n == 0; }
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The task is to calculate the square root. Long arithmetic
Software Programming • arithmetics • • emran

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It's a modification of the Newton method to the non-linear equation.def sqroot(number, eps): a = float(number) # из какого числа извлекаем x0=0 #предыдущее значение x1=a #начальное приближение while abs(x0-x1)>eps: x0=x1 x1 = 0.5 * (x1 + a / x1) # x_(n+1) = 0.5 * (x_n +a / x_n) return x1 print(sqroot(9,0.00000001)) print(sqroot(2,0.001))
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https://docs.python.org/3/reference/expressions.html#operator-precedence :Operators in the same box group left to right (except for exponentiation, which groups from right to left)
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What's the problem?cout << "1888000721011000" << setw(3) << setfill('0') << x; https://ideone.com/Jk33j9 :Yes and https://ideone.com/BXHPli long long y = 1888000721011000000; for (x = 1; x < 301; x++) cout << y+x << endl;
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Because the numbers... intmultiplied like intand resulting int With reduced overcrowding: 100,00000000 in the sixteenth record: 2540BE400. Cut to 4 Byte, we have 540BE400, or 1410065408.Try to point out clearly that you're multiplying. long long'and don't regret:long long int var=100000ll*100000ll;

Estimate JS interest

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