List through a flat length input
n=int(input()) s=ln(list(input()) #длина введенного списка (почему-то стак не пропускает оператор) while s<n:
I don't understand what I've written, but as far as I'm concerned, tell me how to put a fixed dime on the list, i.e. to determine the condition of the end of the entry and to accept an unlimited number of elements before this condition comes.
Bogopo last edited by
I guess that's how you do it.
n = int(input()) data = list(map(int, input().split()))[:n]
or if the length of the list was less than the given number, it may be:
n = int(input()) data = (list(map(int, input().split())) + *n)[:n]