There is a zip and enumerate function. How can the code be simplified?

[inna]

def zi(*iterables):
    length = min(map(len, iterables))
    result = []
    for index in range(length):
        new_item = tuple(map(lambda item: item[index], iterables))
        result.append(new_item)
    return result

def enumerat(iterable, start=0):
    result = []
    for index in range(len(iterable)):
        new_item = (index + start, iterable[index])
        result.append(new_item)
    return result

[guilherme]

The key question is "HOW":

But you can ask for the code:

def zi(*iterables):
    return [tuple(map(lambda item: item[index], iterables)) for index in range(min(map(len, iterables)))]

and

def enumerat(iterable, start=0):
    return [(index + start, iterable[index]) for index in range(len(iterable))]

P. S.

using a function zip could be reduced. enumerat:

def enumerat(iterable, start=0):
    return zip(range(start, start + len(iterable)), iterable)