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Explain, please, a piece of code.

N
Nykeriab last edited by
Two NxN dimensions A and B are available.
```
    for (Elem=(!Row)?0:(Row-1); Elem<N; B[Row][Elem]=A[Row][Elem], Elem++) 
      cout<<Elem+1<<", ";
     }
```
Problems with this part Elem=(!Row)?0:(Row-1)
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zymir last edited by
It's written. https://purecodecpp.com/archives/554 ♪
His appearance:
```
<Выражение> ? <если истина> : <если ложь>
```
In your case, if the value Row No, then the meaning. Elem No, no. Row-1♪
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This fragment of the code is perfectly correct, as the operator delete Use the value stored in the indicator, which is equivalent to the value previously obtained using the operator new. int* a = new int[4]; ++a; --a; delete [] a; It doesn't matter to the operator what the signer had before, and how it changed. To make it even more visible, you can write, for example,int x; int *px = &x; int* a = new int[4]; px = a; a = &x; delete [] px; However, this fragment of the codeint* a = new int[4]; ++a; delete [] a; Incorrect, as an index a does not contain the address of the dynamic memory. delete and free Applicable to the value of the indicator new or malloc: this requirement of the standard. Usually, under the hood, the operator is doing the following. The required amount of memory that you want to distinguish is added to the beginning of the block of prefix, which will store this size of the memory block. And the address of this prefix is simply calculated as a change in the size of the word (usually sizeof( int)) from the beginning of the memory area to which the new operator ' s user returns. This value is used to correctly assess the size of the memory when it is removed.As for your second question, you can write, for example,int* a = new int[4]; int ( p )[4] = reinterpret_cast<int()[4]>( a );
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It was supported by a book called Information Coding (twice codes). Berezyuk N. T., Andrushenko A. G., Mighty S. C."In the correlation method, the dual code changes 0 to 01 and 1 to 10 respectively. In that case, instead of k=7 numbers in the code, there will be k*2, i.e. twice as many.You just need to make a couple of units in the password check. If the units aren't a couple, they just add a unit at the end of the code. If it's a couple, it's zero.It turned out pretty simple.
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#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; int main() { const auto req_ext = ".a"; for (const auto& filename : fs::directory_iterator("/usr/lib")) { if (!fs::path(filename).extension().compare(req_ext)) std::cout << "file: " << filename << "\n"; } return 0; } Don't forget to point out. stdc++fs On the library list for the blinkers.Option for CMake:target_link_libraries(${PROJECT_NAME} PRIVATE stdc++fs) UPD. : If you need regular expressions for some reason, see the code below (option for linux-based OS). #include <iostream> #include <dirent.h> #include <regex> int main() { dirent* dirp; std::regex ext_regex("[a-z]+\.a"); if (DIR *dp = opendir("/usr/lib")) { while ((dirp = readdir(dp))) { if (std::regex_match(dirp->d_name, ext_regex)) { std::cout << dirp->d_name << "\n"; } } closedir(dp); } return 0; }
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Please indicate how to put the code from the block else into a separate java method.
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Hurry up, of course you have a container.You need to transfer to the function not the primitives themselves, but the containers and indices for exchange:public static void swapChars(char[] s, int i, int j) { char t = s[i]; s[i] = s[j]; s[j] = t; } swapChars(letters, i, j); It's your swap function.Java can't do that for primitives.I need a scrubbler.You can make this colt.char swap(char a, char b) { return a; } letters[j] = swap(letters[i], letters[i]=letters[j]); The first argument is replicated before the assignment is performed for the second argument)
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I guess. Not true_total += cost atrue_total += price * amount
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How can I repeat this, how ridiculous it sounds without repeating it?I don't need a mass without repetition, and I just need to get a repetition.void Main() { var nums = new[] {1,2,2,3,4,5,5,5,7}; GetDupes(nums).Dump(); } // You can define other methods, fields, classes and namespaces here public int[] GetDupes(int[] nums) { var dict = new HashSet<int>(); var result = new HashSet<int>(); foreach (var item in nums) { if(dict.Contains(item)) result.Add(item); else dict.Add(item); } return result.ToArray(); }
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Try organizing the Models (or the essence) differently.public class Employee { [Key] public int Id { get; set; } [Required] public string FirstName {get; set;} [Required] public string Lastname {get; set;} public string Patronimic {get; set;} [Display(Name = "Company Name")] public int CompanyId { get; set; } [ForeignKey("CompanyId")] public virtual Company Company {get; set;} } public class Company { [Key] public int CompanyId { get; set; } public string CompanyName {get; set;} } Next, you need to create a CRUD operation for these two models. ViewBag could be used to extract a list of existing companies, but it would be better to adhere to the strict typology of the submissions, so that ViewModel would still be needed for the Employees. Here. https://github.com/AndyBrizhak/Rocky Repository with ASP.NET Core MVC for NET 5, which addresses a similar problem for the connections of the Tovars and their Categories.
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You misread the capital letter. I (ye) with a letter l (el) In words writeLn and readLn♪
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I'll risk assuming there's a problem with the thermal operator. The terminal operator returns r-value, and the reference returned from the method refers specifically to the temporal variable with the r-value rather than to the mass element.PS code:why accentuate count before or after call Allocateif Allocate It's the field. count new meaning?Indicator signatures are strange. Usually, in the collections, the constant overloading of the indexor returns the constant reference and the non-constant overloading is the usual reference. Because when someone writes const Data::Array<Point> - he's expecting a complete recurrenceAllocate will lead to memory leaks if the code in the cycle leaves the exceptionIn method Allocate Appropriation temp[i] = T() superfluous for all but primitive. new
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1st declare the library: #include <locale.h> 2nd place at the beginning of the main function:setlocale(LC_ALL,""); // Este comando pega o idioma da maquina que está rodando. //setlocale(LC_ALL, "Portuguese"); // Caso o idioma da sua máquina não seja Portugues, use este. #include <iostream> #include <locale.h> using namespace std; int main() { setlocale(LC_ALL,""); cout <<"Acento é legal"<< endl; }
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That's the full code and you can see what he's doing.Well, for you to understand how it works, just look what the cycle is. https://developer.mozilla.org/ru/docs/Web/JavaScript/Reference/Statements/for ♪What does the operator mean? https://developer.mozilla.org/ru/docs/Web/JavaScript/Reference/Operators/Arithmetic_Operators %♪function chess(){ for(var i = 0;i<8;i++){ for(var j = 0;j<8;j++){ if((i%2==0 && j%2== 0) || (j%2!=0 && i%2!==0)){ $("#board").append('<div class="white"></div>'); }else{ $("#board").append('<div class="black"></div>'); } } } } chess();#board{ width: 80px; height: 80px; background: green; padding: 5px; } .white, .black{ width:10px; height: 10px; float: left; } .white{ background: white; } .black{ background: black; }<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div id="board"></div>
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You mean this?where T1 : BaseCollectionDefinition<T1, T2, T3, T4> where T2 : BaseCollection<T1, T2, T3, T4> where T3 : BaseItemDefinition<T1, T2, T3, T4> where T4 : BaseItem<T1, T2, T3, T4> It's so-called. https://docs.microsoft.com/ru-ru/dotnet/csharp/programming-guide/generics/constraints-on-type-parameters ♪ BaseCollection<T1, T2, T3, T4> - We have. https://docs.microsoft.com/ru-ru/dotnet/csharp/programming-guide/generics/generic-classes where T1, T2 etc are objects satisfying the limitations of the blocks where - in this case they must be copies of the heirs of the classes.
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The problem I have in this case is in the Student class when using vectors I can enter data but at the time of showing the data only shows me the same data several timesSomething, on the other hand, logical and normal, since on the list you are entering, all the time, the same pointerint main() { vector <Persona*> persona; Estudiante* objEstudiante=new Estudiante(); // <<--- The highlight line is the only place where an instance of Estudiante ... the only thing you do later is modify the data stored on that pointer and add the pointer to the list.If you print the memory addresses stored on the pointer you'll get something like this:0x04f5340c 0x04f5340c 0x04f5340c 0x04f5340c 0x04f5340c ... I mean, on the list you're storing the same data repeatedly.To make the program work, consider creating a new element every time you need it: case 1: system("cls"); do { Estudiante* estudiante = new Estudiante; estudiante ->addData(); persona.push_back(estudiante ); cout << "Desea ingresar otro dato (S/N)" << endl; cin >> resp; } while (resp == 's' || resp == 'S'); _getch(); break; Now you could claim you're not having the same time with class. Empleado ... when the truth is that the object is only created once. In this second case the program works because the list stores the objects value instead of storing pointers. This trivial detail is important because, by adding an element to this list, the program has to create a copy type object Empleado. The copy will be completely autonomous, so your state will not be altered if you later modify the original instance.It can be seen quickly with native types:int a = 5; int b = a; // Copiamos el estado de 'a' en 'b' a = 7; // Es obvio que este cambio no afecta a 'b' And to finish, don't forget that the memory you book then you have to release it. That of waiting for the program to die for the release of resources is not a custom you want to acquire, believe me.You filled the list. persona of objects stored in dynamic memory reserves and its thing is to release such reservations when they are no longer necessary: }while (op); for( auto elemento : persona ) delete elemento; return 0; }
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In order to answer this question, reference should first be made to the language standard C, which introduced the concept of anonymous structures and anonymous associations.Standard C 2011 defines anonymous structures and anonymous associations as follows (6.7.2.1 Structure and union specifiers)13 An unnamed member of structure type with no tag is called an anonymous structure; an unnamed member of union type with no tag is called an anonymous union♪ The members of an anonymous structure or union are considered to be members of the containing structure or union. This applies recursively if the containing structure or union is also anonymous.As can be seen from this definition, not every unnamed structure or unnamed association is anonymous. Only unnamed structures and no-named associations that are members of other structures or associations are anonymous.There are no anonymous classes in C+++, i.e. classes declared with a key word struct or classbut there are anonymous associations defined as follows (Standurt C++, Section 9.5 Unions)5 A union of the formunion { member-specification } ; is called an anonymous union; it defines an unnamed object of unnamed type♪ The member-specification of an anonymous union shall only define non-static data members. [ Note: Nested types and functions cannot be declared within an anonymous union. The names of the members of an anonymous union shall be distinct from the names of any other entity in the scope in which the anonymous union is declared. For the purpose of name lookup, after the anonymous union definition, the members of the anonymous union are considered to have been defined in the scope in which the anonymous union is declared. [ Example:void f() { union { int a; const char* p; }; a = 1; p = "Jennifer"; } Here a and p are used like ordinary (nonmember) variables, but since they are union members they have the same address. -end example ]As can be seen from this definition, the notion of anonymous association in C+++ is different from the corresponding definition of anonymous association in C. In C+++, you may declare an anonymous association outside any structure or association.Who is more interested in this issue, may also examine the topic I have opened on the subject. https://groups.google.com/a/isocpp.org/forum/#!topic/std-discussion/ZIVHmLqGqaY
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The return of the method may be part of the class? C++
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class TestClass { public: AnyStructure& getStructure() { return this->testStructure; } private: AnyStructure testStructure; }; That's the way it is.

Explain, please, a piece of code.

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