How to transform the list with dictionaries inside the line

[terrea]

Such a list

['Текст в списке вне словаря', {'Индекс 1': 'Элемент 1'}, {'Индекс 2': 'Элемент 1'}, {'Индекс 1': 'Элемент 2'}, {'Индекс 2': 'Элемент 2'}, {'Индекс 1': 'Элемент 3'}, {'Индекс 2': 'Элемент 3'}, 'Текст вне словаря']

How do you turn this into a normal line?

You should check if there's a dictionary on the list.

I tried to convert the list into a line by various methods, but because of the vocabulary inside, I couldn't make it.

[Nykeriab]

To see if there's such a code on the list of dictionaries:

data = ['Текст в списке вне словаря', {'Индекс 1': 'Элемент 1'}, {'Индекс 2': 'Элемент 1'}, {'Индекс 1': 'Элемент 2'}, {'Индекс 2': 'Элемент 2'}, {'Индекс 1': 'Элемент 3'}, {'Индекс 2': 'Элемент 3'}, 'Текст вне словаря']
dict_enabled = any(type(obj) == type(dict()) for obj in data)
print(dict_enabled)

Naturally, the code is not a classic, i.e., that if there is a dictionary on the list, it is an element of the list, not an element of the list, for example.

I don't get it on the line. I need that code.

res = []

for obj in data:

if type(obj) == type(str()):

res.append(obj)

elif type(obj) == type(dict()):

for key in obj:

res += [key, obj[key]]

text = ' '.join(res)

print(text)