List through a flat length input
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n=int(input()) s=ln(list(input()) #длина введенного списка (почему-то стак не пропускает оператор) while s<n:
I don't understand what I've written, but as far as I'm concerned, tell me how to put a fixed dime on the list, i.e. to determine the condition of the end of the entry and to accept an unlimited number of elements before this condition comes.
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I guess that's how you do it.
n = int(input()) data = list(map(int, input().split()))[:n]
or if the length of the list was less than the given number, it may be:
n = int(input()) data = (list(map(int, input().split())) + [0]*n)[:n]