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Removed countries connect a number of countries to the three largest cities of each country. The program will have the city's name on the entrance to the variable city. And your job is to find what country the city has built. If the country is successfully found, the message must be deleted:

    countries = {
        "Sweden": ["Stockholm", "Göteborg", "Malmö"],
        "Norway": ["Oslo", "Bergen", "Trondheim"],
        "England": ["London", "Birmingham", "Manchester"],
        "Germany": ["Berlin", "Hamburg", "Munich"],
        "France": ["Paris", "Marseille", "Toulouse"]
    }
city = input()
for city in countries:
    if city == countries[1]:
        print(f 'INFO: {city} is a city in {countries}')
    else:
        print(f 'ERROR: Country for {city} not found')

Cleofas

countries = {
    "Sweden": ["Stockholm", "Göteborg", "Malmö"],
    "Norway": ["Oslo", "Bergen", "Trondheim"],
    "England": ["London", "Birmingham", "Manchester"],
    "Germany": ["Berlin", "Hamburg", "Munich"],
    "France": ["Paris", "Marseille", "Toulouse"]
}

city = input()
for country, cities in countries.items():
    if city in cities:
        print(f'INFO: {city} is a city in {country}')
        break
else:
    print(f'ERROR: Country for {city} not found')

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How to remove each ip address from a range like 192.168.1.5-10
Software Programming • python ip • • Pearlaqua

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Range>>> import ipaddress >>> start = ipaddress.ip_address('192.168.0.1') >>> stop = ipaddress.ip_address('192.168.0.15') >>> >>> while start<=stop: ... print(start) ... start+=1 ... 192.168.0.1 192.168.0.2 192.168.0.3 192.168.0.4 192.168.0.5 192.168.0.6 192.168.0.7 192.168.0.8 192.168.0.9 192.168.0.10 192.168.0.11 192.168.0.12 192.168.0.13 192.168.0.14 192.168.0.15 Even without a cycle.for addr in ipaddress.summarize_address_range(start, stop): print(addr) Or sit down.>>> for addr in ipaddress.ip_network('192.0.2.0/255.255.255.0'): ... addr ... IPv4Address('192.0.2.0') IPv4Address('192.0.2.1') IPv4Address('192.0.2.2') IPv4Address('192.0.2.3') IPv4Address('192.0.2.4') IPv4Address('192.0.2.5') IPv4Address('192.0.2.6') IPv4Address('192.0.2.7') IPv4Address('192.0.2.8') .... IPv4Address('192.0.2.255') These methods also work for ipv6
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Use of rollback team in PostgreSQL
Software Programming • python postgresql psycopg2 • • Cleofas

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This method will reverse the changes in the current transaction:conn.autocommit = False cursor.execute("CREATE TABLE test()") cur.rollback() After completion, the table with the name test will not be established. If you do so:conn.autocommit = False cursor.execute("CREATE TABLE test()") cur.commit() the table will be established. The same applies to any transactions from the beginning to the end of the transaction. Transaction Manual https://postgrespro.ru/docs/postgrespro/10/tutorial-transactions
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Call python machine learning model from UDF or SP
SQL, Database Testing • python postgresql functions stored procedure • • guilherme

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You have basically three options: Have a program written in Python, that uses PsycoPG, PyGreSQL or some other driver with equivalent functionality to get the data out of PostgreSQL and process it in Python. Or you could use some toolkit like SQLAlchemy, which works as an Object Relational Mapper. Write a User Defined Function using PL/Python, which means you actually write UDFs within PostgreSQL using the Python language. If your model works with a certain function model_predict(a, b, c), you can call it in a fashion similar to: SELECT a, b, c, model_predict(a, b, c) AS prediction FROM table WHERE Export the data from PostgreSQL (with COPY FROM ..., or using any tool such as pgAdmin), into a suitable format (such as CSV), and then import it and process in Python (you could use Pandas read csv, e.g.).
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Help with jquery
Software Programming • jquery • • jules

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Create a function:var resize_ = function () { var alto = $('#bigPic img').height(); //alto de la imagen $('#bigPic').height(alto * 1.1); }); //alto div = alto imagen * 1.1 } Then you call it where you need it:var resize_ = function () { var alto = $('#bigPic img').height(); //alto de la imagen $('#bigPic').height(alto * 1.1); //alto div = alto imagen * 1.1 } $( window ).on( "load", function() { alert("paso"); resize_ (); }); $(window).resize(function() { resize_ (); }); So the function resize, it works for you at the two events that you ask.Greetings,
K

Event- challenge
Software Programming • javascript html web programming • • kalena

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<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8"> <title>Chat</title> <link rel="stylesheet" href="style/style.css"> <style> .mainmenu { width: 250px; height: 638px; background-color: gray; margin-left: -240px; transition-property: margin-left; transition-duration: 2s; </style> </head> <body class="chatbg"> <div class="header"></div> <div class="mainmenu" id="menu" onclick="scrolMenu()"></div> <div class="chat"></div> <script type="text/javascript"> var isClicked = false; function scrolMenu() { var main = document.getElementById('menu'); if (!isClicked) { main.style.marginLeft = "0px"; isClicked = true; } else { main.style.marginLeft = "-240px"; isClicked = false; } }; </script> </body> </html>
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Help me meet the list challenge.
Software Programming • python python 3.x • • magpie

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not correctly read the condition, the solution is appropriate for the reverse task and is looking for the amount of the Fibonacci numbers on the list.I think it's convenient for me to check if the number on the list is Fibonacci.T.e. available https://ru.wikipedia.org/wiki/%D0%A7%D0%B8%D1%81%D0%BB%D0%B0_%D0%A4%D0%B8%D0%B1%D0%BE%D0%BD%D0%B0%D1%87%D1%87%D0%B8#%D0%A4%D0%BE%D1%80%D0%BC%D1%83%D0%BB%D0%B0_%D0%91%D0%B8%D0%BD%D0%B5 (both of n) and pick up definition for the gold section. Ah, also the investigation that the number of Fibonacci is rounded and Function will be:def is_fib(n): phi = .5 + .5 * math.sqrt(5.0) value = phi * n return abs(round(value) - value) < 1 / n or n == 0 Well, then check all the sequences and the meaning True take charge numbers and sumresult = 0 our_list = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17] for value in our_list: if is_fib(value): result += our_list.index(value) print(result) Don't forget to connect. mathI'll add the right decision.The basis was to give up the unnecessarily number of iterations, the cycle while the correct solution.So, we'll work on the following list:our_list =[1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,0] We can find a zero index:last_index = our_list.index(0) >>> last_index 17 The following function determines the nearest number of Fibonaccis to the designated entrance:def reverse_fib(value): phi = .5 + .5 * math.sqrt(5.0) if value < 2: return value return (int(round(log(value * 5 ** .5) / log(phi)))) # phi определено выше reverse_fib(last_index) >>> amount_fib = reverse_fib(last_index) 8 We'll write a lecture to find Fibonacci's chiel with a given number of members n:def fib(n): if n == 0 or n == 1: return n else: return fib(n - 1) + fib(n - 2) Let's try:indexes = [fib(i) for i in range(amount_fib)] >>> indexes [0, 1, 1, 2, 3, 5, 8, 13] Oh, now to our list:result = 0 for k in indexes: result += our_list[k] >>print(result) 41 It may be necessary to add some extremes to be processed, but logically, it is correct.
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localStorage Help
Software Programming • • Saumya

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We will introduce three ways from abusive method to a decent method.A. Save and return innerHTML as it isWhen the TODO list is updated (if you delete the data when you change the present click handler or ◉),todolist-a innerHTMLHomelocalStorageSave.On page loadinglocalStorageIf you have data inside,todolist-a innerHTMLset.It can be realized by a few lines in the code that is presented, but it is a totally miscellaneous method and it is difficult to change the markup in the list. This means will not be taken.B.を生成するrate data arrays only when neededWhen the TODO list is updated,todolist-aIn the構造 structure, we construct the following array,JSON.stringify()HomelocalStorageSave[ {status:'◉', task:'家賃を払う'}, {status:'◉', task:'〇〇さんのメールに返答する'}, ] On page loadinglocalStorageIf you have data insideJSON.parse()return the array data and from the array datatodolist-aReconstruction of markup insideC. Array primary informationAlways keep it not to build every time you save an array like配列.If there is a change in the TODO item, find the corresponding array element and update it only.JSON.stringify()HomelocalStorageSave Example: Delete the third item in the array when the trash icon of the third <li> is pressedSame as page loadingI think C is the most matomo, but I think it is enough for B if the amount of data is low.There are many libraries in the world that make it easy to respond to JavaScript data and HTML expressions.
Help solve the problem with Unity/Android
Software Programming • unity3d • • morde

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Come in. Edit ation Preferences ation External Tools And see if there's a JDK necklace, if there's no way you can rewrite it.What's your version of Unity? I had a problem like this at 2021.1.16f1, set up at 2021.1.15f1 and a mistake went missing.
Unindent, I don't find it
Software Programming • python • • Demir

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The mistake is in try without except. That's how he looked before:def leer(id): try: sql = ''' SELECT NOMBRE, APELLIDOS, CONTRASEÑA, DIRECCION FROM DATOSUSUARIOS WHERE ID= {} '''.format(id) cursor = db.cursor() cursor.execute(sql) data = cursor.fetchall() db.commit() return data def actualizar(id, datos): try: Like try is not complete, Python meets with def actualizar When he's waiting for a exceptLike this:def leer(id): try: sql = ''' SELECT NOMBRE, APELLIDOS, CONTRASEÑA, DIRECCION FROM DATOSUSUARIOS WHERE ID= {} '''.format(id) cursor = db.cursor() cursor.execute(sql) data = cursor.fetchall() db.commit() return data except SomeException: do_something def actualizar(id, datos): try: Note: This is just an example of how it could be written. The final code should reflect the requirements of the original problem.
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How do I draw random names from each list without repeating them
Software Programming • python python 3.x random • • Saumya

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You can simply shuffle the lists and then browse them with https://docs.python.org/3/library/functions.html#zip (which serves to go through several lists at the same time):from random import shuffle j1 = ['Jose', 'Bruno', 'Lucas', 'Eduardo', 'Pedro', 'Luciano', 'Vitor', 'Diego', 'Rômulo', '*Pisca'] j2 = ['Carlinhos', 'Carlos', 'Davi', 'Thiago', 'Paulo', 'Igor', 'Felipe', 'Marcelo', 'Matheus', 'Fabio'] j3 = ['Artur', 'Anderson', 'Gustavo', 'Rogerio', 'Marcus', 'Nando', 'Jorge', 'Rodrigo', 'Caio', 'Jonas'] shuffle(j1) shuffle(j2) shuffle(j3) for n, (c1, c2, c3) in enumerate(zip(j1, j2, j3), start=1): # imprime as outras mensagens, etc print(f' \033[34mEQUIPE {n}\033[m') print(f'{c1}\n{c2}\n{c3}') I also use https://docs.python.org/3/library/functions.html#enumerate to get the index at the same time I scroll through the lists (and use the argument start so that the count starts with 1, since by default it starts at zero). That's better than using a range specific, since this works independently of the size of the lists (assuming that all of them have the same size, since zip ends when the smallest of them ends).So, every iteration, n is the index and c1, c2 and c3 are one of the list names j1, j2 and j3. And since they were previously embarrassed, I guarantee that teams will be chosen randomly.The problem is that https://docs.python.org/3/library/random.html#random.shuffle ends up modifying the list itself.If you want to keep the original lists intact, you can use https://docs.python.org/3/library/random.html#random.sample , which returns another shuffled list:from random import sample j1 = ['Jose', 'Bruno', 'Lucas', 'Eduardo', 'Pedro', 'Luciano', 'Vitor', 'Diego', 'Rômulo', '*Pisca'] j2 = ['Carlinhos', 'Carlos', 'Davi', 'Thiago', 'Paulo', 'Igor', 'Felipe', 'Marcelo', 'Matheus', 'Fabio'] j3 = ['Artur', 'Anderson', 'Gustavo', 'Rogerio', 'Marcus', 'Nando', 'Jorge', 'Rodrigo', 'Caio', 'Jonas'] def embaralha(lista): # retorna uma cópia da lista, só que embaralhada return sample(lista, k=len(lista)) for n, (c1, c2, c3) in enumerate(zip(embaralha(j1), embaralha(j2), embaralha(j3)), start=1): print(f' \033[34mEQUIPE {n}\033[m') print(f'{c1}\n{c2}\n{c3}') Or still:for n, (c1, c2, c3) in enumerate(zip(*map(embaralha, [j1, j2, j3])), start=1): print(f' \033[34mEQUIPE {n}\033[m') print(f'{c1}\n{c2}\n{c3}')
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Javascript: one-time challenge - (definition of function and challenge of function) in one line
Software Programming • javascript parameter founction • • Cleofas

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I understand that you need this task. In order for the function to be carried out in initialization, it should be placed in brackets and, after the new brackets, the parameters of the function should be indicated or left empty.(function (value) { console.log(value) })(15);If you're interested in the one-time challenge of the function, you'll have the first case, in the second case, if you need to link this function to a processor of events, because you can't turn to such a function from the global field of visibility. var eventHandler = function functionName() { alert('Вызов функции'); return functionName; }(); document.getElementById('button').onclick = eventHandler;<button id="button">Click me!</button>
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It's not possible to create virtualenv
Software Programming • python • • emerson

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I'd like to know what team you're building a virtual environment.However, on the basis of your communication, there is no error, and it says that: A virtual environment has been created for 1935ms CPython3Windows(dest=P:\test5\venv, clear=False, global=False) with seeder FromAppData pip=latest settools=latest wheel=app_dpyir=C:Users\John\vrt1This is the place where the environment was created:For launch, go through the terminal to Director P:\test5 and write venv\Scripts\activate
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Help with Fetch_Array
Software Programming • php sql • • authera

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La http://php.net/manual/es/mysqli-result.fetch-array.php reads as follows:Gets a row of results as an associative, numerical array, or both.Really, when you run query is returned a set of results that must be read with any of the methods that exist, among them fetch_array. But we have to go through the results. If you use it without going row by row it will return only the front row, as it is actually happening. Therefore, when you wait multiple rows, you must open a loop that collects the set of results and enter an array (or prints directly if necessary) the different rows.For example, we will read row by row using a loop while:$MDB = mysqli_connect( 'localhost', 'root', '', 'LOGIC' ) ; $Q = mysqli_query( $MDB, "SELECT nombreAlumnos FROM DATES" ) ; while($row = mysqli_fetch_array($Q, MYSQLI_ASSOC);) { $a_y[] = $row; } Here's your variable $a_y will be an associative array with the data of each row.To read it you can do something like:foreach ($a_y as $row){ echo $row["nombreAlumnos"].PHP_EOL; } If you want a numerical array, you do it like this:while($row = mysqli_fetch_array($Q, MYSQLI_NUM);) { $a_y[] = $row; } And the reading would be like this:foreach ($a_y as $row){ echo $row[0].PHP_EOL; } Object-oriented styleAs a last recommendation, I suggest you pass the object-oriented style, it is much clearer and much more modern:$MDB = new mysqli("localhost", "root", "", "LOGIC"); $Q = $MDB->query("SELECT nombreAlumnos FROM DATES" ); while($row = $Q->fetch_array(MYSQLI_ASSOC)) { $a_y[] = $row; } You can also use the methods directly: http://php.net/manual/es/mysqli-result.fetch-assoc.php : when you want an associative arrangement. http://php.net/manual/es/mysqli-result.fetch-row.php : when you want a listed arrangement http://php.net/manual/es/mysqli-result.fetch-all.php : when you want to pass all the results directly to an array. You don't need to open a loop here. But this is not recommended when many results are expected because memory may collapse. Also, this method only works if you have installed the driver mysqlnd (see documentation on the link).
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How do you find the average value of every four elements of the mass?
Software Programming • python pandas numpy data analysis • • terrea

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Try this:res = (df .groupby(np.arange(len(df)) // 4) .agg({"Time": "last", "Value1": "mean", "Value2": "mean"})) Result: Time Value1 Value2 0 15 38.90 21.7825 1 10 10.55 7.6250
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Acceleration of processing itertools.permutations()
Software Programming • python python 3.x memory producer • • Saumya

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Method itertools.permutations generates a terator for all the transformations. This means that all combinations are not listed immediately, but only the calculation rule is applied. When you writelist(itertools.permutations(mess[i])) all the reverts and a list of them are being calculated and forgotten. The terator allows it to pass through the cycle, computing each terrain of the following value and forgetting the old one. That's why you have to write:for j in itertools.permutations(mess[i]): For example, https://ideone.com/GSC1DW import itertools, sys a = itertools.permutations([1, 2, 3, 4, 5, 6]) print(sys.getsizeof(a)) # 184 print(sys.getsizeof(list(a))) # 5888 shows what the difference is in memory consumption between these records.

Help me solve the challenge.

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