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How do you turn the numbers on the list into numbers?

briley last edited by
Let's say we have a list:
```
r = ['Alica', '884', 'Bread', '231']
```
We need to convert the numbers into numbers, and we don't have rows.
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1 Reply Last reply

Cleofas

Is that the option?

r = ['Alica', '884', 'Bread', '231']
n = [int(i) if i.isnumeric() else i for i in r]
print(n)

The truth is, it only works with natural numbers, which are only numerical.

a more universal method:

r = ['Alica', '884', 'Bread', '-231', '2.1e5', '3.1415']
n = []
for i in r:

# пробуем преобразовать в float

try:

value = float(i)

n.append(int(value) if value == int(value) else value)

except ValueError:

n.append(i)
print(n)

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Return only the file name in the view
Software Programming • python django • • Rossere

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Use the function basename module os.path:>>> from os import path >>> a='/usr/local/share/pixmaps/sample_image.png' >>>> path.basename(a) 'sample_image.png' You can create a function within the template to return this value:class Documento(models.Model): # ... @property def apenas_o_nome_do_arquivo(self): return path.basename(self.arquivo) And inside template call it as:<td>{{ documento.apenas_o_nome_do_arquivo }}</td>
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Add elements to a List extends Number
Software Programming • java objec languaget orientati • • Pearlaqua

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Adding elements to this type of list is not possible because the wildcard statement List<? extends Number> ml means that the variable ml may contain any family value Number, instead of any value of a specific type. See the equivalent assignments below that would be permitted:List<? extends Number> foo3 = new ArrayList<Number>; // Number "extends" Number List<? extends Number> foo3 = new ArrayList<Integer>; // Integer extends Number List<? extends Number> foo3 = new ArrayList<Double>; // Double extends Number Given this, the type of object you can add to List foo3 that would be valid after any of the assignments above one ArrayList would bump into the problems below:You can't add one Integerbecause foo3 could be pointing to one List<Double>.You can't add one Doublebecause foo3 could be pointing to one List<Integer>.You can't add one Numberbecause foo3 could be pointing to one List<Integer>.So:You cannot add any object to List<? extends T> because you cannot guarantee that List is really pointing to this type, so you cannot guarantee that the object to be added is allowed in that list. The only "guarantee" you have is that you can only read this list and will have one T subclass T.The reverse logic applies to the use of super, according to the assignments below, which are also valid:List<? super Number> foo3 = new ArrayList<Number>; // Number é "superclasse" de Number List<? super Number> foo3 = new ArrayList<Object>; // Object é "superclasse" de Number About List<? super T>The following conclusion can be reached:You can't read the type T specific (e.g. Number) from List<? super T> because you cannot guarantee what kind of List is really pointing to it. The only "guarantee" you have is that you are able to add a type value T(or any subclass of T) without violating the integrity of the list being pointed out.The left statement(List<? extends Number> foo3) defines the type of data that can be assigned to your right ArrayLists(= new ArrayList<Integer>();), and not the type of data that can be added in the created list.Translated and adapted from this https://stackoverflow.com/a/2777297/5524514 References for reading: https://pt.stackoverflow.com/q/32880/28595 https://pt.stackoverflow.com/q/117765/28595
How to turn a reading of numbers directly into stream?
Software Programming • java java 8 • • Mystic

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With https://docs.oracle.com/javase/10/docs/api/java/util/stream/Stream.html#generate(java.util.function.Supplier) , you can read the numbers of Scanner without needing ArrayList.I know the tag is /questions/tagged/java-8 . But if you accept using Java 9 or higher, you can use https://docs.oracle.com/javase/10/docs/api/java/util/stream/Stream.html#takeWhile(java.util.function.Predicate) to make the stop criterion.Here's the result:Scanner input = new Scanner(System.in); DoubleSummaryStatistics summary = Stream .generate(input::nextDouble) .takeWhile(z -> z != 0) .collect(Collectors.summarizingDouble(Double::doubleValue)); double maior = summary.getMax(); double menor = summary.getMin(); System.out.println("maior " + maior); System.out.println("menor " + menor);
How to divide the number into the list
Software Programming • python python 3.x • • Analeea

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Hello.a = int(input()) print(list(map(lambda x: int(x), str(a))) The programme will respond:[1, 2, 3] #При вводе 123 Either:a = [int(i) for i in input()] print(a) The programme will respond:[1, 2, 3] #При вводе 123
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List on the list
Software Programming • java list arraylist • • Avante

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As I understand the example, you want a list of cuts (or intervals between two values). That's why you need to set up a class of "Slashes" and make a list of this class. In the example, the beginning and end of the cut is the calculated coordinates on the X axis. If intervals should be made between other data types, such as dates, the relevant fields of this type, plus all other methods, are needed.Anyway, use the lists for the same data. If you have a group of values of one type somewhere, but with different meanings (e.g. growth, weight and age, type) int- create a class.import java.util.ArrayList; import java.util.List; public class Segments { public static void addIfNotIntersects( List<Segment> segments, Segment segment ) { for( Segment s : segments ) { if ( s.intersects( segment ) ) return; } segments.add( segment ); } public static void main(String[] args) { List<Segment> segments = new ArrayList<Segment>(); segments.add( new Segment( 2, 5 ) ); // т.к. мы управляем тем, что добавляется в коллекцию, // возможно следует создать отдельный класс для набора отрезков // и перенести метод addIfNotIntersects в него addIfNotIntersects( segments, new Segment( 6, 7 ) ); // добавится addIfNotIntersects( segments, new Segment( 4, 7 ) ); // не добавится System.out.println( segments ); System.out.println( segments.get( 0 ) ); // первый элемент списка System.out.println( segments.get( 1 ).x1() ); // поле x1 второго элемента } } // класс не public, т.к. мне лень создавать отдельный файл class Segment { // класс "Отрезок" (одномерный) с двумя точками private int x1, x2; // поля объявлены как private, чтобы сделать класс // неизменяемым (immutable) // конструктор проверяет корректность входных параметров // и выбрасывает исключение public Segment( int x1, int x2 ) { if ( x1 > x2 ) { throw new IllegalArgumentException( String.format( "Bad argument x1: %d > x2: %d", x1, x2 ) ); } this.x1 = x1; this.x2 = x2; } // создаем только методы чтения (геттеры, аксесоры) public int x1() { return x1; } public int x2() { return x2; } // метод класса проверяет пересечение этого отрезка с другим // если я тут не накосячил в логике public boolean intersects( Segment other ) { return ( this.x1 <= other.x1 && other.x1 <= this.x2 ) || ( this.x1 <= other.x2 && other.x2 <= this.x2 ) || ( other.x2 <= this.x1 && this.x2 <= other.x2 ); } // т.к. это value-класс и объекты этого класса должны поддерживать // эквивалентность по значению, переопределяем equals и hashCode // методы сгенерированы IDE, поскольку невозможно это все руками // делать каждый раз... @Override public int hashCode() { final int prime = 31; int result = 1; result = prime * result + x1; result = prime * result + x2; return result; } @Override public boolean equals(Object obj) { if (this == obj) return true; if (obj == null) return false; if (getClass() != obj.getClass()) return false; Segment other = (Segment) obj; if (x1 != other.x1) return false; if (x2 != other.x2) return false; return true; } // возвращает строковое представление нашего объекта // используется в System.out.println // и опосредовано в List.toString() (при выводе списка) @Override public String toString() { return "[" + x1 + ", " + x2 + "]"; } }
Python issue
Software Programming • python python 3.x beautiful soup paraser • • Mystic

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I think that since the page is running with scruples, requests It won't help. Makes the decision below selenium♪Get down before the violin launch. https://github.com/mozilla/geckodriver/releases For his OS. geckodriverIf you want to write under Chrome, the crypt will need to be adapted to it and the driver will need another. Place the packaged. geckodriver In a crypt file. And don't forget to set firefox himself.# pip install selenium (если не установлен) from bs4 import BeautifulSoup as Soup from selenium.webdriver import Firefox, FirefoxOptions opt = FirefoxOptions() opt.headless = True site = Firefox(options=opt) site.implicitly_wait(10) class Client: def __init__(self): pass def load_page(self): town = input('Введите название города на английском в нижнем регистре : ') category = input('Введите название категории : ') pages = int(input('Введите примерное число страниц :')) url_list = ['https://2gis.ru/{town}/search/{category}/page/{page}'.format( page=page, town=town, category=category ) for page in range(1, pages + 1)] print(url_list) for url in url_list: site.get(url) table = site.find_element_by_tag_name('body') text = table.get_attribute('outerHTML') self.parse_page(text=text) def parse_page(self, text): soup = Soup(text, 'html.parser') container = soup.find_all('div', class_='_y3rccd') for block in container: self.parse_block(block=block) def parse_block(self, block): name = block.find('span', class_='_hc69qa').text name_zav = block.find('span', class_='_oqoid').text location = block.find('span', class_='_tluih8').text print(name, ' - ', name_zav, ' - ', location) if name == 'main': parser = Client() parser.load_page() site.close() site.quit() It's not very clear why you created a class here.
List the registration number in Java
Software Programming • java loops c languageyc languageles • • jeanid

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I don't know how well you want to list, I understand it's the way out of your program.Since you print the messages in a loop for use to list.System.out.println((x+1) + " Nombre: "+ nombre[x].toUpperCase()+" Edad: "+ edad[x]+" Eres menor de edad Sexo:Mujer Nacionalidad: Mexicana ");
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How do you find a minimum number among the numbers of the numbers?
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I don't see about the 2 thes, but let's say they are.let arr1 = [-10, 12, -12, 40, 35, 100] let arr2 = [-100, 81, 0, 1, 1, -101.2]; let min = Math.min(...arr1.concat(arr2)); console.log(min);
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How do you change the background-image size in PyQt5?
Software Programming • python pyqt5 gui pyqt qs • • Saumya

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Try this:import sys from PyQt5 import QtCore, QtGui, QtWidgets #, QtQuick from PyQt5.Qt import * #import os #import pathlib #import PyQt5 class Login(QtWidgets.QMainWindow): switch_window = QtCore.pyqtSignal() def __init__(self): QtWidgets.QMainWindow.__init__(self) self.setFixedSize(400, 180) self.setWindowTitle('Login') self.setObjectName("log") vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv self.resize(400, 180) background = QPixmap("im.png").scaled(400, 180) pal = self.palette() pal.setBrush(QPalette.Background, QBrush(background)) self.setPalette(pal) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ self.button = QtWidgets.QPushButton(self) self.button.setGeometry(QtCore.QRect(135, 100, 130, 40)) self.button.setText("Login") self.verification_lane = QtWidgets.QLineEdit(self) self.verification_lane.setGeometry(QtCore.QRect(100, 50, 200, 30)) self.verification_lane.returnPressed.connect(self.button.click) self.verification_lane.setAttribute(QtCore.Qt.WA_MacShowFocusRect, 0) def main(): app = QtWidgets.QApplication(sys.argv) ls = Login() ls.show() sys.exit(app.exec_()) if name == 'main': main() Do you have to give the screen size through the resize? I don't want to be able to change the size of the window by the cadet. Not necessarily. Do what you need.import sys from PyQt5 import QtCore, QtGui, QtWidgets #, QtQuick from PyQt5.Qt import * class Login(QtWidgets.QMainWindow): switch_window = QtCore.pyqtSignal() def __init__(self): QtWidgets.QMainWindow.__init__(self) self.setFixedSize(400, 180) self.setWindowTitle('Login') self.setObjectName("log") vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv self.resize(400, 180) background = QPixmap("im.png").scaled(400, 180) pal = self.palette() pal.setBrush(QPalette.Background, QBrush(background)) self.setPalette(pal) ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ self.button = QtWidgets.QPushButton(self) self.button.setGeometry(QtCore.QRect(135, 100, 130, 40)) self.button.setText("Login") self.verification_lane = QtWidgets.QLineEdit(self) self.verification_lane.setGeometry(QtCore.QRect(100, 50, 200, 30)) self.verification_lane.returnPressed.connect(self.button.click) self.verification_lane.setAttribute(QtCore.Qt.WA_MacShowFocusRect, 0) def main(): app = QtWidgets.QApplication(sys.argv) ls = Login() ls.show() sys.exit(app.exec_()) if name == 'main': main()
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I believe that https://docs.djangoproject.com/en/1.9/ref/contrib/admin/#django.contrib.admin.ModelAdmin.filter_horizontal django will solve your problem.In your admin.py class, put the tag to indicate that.class BookAdmin(admin.ModelAdmin): filter_horizontal = ('author',) admin.site.register(Book) You will have a multiple select equal to that of permission with the option of adding a new element.
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Column filter in DataFrames
Software Programming • python python 3.x pandas jupyter • • jules

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The problem is that in the column income There is no string "<=50k", it is " <=50k"There's a space ahead. This occurs in all columns less in the first and is caused because the file has the following structure:39, State-gov, 77516, Bachelors, 13, ..., <=50K By default pandas.read_csv Use "," as a column separator which makes you consider the space after the coma as part of the next column. In columns that are parsed to int space is simply discarded, but in columns that are of type str (object) the space remains part of it, being quite easy to overlook it by showing the DataFrame or the crib, unless we show the contents of a particular cell:>>> data.income[0] ' <=50K' The solution is as simple as specifying ", " as a separator:data = pd.read_csv('adult.data', header=None, names=names, sep=", ") As a separate note, do not use the inverted bar (\) on routes even if you are on Windows, this character is used in an unraveled chain to indicate escape sequences (\n, \r, \t, \s, \x45etc.). Sooner or later you will have a problem with it, for example "C:\nuevos_datos" It's an invalid route because \n indicates a line jump.... Use raw chains, r"C:\nuevos_datos", although given as a solution in many cases, it also has problems and should be avoided. Instead, always use the tilted bar /which is also universal between operating systems.
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Unit testing for chains of generators in Python
Automated Testing • python unit tests • • Kadir

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Looks like a usefull test, its possibly an integration test. That said you should put this in a unitest2.testcase class https://docs.python.org/dev/library/unittest.html It works nicely with pytest https://docs.pytest.org/en/latest/unittest.html You can create all your fixtures in the setUpClass method then all the methods starting with test_ are executed and you can use a nice library of built in assertions. You you can add your generator generator functions as methods on your TestCase instance then call them from its test_ methods. Both those links cover the rest of the details.
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Login on facebook with python
Software Programming • python python 3.x http • • magpie

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With requests (only) it's hard to log into the facebook, because they should bet on javascript to generate additional data for security, and it would be very tricky to track everything that happens. In addition, you must submit (method post) all the form values. I know that because I've tried it too and it didn't just work with requests.However it has other modulos that can help.For python >= 2.4 and < 3 (python 2.x), you can use http://wwwsearch.sourceforge.net/mechanize/ : import mechanize url = 'https://m.facebook.com' loggedin_title = 'Facebook' # isto vai servir para confirmarmos que estamos loggedin, vendo o titulo da pagina para onde fomos redirecionados username = 'USERNAME' password = 'PASSWORD' browser = mechanize.Browser() browser.set_handle_robots(False) browser.addheaders = [('User-Agent', 'Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US; rv:1.9.0.6)')] browser.open(url) browser.select_form(nr=0) browser.form["email"] = username browser.form["pass"] = password browser.submit() if browser.title() == loggedin_title: print '[+] SUCCESS' print 'Username: {}\nPassword: {}'.format(username, password) else: LOGIN FAILED' For python >= 3, can http://robobrowser.readthedocs.io/en/latest/installation.html the http://robobrowser.readthedocs.io/en/latest/index.html , this also makes use of modulo requests:import robobrowser import re url = 'https://m.facebook.com' loggedin_title = 'Facebook' # isto vai servir para confirmarmos que estamos loggedin, vendo o titulo da pagina para onde fomos redirecionados browser = robobrowser.RoboBrowser(history=True, parser='html.parser') browser.open(url) form = browser.get_form(id='login_form') form['email'].value = 'USERNAME' form['pass'].value = 'PASSWORD' browser.submit_form(form, submit=form['login']) redirect_title = re.compile('<title>(.*?)</title>').search(str(browser.parsed)).group(1) if(redirect_title == loggedin_title): print('[+] SUCCESS') print('Username: {}\nPassword: {}'.format(form['email'].value, form['pass'].value)) else: LOGIN FAILED') This last one doesn't have to define headers, but it can. This by default headers are sufficient and valid for facebook.Note that this code is only stable until the facebook changes the login mechanics, if this happens will need to be adapted http://facebook-sdk.readthedocs.io/en/latest/api.html has the 'official' alternative offered by the facebook itself.
N

Turn the list into one list
Software Programming • python python 3.x python 3.7 python 3.6 • • nishika

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l1 = [[1, 2, 3], [4, 5, 6]] print(sum(l1, [])) # [1, 2, 3, 4, 5, 6] from itertools import chain print(list(chain.from_iterable(l1))) # [1, 2, 3, 4, 5, 6] l2 = [['12', '34'], ['56', '78']] print(list(map(''.join, l2))) # ['1234', '5678'] Options with librarians:from numpy import array from pandas.core.common import flatten l = [[1, 2, 3], [4, 5, 6]] print(list(array(l).flat)) print(list(flatten(l)))
T

Imaging libraries
Software Programming • python python 3.x numpy opencv image processing • • tahishae

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There are a few libraries that will be able to accomplish your task. One of the most powerful and committed https://opencv.org/ ♪ It is relatively complex installing and requires some skills with the Unix system (Windows) preferably through the console. There's a big collar of your functions to process images. https://www.geeksforgeeks.org/reading-images-in-python/ work.Another library that is designed to work with images. It's easier in the installation, but less comfortable. That's it. https://pillow.readthedocs.io/en/stable/ ♪ https://stackoverflow.com/questions/48729915/reading-images-in-python work. It should be noted that, in both cases, images can lead to images. numpy.array♪ https://numpy.org/ standard library written on C to work effectively with the matrices.Example of ghosts:from PIL import Image import numpy as np im = Image.open('hopper.jpg') a = np.asarray(im) After that, you'll be able to cross all the pics of the picture around the way:for i in a: for j in a[i]: do_smth(a[i][j])

How do you turn the numbers on the list into numbers?

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