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Listing of objects

R
Rossere last edited by
How do you frustrate a list of objects the python? Let's say a list like this:
```
array = [
  {'x': 9, 'y': 357}, 
  {'x': 19, 'y': 357}, 
  {'x': 20, 'y': 357}, 
  {'x': 21, 'y': 357}
]
```
We need to quarry (upgrading) on the key of the object. x
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T
tahishae last edited by
If you need to change the reference list, use the function. sort:
```
array.sort(key=lambda dict_:dict_["x"])
```
and if a new one is to be created, sorted
```
array2 = sorted(array, key=lambda dict_:dict_["x"])
```
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The method persist of class EntityManager expect an entity (class noted with @Entity) as an argument, but in the passage em.persist(listaFornecedores) you are passing through one ArrayList which, although it contains, is not an entity. So the exception.To persist the list of suppliers, you must invoke the method persist for each vendor, example:public Produto inserir(Produto produto,List<Fornecedor> listaFornecedores ,Categoria categoria) { listaFornecedores=new ArrayList<>(); Conexao con = new Conexao(); EntityManager em = con.getEntidade(); em.getTransaction().begin(); for(Fornecedor fornecedor : listaFornecedores) { em.persist(fornecedor); } em.persist(categoria); em.persist(produto); em.getTransaction().commit(); em.close(); return produto; } If you are using Java 8 or larger, you can do this other way:public Produto inserir(Produto produto,List<Fornecedor> listaFornecedores ,Categoria categoria) { listaFornecedores=new ArrayList<>(); Conexao con = new Conexao(); EntityManager em = con.getEntidade(); em.getTransaction().begin(); listaFornecedores.forEach(em::persist); em.persist(categoria); em.persist(produto); em.getTransaction().commit(); em.close(); return produto; }
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Cycle longPoll.listen() is endless. The last line will never be implemented.But it's not gonna work out before the cycle, either, because in a certain time, they need to be checked, and longPoll.listen() It could sleep for a long time.I suggest that you launch a task-checking cycle (instead of their announcements) in a separate flow using the module. threading♪ To this end, create a function in which an endless cycle of checking and declaring tasks (optional). About:def scheduler(): schedule.every(5).seconds.do(send_message, 2000000013, 'Test message') while True: schedule.run_pending() sleep(1) # Выберите оптимальное значение под свои задачи планировщика And get her in a separate flow (natural, endless cycle) so she doesn't depend on it. longPoll.listen() (who can sleep for a long time) and did not interfere with his speed:t = Thread(target=scheduler) t.start() This small example, every 5 seconds, will be a function send_message(2000000013, 'Test message')♪ Example:from vk_api import VkApi from vk_api.bot_longpoll import VkBotLongPoll from vk_api.utils import get_random_id import schedule from threading import Thread from time import sleep def send_message(peer_id, message): vk.messages.send( peer_id=peer_id, message=message, random_id=get_random_id(), ) def scheduler(): schedule.every(5).seconds.do(send_message, 2000000013, 'Test message') while True: schedule.run_pending() sleep(1) # Выберите оптимальное значение под свои задачи планировщика accessToken = 'removed for security reasons' groupId = 'removed for security reasons' vkBotSession = VkApi(token=accessToken) longPoll = VkBotLongPoll(vkBotSession, groupId) vk = vkBotSession.get_api() Создаём и запускаем планировщик в отдельном потоке t = Thread(target=scheduler) t.start() Бесконечный цикл for event in longPoll.listen(): pass
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self.__patients = sorted(args, key=lambda x: x.address)
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To address the field/method, you must first clearly transform the list element to your type:((Category) list.get(0)).categoryMember But in my opinion, the initial task of sorting is done in another way.In addition to this reply, I will describe the way I meant above. This is a way of implementing the interface. Comparable facilities to be sorted.Suppose there's an object, an animal with a parameter, a weight. The list of animals should be discarded by increasing their weight. To accomplish this, we will create a class Animalan interface Comparable:public class Animal implements Comparable { private float mWeight; public Animal(float weight) { mWeight = weight; } public float getWeight() { return mWeight; } public void setWeight(float weight) { mWeight = weight; } @Override public int compareTo(Object o) { float diff = this.mWeight - ((Animal) o).mWeight; if (diff > 0) return 1; else if (diff < 0) return -1; else return 0; } } Now we can sort out a set of these animals with help. Collections.sort(...):List<Animal> animals = new ArrayList<>(); animals.add(new Animal(10.3f)); animals.add(new Animal(10.1f)); animals.add(new Animal(10.2f)); Collections.sort(animals);

Listing of objects

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