After var = int(input() does not work if var == sync, corrected by elderman == @elder_man

[derk]

I'm trying to create a program that calculates the number of beads that need to be obtained so that the colors can be repeated. I want to prohibit the selection of 0 as the number of flowers (that is illogical) and to prohibit the writing of any other symbols other than the numbers, because the program just breaks. I would also like to receive advice on how to make the code more comfortable. I'll gram for a couple of days. ♪ ♪ I tried through. typick = type(colors) If typick == sync, corrected by elderman == @elder_man And if the solors == sync, corrected by elderman == @elder_man I hope you'll help me.

    # Минимальное число бусин, которое нужно достать, чтобы цвета повторились при производном количестве цветов
def businki():  # задаём функцию businki и вкладываем в неё наш калькулятор

print('Введите количество цветов:')

colors = int(input('> '))

result = colors + 1

posled = result % 10  # сокращает число до последней цифры

result = str(result)

if posled == 1:

print('Нужно достать ' + result + ' бусинку, чтобы цвета повторились')

elif posled == 2 or posled == 3 or posled == 4:

print('Нужно достать ' + result + ' бусинки, чтобы цвета повторились')

else:

print('Нужно достать ' + result + ' бусинок, чтобы цвета повторились')
while True:

businki()

[carriann]

Just make sure it's still in control. Structural type♪ And if the row is composed of numbers, then turn it into number and check the number tolerance. All this will be arranged in a cycle that will be re-examined until the introduction meets all the conditions.

    print('Введите количество цветов:')
    while True:
        colors = input('> ')
        if not colors.isdigit():
            print('Количество должно быть ЧИСЛОМ! Повторите ввод.')
            continue
        colors = int(colors)
        if colors > 0:
            break
        print('Количество должно быть БОЛЬШЕ НУЛЯ! Повторите ввод.')
result = colors + 1
...