The logic of my program looks like:There's one cycle that passes all the symbols of the first line, and there's a cycle in it that passes all the symbols of the second line. If there are two identical symbols, add them at the end of the retracting line.Not much that is boring, but also when the symbols are repeated in the lines in the final line, there will be duplicates. It's not nice, and it's not technically the assignment.I suggest the next approach.Stand by and obligate the table assistant at 256 Byte.Walk on the first line and use the symbol code as an index, establish the first battle of the radius of the mass. OR byte ptr [BP+AX], 1It's the second line, but you're setting up a second battle of the same. OR byte ptr [BP+AX], 2Come over the mass, compare the elements to 3 (1 OR 2), and remove the symbols to the code equal to the index of the completed component.
I propose an implementation of the method that accepts by parameter the number of decimals to show, filled with zeros on the right to complete the indicated size:function bcdiv(num, decimales) {
let num_str = new String(num);
let pad_ceros = new Array(decimales).fill("0").join('');
let dot = num_str.indexOf('.');
if (dot === -1) {
return num_str + '.' + pad_ceros;
}
return num_str.substring(0, dot) + num_str.substr(dot, decimales+1) + pad_ceros.substring(num_str.length - dot - 1);
}
For example:> bcdiv(12.1, 4)
'12.1000'
> bcdiv(121.319911, 2)
'121.31'
You seem to be optimizing the wrong side.Honestly, "but the code is very loud" in the cycle is no good anymore. There's a rule that if it's possible make it out of the cycle. I need you to. Do it outside the cycle.Second. If your cycle were to do a billion repetitions, then it would make sense. But you have 1,000 repetitions - forget and forget. ♪ Pessimistic prediction. It will work in a processor with at least 500 million tt/sec. Comparison of the register with memory takes two tats as I remember. ♪ ♪ Plus, on the back of the "great" cycle, plus zm, minus zm. Yeah, and how do you know what kind of dolphe this is gonna take in the compilation?
I suggest we use standard. TBits (single bulb) instead Array Of Array Of Byte and functions getBit/setBit Just count. Row and Col index (measured for getBitVIndex := FWidth * Row + Col;
Result := FArr[VIndex];
where FWidth in the designer:constructor TArr.Create(AWidth, AHeight: Integer);
begin
FArr := TBits.Create;
FArr.Size := AWidth * AHeight;
FWidth := AWidth;
FHeight := AHeight; // не обязательно
...
I mean, the standard task is to dampen a multi-dimensional body into a single-dimensional mass.Write your implementation TBitsOh, yeah. x64without the bagos and faster than the standard, maybe it's just not gonna work.P.S. As an option, you can take the TBits code and slightly adjust it to the right index, but I wouldn't recommend it. Because it's a bagamy, you have to do an extra job, and there's a significant profiling in the rapid operation that might not happen.
Separate injections simply:var inputLine = Console.ReadLine();
var parts = inputLine.Split();
var numbers = parts.Select(int.Parse).ToList();
Now you've got a list of two ( ideally) chisel, you've got to call them on the index, and put where you want:a1[i] = numbers[0];
a2[i] = numbers[1];
Notice that a laser can easily be introduced from the keyboard not necessarily two and not necessarily number. If you need to catch this case and do something meaningful, you'll need an extra logic in the code.
You created a condition to add the point in your calculator:if (valor === '.') {
var conteudo = document.getElementById('resultado').value
conteudo.includes('.') ? document.getElementById('resultado').value : document.getElementById('resultado').value += valor
}
In this condition, you check that there is already some point in the value of the input, if there is, nothing happens if there is no point is added to the input.Instead of checking if there is already a point in your entire input, you could break the value of that input into an array, in which each position contains one of the numerical values that are separated by an operator, and then check if there is already a point only in that last number:var value = '99.666+336'
var values = value.split(/[^0-9.]/)
console.log(values)Just do your own if you don't know using this array.
Since the stored data is integer, to get the last two digits you can apply the operator module % A hundred.select ano_vigencia%100 [año]
from MiTabla
The module operator returns the residue of an entire division.In 2018 divided 100, the quotient is 20 (the result of the division) and the residue is 18, which is the difference of 2018 - (20*100).
There are two modes of transmission of parameters - to put them in the glass or to record them in the registers, and the result is usually recorded in the rax/eax register.Option 1proc func1
add eax, ebx
cmp eax, ecx
jg label1
jl label2
mov eax, 0
retn
label1:
mov eax, 1
retn
label2:
mov eax, -1
retn
Option 2:proc func2
pop ecx
pop ebx
pop eax
call func1
retn
Synthaxis can get a little confused, but I hope you understand.P. S.
I found a few references.
http://devotes.narod.ru/Books/3/ch05_02a.htm
If the program is written on Net, take JetBrains dotPeek. He's gonna decompil her and create a ready project that can make changes and collect him back.
For example:P8086
MODEL TINY
DATASEG
test_string db '11 222 3333 ', 0
CODESEG
STARTUPCODE
mov di, offset test_string
push di
mov cx, -1
xor ax, ax
cld
repne scasb
not cx
dec cx ; здесь в CX получаем длину строки
pop si
xor bx, bx
skip_spaces:
lodsb
or al, al
jz finish
cmp al, ' '
jle skip_spaces
inc bx
skip_word:
or al, al
jz finish
cmp al, ' '
jle skip_spaces
lodsb
jmp short skip_word
finish:
; а здесь в BX - количество строк
ret
END
Taking into account that the first number is smaller...n = int(input("Ingrese el primer numero: "))
n2 = int(input("Ingrese elo segundo numero: "))
suma = 0;
for i in range (n, n2+1):
suma = suma + i
print("La suam es: ", suma)
When you write a console application, the compiler in the exe heading (in the so-called PE headline) displays a special flashlight that the application is console. After that, when the time comes to start the application, Windows himself will create a terminal emulsion for your application. Like he's in this Windows, it's the OS itself.When you have to make a conclusion to the console, the plus++ compilator for the vindas will just challenge the WriteConsole that can do it. There's no interruption there, and there's no interruption.The other thing is an old 16-bit code that still exists and wants to take something out. Although the files have an exe expansion, the structure is slightly different (there is no re heading but only MZ). Vinda understands it creates a similar terminal, but all interruptions intercept, deal with them and emulate them whenever possible.Therefore, while the code does the same for the user, there are two completely different systems at the internal level.
Looks like you just need to import the library for moment.do it this way:var moment = require('moment');
I have tried with a simple line to check:var diferenciafechas = moment(moment().add(15, 'days')).diff(moment(), 'days');
console.log(diferenciafechas); // 15 (resultado por consola)
