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Remote access to the server?

jeanid last edited by

The situation is next, I'm in the driveway, and sometimes I need a remote job with my server, no one in the class, who can do that when I'm stationed?
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Anderson last edited by

Solomon? Linux or a wed? In the case of linux, the VNC or SSH launch, and with the venda, the RDP protocol. If your car is the problem? Almost all the hosters provide SSH access to the server. Like majordomo.ru, I don't have my server, it's just VDS, but I have access to SSH up to the root user.
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How to make a server course visible in a remote car. Use the VNC
Software Programming • linux vnc • • Burma

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To show up the cadet, we need a fresh version of x11vnc.git clone git@github.com:LibVNC/x11vnc.git cd x11vnc sudo apt-get install libvncserver-dev ./autogen.sh ./configure make sudo make install Source: https://github.com/kbumsik/VirtScreen/issues/19#issuecomment-429573666
Problems with Tomcat 7
Software Programming • apache server tomc languageat • • Laycee

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The Tomcat server can work normally, including multiple applications installed on it, but its application is not booted.When Tomcat initializes, it deploys all configured applications, one by one, creating the context of each one to then serve requests.However, if during the deploy one of the applications occurs an error, its context is discarded and Tomcat continues its operations normally.The most common causes of an application that works locally, but not on another server are:Difference of the environment: database or other features are not available or are with modified access data.Improper configuration: It may be missing some configuration. Check if context.xml your application has the correct data for the DataSources necessary. Also check if the application has file dependencies or directories (logs, properties, ...).Difference in WAR: It may be that the WAR used on the server does not have the same content being used in the development environment. In this case, check the version generation procedure.Tomcat Difference: check if there are different libs (jars) between your Tomcat installation to which it is on the server, because it is missing or remaining classes and generating problems class loaders. Also check if something is missing server.xml or context.xml Tomcat general. I've seen some applications that needed specific settings in catalina.properties. It's good to compare the Tomcats files. It is also good to check if the system has any installation manual where you can describe the procedure for deploy in a "new" Tomcat.The main tip is to always start by analyzing the logs generated by Tomcat during the attempt to start the application. Almost always it will give the solution or at least a hint.
How to encrypt traffic when accessing a client or server
Software Programming • encryption cryptography sl • • Bogopo

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Maybe even. https://geti2p.net/en/faq Do you want to clean this up? The truth is, it's a long time on the client side. List of protocols to be used in such a way as to:256 бит AES режим CBC с PKCS#5; 2048 бит Схема Эль-Гамаля; 2048 бит Алгоритм Диффи — Хеллмана; 1024 бит DSA; 256 бит HMAC — Алгоритм усиления криптостойкости других криптоалгоритмов; 256 бит Хэширование SHA256.
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SQL SERVER Mathematical calculations with variables
Software Programming • sql server table variables • • rosemadder

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One of the possibilities that dynamic querys have before running them, is that you can throw them through a simple print, to know what the error is, as the same one then sticks it in the editor window and the intellisense tells you what the problem might be.In addition in the code you have glued you have areas of improvement with the syntax, as it is currently used to relate the tables on and not the "old" way Where.declare @archivo1 nvarchar (500) = N'A', @archivo2 nvarchar (500) = N'B', @COEFiCIENTE varchar(10) = '0', @script nvarchar (500); SET @Script = N'SELECT * FROM [Base].[dbo].['+ @ARCHIVO1 + '] as a inner join [Base].[dbo].['+ @ARCHIVO2+ '] as b on a.id = b.id WHERE b.[campo2] > = (a.[campo2] * (Cast( '+ @COEFiCIENTE + ' as int))))' PRINT @SCRIPT SELECT * FROM [Base].[dbo][A] as a inner join [Base].[dbo].[B] as b on a.id = b.id WHEREb.[campo2] 한 = (a.[campo2] * (Cast( 0 as int))))If you look at the proposed output, the A base is related to alias a and you no longer have to worry about the concatenation of the value of @archivo1 with base B with alias b.Then the restriction and names of columns already do them with the assigned alias.Also, deal with text strings in dynamic querys, it means you use double or triple apostrophes. For the solution, the easiest thing is to use the @COEFICIENTE variable as a flush, and cast your content on the where.To generate the file2 columns that you want to visualize, use Select b.*. So you don't get those from table a.
Locked access to Socket server
Software Programming • python server soc languageket ports websoc languageket • • Bogopo

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The problem is not in which the port is blocked, this is a normal behavior your problem is probably that you stay out of connections or the process in if you stop responding, in your case are 5 connections available, if a sixth is connected you will not be able to do so as the maximum has been reached.I recommend the use of this bookstore to avoid this kind of problems and that your focus is on your business logic: https://python-socketio.readthedocs.io/en/latest/server.html
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Access web application that is running in apache of a docker container inside a linux server that I access by ssh
Software Programming • linux windows ssh doc languageker • • Avante

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First of all you need to know if the network that this server is, it can be accessed by your direct IP machine, voĉe can test this by giving a ping on her ip.If your machine can ping on the server, it means it's possible. This way you need to climb this container by mapping a door you want, for example -p 8000:8000.With the active container and the port mapped, you can directly access the browser by typing the Ip of the machine next to the door, for example, 172.16.108.10:8000
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Remote server with reverse tunnel, the occupied port is sometimes closed
Software Programming • linux ssh server • • Burma

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There may be a process that is occupying that port. You can simply kill the process that is running in that port and then connect but first check the process occupies that port. Enter with ssh and monitor that port with some script, cronjob or watch and with sudo netstat -tlpn | grep 2022 or with sudo lsof -i tcp:2022. That's thinking there may be another process using that port, maybe if you can't connect, close it and then open it to connect. If I were in your case, that would be the first thing I would do since it could be (in one of the worst scenarios) an intrusion through that port.The other is that you try to connect by another port to the server1 and by another to the server2, that is to say.Server1It will allow connections through the port, is an example of port, 2001 from the server2 (remoto) to the local port 22. That is, the server2 will connect to your localhost by the port 2001 (the one occurred to me to indicate that it is the server1).ssh -N -f -R 2001:127.0.0.1:22 usuario@ip_servidor2 Server2It will allow connections through the port, is an example of port, 2002 of the server1 (now it is the remote) to the local port 22. Similar to the previous one.ssh -N -f -R 2002:127.0.0.1:22 usuario@ip_servidor1 And you can connect to the server2 from the server1 with:$ ssh usuario_de_servidor2@127.0.0.1 -p 2002 And vice versa, from server2 to server1 with:$ ssh usuario_de_servidor1@127.0.0.1 -p 2001 The explanation of what the parameters do -N, -f and -R You can find her in man ssh. But in short -f send all requests to background, -N does not execute any command remotely and -R makes a forwarding port as follows -R <puerto del servidor remoto>:<host>:<puerto_local_de_conexión> i.e., with ssh-R to a remote ip, it allows that remote server to connect to its own host and local port agreed and enter the server that allowed that connection, allows you to see the traffic. And, in the case of the example above, as is the port of ssh (port 22), it allows to obtain a shell.Remember that all this can work with your couple of keys, or whatever, if you know the password of both users on both servers also works.
Remote web server for calculations
Software Programming • python python 3.x google app engine • • Laycee

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You can watch Microsoft Azure again. They sometimes advertise themselves, including for scientific purposes.There. http://aws.amazon.com/ru/ec2/ (Amazon EC2). Here's a quote from their website:Amazon Elastic Compute Cloud (Amazon EC2) is a web service that provides vast computing resources in the cloud. It facilitates the process of large-scale calculations in the designer cloud.
How do I shoot a remote event for the server and the client in the same script at ROBLOX Studio?
Software Programming • moon c languagelient server • • irl

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Well... I found out for myself. And I called this "Master Client" method. Basically I added a remote event, an object value, a server script in the workspace and a local script in StarterPlayer.StarterPlayerScripts. I wrote this in the server script:detail:objValue is the object of the master clientgame.Players.PlayerAdded:connect(function(player)--Bloco que irá ser executado quando um jogador entrar if objValue.Value==nil then--Vê se há um master client.Se não tiver... objValue.Value=player --Irá fazer desse jogador o master client print('master client agr e '..objValue.Value.Name..' :D:D:D') end end) game.Players.PlayerRemoving:connect(function(player) --Bloco que irá ser executado quando um jogador sair if player==objValue.Value then--Vê se esse jogador que saiu é o master client.Se é... print('master client saiu :(') objValue.Value=game.Players:GetPlayers()[1] --Irá definir um novo master client print('novo master client e '..objValue.Value.Name..'yaya :D:D:D') end end) rEvent.OnServerEvent:connect(function() print'e voala! evento disparado para o client e o server!' end) while wait(1) do rEvent:FireAllClients() end rEvent:FireAllClients() And I inserted it into the local script in StarterPlayer.StarterPlayerScriptsrEvent.OnClientEvent:connect(function() --Bloco que irá ser executar quando OnClientEvent for disparado if objValue.Value==game.Players.LocalPlayer then --Vê se o master client é o jogador local.Se é... print'sou euuu o tiriricaaa' rEvent:FireServer() else --Senão... print'nao sou eu :(' end end) If it doesn't work, I found another way to shoot the client and the server. Simply create a BindableEvent and inside it enter a RemoteEvent. Enter this into the server scriptbindableEvent.Event:connect(function() remoteEvent:FireAllClients() end) bindableEvent:Fire() and then enter this into the local scriptremoteEvent.OnClientEvent:connect(function() print'funcionou aaaeeeeeeeeeeeeeeeeeeeeeeeeeee' end) I haven't tested yet but I think it'll work.
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c# HtpClient System.Net.WebException: Can't connect with a remote server
Software Programming • c sharp httpclient • • zymir

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You did something weird with the code. I know the comments, I don't think I've been writing them that long.Try that.private async void Button_Click_1Async(object sender, RoutedEventArgs e) { IProgress<string> progress = new Progress<string>(p => AllDomains.Content = Convert.ToString(j++)); IProgress<string> progress1 = new Progress<string>(p => good.Text += p + "\n"); IProgress<string> progress2 = new Progress<string>(p => bad.Text += p + "\n"); IProgress<string> progress3 = new Progress<string>(p => Catch.Text += p + "\n"); string[] arrString = File.ReadAllLines(@"C:\Users\Desktop\domain.txt"); int maxConcurrency = 30; // сколько одновременно может работать потоков using (SemaphoreSlim semaphore = new SemaphoreSlim(maxConcurrency)) { List<Task> tasks = new List<Task>(); foreach (string s in arrString) { await semaphore.WaitAsync(); tasks.Add(loadingPage.ProcessPage(s, progress, progress1, progress2, progress3, semaphore)); // запуск I/O-bound операции } await Task.WhenAll(tasks); // ждать завершения всех } } public async Task ProcessPage(string url, IProgress<string> progress, IProgress<string> progress1, IProgress<string> progress2, IProgress<string> progress3, SemaphoreSlim semaphore) { try { string html; using (HttpResponseMessage response = await client.GetAsync(url, HttpCompleteionOption.ResponseHeadersRead).ConfigureAwait(false)) { response.EnsureSuccessStatusCode(); html = await response.Content.ReadAsStringAsync().ConfigureAwait(false); } searsh.SearchCMS(url, html, progress, progress1, progress2, progress3); } catch (Exception ex) { progress3.Report(ex.ToString()); } finally { semaphore.Release(); } } There will be 30 simultaneous inquiries now.I checked twice the address you gave the page. That's the code in the console. It's probably your Windows problem.public class Program { private static HttpClient client = new HttpClient(); public static async Task Main() { string html = await client.GetStringAsync("https://hairline.hu"); Console.WriteLine(html); } } It's a big HTML.
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Verify the authenticity of the application of a client
Software Programming • c sharp security server • • Oba22

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Using a binary hash is easy to attack, with a sniffer and a self-signed certificate installed on the pc you can see the requests made by the client and get the toquen that is always the same, sofware is not modified you create a new one that impersonalizes it. You can make the coas more complicated by defining that the server sends you a random string ("challenge") so that the client signs it with a private key RSA and sent the information back to the server, even if you can see the requests the "challenge" and the customer's response will always be different, the server can validate the client's signature with the public key and if it is satisfactory to deliver a valid token for a short time (minution).The token must be unique so it is compromised can be excluded as valid of the server. The same with the private keys, you must implement a mechanism to invalidate them if any are compromised.This makes it quite safe to get the token, and complicated to find a way to get it (in spite of this with a lot of patience and knowledge, it is not an easy task, it could be done using a sniffer and a customer- glued debugger)To avoid MiTM with signed auto certificates you can implement a pinning certification mechanism where your client only accepts a list of certified entities.
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User name with file Excel open - VBA
Software Programming • vba server • • amarantha

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The Windows computer user name can be viewed as follows:Dim usuarioPC As String, usuario As String usuario = Environ("username") usuarioPC = Application.UserName MsgBox "O usuário deste PC é o " & usuarioPC MsgBox "O usuário é o " & usuario In which it is used https://docs.microsoft.com/pt-br/office/vba/api/excel.application.username or https://docs.microsoft.com/pt-br/office/vba/language/reference/user-interface-help/environ-function Or use the following function with reference wScript to get the name of the Computer in which Excel was opened:Public Function ComputerName() As String '' Returns the host name '' Uses late-binding: bad for performance and stability, useful for '' code portability. The correct declaration is: '' https://stackoverflow.com/a/10108951/7690982 ' Dim objNetwork As IWshRuntimeLibrary.WshNetwork ' Set objNetwork = New IWshRuntimeLibrary.WshNetwork Dim objNetwork As Object Set objNetwork = CreateObject("WScript.Network") ComputerName = objNetwork.ComputerName Set objNetwork = Nothing End Function For a test view the function output in an MsgBox:MsgBox ComputerName() Or another function to get the computer user:Public Function UserName(Optional WithDomain As Boolean = False) As String '' Returns the user's network name '' https://stackoverflow.com/a/10108951/7690982 '' Uses late-binding: bad for performance and stability, useful for '' code portability. The correct declaration is: ' Dim objNetwork As IWshRuntimeLibrary.WshNetwork ' Set objNetwork = New IWshRuntimeLibrary.WshNetwork Dim objNetwork As Object Set objNetwork = CreateObject("WScript.Network") If WithDomain Then UserName = objNetwork.UserDomain & "\" & objNetwork.UserName Else UserName = objNetwork.UserName End If Set objNetwork = Nothing End Function Or the function https://docs.microsoft.com/en-us/office/vba/access/concepts/windows-api/retrieve-the-name-of-the-user-logged-on-to-the-network of the library "advapi32. dll":' Access the GetUserNameA function in advapi32.dll and ' call the function GetUserName. Declare Function GetUserName Lib "advapi32.dll" Alias "GetUserNameA" _ (ByVal lpBuffer As String, nSize As Long) As Long ' Main routine to retrieve user name. Function GetLogonName() As String ' Dimension variables Dim lpBuff As String * 255 Dim ret As Long ' Get the user name minus any trailing spaces found in the name. ret = GetUserName(lpBuff, 255) If ret > 0 Then GetLogonName = Left(lpBuff, InStr(lpBuff, Chr(0)) - 1) Else GetLogonName = vbNullString End If End Function
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Changes to my site do not appear
Software Programming • server cache google c languagehrome vps • • esther

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I decided!!!! I just disabled through easyengine using the command:ee site disable dominio.com.br And then I enabled using:ee site enable dominio.com.br And so the latest updates appeared. ... I don't know if it's the right way, but it's solved!
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Python Flask is the problem of access to the server
Software Programming • python python 3.x flask port • • Nykeriab

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Connection remains undone and therefore cannot take port. We need to close the client-- the browser, if he didn't have a ruptured connection when the server was finished. Browsers sometimes leave the compounds open for faster access to data.
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Is it safe to use flex and bison as a protocol parser?
Security, Penetration Testing • server protoc languageols • • yajahira

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Bison and flex are reasonable tools to write parsers for protocols which fit in an LALR(1) grammar; but they are just tools like, e.g., a C compiler. It is still up to you not to do anything wrong with them. For that matter, bison and flex mean that you are about to implement your code with C or C++, languages which are known to be difficult to handle properly and prone to trigger security holes, especially because of pointer aliasing issues, manual memory management, lack of decent character string handling facilities, and unchecked array bounds. These are C issues, not bison issues, but you'll get them nonetheless. LALR(1) parsing can be a bit confusing because you tend to get the "reduce" rules on a right-to-left basis. When you write the code attached to the grammar clauses, this can make things awkward (you have to handle the leaves of the syntax tree is a mostly context-free way). The good thing about flex and bison is that they are systematic: they will implement all the corner cases of the grammar. That's a great property for security (most of secure coding is about covering all possible cases without forgetting any).

Remote access to the server?

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